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Trying to run .ahk files in tkinter

this is my first time here so if I break some unwritten rules please don't shoot me
I've been trying build an app for editing, reading and opening .ahk files. The last one gives me problems.
this code kind of does what I want except it fires the command immediately after opening the app.
from tkinter import *
from tkinter import filedialog
import os
import threading
root = Tk()
def openfile():
os.system( r'\Users\merijn\PycharmProjects\infoprojectP3\venv\Scripts\ahkScript1.ahk')
def func():
print("hello")
btn1 = Button(text='programma', command=threading.Thread(target=openfile).start())
btn2 = Button(text='ander ding', command=func)
btn1.pack()
btn2.pack()
root.mainloop()
Any help would be much appreciated!

Change the following line (it just assigns the result of threading.Thread(...) to command option):
Button(text="run program1", command=threading.Thread(target=lambda: os.system(r'\Users\merijn\PycharmProjects\infoprojectP3\venv\Scripts\ahkScript1.ahk').start()))
to
Button(text="run program1", command=lambda: threading.Thread(target=lambda: os.system(r'\Users\merijn\PycharmProjects\infoprojectP3\venv\Scripts\ahkScript1.ahk')).start())
or
Button(text="run program1", command=lambda: threading.Thread(target=os.system, args=[r'\Users\merijn\PycharmProjects\infoprojectP3\venv\Scripts\ahkScript1.ahk']).start())
Same for buttons of run program2 and run program3.
Update: based on your updated code, you need to change the following line:
btn1 = Button(text='programma', command=threading.Thread(target=openfile).start())
to
btn1 = Button(text='programma', command=lambda: threading.Thread(target=openfile).start())

How would I continue to run code after importing a Tkinter file?

So I'm trying to use a Tkinter window as an output log. My main program is a command line interface, so if the output from the "side programs" that run fills up the python console, it can ruin the user experience.
I have the Tkinter output log program in a seperate file, which I import into my main file. This is the gyst of the Tkinter file I created:
import time
from datetime import datetime
root = Tk()
root.configure(background='black')
root.geometry('700x460')
console = Listbox(root, width=40000, height=30000, font=('Lucida Console', 14), relief=FLAT, bg='black',
fg='white',
borderwidth=0, highlightbackground='black', selectbackground='black',
selectforeground='white')
console.pack()
def log(what_to_log):
now = datetime.now()
console.insert('[' + now.strftime("%H:%M:%S") + ']: ' + what_to_log)
root.mainloop()
So I import it into my main program like so:
# this is the file with the Tkinter code
import Logs
Logs.log('Test')
The issue is that the main program doesn't continue running after importing Logs, it just stops, and continues to run the mainloop in the Logs file.
So my question is, how could I get both files to continue running, while also being able to update the Tkinter listbox via the log function??

You should not execute root.mainloop() as it will block your console application. Use root.update() at the end of log() to force tkinter to update the list box. Also there is syntax error in console.log(...).
Below is a modified Logs.py:
from tkinter import *
from datetime import datetime
root = Tk()
root.configure(background='black')
root.geometry('700x460')
console = Listbox(root, font=('Lucida Console', 14), relief=FLAT, bg='black', fg='white',
borderwidth=0, highlightbackground='black', selectbackground='black',
selectforeground='white')
console.pack(fill='both', expand=1)
def log(what_to_log):
now = datetime.now()
console.insert('end', '['+now.strftime("%H:%M:%S")+']: '+what_to_log)
console.see('end') # make sure last log is visible
root.update() # force tkinter to update

How can I make the Button click Event

I Would like to create a little Game. Now my Problem is that nothing is happening when I'm pressing the Button:
Main Code:
from tkinter import *
import os
def Aufgabe():
os.system('python Test.py')
def Wahrheit():
os.system('python Test.py')
master= Tk()
master.geometry("200x60")
master.configure(bg='light blue')
Button(master, text="Aufgabe", command= print(Aufgabe)).place(x=20, y=20)
Button(master, text="Wahrheit", command="Wahrheit").place(x=100, y=20)
mainloop()
Test.py Code:
import random
print(random.randint(1,6))

Writing a Python UI for a seperate program with tkinter. The stop button for this program basically freezes the UI and continues with the script

Here is what I coded...
import tkinter as tk
import subprocess
import sys
import time
import os
import tkinter.font as font
from tkinter.ttk import *
app = tk.Tk()
app.geometry("400x400")
app.configure(bg='gray')
photo = tk.PhotoImage(file=r"C:\Users\ex\ex_button_active.png")
myFont = font.Font(family='Helvetica', size=20, weight='normal')
tk.Label(app, text='EX', bg='gray', font=(
'Verdana', 15)).pack(side=tk.TOP, pady=10)
app.iconbitmap(r'C:\Users\ex\ex_icon.ico')
start = time.time()
cmd = sys.executable + " -c 'import time; time.sleep(2)' &"
subprocess.check_call(cmd, shell=True)
assert (time.time() - start) < 1
p = subprocess.Popen(cmd, shell=True)
def ex_activation():
#Python Code
#Python Code...
def ex_stop():
sys.exit(ex_activation) #This area is basically where I have a button to terminate the other script running.
#I have tried sys.exit() and had the same result
ex_activation_button = tk.Button(app,
bg='black',
image=photo,
width=120,
height=120,
command=ex_activation)
ex_stop_button = tk.Button(app,
bg='Gray',
text='ex',
width=12,
command=ex_stop
height=3)
ex_stop_button['font'] = myFont
app.title("Example")
ex_activation_button.pack(side=tk.TOP)
ex_stop_button.pack(side=tk.LEFT)
app.mainloop()
I am looking for a way to get my program to stop the program the other button runs. I realized that this maybe be a "self destruct button" but I don't know how to do this with the script the other button runs. Any help greatly appreciated! I tried killing the code by putting the def ex_activation in the p.kill
This did not work...

If the other python script is made to run forever (has some kind of while True:), you can't run it on the command line as you did, because it will freeze your window while that script is running.
In order to run a python script on background you will need to do it with the subprocess library. (Find out here)
I also found an answer of another question that uses check_ouput() in order to know when the python program has finished. This can also be useful if you want to send a status to the tkinter app: you can print("33% Complete"), for example. You could add this in tkinter's main loop, so you always know if your program is running or not.
And last but not least, to kill that process (using the stop button), you should do it using os, and looking for the subprocess' ID. Here you can also find a good example.
I would try something like this:
cmd = "exec python file.py"
p = subprocess.Popen(cmd, shell=True)
# Continue running tkinter tasks.
tk.update()
tk.update_idletasks() # These both lines should be inside a while True
# Stop secondary program
p.kill()
EDIT
Example code using your question's code. WARNING: I have changed the png file location for testing, commented the app icon, and tested ONLY on Windows.
It's important to remove the mainloop() on the main file and put update...() in order to catch the keyboardInterrupt that (I don't know why) is killing both parent and child process.
I invite you to try it and be as happy as I have been when it was working after half an hour of testing!!
File 1: daemon.py - this file will run forever.
from time import sleep
from sys import exit
while True:
try:
print("hello")
sleep(1)
except KeyboardInterrupt:
print("bye")
exit()
File 2: tkinterapp.py - The name is self-explainatory
import tkinter as tk
import subprocess
import sys
import time
import os
import tkinter.font as font
from tkinter.ttk import *
app = tk.Tk()
app.geometry("400x400")
app.configure(bg='gray')
photo = tk.PhotoImage(file=r"C:\Users\royal\github\RandomSketches\baixa.png")
myFont = font.Font(family='Helvetica', size=20, weight='normal')
tk.Label(app, text='EX', bg='gray', font=(
'Verdana', 15)).pack(side=tk.TOP, pady=10)
# app.iconbitmap(r'C:\Users\ex\ex_icon.ico')
def ex_activation():
global pro
print("running!")
pro = subprocess.Popen("python daemon.py", shell=True)
def ex_stop():
global pro
print("stopping!")
os.kill(pro.pid, 0)
ex_activation_button = tk.Button(app,
bg='black',
image=photo,
width=120,
height=120,
command=ex_activation)
ex_stop_button = tk.Button(app,
bg='Gray',
text='ex',
width=12,
command=ex_stop, # BE CAREFUL You were missing a "," here !!!
height=3)
ex_stop_button['font'] = myFont
app.title("Example")
ex_activation_button.pack(side=tk.TOP)
ex_stop_button.pack(side=tk.LEFT)
# app.mainloop()
while True:
try:
app.update()
app.update_idletasks()
except KeyboardInterrupt:
pass

how to link a button to another .py file in python2.7

How do I link a python button?
Basically I want a python button to execute another python file.
I am using Tk.
I've created this button and would like it to execute the script
from Tkinter import *
import Tkinter as tk
root = tk.Tk()
b = Button(toolbar, text="Travelling", width=9 )
b.pack(side=LEFT, padx=2, pady=2)
mainloop()
How do I make this button execute another python script on click?

If you want execute another python script use execfile():
#-*- coding: utf-8 -*-
from Tkinter import *
master = Tk()
def callback():
execfile("script.py")
b = Button(master, text="OK", command=callback)
b.pack()
mainloop()