This question already has answers here:
How should I write a Windows path in a Python string literal?
(5 answers)
Closed 4 years ago.
what should i do to fix this error?
f = open('C:\Users\BARANLAPTOP\Desktop\test') #my python code
SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 2-3: truncated \UXXXXXXXX escape
This is happening because the backslashes in your file path string our being treated as special characters. To fix this issue you need to let python know they are part of the path you can do this by converting the string into a raw string by putting a r before the start of the string or by escaping the backslashes by putting another backslash before them so all backslashes become double backslashes.
Related
This question already has answers here:
How should I write a Windows path in a Python string literal?
(5 answers)
Closed 1 year ago.
import os
os.startfile("C:\Users\Sumit\AppData\Local\Microsoft\Teams.exe")
if i do this this error is coming
'C:\Users\Sumit\AppData\Local\Microsoft\Teams.exe'
^
SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 2-3: truncated \UXXXXXXXX escape
if I put r its showing no such file or directory
The issue is with the path("C:\Users\Sumit\AppData\Local\Microsoft\Teams.exe"). In Python source code, specific Unicode code points can be written using the \U escape sequence, which is followed by eight hex digits giving the code point.
But you have in your path \U with eight non hex digits(Which is causing this SyntaxError)
C:\Users\
So one way to solve this by using r(raw strings).
>>> import os
>>> os.startfile(r"C:\Users\Sumit\AppData\Local\Microsoft\Teams.exe")
This question already has answers here:
Why do I get a SyntaxError for a Unicode escape in my file path? [duplicate]
(5 answers)
Closed 1 year ago.
SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 2-3: truncated \UXXXXXXXX escape
I wrote this code :
from playsound import playsound
playsound('C:\Users\City Computer\Music\New folder\\play.mp3')
Here, \U in the path 'C:\Users... starts an eight-character Unicode escape, such as \U00014321. In your code, the escape is followed by the character 's', which is invalid. (As explained here)
Solutions:
There are three ways to solve this issue
1. Duplicate all backslashes (basically escape the escape character)
'C:\\Users\\City Computer\\Music\\New folder\\play.mp3'
2. Prefix the string with r (to produce a raw string)
r'C:\Users\City Computer\Music\New folder\play.mp3'
3. Use forward slashes(/) to avoid confusion
'C:/Users/City Computer/Music/New folder/play.mp3'
This question already has answers here:
"Unicode Error "unicodeescape" codec can't decode bytes... Cannot open text files in Python 3 [duplicate]
(10 answers)
Closed 1 year ago.
I'm trying to write a simple script to display an image in a window using tkinter.
I've tried to use PIL/Pillow and I've tried using the standard tkinter features but always get the same error when the script tries to read the filepath.
File "c:/Users/Sandip Dhillon/Desktop/stuff/dev_tests/imgtest2.py", line 6
photo=tk.PhotoImage(file="C:\Users\Sandip Dhillon\Pictures\DESlogo1.png")
^
SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 2-3: truncated \UXXXXXXXX escape
Here is my code,
import tkinter as tk
window=tk.TK()
window.geometery("400x300+200+100")
photo=tk.PhotoImage(file="C:\Users\Sandip Dhillon\Pictures\DESlogo1.png")
l1=tk.Label(text="image")
l1.pack()
l2=tk.Label(image=photo)
l2.pack
window.mainloop()
Thank you!
Backslashes are escape characters in Python strings, so your string is interpreted in an interesting way.
Either:
use forward slashes: tk.PhotoImage(file="C:/Users/Sandip Dhillon/Pictures/DESlogo1.png")
use a raw string: tk.PhotoImage(file=r"C:\Users\Sandip Dhillon\Pictures\DESlogo1.png")
Both string and bytes literals may optionally be prefixed with a letter 'r' or 'R'; such strings are called raw strings and treat backslashes as literal characters.
double the slashes: tk.PhotoImage(file="C:\\Users\\Sandip Dhillon\\Pictures\\DESlogo1.png")
Escape sequence: \\: Backslash (\)
This question already has answers here:
How can I put an actual backslash in a string literal (not use it for an escape sequence)?
(4 answers)
Closed 7 months ago.
I am used to working in python 2.7 so there was some new things like the print function being different. So excuse my ignorance. I am also pretty new to programming.
So here is my script, I keep getting errors that highlight some commas or spaces and saying there is a
SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 16-17: malformed \N character escape
Code:
import arcpy
print("mosaic to new raster starting!")
env.workspace = "F:\GDAL"
arcpy.env.pyramid = "NONE"
arcpy.env.rasterStatistics = "NONE"
arcpy.env.compression = "JPEG 87"
arcpy.env.tileSize = "256 256"
print("Environment set")
RasterInput = "m_3511401_ne_11_1_20130731.jpg;m_3511401_nw_11_1_20130731.jpg;m_3511401_se_11_1_20130731.jpg;m_3511401_sw_11_1_20130731.jpg;"
print("Input set")
arcpy.MosaicToNewRaster_management(RasterInput,"F:\Pro_Projects\NAIP2013\raster.sde","MosaicFile1","","8_BIT_UNSIGNED","","3","LAST","FIRST")
print("mosaic done!")
Backslashes (used by you as Windows path separators) signal escape sequences in Python strings. Double the backslashes or use a raw string literal:
"F:\\Pro_Projects\\NAIP2013\\raster.sde"
or
r"F:\Pro_Projects\NAIP2013\raster.sde"
Windows also accepts forward slashes in paths, avoiding the issue altogether:
"F:/Pro_Projects/NAIP2013/raster.sde"
This question already has answers here:
Why do I get a SyntaxError for a Unicode escape in my file path? [duplicate]
(5 answers)
Closed 5 years ago.
I am trying to load a array from another file(for a while now, and have been going through a lot of Stack Overflow Questions), but I can't get the easiest things to work. This is one of the errors I got:
>>> inp = open ('C:\Users\user\Documents\w-game\run\map1.txt','r')
SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes
in position 2-3: truncated \UXXXXXXXX escape
Sometimes I didn't get that error. It simply couldn't find the file, although I am sure it was there and it was a text file.
Does anybody know what is up or if this method doesn't work in python 3.3.3 anymore?
The error is not in the file, but in the filename string. You need to escape the backslashes in your filename; use a raw string:
open(r'C:\Users\user\Documents\w-game\run\map1.txt')
because \Uhhhhhhhh is a unicode escape code for a character outside of the BMP.
You can also double the slashes:
open('C:\\Users\\user\\Documents\\w-game\\run\\map1.txt')
or use forward slashes:
open('C:/Users/user/Documents/w-game/run/map1.txt')
Demo:
>>> print('C:\Users')
File "<stdin>", line 1
SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 2-3: truncated \UXXXXXXXX escape
>>> print(r'C:\Users')
C:\Users
>>> print('C:\\Users')
C:\Users
>>> print('C:/Users')
C:/Users