I'm trying to do a guessing game in python but I cant figure some stuff out. I have to enter a word and it will print a lot of spaces and the person is suppose to guess the word. It has to look like this after the word it's been typed. The user will enter a letter and is suppose to look like this (word is dog):
Enter a letter: a
So far you have:
***
if they guess the "o" for example, it will replace the * with an 'o' and so on until you get all the words right. And that's what I can't figure out, can somebody please help me? here is my program for far:
def main():
letters_guessed = set()
# Read word
word = input("\n Please Enter a word: ")
# print 100 spaces
print("\n" * 100)
# Storing the length of the word
word_length = len(word)
guess = '*' * word_length
while True:
print ("So far you have: ",
guess_letter = input ("Please guess a letter: ")
if len(guess_letter) != 1:
print ("Please guess one letter at a time")
if guess_letter in letters_guessed:
print ("\n You already guessed that letter, please try again")
letters_guessed.add(guess_letter)
if set(word) == set(letters_guessed):
break
print("You won, the word is " % word)
Somebody tried to help me but I just didn't understand how this works because I am new to the program, I want to be able to understand it also. Thank you. Here it was his output, just part of it.
while True:
print ("So far you have: ", "".join([c if c in letters_guessed else "*"
for c in word]))
guess_letter = input ("Please guess a letter: ")
I'll first explain the solution code you received. The following code:
[c if c in letters_guessed else "*" for c in word]
generates a list. If you see square brackets [ and ] , then we're list likely creating a list.
now what your friend is using is a generator. It's a short way of creating a for loop. In other words, this would do the same thing.
word = "dog"
letter_guessed = "go"
ourList = list() #new list
for letter in word: #we check every letter in the word
if letter in letter_guessed: #if our letter has been guessed
ourList.append(letter) # we can show that letter in our word
else:
ourList.append("*") # if the letter has not been guessed, we should
# not show that letter in our word, and thus we change it to a *
print(ourList)
This gives us the following list: ["*", "o", "g"]
What your friend then does, is take that list, and use join:
"".join[ourList]
This is a good way of turning a list of letters back into a string.
See: https://www.tutorialspoint.com/python/string_join.htm
Your own code has a few problems. Is it possible you didn't copy everything?
In python, using tabs effects the way your program runs. Because you put a tab before
print("You won, the word is " % word)
you'll run this line every single time, rather than only when the break statement is activated!
You have a similar problem with .add! Try to see if you can't spot it yourself.
I also recommend writing
print("You won, the word is " + word)
because this is much easier to use. (for more advanced formatting, look up .format() see https://pyformat.info/
Related
I am in high school and am currently teaching myself Python. I am programming Hangman and it is going well so far (it is not very organized yet) but I am having a problem. I created a list of words that I would use for the game and replaced them with asterisks using the range function. Here is the code for that:
words = ['utopia', 'prosecute', 'delirious', 'superficial', 'fowl', 'abhorrent', 'divergent',
'noxious', 'scarce','lavish', 'hinder', 'onerous', 'colossal', 'infringe']
picked_words = random.choice(words)
for i in range(len(picked_words)):
print(picked_words.replace(picked_words,'*'), end = '')
I am at the point where I am guessing the letters and I need to slowly reveal the position of certain letters. I have tried looking for certain functions (I even thought that the find() function would work since it prints the location of a letter in a string but it did not) and I am at a loss. Especially for words with multiples of the same letter such as "onerous" and "infringe." I will write the code that I have so far for this section:
def right_letter(correct):
if correct == True:
print("There are {} {}'s.".format(number_of_char, guess))
for x in range(len(picked_words)):
print(picked_words.replace(picked_words,guess, #find way to fill in specific letters),end = '')
I have no clue what parts of the code are necessary to get an answer but my code is really unorganized because I do not know proper techniques yet. The portion that says for x in range(len(picked_words))... is where I am having trouble. The rest of the code ran fine before I added the print statement underneath it. Basically I am asking how to change a certain character or specific characters and put them where they belong. For example, if the randomized word was "infringe" and the first guess was "i" how do I go from ******** to i***i***?
Also, in case anyone was wondering what I originally thought the solution was...
picked_words[(picked_words.find(guess))]
I thought that it would simplify and become picked_words[index]
Here's an example of converting your code to the hangman game.
Note how variable display in the code is updated to show user the correct guessed letters.
import random
def hangman():
words = ['utopia', 'prosecute', 'delirious', 'superficial', 'fowl', 'abhorrent', 'divergent',
'noxious', 'scarce','lavish', 'hinder', 'onerous', 'colossal', 'infringe']
max_guesses = 5
word = random.choice(words)
guesses = 0
display = "*" * len(word)
print(display, " Is the word")
while guesses < max_guesses:
letter = input("Please Enter Your guess letter: ")
if letter.lower() not in word:
guesses += 1
print("You got it incorrect, you have: ", max_guesses - guesses , " Additional trials")
else:
print("Right guess!")
new_display = ''
for w, l in zip(word, display):
if letter.lower() == w:
new_display += letter.lower()
else:
new_display += l
display = new_display
print(display)
if not '*' in display:
print("You won!")
return
hangman()
Basically you will need to find a partial match between your letter and the word here.
The easiest way i can think of is Pythons in Operator. It can be used like this
if picked_letter in picked words
% here you need to figure out at which position(s) the letter in your word occurs
% and then replace the * at the correct positions. A nice way to do this is
% the use of regular expressions
picked_words = re.sub('[^[^picked_letter]*$]', '*', picked_words)
%this will replace every letter in your word with the Asterisk except for the one picked
else
%do Nothing
Note that running this Code in a loop would replace every character in your string except the picked one EVERY time., therefore it is probably best to design your picked_letter as a list containing all characters that have been picked so far. This also makes it easier to check wether a letter has already been entered.
I am currently writing code for an interactive game of hangman. I have been given code to select a word at random, which I have then assigned to 'X' and made into a list.
I would like to be able to display a list of hyphens (correct_guesses) where the correct guesses are filled in in the correct place.
For example: if the word is 'glass', and the user guesses 'a', the computer displays "Good guess! [ - - a - -]" or something similar.
I'm not quite sure how to replace the hyphens with the correct guesses as the game goes on, or if I should I be approaching this in a different manner.
I apologize that this isn't very well articulated; I'm very new to coding.
I've included my code below.
X = random.choice(wordlist)
X.split()
print "Welcome to Hangman."
print "I've chosen a word that is", len(X), "letters long. Can you guess it? You have", (len(X) + 5 ), "guesses."
alphabet = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
correct_guesses = [(len(X))*'-']
guess = raw_input('Guess a letter.')
for guess in alphabet:
if guess in alphabet:
alphabet.remove(guess)
for guess in X:
if guess in X:
print 'Good guess!'
break
else:
print 'Nope! Try again.'
break
break
else:
print "You have already guesssed that letter, try again."
Keep track of all the letters that have been guessed, then do:
masked_letters = ''.join([if c in guessed then c else '-' for c in chosen_word])
I'm currently learning Python and trying to build a set of minigames to solidify my basic knowledge, however there are a few things I want to do with my game that others on here haven't (from what I've seen, at least), and that is remove whitespace between words from the answer and the "masked" answer. I assume it would be done as an "if, else" sort of statement? Please correct me if I'm wrong.
for x in range(i): ## where i is the word
if x == " ":
continue ## wouldn't it be pointless to append something that you don't want to change?
else:
word.append('_')
Another question I had was regarding a loop statement I have at the beginning of my game, within this loop I have an if/else stating that if there are more than 1 letter in the guess, it'll return a statement telling the user that's not valid. But the game immediately stops working afterword.
while guesses < 6:
guess = raw_input("Please guess a letter: ")
if len(guess) > 1:
return "One letter at a time!"
else: continue
I'm not quite sure what to add to my code to make it continue asking for input after this.
Here's my full code, it's currently not working for me after asking for input... I took the code it from another user on here and fixed it to my tastes, since their game didn't use more than one word and didn't check to see if there was more than one letter being input when prompted, and I figured it would be good practice to modify existing code to make it do a bit more than it originally does.
def hangman():
guesses = 0
word = []
guessed = []
words = ["bichon frise", "maltese", "dachshund", "pomeranian", "golden retriever", "shih tzu", "rottweiler", "pit bull", "beagle", "poodle", "akita", "basset hound", "border collie", "boston terrier", "boxer", "bulldog", "chow chow", "chihuahua", "chinese crested", "french bulldog", "great dane", "great pyrenees", "greyhound", "icelandic sheepdog", "irish wolfhound", "komondor", "mastiff", "shnauzer", "pekingese", "welsh corgi", "redhound coonhound", "samoyed", "shiba inu", "weimaraner", "whippet", "italian greyhound", "yorkshire terrier"]
print "Welcome to Hangman. The words chosen are the names of various breeds of dogs, try and guess the word before the man is hung!"
answer = random.choice(words)
i = len(answer)
print "The length of the word is", i, "characters long"
for x in range(i):
if x == " ":
continue
else:
word.append('_')
while guesses < 6:
guess = raw_input("Please guess a letter: ")
if len(guess) > 1:
return "One letter at a time!"
else:
continue
if (guess in i):
print "The letter is in the word."
for index, letter in enumerate(i):
if letter == guess:
word[index] = guess
guessed.append(guess)
else:
print "The letter is not in the word"
guesses = guesses + 1
guessed.append(guess)
print "You have guessed these letters so far: %s)" % (''.join(guessed))
print "Letters matched so far %s): %" (''.join(word))
if ''.join(word) == answer:
break
if guesses == 6:
print "You didn't guess the right answer in time! The answer was %s" % answer
else:
print "You guessed the word!"
remove whitespace between words from the answer.
Given i (i as a string?) is the string, you probably should not use range(..) on it since range expects an int. Furthermore why do you build a list instead of a new string? You can however easily use a generator:
word = ''.join(c for c in i if c != ' ')
word is here a string that contains all characters of i that are not ' '. If you want however to generate a sequence of underscores, you can use:
word = ''.join('_' for c in i if c != ' ')
If you want to construct a list (which the remainder of the code expects), you can use list comprehension:
word = ['_' for c in i if c != ' ']
it'll return a statement telling the user that's not valid. But the game immediately stops working afterword (sic.).
That's because you use a return statement: return means you jump out of the function and (optionally) return a value. You probably want to print(..):
guesses = 0
while guesses < 6:
guess = raw_input("Please guess a letter: ")
if len(guess) > 1:
print("One letter at a time!")
else:
#process char
continue
I also noticed you use continue. continue means that you abandon the remainder of the iteration and take the next one, so it means you will not process the query. So you have to remove the continue part:
while guesses < 6:
guess = raw_input("Please guess a letter: ")
if len(guess) > 1:
print("One letter at a time!")
return ends the function right there, use print instead:
print "One letter at a time!"
As for the whitespace, why don't you append the space to the masked word? That way, the player won't have to guess it, can see that there are spaces, and your join-check will work:
for x in range(i):
if x == " ":
word.append(' ')
else:
word.append('_')
Im working on a word game. The purpose for the user is to guess a 5 letter word in 5 attempts. The user can know the first letter. And if he doesn't get the word correct, but if he has a letter in the correct place he gets to know this.
This is my code:
import random
list_of_words = ["apple","table", "words", "beers", "plural", "hands"]
word = random.choice(list_of_words)
attempts = 5
for attempt in range(attempts):
if attempt == 0:
tempList = list(word[0] + ("." * 4))
print("The first letter of the word we are looking for: %s" % "".join(tempList))
answer = raw_input("What is the word we are looking for?:")
if len(answer) != 5:
print ('Please enter a 5 letter word')
Else:
if answer != word:
wordlist = list(word)
answerlist = list(answer)
for i in range(min(len(wordlist), len(answerlist))):
if wordlist[i] == answerlist[i]:
tempList[i] = wordlist[i]
print(tempList)
else:
print("correct, you have guessed the word in:", attempt, "attempts")
if answer != word:
print("Sorry maximum number of tries, the word is: %s" % word)
I have two questions about this code:
The first one is a small problem: If the user gives a 6 or 4 letter word it will still print the word. While I'd rather have it that the word is just ignored and the attempt isnt used..
If a letter is given correct (and also the first letter) it doesnt become a standard part of the feedback. Trying to get this with temp but of yet its not working great.
Any suggestions to clean up my code are also appreciated!
Thanks for your attention
I made some changes in your code, now it's working according to your specification. I also wrote a couple of explaining comments in it:
import random
list_of_words = ["apple", "table", "words", "beers", "plural", "hands"]
word = random.choice(list_of_words)
# changed the loop to a 'while', because i don't want to count the invalid length answers
# and wanted to exit the loop, when the user guessed correctly
attempts = 5
attempt = 0
correct = False
while attempt < attempts and not correct:
if attempt == 0:
# i stored a working copy of the initial hint (ex: "w....")
# i'll use this to store the previously correctrly guessed letters
tempList = list(word[0] + ("." * 4))
print("The first letter of the word we are looking for: %s" % "".join(tempList))
answer = raw_input("What is the word we are looking for?:")
if len(answer) != 5:
print("Please enter a 5 letter word")
else:
if answer != word:
# i simplified this loop to comparing the wordlist and answerlist and update templist accordingly
wordlist = list(word)
answerlist = list(answer)
for i in range(min(len(wordlist), len(answerlist))):
if wordlist[i] == answerlist[i]:
tempList[i] = wordlist[i]
print(tempList)
else:
correct = True
print("Correct, you have guessed the word in %s attempts" % (attempt + 1))
attempt += 1
if answer != word:
# also i used string formatting on your prints, so is prints as a string, and not as a tuple.
print("Sorry maximum number of tries, the word is: %s" % word)
There are several problems with the code.
Just 1 for now. I notice in the sample output you are entering five letter words (beeds and bread) and it still prints out Please enter a 5 letter word.
These two lines:
if len(answer) != 4:
print ('Please enter a 5 letter word')
Surely this should be:
if len(answer) != 5:
print ('Please enter a 5 letter word')
continue
This would catch an invalid input and go round the loop again.
Answering your specific questions:
You will need to have a for loop around your input, keeping the user in that loop until they enter a word of appropriate length
If you move guessed letters to the correct places, it is trivial to win by guessing "abcde" then "fghij", etc. You need to think carefully about what your rules will be; you could have a separate list of "letters in the guess that are in the answer but in the wrong place" and show the user this.
To keep the display version with all previously-guessed characters, keep a list of the display characters: display = ["." for letter in answer], and update this as you go.
Other problems you have:
Too much hard-coding of word length (especially as len("plural") != 5); you should rewrite your code to use the length of the word (this makes it more flexible).
You only tell the user they've won if they guess the whole answer. What if they get to it with overlapping letters? You could test as if all(letter != "." for letter in display): to see if they have got to the answer that way.
Your list comprehension [i for i in answer if answer in word] is never assigned to anything.
I am new to Python. I am writing a program that distinguishes whether or not a word starts with a vowel. The problem is, that the program is only able to correctly handle uppercase letters as input. For example, if I provide the word "Apple" as input, the result is True; however, if the word "apple" is provided as input, the result is False. How do I fix it?
word = input ("Please Enter a word:")
if (word [1] =="A") :
print("The word begins with a vowel")
elif (word [1] == "E") :
print("The word begins with a vowel")
elif (word [1] == "I") :
print("The word begins with a vowel")
elif (word [1] == "O") :
print("The word begins with a vowel")
elif (word [1] == "U") :
print("The word begins with a vowel")
else:
print ("The word do not begin with a vowel")
Convert the word entirely to lowercase (or uppercase) first:
word = input("Please Enter a word:").lower() # Or `.upper()`
Also, to get the first letter of your word, use word[0], not word[1]. Lists are zero-indexed in Python and almost all programming languages.
You can also condense your code by quite a bit:
word = input("Please Enter a word:")
if word[0].lower() in 'aeiou':
print("The word begins with a vowel")
else:
print("The word do not begin with a vowel")
Usually you would use str.lower() (or str.upper()) on the input to normalise it.
Python3.3 has a new method called str.casefold() which works properly for unicode
You should use:
word[i] in 'AEIOUaeiou'
You could convert the input to upper case before comparing.
The check for vowels is done using str.startswith which can accept a tuple of multiple values. PEP 8 Style Guide for Python Code recommends the use of startswith with over string slicing for better readability of code:
Use ''.startswith() and ''.endswith() instead of string slicing to
check for prefixes or suffixes.
Conditional Expressions are used to set the message indicating whether the word starts with a vowel or not. Then I used the String Formatting method to prepare the message. Also just as a English grammar correction thing I replaced the sentence "The word do not begin with a vowel" with "The word does not begin with a vowel".
word = input("Please Enter a word:")
is_vowel = 'does' if word.lower().startswith(tuple('aeiou')) else 'does not'
print("The word {} begin with a vowel".format(is_vowel))
You are checking only for the upper case in your code. One way would be to convert any input by the user to upper case and your current code will work. That can be easily be done by changing your code like so ...
word = input("Please Enter a word: ").upper()
You also need to use word[0], instead of word[1] to get the first letter out. The rest of the code could be like this:
if word [0] in "AEIOU" :
print("The word begins with a vowel")
else:
print ("The word does not begin with a vowel")
This will make the first letter in upper case and the rest will remain as is.
swim_wait = input("Alright you reach the river.Do you want to
Swim or Wait\n")
swim_wa = swim_wait.lower()
I am using .lower() to convert user input to lower in program and this was convenient in dealing with input. You can also using .upper()
but I think that you cannot use both at same time ok .
I have written a code for a simple game run it I hope you will understand
print("Welcome to Treasure Island\nYour Mission is to Find the Treasure\n")
choice1 = input('You are at the crossroad ,where do you want to go.Type "left" or "right".\n').lower()
if choice1 == "left":
choice2 = input(
'You\'ve come to a lake.There os a island in the middle of the lake.Type "wait"to wait for the boat.Type "swim" to sim across\n').lower()
if choice2 == "wait":
choice3 = input(
"You arrive at the island unharmed. There is a house with 3 doors. One red, one yellow, and one blue. Which color do you choose?\n").lower()
if choice3 == "red":
print("Its room full of fire. Game Over!")
elif choice3 == "yellow":
print("You found the treasure you won!")
elif choice3 == "blue":
print("You enter a room of beasts.Game over!")
else:
print("You chosen the wrong door. Game over!")
If there is some indentation error in the code use tab and reformat the line of code I don't know how to exactly write code on StackOverflow as I am new here