I am trying to click on the "chercher" button on the left of the page (middle).
url = "https://www.fpjq.org/repertoires/repertoire-des-medias/"
driver = webdriver.Firefox()
driver.get(url)
time.sleep(2)
driver.find_element_by_xpath('//*[#id="recherche"]/input[3]').click()
However, it can't find the element. I copy pasted the XPath so I am not sure why it's not working.
Thanks.
That's because required button located inside an iframe and to be able to click it you need to switch to that iframe:
url = "https://www.fpjq.org/repertoires/repertoire-des-medias/"
driver = webdriver.Firefox()
driver.get(url)
time.sleep(2)
driver.switch_to.frame(driver.find_element_by_tag_name("iframe"))
driver.find_element_by_xpath('//*[#id="recherche"]/input[3]').click()
Also note that using time.sleep() is not a good practice. You can try to implement Explicitwait instead
Related
I am trying to click to an object that I select with Xpath, but there seems to be problem that I could not located the element. I am trying to click accept on the page's "Terms of Use" button. The code I have written is as
driver.get(link)
accept_button = driver.find_element_by_xpath('//*[#id="terms-ok"]')
accept_button.click()
prov = driver.find_element_by_id("province-region")
prov.click()
Here is the HTML code I have:
And I am getting a "NoSuchElementException". My goal is to click this "Kabul Ediyorum" button at the bottom of the HTML code. I started to think that we have some restrictions on the tasks we could do on that page. Any ideas ?
Not really sure what the issue might be.
But you could try the following:
Try to locate the element by its visible text
accept_button = driver.find_element_by_xpath("//*[text()='Kabul Ediyorum']").click()
Try with ActionChains
For that you need to import ActionChains
from selenium.webdriver.common.action_chains import ActionChains
accept_button = driver.find_element_by_xpath("//*[text()='Kabul Ediyorum']")
actions = ActionChains(driver)
actions.click(on_element=accept_button).perform()
Also make sure you have implicitly wait
# implicitly wait
driver.implicitly_wait(10)
Or explicit wait
element = WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//*[text()='Kabul Ediyorum']"))).click()
Hope this helped!
I am trying to click on the navigation tab 'MPass' however, it doesn't work.
https://www.gv.com.sg/GVMovies
nav = driver.find_element_by_css_selector('ul.nav.nav-tabs')
tabs = nav.find_elements_by_css_selector('a.ng-binding')[1]
tabs.click()
error
[overview][2]
Try using full XPath:
I am using Firefox web-driver(You can download it from here):
from selenium import webdriver
site = 'https://www.gv.com.sg/GVMovies'
#providing driver path
driver = webdriver.Firefox(executable_path = 'C:\Drivers\geckodriver.exe')
driver.get(site)
try:
driver.find_element_by_xpath("/html/body/div[3]/div[2]/div/div/div[2]/div/ul/li[2]/a").click()
except Exception as e:
pass
Make sure you are waiting for the element to load and visible in the dom.
and then use find_element_by_css_selector
selector = driver.find_element_by_css_selector("li[select=\"changeTab('M Pass Movies')\"]")
selector.click()
or
selector = driver.find_elements_by_css_selector("li[class='tab-pane ng-isolate-scope']")[0]
You could just invoke click on the a tag with M Pass Movies and bypass the element in front.
nav = driver.find_element_by_css_selector('ul.nav.nav-tabs')
tab = nav.find_element_by_xpath("//*[text()='M Pass Movies']")
driver.execute_script("arguments[0].click();", tab)
I am scraping an angular.js site. My initial link has a search button. I find by xpath and click with no issues. After I click search, I want to be able to click each of the athletes in the table to go to their info pages, but I am not having success with the click method. The links are attached to their names.
from selenium import webdriver
from selenium.common.exceptions import TimeoutException
TIMEOUT = 5
driver = webdriver.Firefox()
driver.set_page_load_timeout(TIMEOUT)
url = 'https://n.rivals.com/search#?formValues=%7B%22sport%22:%22Football%22,%22recruit_year%22:2021,%22offer_and_visit_type%22:%5B%22Offer%22%5D,%22prospect_profiles.prospect_colleges.offer%22:true,%22page_number%22:1,%22page_size%22:50%7D'
try:
driver.get(url)
except TimeoutException:
pass
search_button = driver.find_element_by_xpath('//*[#id="articles"]/div/div[2]/div/div/div[1]/form/div[2]/div[5]/button')
search_button.click();
#below is where I tried, but could not get to click
first_athlete = driver.find_element_by_xpath('//*[#id="content_"]/td[1]/div[2]/a')
first_athlete.click();
Works if you remove the last /a in the xpath:
first_athlete = driver.find_element_by_xpath('//*[#id="content_"]/td[1]/div[2]')
first_athlete.click()
If you want to search for all athletes and you have the name of athletes with you, you can use CSS selector as well.
athelete = driver.find_elements_by_css_selector(`#content_ > td > div > a[href *="donovan-jackson"]);
athelete.click();
This code will give you a unique web element for each player.
Thanks
My Python Selenium can't click target element, instead seem click element behind target element?
I try to click, or enter text in 'drop-down meun', but I find that I am result in clicking element behind this 'drop-down. I know this is element behind it, because there is advistering area behind, and the result top-up showing the same advistering material. Here is my code:
# info for login
my_email = 'my_email'
my_passcode = 'my_passcode'
email_url = r'https://www.gmx.com/#.1559516-header-navlogin2-1'
# start driver and open url
driver = webdriver.Chrome(chrome_path)
driver.get(email_url)
# input email account
xpath = r'//*[#id="login-email"]'
WebDriverWait(driver, 10).until(EC.presence_of_element_located((By.XPATH, xpath)))
target = driver.find_element_by_xpath(xpath)
actions = ActionChains(driver)
actions.move_to_element(target).perform()
actions.click().send_keys(my_email).perform()
# input passcode and hit 'enter' to login
xpath = r'//input[#id="login-password"]'
WebDriverWait(driver, 10).until(EC.presence_of_element_located((By.XPATH, xpath)))
target = driver.find_element_by_xpath(xpath)
actions = ActionChains(driver)
actions.move_to_element(target).perform()
actions.click().send_keys(my_passcode).send_keys(Keys.ENTER).perform()
It happens to me for some other site when the site appear to have 'two layers' (not sure if I am using the right word). I can process anything on top layer, and only result in activate anything behind it. Many thank when provide solution!!
You don't need to use this ActionChains class, all you need to do can be done using WebElement.send_keys() and WebElement.click()
You don't need to re-find the element after using WebDriverWait as it returns the WebElement in case of success
I fail to see clickign on login button anywhere in your script, you can locate the relevant button using XPath contains() function like:
xpath = r'//button[contains(#class,"login-submit")]'
and then just call click() function on the resulting variable
Example suggested code:
You don't need to use this ActionChains class, all you need to do can be done using WebElement.send_keys() and WebElement.click()
You don't need to re-find the element after using WebDriverWait as it returns the WebElement in case of success
I fail to see clickign on login button anywhere in your script, you can locate the relevant button using XPath contains() function like:
xpath = r'//button[contains(#class,"login-submit")]'
and then just call click() function on the resulting variable
Example suggested code:
# input email account
xpath = r'//*[#id="login-email"]'
target = WebDriverWait(driver, 10).until(EC.presence_of_element_located((By.XPATH, xpath)))
target.send_keys(my_email)
# input passcode and hit 'enter' to login
xpath = r'//input[#id="login-password"]'
target = WebDriverWait(driver, 10).until(EC.presence_of_element_located((By.XPATH, xpath)))
target.send_keys(my_passcode)
xpath = r'//button[contains(#class,"login-submit")]'
target = WebDriverWait(driver, 10).until(EC.presence_of_element_located((By.XPATH, xpath)))
target.click()
I am trying to access an iframe within an iframe using Selenium, Python, and BS4
from bs4 import BeautifulSoup
from selenium import webdriver
import time
import html5lib
driver = webdriver.Firefox()
driver.implicitly_wait(10)
driver.get('http://myurl.com')
try:
time.sleep(4)
iframe = driver.find_elements_by_tag_name('iframe')[0]
driver.switch_to_default_content()
driver.switch_to_frame(iframe)
driver.switch_to_default_content()
driver.find_elements_by_tag_name('iframe')[0]
output = driver.page_source
print output
finally:
driver.quit();
Within the returned text, there appears to be two more iframes. How would I access those? I have attempted in the code above without success.
switch_to_default_content() will return you to the top of the document. What was happening is you switched into the first iframe, switched back to the top of the document, then tried to find the second iframe. Selenium can't find the second iframe, because it's inside of the first iframe.
If you remove the second switch_to_default_content() you should be fine:
iframe = driver.find_elements_by_tag_name('iframe')[0]
driver.switch_to.default_content()
driver.switch_to.frame(iframe)
driver.find_elements_by_tag_name('iframe')[0]