I'm taking my first-ever Python class and, like most Python classes, the last assignment is to create a guessing game from 1-100 that tracks the number of VALID tries. The element that I just cannot get (or find here on stackoverflow) is how to reject invalid user input. The user input must be whole, positive digits between 1 and 100. I can get the system to reject everything except 0 and <+ 101.
The only things I can think to do end up telling me that you can't have operators comparing strings and integers. I keep wanting to use something like guess > 0 and/or guess < 101. I've also tried to create some sort of function, but can't get it to work right.
# Generate random number
import random
x = random.randint(1,100)
# Prompt user for input
print("I'm thinking of a number from 1 to 100")
counter = 0
while True:
guess = input("Try to guess my number: ")
# Check if input is a positive integer and is not 0 or >=101
# this line doesn't actually stop it from being a valid guess and
# counting against the number of tries.
if guess == "0":
print(guess, "is not a valid guess")
if guess.isdigit() == False:
print(guess, "is not a valid guess")
else:
counter += 1
guess = int(guess)
# Begin playing
if guess > x:
print(guess, "is too high.")
elif guess < x:
print(guess, "is too low.")
else:
print(guess, "is correct! You guessed my number in", counter, "tries!")
import random
x = random.randint(1,100)
# Prompt user for input
print("I'm thinking of a number from 1 to 100")
counter = 0
while True:
guess = input("Try to guess my number: ")
try:
guess = int(guess)
if(100 > guess > 0):
counter += 1
guess = int(guess)
# Begin playing
if guess > x:
print(guess, "is too high.")
elif guess < x:
print(guess, "is too low.")
else:
print(guess, "is correct! You guessed my number in", counter, "tries!")
break
else:
print("Number not in range between 0 to 100")
except:
print("Invalid input")
# Generate random number
import random
x = random.randint(1,100)
# Prompt user for input
print("I'm thinking of a number from 1 to 100")
counter = 1
while True:
try:
guess = int(input("Try to guess my number: "))
if guess > 0 and guess < 101:
print("That's not an option!")
# Begin playing
elif guess == x:
print(guess, "is correct! You guessed my number in", counter, "tries!")
break
elif guess > x:
print(guess, "is too high.")
elif guess < x:
print(guess, "is too low.")
else:
counter += 1
except:
print("That's not a valid option!")
My instructor helped me out. (I posted to keep from needing that from the guy who's giving me the grade.) Here is what we came up with. I'm posting it to help out any future Python learner that may have this particular rejecting user input problem.
Thank you guys for posting SO FAST! Even though I needed the instructor's help, I would've looked even more incompetent without your insights. Now I can actually enjoy my holiday weekend. Have a great Memorial Day weekend!!!
import random
x = random.randint(1,100)
print("I'm thinking of a number from 1 to 100.")
counter = 0
while True:
try:
guess = input("Try to guess my number: ")
guess = int(guess)
if guess < 1 or guess > 100:
raise ValueError()
counter += 1
if guess > x:
print(guess, "is too high.")
elif guess < x:
print(guess, "is too low.")
else:
print(guess, "is correct! You guessed my number in", counter, "tries!")
break
except ValueError:
print(guess, "is not a valid guess")
Related
This question already has answers here:
Asking the user for input until they give a valid response
(22 answers)
Closed 7 months ago.
I'm trying to make a simple number guessing game. I wanted to try to see if I could do this myself without looking up any answers but I'm very confused on how to keep the game going if the guess is not correct. Here is what I have so far:
import random
#ask user to guess a number:
guess = int(input("Guess a number from 0 to 100: \n"))
#create random number:
computer_number = random.randint(0, 100)
#How can i make this block of code loop to keep on giving the user tries??
if guess == computer_number:
print("You won")
elif guess > computer_number:
print("Try a lower number!")
else:
print("Try a higher number!")
import random
#ask user to guess a number:
#create random number:
computer_number = random.randint(0, 100)
#How can i make this block of code loop to keep on giving the user tries??
while True:
guess = int(input("Guess a number from 0 to 100: \n"))
if guess == computer_number:
print("You won")
break
elif guess > computer_number:
print("Try a lower number!")
else:
print("Try a higher number!")
You could use a while loop to loop the game until a condition is met.
For example:
#create random number:
computer_number = random.randint(0, 100)
while True:
#ask user to guess a number:
guess = int(input("Guess a number from 0 to 100: \n"))
#How can i make this block of code loop to keep on giving the user tries??
if guess == computer_number:
print("You won")
break
elif guess > computer_number:
print("Try a lower number!")
else:
print("Try a higher number!")
it's very easy you just need an while loop:
while condition:
#while condition True run what stands here
So the answer to your question is:
import random
#create random number:
computer_number = random.randint(0, 100)
guess = -1
#we need to firs declare the variables so we can use them in the condition
while guess != computer_number:
#ask user to guess a number:
guess = int(input("Guess a number from 0 to 100: \n"))
if guess == computer_number:
print("You won!")
elif guess > computer_number:
print("Try a lower number!")
else:
print("Try a higher number!")
My son has this project he has to do in python and is stuck.
He needs to make a number guessing game. The code must generate a random secret number between 0 and 10, then give the user 5 attempts to guess that number, each guess if not correct must indicate if it is higher or lower than the secret random number. After each guess the code needs to display text stating what has happened. The code also needs to store all guesses and display them at the end. Needs to be made using loop, if, elif, else and an array or list code.
The attempt so far is below
print("Hi there, lets play a little guessing game. Guess the number between 0 and 10")
from random import randint
x = [randint(0,10)]
counter = 0
guess = input("Enter guess:")
while counter < 5:
print("You have " + str(counter) + " guesses left")
counter = counter +1
if guess == x:
print("Congrats you got it")
break
elif guess > x:
print("Too high")
elif guess < x:
print("Too low")
else:
print("You lost")
break
Any help to correct my sons code would be appreciated as this project is due soon and he cannot access his tutor
This should do it. What the code does is explained in comments below.
You need to do x=randint(0,10) which will assign the random number to a variable, i.e x=4 rather than `x = [randint(0,10)], which assigns the random number to a list ,x=[4]```
Also you need to ask for a guess in the loop, instead of doing it only one before the loop started.
Also you would need to convert the string to an int for comparison i.e. guess = int(input("Enter guess:"))
print("Hi there, lets play a little guessing game. Guess the number between 0 and 10")
#Create a random number
from random import randint
x = randint(0, 10)
counter = 0
won = False
#Run 5 attempts in a loop
while counter<5:
#Get the guess from the user
guess = int(input("Enter guess:"))
counter = counter+1
#Check if the guess is the same, low or high as the random number
if guess == x:
print("Congrats you got it")
won = True
break
elif guess > x:
print("Too high")
elif guess < x:
print("Too low")
print("You have " + str(5 - counter) + " guesses left")
#If you didn't won, you lost
if not won:
print("The number was ", x)
print("You Lost")
So here are the corrections. So x has been initialized as array rather than an integer. So none of the comparisons with guess will be working. Also the counter logic is wrong. Rather than starting from zero, start from 5 which is the maximum number of chances and go from the reverse rather. Then at each if/elif loop append all the guesses and print it in the end.
Here is the corrected code
from random import randint
x = randint(0,10)
print(x)
counter = 5
guesses=[] #initalize an empty list to store all guesses
while counter != 0:
guess = input("Enter guess:")
if guess == x:
print("Congrats you got it")
guesses.append(guess)
break
elif guess > x:
print("Too high")
guesses.append(guess)
elif guess < x:
print("Too low")
guesses.append(guess)
else:
print("You lost")
break
counter = counter-1
print("You have " + str(counter) + " guesses left")
print(guesses)
Edit:
x = [randint(0,10)] wouldn't work as you are creating a list here instead of single guess
print("You have " + str(counter) + " guesses left") is also incorrect. You might instead set counter to 5 and check for counter > 0 and do counter -= 1, that way message can be fixed
Lastly to store all guesses you would need a variable
from random import randint
if __name__ == "__main__":
number_to_guess = randint(0,10)
guesses = []
for c in range(5,0,-1):
guessed = input("Enter guess:")
guessed = guessed.strip()
assert guessed.isnumeric()
guessed = int(guessed)
guesses.append(guessed)
if guessed == number_to_guess:
print("yes")
break
elif guessed > number_to_guess:
print("more")
else:
print("less")
c -= 1
print("pending guesses", c)
print("Expected - ", number_to_guess)
print("All guesses - ", guesses)
For a class assignment, I'm trying to make a number guessing game in which the user decides the answer and the number of guesses and then guesses the number within those limited number of turns. I'm supposed to use a while loop with an and operator, and can't use break. However, my issue is that I'm not sure how to format the program so that when the maximum number of turns is reached the program doesn't print hints (higher/lower), but rather only tells you you've lost/what the answer was. It doesn't work specifically if I choose to make the max number of guesses 1. Instead of just printing " You lose; the number was __", it also prints a hint as well. This is my best attempt that comes close to doing everything that this program is supposed to do. What am I doing wrong?
answer = int(input("What should the answer be? "))
guesses = int(input("How many guesses? "))
guess_count = 0
guess = int(input("Guess a number: "))
guess_count += 1
if answer < guess:
print("The number is lower than that.")
elif answer > guess:
print("The number is higher than that")
while guess != answer and guess_count < guesses:
guess = int(input("Guess a number: "))
guess_count += 1
if answer < guess:
print("The number is lower than that.")
elif answer > guess:
print("The number is higher than that")
if guess_count >= guesses and guess != answer:
print("You lose; the number was " + str(answer) + ".")
if guess == answer:
print("You win!")
What about something like this?
answer = int(input("What should the answer be? "))
guesses = int(input("How many guesses? "))
guess_count = 1
guess_correct = False
while guess_correct is False:
if guess_count < guesses:
guess = int(input("Guess a number: "))
if answer < guess:
print("The number is lower than that.")
elif answer > guess:
print("The number is higher than that")
else: # answer == guess
print("You win!")
break
guess_count += 1
elif guess_count == guesses:
guess = int(input("Guess a number: "))
if guess != answer:
print("You lose; the number was " + str(answer) + ".")
if guess == answer:
print("You win!")
break
It's very similar to your program, but has a couple break statements in there. This tells Python to immediately stop execution of that loop and go to the next block of code (nothing in this case). In this way you don't have to wait for the program to evaluate the conditions you specify for your while loop before starting the next loop. If this helped solve your problem, it'd be great of you to click the checkmark by my post
Implement the GuessNumber game. In this game, the computer
- Think of a random number in the range 0-50. (Hint: use the random module.)
- Repeatedly prompt the user to guess the mystery number.
- If the guess is correct, congratulate the user for winning. If the guess is incorrect, let the user know if the guess is too high or too low.
- After 5 incorrect guesses, tell the user the right answer.
The following is an example of correct input and output.
I’m thinking of a number in the range 0-50. You have five tries to
guess it.
Guess 1? 32
32 is too high
Guess 2? 18
18 is too low
Guess 3? 24
You are right! I was thinking of 24!
This is what I got so far:
import random
randomNumber = random.randrange(0,50)
print("I’m thinking of a number in the range 0-50. You have five tries to guess it.")
guessed = False
while guessed == False:
userInput = int(input("Guess 1?"))
if userInput == randomNumber:
guessed = True
print("You are right! I was thinking of" + randomNumber + "!")
elif userInput>randomNumber:
print(randomNumber + "is too high.")
elif userInput < randomNumber:
print(randomNumber + "is too low.")
elif userInput > 5:
print("Your guess is incorrect. The right answer is" + randomNumber)
print("End of program")
I've been getting a syntax error and I don't know how to make the guess increase by one when the user inputs the wrong answer like, Guess 1?, Guess 2?, Guess 3?, Guess 4?, Guess 5?, etc...
Since you know how many times you're going through the loop, and want to count them, use a for loop to control that part.
for guess_num in range(1, 6):
userInput = int(input(f"Guess {guess_num} ? "))
if userInput == randomNumber:
# insert "winner" logic here
break
# insert "still didn't guess it" logic here
Do you see how that works?
You forgot to indent the code that belongs in your while loop. Also, you want to keep track of how many times you guessed, with a variable or a loop as suggested. Also, when giving a hint you probably want to print the number guessed by the player, not the actual one. E.g.,
import random
randomNumber = random.randrange(0,50)
print("I’m thinking of a number in the range 0-50. You have five tries to guess it.")
guessed = False
count = 0
while guessed is False and count < 5:
userInput = int(input("Guess 1?"))
count += 1
if userInput == randomNumber:
guessed = True
print("You are right! I was thinking of" + randomNumber + "!")
elif userInput > randomNumber:
print(str(userInput) + " is too high.")
elif userInput < randomNumber:
print(str(userInput) + " is too low.")
if count == 5:
print("Your guess is incorrect. The right answer is" + str(randomNumber))
print("End of program")
You are facing the syntax error because you are attempting to add an integer to a string. This is not possible. To do what you want you need to convert randomNumber in each print statement.
import random
randomNumber = random.randrange(0,50)
print("I’m thinking of a number in the range 0-50. You have five tries to guess it.")
guessed = False
while guessed == False:
userInput = int(input("Guess 1?"))
if userInput == randomNumber:
guessed = True
print("You are right! I was thinking of" + str(randomNumber) + "!")
elif userInput>randomNumber:
print(str(randomNumber) + "is too high.")
elif userInput < randomNumber:
print(str(randomNumber) + "is too low.")
elif userInput > 5:
print("Your guess is incorrect. The right answer is" + randomNumber)
print("End of program")
import random
arr=[]
for i in range(50):
arr.append(i)
answer=random.choice(arr)
for trial in range(5):
guess=int(input("Please enter your guess number between 0-50. You have 5
trials to guess the number."))
if answer is guess:
print("Congratulations....You have guessed right number")
break
elif guess < answer-5:
print("You guessed too low....Try again")
elif guess > answer+5:
print("You guessed too high..Try again")
else:
print("Incorrect guess...Try again please")
print("the answer was: "+str(answer))
Just a three things to add:
The "abstract syntax tree" has a method called literal_eval that is going to do a better job of parsing numbers than int will. It's the safer way to evaluate code than using eval too. Just adopt that method, it's pythonic.
I'm liberally using format strings here, and you may choose to use them. They're fairly new to python; the reason to use them is that python strings are immutable, so doing the "This " + str(some_number) + " way" is not pythonic... I believe that it creates 4 strings in memory, but I'm not 100% on this. At least look into str.format().
The last extra treat in this is conditional assignment. The result = "low" if userInput < randomNumber else "high" line assigns "low" of the condition is met and "high" otherwise. This is only here to show off the power of the format string, but also to help contain conditional branch complexity (win and loss paths are now obvious). Probably not a concern for where you are now. But, another arrow for your quiver.
import random
from ast import literal_eval
randomNumber = random.randrange(0,50)
print("I’m thinking of a number in the range 0-50. You have five tries to guess it.")
win = False
for guess_count in range(1,6):
userInput = literal_eval(input(f"Guess {guess_count}: "))
if userInput == randomNumber:
print(f"You are right! I was thinking of {randomNumber}!")
win = True
break
else:
result = "low" if userInput < randomNumber else "high"
print(f"{userInput} is too {result}")
if win:
print ("YOU WIN!")
else:
print("Better luck next time")
print("End of program")
I am trying to create a guessing game and it works all well. However, I want to include a part where if a user puts a number above 100, you are told that your choice should be less than 100. The code below doesn't seem to do that. What am I doing wrong?
import random
comGuess = random.randint(0,100)
while True:
userGuess = int(input("Enter your guess :"))
if userGuess > comGuess:
print ("Please go lower")
elif userGuess < comGuess:
print ("Please go higher")
elif userGuess > (100):
print ("Your choice should be less than 100")
elif userGuess <1:
print ("Your choice should be less than 100")
else:
print ("Great, you got it right")
break
Any number above 100 will definitely be higher than the target, and enter the if condition. Any number below 1 will definitely be lower than the target, and enter the first elif. If you want to validate the user's input, you should do that before comparing it to comGuess:
if userGuess > (100):
print ("Your choice should be less than 100")
elif userGuess <1:
print ("Your choice should be less than 100")
elif userGuess > comGuess:
print ("Please go lower")
elif userGuess < comGuess:
print ("Please go higher")
else:
print ("Great, you got it right")
break
Your first if statement is catching anything greater than comGuess, even if it's also over 100, and so the elif userGuess > (100) that comes later never gets a chance to fire. Either move that elif up, or change the first if statement to something like if (userGuess > comGuess) and (userGuess <= 100).