MRI (brain tumor) image processing and segmentation, skull removing - python

I need help for image segmentation. I have a MRI image of brain with tumor. I need to remove cranium (skull) from MRI and then segment only tumor object. How could I do that in python? with image processing. I have tried make contours, but I don't know how to find and remove the largest contour and get only brain without a skull.
Thank's a lot.
def get_brain(img):
row_size = img.shape[0]
col_size = img.shape[1]
mean = np.mean(img)
std = np.std(img)
img = img - mean
img = img / std
middle = img[int(col_size / 5):int(col_size / 5 * 4), int(row_size / 5):int(row_size / 5 * 4)]
mean = np.mean(middle)
max = np.max(img)
min = np.min(img)
img[img == max] = mean
img[img == min] = mean
kmeans = KMeans(n_clusters=2).fit(np.reshape(middle, [np.prod(middle.shape), 1]))
centers = sorted(kmeans.cluster_centers_.flatten())
threshold = np.mean(centers)
thresh_img = np.where(img < threshold, 1.0, 0.0) # threshold the image
eroded = morphology.erosion(thresh_img, np.ones([3, 3]))
dilation = morphology.dilation(eroded, np.ones([5, 5]))
These images are similar to the ones I'm looking at:
Thanks for answers.

Preliminaries
Some preliminary code:
%matplotlib inline
import numpy as np
import cv2
from matplotlib import pyplot as plt
from skimage.morphology import extrema
from skimage.morphology import watershed as skwater
def ShowImage(title,img,ctype):
plt.figure(figsize=(10, 10))
if ctype=='bgr':
b,g,r = cv2.split(img) # get b,g,r
rgb_img = cv2.merge([r,g,b]) # switch it to rgb
plt.imshow(rgb_img)
elif ctype=='hsv':
rgb = cv2.cvtColor(img,cv2.COLOR_HSV2RGB)
plt.imshow(rgb)
elif ctype=='gray':
plt.imshow(img,cmap='gray')
elif ctype=='rgb':
plt.imshow(img)
else:
raise Exception("Unknown colour type")
plt.axis('off')
plt.title(title)
plt.show()
For reference, here's one of the brain+skulls you linked to:
#Read in image
img = cv2.imread('brain.png')
gray = cv2.cvtColor(img,cv2.COLOR_BGR2GRAY)
ShowImage('Brain with Skull',gray,'gray')
Extracting a Mask
If the pixels in the image can be classified into two different intensity classes, that is, if they have a bimodal histogram, then Otsu's method can be used to threshold them into a binary mask. Let's check that assumption.
#Make a histogram of the intensities in the grayscale image
plt.hist(gray.ravel(),256)
plt.show()
Okay, the data is nicely bimodal. Let's apply the threshold and see how we do.
#Threshold the image to binary using Otsu's method
ret, thresh = cv2.threshold(gray,0,255,cv2.THRESH_OTSU)
ShowImage('Applying Otsu',thresh,'gray')
Things are easier to see if we overlay our mask onto the original image
colormask = np.zeros(img.shape, dtype=np.uint8)
colormask[thresh!=0] = np.array((0,0,255))
blended = cv2.addWeighted(img,0.7,colormask,0.1,0)
ShowImage('Blended', blended, 'bgr')
Extracting the Brain
The overlap of the brain (shown in red) with the mask is so perfect, that we'll stop right here. To do so, let's extract the connected components and find the largest one, which will be the brain.
ret, markers = cv2.connectedComponents(thresh)
#Get the area taken by each component. Ignore label 0 since this is the background.
marker_area = [np.sum(markers==m) for m in range(np.max(markers)) if m!=0]
#Get label of largest component by area
largest_component = np.argmax(marker_area)+1 #Add 1 since we dropped zero above
#Get pixels which correspond to the brain
brain_mask = markers==largest_component
brain_out = img.copy()
#In a copy of the original image, clear those pixels that don't correspond to the brain
brain_out[brain_mask==False] = (0,0,0)
ShowImage('Connected Components',brain_out,'rgb')
Considering the Second Brain
Running this again with your second image produces a mask with many holes:
We can close many of these holes using a closing transformation:
brain_mask = np.uint8(brain_mask)
kernel = np.ones((8,8),np.uint8)
closing = cv2.morphologyEx(brain_mask, cv2.MORPH_CLOSE, kernel)
ShowImage('Closing', closing, 'gray')
We can now extract the brain:
brain_out = img.copy()
#In a copy of the original image, clear those pixels that don't correspond to the brain
brain_out[closing==False] = (0,0,0)
ShowImage('Connected Components',brain_out,'rgb')
If you need to cite this for some reason:
Richard Barnes. (2018). Using Otsu's method for skull-brain segmentation (v1.0.1). Zenodo. https://doi.org/10.5281/zenodo.6042312

Have you perhaps tried to use python skull_stripping.py
You can modify the parameters but it normally works good.
There are some new studies using deep learning for skull stripping which I found it interesting:
https://github.com/mateuszbuda/brain-segmentation/tree/master/skull-stripping

# -*- coding: utf-8 -*-
"""
Created on Wed Jul 28 17:10:56 2021
#author: K Somasundaram, ka.somasundaram#gmail.com
"""
import numpy as npy
from skimage.filters import threshold_otsu
from skimage import measure
# import image reading module image from matplotlib
import matplotlib.image as img
#import image ploting module pyplot from matplotlib
import matplotlib.pyplot as plt
inim=img.imread('015.bmp')
#Find the dimension of the input image
dimn=inim.shape
print('dim=',dimn)
plt.figure(1)
plt.imshow(inim)
#-----------------------------------------------
# Find a threshold for the image using Otsu method in filters
th=threshold_otsu(inim)
print('Threshold = ',th)
# Binarize using threshold th
binim1=inim>th
plt.figure(2)
plt.imshow(binim1)
#--------------------------------------------------
# Erode the binary image with a structuring element
from skimage.morphology import disk
import skimage.morphology as morph
#Erode it with a radius of 5
eroded_image=morph.erosion(binim1,disk(3))
plt.figure(3)
plt.imshow(eroded_image)
#---------------------------------------------
#------------------------------------------------
# label the binar image
labelimg=measure.label(eroded_image,background=0)
plt.figure(4)
plt.imshow(labelimg)
#--------------------------------------------------
# Find area of the connected regiond
prop=measure.regionprops(labelimg)
# Find the number of objecte in the image
ncount=len(prop)
print ( 'Number of regions=',ncount)
#-----------------------------------------------------
# Find the LLC index
argmax=0
maxarea=0
#Find the largets connected region
for i in range(ncount):
if(prop[i].area >maxarea):
maxarea=prop[i].area
argmax=i
print('max area=',maxarea,'arg max=',argmax)
print('values=',[region.area for region in prop])
# Take only the largest connected region
# Generate a mask of size of th einput image with all zeros
bmask=npy.zeros(inim.shape,dtype=npy.uint8)
# Set all pixel values in whole image to the LCC index to 1
bmask[labelimg == (argmax+1)] =1
plt.figure(5)
plt.imshow(bmask)
#------------------------------------------------
#Dilate the isolated region to recover the pixels lost in erosion
dilated_mask=morph.dilation(bmask,disk(6))
plt.figure(6)
plt.imshow(dilated_mask)
#---------------------------------------
# Extract the brain using the barinmask
brain=inim*dilated_mask
plt.figure(7)
plt.imshow(brain)
-----------------------------------------
Input Image
--------------------

Related

Auto-crop the image, and extract the area of interest from image

I want to crop image automatically, it means I don't want to specify the pixels or coordinates each time, the module/code which should detect the object (i.e. area of interest) and extract it from an image.
Or there is any algorithm to crop desired part from image (Area of Interest)
[for example my image contains two part one is white and other is in RGB form, but I want only the RGB form part from complete image].
I have also tried below code, but it was not helpful.
from PIL import Image
from skimage.io import imread
from skimage.morphology import convex_hull_image
im = imread('L_2d.jpg')
plt.imshow(im)
plt.title('input image')
plt.show()
# create a binary image
im1 = 1 - rgb2gray(im)
threshold = 0.5
im1[im1 <= threshold] = 0
im1[im1 > threshold] = 1
chull = convex_hull_image(im1)
plt.imshow(chull)
plt.title('convex hull in the binary image')
plt.show()
imageBox = Image.fromarray((chull*255).astype(np.uint8)).getbbox()
cropped = Image.fromarray(im).crop(imageBox)
cropped.save('L_2d_cropped.jpg')
plt.imshow(cropped)
plt.show()

Get mask of image without using OpenCV

I'm trying the following to get the mask out of this image, but unfortunately I fail.
import numpy as np
import skimage.color
import skimage.filters
import skimage.io
# get filename, sigma, and threshold value from command line
filename = 'pathToImage'
# read and display the original image
image = skimage.io.imread(fname=filename)
skimage.io.imshow(image)
# blur and grayscale before thresholding
blur = skimage.color.rgb2gray(image)
blur = skimage.filters.gaussian(blur, sigma=2)
# perform inverse binary thresholding
mask = blur < 0.8
# use the mask to select the "interesting" part of the image
sel = np.ones_like(image)
sel[mask] = image[mask]
# display the result
skimage.io.imshow(sel)
How can I obtain the mask?
Is there a general approach that would work for this image as well. without custom fine-tuning and changing parameters?
Apply high contrast (maximum possible value)
convert to black & white image using high threshold (I've used 250)
min filter (value=8)
max filter (value=8)
Here is how you can get a rough mask using only the skimage library methods:
import numpy as np
from skimage.io import imread, imsave
from skimage.feature import canny
from skimage.color import rgb2gray
from skimage.filters import gaussian
from skimage.morphology import dilation, erosion, selem
from skimage.measure import find_contours
from skimage.draw import polygon
def get_mask(img):
kernel = selem.rectangle(7, 6)
dilate = dilation(canny(rgb2gray(img), 0), kernel)
dilate = dilation(dilate, kernel)
dilate = dilation(dilate, kernel)
erode = erosion(dilate, kernel)
mask = np.zeros_like(erode)
rr, cc = polygon(*find_contours(erode)[0].T)
mask[rr, cc] = 1
return gaussian(mask, 7) > 0.74
def save_img_masked(file):
img = imread(file)[..., :3]
mask = get_mask(img)
result = np.zeros_like(img)
result[mask] = img[mask]
imsave("masked_" + file, result)
save_img_masked('belt.png')
save_img_masked('bottle.jpg')
Resulting masked_belt.png:
Resulting masked_bottle.jpg:
One approach uses the fact that the background changes color only very slowly. Here I apply the gradient magnitude to each of the channels and compute the norm of the result, giving me an image highlighting the quicker changes in color. The watershed of this (with sufficient tolerance) should have one or more regions covering the background and touching the image edge. After identifying those regions, and doing a bit of cleanup we get these results (red line is the edge of the mask, overlaid on the input image):
I did have to adjust the tolerance, with a lower tolerance in the first case, more of the shadow is seen as object. I think it should be possible to find a way to set the tolerance based on the statistics of the gradient image, I have not tried.
There are no other parameters to tweak here, the minimum object area, 300, is quite safe; an alternative would be to keep only the one largest object.
This is the code, using DIPlib (disclaimer: I'm an author). out is the mask image, not the outline as displayed above.
import diplib as dip
import numpy as np
# Case 1:
img = dip.ImageRead('Pa9DO.png')
img = img[362:915, 45:877] # cut out actual image
img = img(slice(0,2)) # remove alpha channel
tol = 7
# Case 2:
#img = dip.ImageRead('jTnVr.jpg')
#tol = 1
# Compute gradient
gm = dip.Norm(dip.GradientMagnitude(img))
# Compute watershed with tolerance
lab = dip.Watershed(gm, connectivity=1, maxDepth=tol, flags={'correct','labels'})
# Identify regions touching the image edge
ll = np.unique(np.concatenate((
np.unique(lab[:,0]),
np.unique(lab[:,-1]),
np.unique(lab[0,:]),
np.unique(lab[-1,:]))))
# Remove regions touching the image edge
out = dip.Image(lab.Sizes(), dt='BIN')
out.Fill(1)
for l in ll:
if l != 0: # label zero is for the watershed lines
out = out - (lab == l)
# Remove watershed lines
out = dip.Opening(out, dip.SE(3, 'rectangular'))
# Remove small regions
out = dip.AreaOpening(out, filterSize=300)
# Display
dip.Overlay(img, dip.Dilation(out, 3) - out).Show()

Denoising a photo with Python

I have the following image which is a scanned copy of an old book. I want to remove the noise in the background (which is a bit reddish) that is coming due to the scanning of the old photo.
Update:
After applying opencv, following the parameter settings in opencv doc, I am getting the following output.
Please help fixing this.
The code that I am using:
import numpy as np
import cv2
from matplotlib import pyplot as plt
def display_image_in_actual_size(im_data):
dpi = 80
height, width, depth = im_data.shape
# What size does the figure need to be in inches to fit the image?
figsize = width / float(dpi), height / float(dpi)
# Create a figure of the right size with one axes that takes up the full figure
fig = plt.figure(figsize=figsize)
ax = fig.add_axes([0, 0, 1, 1])
# Hide spines, ticks, etc.
ax.axis('off')
# Display the image.
ax.imshow(im_data, cmap='gray')
plt.show()
img = cv2.imread('scan03.jpg')
dst = cv2.fastNlMeansDenoisingColored(img,None,10,10,7,21)
display_image_in_actual_size(img)
display_image_in_actual_size(dst)
The color of some pixels which has near threshold pixel values will be affected, but that depends on the task, here is one solution that you might adjust the threshold to a value that suits your task, also you might remove the median filter, or reduce the sigma value(5) if it affects the text badly, you might have some undesired noise, but the text will be readable.
import numpy as np
import matplotlib.pyplot as plt
import cv2
# Read Image
img = cv2.imread('input.jpg')
# BGR --> RGB
RGB = cv2.cvtColor(img, cv2.COLOR_BGR2RGB)
# BGR --> Gray
gray = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY)
# Set thresholds
th_white = 210
th_black = 85
# copy original gray
mask_white = gray.copy()
mask_black = gray.copy()
# Thresholding
mask_white[mask_white<th_white] = 0
mask_black[mask_black<th_black] = 0
mask_white[mask_white>=th_white] = 255
mask_black[mask_black>=th_black] = 255
# Median Filtering (you can remove if the text is not readable)
median_white = cv2.medianBlur(mask_white,5)
median_black = cv2.medianBlur(mask_black,5)
# Mask 3 channels
mask_white_3 = np.stack([median_white, median_white, median_white], axis=2)
mask_black_3 = np.stack([median_black, median_black, median_black], axis=2)
# Masking the image(in RGB)
result1 = np.maximum(mask_white_3, RGB)
result2 = np.minimum(mask_black_3, result1)
# Visualize the results
plt.imshow(result2)
plt.axis('off')
plt.show()
opencv library has couple of denoisong functions.
You can find reading with examples here

I am trying to measure land plot area Using OpenCV in Python

SO far I have been able to perform medianBlur and Edge Detection, Now I want to o further remove noise from the image, Matlabs region **property functions ** was used to remove all white regions that had a total pixel area of less than the mean pixel area value. How can I implement this on python
import matplotlib.image as mpimg
import numpy as np
import cv2
import os
import math
from collections import defaultdict
from matplotlib import pyplot as plt
import imutils
#import generalized_hough
gray = cv2.cvtColor(image, cv2.COLOR_RGB2GRAY)
print(gray.shape)
blur = cv2.bilateralFilter(gray,9,75,75)
median = cv2.medianBlur(gray,5)
# display input and output image
titles = ["bilateral Smoothing","median bulr"]
images = [ blur, median]
plt.figure(figsize=(20, 20))
for i in range(2):
plt.subplot(1,2,i+1)
plt.imshow(images[i])
plt.title(titles[i])
plt.xticks([]), plt.yticks([])
plt.show()
sobelX = cv2.Sobel(median,cv2.cv2.CV_64F, 1, 0)
sobelY = cv2.Sobel(median,cv2.cv2.CV_64F, 0,1)
sobelX = np.uint8(np.absolute(sobelX))
sobelY = np.uint8(np.absolute(sobelY))
SobelCombined = cv2.bitwise_or(sobelX,sobelY)
cv2.imshow('img', SobelCombined)
cv2.waitKey(0)
cv2.destroyAllWindows()
Here is a Matlab code that works for the same task.
close all
%upload image of farm
figure,
farm = imread('small_farms.JPG');%change this to the file path of image
imshow(farm);%this shows the original image
%convert the image to grayscale for 2D manipulation
gfarm = rgb2gray(farm);
figure,
imshow(gfarm);%show grayscaled image
%median filters take a m*n area around a coordinate and
%find the median pixel value and set that coordinate to that
%pixel value. It's a method of removing noise or details in an
%image. may want to tune dimensions of filter.
A = medfilt2(gfarm,[4 4]);
figure,
imshow(A);
%perform a logarithmic edge detection filter,
%this picks out the edges of the image, log setting
%was found to wrok best, although 'Sobel' can also be tried
B = edge(A,'log');
%show results of the edge filter
figure,
imshow(B,[]);
%find the areas of the lines made
areas = regionprops(B,'Area');
%find the mean and one standard deviation
men = mean([areas.Area])+0*std([areas.Area]);
%find max pixel area
big = max([areas.Area]);
%remove regions that are too small
C = bwpropfilt(B,'Area',[men big]);
%perform a dilation on the remaining pixels, this
%helps fill in gaps. The size and shape of the dilation
%can be tuned below.
SE = strel('square',4);
C = imdilate(C,SE);
areas2 = regionprops(C,'Area');
%place white border around image to find areas of farms
%that go off the picture
[h,w] = size(C);
C(1,:) = 1;
C(:,1) = 1;
C(h,:) = 1;
C(:,w) = 1;
C = C<1;
%fill in holes
C = imfill(C,'holes');
%show final processed image
figure,imshow(C);
%the section below is for display purpose
%it creates the boundaries of the image and displays them
%in a rainbow fashion
figure,
[B,L,n,A] = bwboundaries(C,'noholes');
imshow(label2rgb(L, #jet, [.5 .5 .5]))
hold on
for k = 1:length(B)
boundary = B{k};
plot(boundary(:,2), boundary(:,1), 'w', 'LineWidth', 2)
end
%The section below prints out the areas of each found
%region by pixel values. These values need to be scaled
%by the real measurements of the images to get relevant
%metrics
centers = regionprops(C,'Centroid','Area');
for k=1:length(centers)
if(centers(k).Area > mean([centers.Area])-std([areas.Area]))
text(centers(k).Centroid(1),centers(k).Centroid(2),string(centers(k).Area));
end
end

Crop region of interest from binary image using python

Requirement is to crop region of interest from binary image.
I need a rectangle image from a binary image by removing the extra space around the region of interest.
For example:
From this Original image i want only the region of interest marked with yellow color rectangle.
Note: Yellow color rectangle is just for the reference and it is not present in the image that will be processed.
I tried the following python code but it is not giving the required output.
from PIL import Image
from skimage.io import imread
from skimage.morphology import convex_hull_image
import numpy as np
from matplotlib import pyplot as plt
from skimage import io
from skimage.color import rgb2gray
im = imread('binaryImageEdited.png')
plt.imshow(im)
plt.title('input image')
plt.show()
# create a binary image
im1 = 1 - rgb2gray(im)
threshold = 0.8
im1[im1 <= threshold] = 0
im1[im1 > threshold] = 1
chull = convex_hull_image(im1)
plt.imshow(chull)
plt.title('convex hull in the binary image')
plt.show()
imageBox = Image.fromarray((chull*255).astype(np.uint8)).getbbox()
cropped = Image.fromarray(im).crop(imageBox)
cropped.save('L_2d_cropped.png')
plt.imshow(cropped)
plt.show()
Thank you.
Your image is not actually binary on account of two things:
firstly, it has 26 colours, and
secondly it has an (entirely unnecessary) alpha channel.
You can trim it like this:
#!/usr/bin/env python3
from PIL import Image, ImageOps
# Open image and ensure greysale and discard useless alpha channel
im = Image.open("thing.png").convert('L')
# Threshold and invert image as not actually binary
thresh = im.point(lambda p: p < 64 and 255)
# Get bounding box of thresholded image
bbox1 = thresh.getbbox()
crop1 = thresh.crop(bbox1)
# Invert and crop again
crop1n = ImageOps.invert(crop1)
bbox2 = crop1n.getbbox()
crop2 = crop1.crop(bbox2) # You don't actually need this - it's just for debug
# Trim original, unthresholded, uninverted image to the two bounding boxes
result = im.crop(bbox1).crop(bbox2)
result.save('result.png')
even i have similar problem. Also it would be helpful if image saved is in 32X32 px.

Categories