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Running python file through VS Code terminal

My question is I am unable to run a python file in VS Code terminal unless I specify the full path.
Whereas, when I see any python tutorial, only python filename is entered and it works.
Can somebody pls help me with this issue?

The files need to be in the same folder where you are operating / or have the other Python files.
You can use two ways for this:
first:
import os
pwd = os.getcwd()
# again, make sure you file is in the same directory.
the_file = (pwd + "\\filename.xlsx")
or Secondly,
#the below you can use wherever your file is and it will locate it.
# you specify the full path using pathlib.path and:
pathlib.path(directory here without the file itself).joinpath(file name here).

Python/Jupyter getting a FileNotFoundError when attempting to read an excel file however said file is in the correct directory

data = pd.read_excel("ETH-USD")
I continually receive an error message informing me that the file cannot be found
this is despite the fact that
1: my directory has been changed within to Python to the same address as the folder where the excel file is stored
2: the file name is input exactly as displayed
Any ideas on why it is unable to find my file?

Is it possible that the excel file has an extension of .xlsx, but your file explorer is set to "hide file extensions"? Try:
data = pd.read_excel("ETH-USD.xlsx")
Or, see what's in the current directory by running:
import os
print(os.listdir())
A tip from the comments:
Windows tip too: hold Shift, right click the excel file and copy as path, then you can see its path (if you don't enable viewing file extensions in the file browser). –
creanion

Often when running python scripts from compilers the "working directory", or where you are running the script from doesn't match the location of your script, hence why I find it much more reliable to use this instead:
import os
BASE_DIR = os.path.dirname(os.path.abspath(__file__))
data = pd.read_excel(os.path.join(BASE_DIR,"ETH-USD")
To add, while I do not use Jupyter, in VSCode which I use, the working directory (which is where python looks for if you put a path in read_excel() but its not a full path) is often the current directory opened in there, so I expect a similar issue to be the reason for your issue.

python - error occurs on relative path but not absolute path in macOS

I'm having a strange issue. I'm just trying to do a basic show directory contents for relative path.
Created a test directory on the desktop
test directory contents
test.py
test1 -- folder
sample.txt
contents of test.py
import os
dataDir = "test1"
for file in os.listdir("/Users/username/Desktop/test"):
print(file)
Summary - absolute path
works - in visual studio code
works - macOS terminal python3 /Users/username/Desktop/test/test.py
however when use the variable I get an error:
contents of test.py
import os
dataDir = "test1"
for file in os.listdir(dataDir):
print(file)
Summary - relative path
works - in visual studio code
ERROR - macOS terminal python3 /Users/username/Desktop/test/test.py
Traceback (most recent call last):
File "/Users/username/Desktop/test/test.py", line 4, in
for file in os.listdir(dataDir):
FileNotFoundError: [Errno 2] No such file or directory: 'test1'

I all depends on what folder you are in when you launch the code.
Let's say your .py file is in folder1/folder2/file.py and your test1 folder is folder1/folder2/test1/.... You open a terminal in the folder1 and launch python3 /folder2/file.py. The program is going to check for files in folder1/test1/.
Try navigating to the actual file folder, that should work. If you want to use it wherever you launch the code you will have to do some checks on the current directory and manually point the code to the wanted path.

The following solution is inspired by that answer
A simple way to solve your problem is to create the absolute path. (I recommend using that always when you're working with different directories and files)
First of all, you need to care about your actual working directory. While using VS Code your working directory is in your desired directory (/Users/username/Desktop/test/).
But if you use the command line your actual working directory may change, depending where you're calling the script from.
To get the path where script is actually located, you can use the python variable __file__. __file__ is the full path to the directory where your script is located.
To use your script correctly and being able to call it using both ways, the following implementation can help you:
import os
dataDir = "test1"
# absolute path to the directory where your script is in
scriptDir = os.path.dirname(__file__)
# combining the path of your script and the 'searching' directory
absolutePath = os.path.join(scriptDir, dataDir)
for file in os.listdir(absolutePath):
print(file)

python code can't find file while its in folder marked as resource root in PyCharm

In PyCharm, I created folder named test, created txt file named test inside and marked folder as content root. When I added python file outside the test folder and tried to access test.txt file with open it suggested me file name. But when I tried running the code it couldn't find the file.
Traceback (most recent call last):
File "/home/elmo/PycharmProjects/TBC_PAY_API_TESTING/testing.py", line 32, in <module>
print(open("test.txt").read())
FileNotFoundError: [Errno 2] No such file or directory: 'test.txt'
This is how the code and folders look like ( ingore the trash folder)
How can I fix it? The main reason I am doing this is to avoid writing full path's for accessing file.

You are talking about two totally different things in your question. If you mark a folder as Sources root that means the Python interpreter will be able to find the modules in that folder.
For example:
When you write an own module and you want to use it in another file the Python won't find it automatically. The PYTHONPATH should contain the path of the folder which contains your module. And actually the Sources root option does this!
The other thing what you have mentioned in your question is that you don't provided a correct path in your code. It is a real error. In your code, you have to provide the correct path for open. The Pycharm is an IDE but your (or other's) Python interpreter will use your code.
You can solve your problem in many ways.
For example:
You can hard-code the path of your txt (It is totally not recommended):
print(open("/home/elmo/PycharmProjects/TBC_PAY_API_TESTING/test/text.txt").read())
You can use relative path:
print(open("test/text.txt").read())
You can use full path based on your Python file (I recommend this solution):
import os
dir = os.path.realpath(os.path.dirname(__file__)) # Directory of your Python file
file_path = os.path.join(dir, "test", "test.txt") # Create the path of the file
print(open(file_path).read())

Call a file in another folder in Eclipse for Python project

I have a small enough Python project in Eclipse Neon and keep getting the same error and can't find proper documentation on how to solve. In my main I need to call a file that is located in another folder. The error I receive is IOError: [Errno 2] No such file or directory:
I have an empty init.py file in the folder (XML_TXT) that I'm trying to use.

It looks like Groovy is importing okay, or else you would get an ImportError. An IOError indicates that it can't find "test.txt". Does that file exist?
It will work if the file path is relative to where you are running the script from. So for example if test.txt is in a folder
Groovy("folder_name/test.txt")
You can also go up in the directory structure if you need to, for example
Groovy("../folder_name/test.txt")
Or, if you want to be able to run the file from anywhere, you can have python work out the absolute path of the file for you.
import os
filename = os.path.join(os.path.dirname(__file__), 'folder_name/test.txt')
u = Groovy(filename)