I am little bit comfused. Lets say I have such models.
models.py:
class Company(models.Model):
name = models.CharField(blank=False, null=False)
class Game(models.Model):
developer = models.ForeignKey(Company, on_delete=models.CASCADE)
publishers = models.ManyToManyField(Company)
If I use next code:
current_company = Company.object.get(pk=1)
current_company.game_set.all()
as I understand it return all games of current_company, but what field (developer or publishers) Django used?
But this code wouldn't be valid, for precisely this reason. If you tried to run it, Django would tell you that there was a conflict in the reverse relation.
If you have two relationships pointing to the same model, you need to explicitly set related_name on one of them to avoid this conflict.
Related
In Django, if I have something like this:
class Library(models.Model):
name = models.CharField(...)
address = models.CharField(...)
book_of_the_week = ?
class Book(models.Model):
library = models.ForeignKey(Library, on_delete=models.CASCADE, related_name="books")
name = models.CharField(...)
This gives me the ability to create multiple libraries, each with a large number of books.
For book_of_the_week, I want this to be a reference to a Book instance, so that in Django Admin, the field is represented as a dropdown that lets you select from the books in the current library, and in code, you can use .book_of_the_week to access a specific instance of Book.
Is this possible?
Sure, it's possible. But if you do this, you'll only ever be able to save the current book of the week. What happens if you want to show a library's book-of-the-week history? Seems like a likely scenario to me. Consider doing something like:
class Library(models.Model):
name = models.CharField(...)
address = models.CharField(...)
book_of_the_week = ?
class Book(models.Model):
library = models.ForeignKey(Library, on_delete=models.CASCADE, related_name="books")
name = models.CharField(...)
class BookOfTheWeek(models.Model):
book = models.ForeignKey(Book, on_delete=models.CASCADE, related_name='book_of_the_week')
library = models.ForeignKey(Library, ...etc)
week_of = models.DateField()
In this manner every book of the week will be a discrete database record, and you'll be able to track a history of each library's book of the week over time.
However...
That said, if you do not need to do this and a single instance record is fine, you should be able to create a ForeignKey relation from Library to Book. However, you may run into some circular and/or hierarchical reference issues depending on how where your model classes are written. In the example you show above, you'd need to declare your ForeignKey model name as a string, like so:
book_of_the_week = models.ForeignKey('Book', on_delete ... etc)
instead of:
book_of_the_week = models.ForeignKey(Book, on_delete ... etc)
...otherwise Django will throw an error because the Book model class is referenced before it is defined. Making 'Book' a string will let Django parse the full models.py file, build the logic, and avoid the error.
Sidenote:
Depending on your specific case you may also consider a ForeignKey to self, like so:
class Book(models.Model):
library = models.ForeignKey(Library, on_delete=models.CASCADE, related_name="books")
name = models.CharField(...)
book_of_the_week = models.ForeignKey('self', on_delete=models.SET_NULL, ...etc)
This would allow any Book on the database table to reference another single Book instance.
I am just starting with Django and want to create a model for an application.
I find Djangos feature to
- automatically define validations and html widget types for forms according to the field type defined in the model and
- define a choice set for the field right in the model
very usefull and I want to make best use of it. Also, I want to make best use of the admin interface.
However, what if I want to allow the user of the application to add fields to the model? For example, consider a simple adress book. I want the user to be able to define additional atributes for all of his contacts in the admin settings, i.e. add a fax number field, so that a fax number can be added to all contacts.
from a relational DB perspective, I would have a table with atributes (PK: atr_ID, atr_name, atr_type) and an N:N relation between atributes and contacts with foreign keys from atributes and contacts - i.e. it would result in 3 tables in the DB. right?
but that way I cannot define the field types directly in the Django model. Now what is best practice here? How can I make use of Djangos functionality AND allow the user to add aditional/custom fields via the admin interface?
Thank you! :)
Best
Teconomix
i would suggest storing json as a string in the database, that way it can be as extendable as you want and the field list can go very long.
Edit:
If you are using other damn backends you can use Django-jsonfield. If you are using Postgres then it has a native jsonfield support for enhanced querying, etc.
Edit 2:
Using django mongodb connector can also help.
I've used this approach, first seen in django-payslip, to allow for extendable fields. This provides a structure for adding fields to models, from which you can allow users to add/edit through standard view procedures (no admin hacking necessary). This should be enough to get you started, and taking a look at django-payslip's source code (see the views) also provides view Mixins and forms as an example of how to render to users.
class YourModel(models.Model):
extra_fields = models.ManyToManyField(
'your_app.ExtraField',
verbose_name=_('Extra fields'),
blank=True, null=True,
)
class ExtraFieldType(models.Model):
"""
Model to create custom information holders.
:name: Name of the attribute.
:description: Description of the attribute.
:model: Can be set in order to allow the use of only one model.
:fixed_values: Can transform related exta fields into choices.
"""
name = models.CharField(
max_length=100,
verbose_name=_('Name'),
)
description = models.CharField(
max_length=100,
blank=True, null=True,
verbose_name=_('Description'),
)
model = models.CharField(
max_length=10,
choices=(
('YourModel', 'YourModel'),
('AnotherModel', 'AnotherModel'), # which models do you want to add extra fields to?
),
verbose_name=_('Model'),
blank=True, null=True,
)
fixed_values = models.BooleanField(
default=False,
verbose_name=_('Fixed values'),
)
class Meta:
ordering = ['name', ]
def __unicode__(self):
return '{0}'.format(self.name)
class ExtraField(models.Model):
"""
Model to create custom fields.
:field_type: Connection to the field type.
:value: Current value of this extra field.
"""
field_type = models.ForeignKey(
'your_app.ExtraFieldType',
verbose_name=_('Field type'),
related_name='extra_fields',
help_text=_('Only field types with fixed values can be chosen to add'
' global values.'),
)
value = models.CharField(
max_length=200,
verbose_name=_('Value'),
)
class Meta:
ordering = ['field_type__name', ]
def __unicode__(self):
return '{0} ({1}) - {2}'.format(
self.field_type, self.field_type.get_model_display() or 'general',
self.value)
You can use InlineModelAdmin objects. It should be something like:
#models.py
from django.db import models
class Person(models.Model):
name = models.CharField(max_length=100)
class ContactType(models.Model):
name = models.CharField(max_length=100)
class Contact(models.Model):
person = models.ForeignKey(Person, on_delete=models.CASCADE)
contact_type = models.ForeignKey(ContactType, on_delete=models.CASCADE)
value = models.CharField(max_length=100)
#admin.py
from django.contrib import admin
class ContactInline(admin.TabularInline):
model = Contact
class PersonAdmin(admin.ModelAdmin):
inlines = [
ContactInline,
]
By the way... stackoverflow questions should contain some code. You should try to do something before asking a question.
I used inheritance model in my project after changing the model; but I give non-nullable field error. What should I do?
I am using Django 1.7
class Questions(models.Model):
question_category = models.ForeignKey(Course, blank=False)
question_author = models.ForeignKey(Author, blank=False)
question_details = models.CharField(max_length=100, blank=False, default='')
timestamp = models.DateTimeField(auto_now_add=True)
class TypeFive(Questions):
question_title = models.CharField(max_length=100, blank=False, default=generator(5), unique=True, editable=False)
def __str__(self):
return "{}".format(self.question_title)
class TypeFiveChoice(models.Model):
question_choice = models.ForeignKey(TypeFive)
is_it_question = models.BooleanField(default=False)
word = models.CharField(default='', blank=False, max_length=20)
translate = models.CharField(default='', blank=False, max_length=20)
timestamp = models.DateTimeField(auto_now_add=True)
def __str__(self):
return "{} : {}, {}".format(self.question_choice, self.word, self.translate)
After migrations:
You are trying to add a non-nullable field 'questions_ptr' to typefive without a default; we can't do that (the database needs something to populate existing rows).
Please select a fix:
1) Provide a one-off default now (will be set on all existing rows)
2) Quit, and let me add a default in models.py
In order to inherit from Questions in TypeFive, Django needs to add a relation from TypeFive to Questions. For all records in TypeFive that might already be in the database.
Django now doesn't know which question it should relate TopFive to. This is what the migrate command asks you for. You have a few options, but they greatly depend on your use case and whether you are in early development or if there is a production database where this migration has to run later.
I'm in early development and running it on localhost, so iI don't care
about my records. Now, what should I do?
In this case you haven't much to worry about, when migrate asks you type 1 and then press enter. Now add a primary key of a Questions instance that is in your database and then hit enter again.
Django now relates all TypeFive instances that are currently in the database to this question, so you might have to clean that up afterwards (e.g. by editing the TypeFive in Django admin).
#Nick Brady pointed this out in the question above so I don't mean to take credit but I wanted to highlight.
If your new inheritance class is only used for the purpose of being inherited from, you can easily get around this by setting your parent class to abstract.
class Parent(models.model):
Name = models.CharField(max_length=50)
class Meta:
abstract = True
class Child(Parent):
foobar = models.CharField(max_length=50)
class Meta:
db_table = "typenex_taxonomy_nodes"
Using the django-rest-framework is it possible to retrieve content from a related field. So for example I want to create a genre list which contains all projects within it. This is what I have but I keep on getting the error:
'Genre' object has no attribute 'project_set'
models.py
class Genre(models.Model):
name = models.CharField(max_length=100, db_index=True)
class Project(models.Model):
title = models.CharField(max_length=100, unique=True)
genres = models.ManyToManyField(Genre, related_name='genres')
serializers.py
class GenreSerializer(serializers.ModelSerializer):
project_set = serializers.ManyRelatedField()
class Meta:
model = Genre
fields = ('name', 'project_set')
The related name you're using on the Project class is badly named. That related name is how you access the set of projects related to a given genre instance. So you should be using something like related_name='projects'. (As it is you've got it the wrong way around.)
Then make sure that your serializer class matches up with the related name you're using, so in both places project_set should then instead be projects.
(Alternatively you could just remove the related_name='genres' entirely and everything will work as you were expecting, as the default related_name will be 'project_set'.)
When I try to syncdb I get the error Menu is not a valid class Name.
How can I resolve that relationship case :
class MenuItem(model.Models)
title = models.CharField(max_length=200)
submenus = models.ManyToManyField(Menu, blank=True, null=True)
class Menu(Container):
links = models.ManyToManyField(MenuItem)
From the Django book:
If you need to create a relationship on a model that has not yet been
defined, you can use the name of the model, rather than the model
object itself:
E.g.:
class MenuItem(model.Models)
title = models.CharField(max_length=200)
submenus = models.ManyToManyField('Menu', blank=True, null=True)
^ ^
Edit:
As Francis mentions (and as is written in the documentation):
It doesn't matter which model has the ManyToManyField, but you should only put it in one of the models -- not both.
One of these models has a many to many, the other one uses Django's reverse relations (https://docs.djangoproject.com/en/dev/topics/db/queries/#following-relationships-backward)
So how I would set it up:
class Menu(Container):
links = models.ManyToManyField(MenuItem)
class MenuItem(model.Models)
title = models.CharField(max_length=200)
Then when I wanted a MenuItem's Menus:
menu_item_instance.menu_set.all()