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LDAP Query Filter User's with Groups Like *x*

I'm currently using Python and LDAP to query Active Directory for users.
I have a list of names that are First Last. Not specific enough to find the exact user.
I would like a filter that would find all users matching 'Last, First*'
and belonging to any group with a keyword in it.
_filter = '''(& (objectclass=user)
(objectcategory=person)
(name={}*) )'''.format(search_string)
and I've tried adding...
(memberOf=CN=*Keyword*,OU=Delegated,OU=Groups,DC=amr,DC=corp,DC=xxxxxx,DC=com)
To my filter, but with no success.
If this was SQL, I would write something like:
Select *
From
Users
Where
Users.name like 'First, Last%'
and Users.memberOf like 'Keyword%'
Update:
After reviewing Gabriel's answer I'm running this.
def get_idsids(self, search_string):
_filter = '''(& (objectclass=user)
(objectcategory=person)
(anr={}) )'''.format(search_string)
# Search for user.
# Will return list of users matching criteria.
# The results are wrapped up as a list(tuple(dict))) where the dict vals are binary strings or lists of binary strings.
users = self.con.search_s(ActiveDirUser.BASEDN, ldap.SCOPE_SUBTREE, _filter, ['displayName', 'sAMAccountName', 'memberOf'])
# This line is ugly... It just converts the results to a list of ids
# So long as the user has at least one group with 'Keyword' in the name.
# upper() is used to make the Keyword requriement case insensitive.
return [user[1]['sAMAccountName'][0].decode() for user in users if 'KEYWORD' in ''.join(map(str, user[1]['memberOf'])).upper()]
I do wonder though, could I search for groups with 'Keyword' in the name and build filters from that? Further, would that be faster? I assume it would as AD probably hashes group membership.
I will go do some reading, but I assume group names are wildcard searchable?

I suggest you use Ambiguous Name Resolution:
_filter = '''(& (objectclass=user)
(objectcategory=person)
(anr={}) )'''.format(search_string)
Read that documentation to understand how it works, but it can find users if you give it a string of "first last". This is what the search box in AD Users and Computers uses.
Just be aware that you can get doubles if people have similar names. If you take my name for example: if you would search for "Gabriel Luci", and there was someone else with the name "Gabriel Luciano", you would find both of us.
This:
(memberOf=CN=*Keyword*,OU=Delegated,OU=Groups,DC=amr,DC=corp,DC=xxxxxx,DC=com)
doesn't work because you can't use wildcards on any attribute that is a distinguishedName, like memberOf.
That's for Active Directory anyway. Other LDAP directories might allow it.
If you need to check if the users are members of groups, then you can tell your search to return the memberOf attribute in the search (I don't know phython, but you should have a way of telling it which attributes you want returned). Then you can loop through the groups in the memberOf attribute and look for that keyword.

Django Full Text Search Not Matching Partial Words

I'm using Django Full Text search to search across multiple fields but have an issue when searching using partial strings.
Lets say we have a report object with the name 'Sample Report'.
vector = SearchVector('name') + SearchVector('author__username')
search = SearchQuery('Sa')
Report.objects.exclude(visible=False).annotate(search=vector).filter(search=search)
The following QuerySet is empty but if I include the full word 'Sample' then the report will appear in the QuerySet.
Is there anyway to use icontains or prefixing with django full text search?

This is working on Django 1.11:
tools = Tool.objects.annotate(
search=SearchVector('name', 'description', 'expert__user__username'),
).filter(search__icontains=form.cleaned_data['query_string'])
Note the icontains in the filter.

#santiagopim solution is correct but to address Matt's comment for if you get the following error:
ERROR: function replace(tsquery, unknown, unknown) does not exist
at character 1603 HINT: No function matches the given name
and argument types. You might need to add explicit type casts.
You have to remove the call to SearchQuery and just use a plain string.
I know this doesn't address the underlying issue for if you need to use SearchQuery but if you are like me and just need a quick fix, you can try the following.
vector = SearchVector('name') + SearchVector('author__username')
# NOTE: I commented out the line below
# search = SearchQuery('Sa')
search = 'Sa'
Report.objects.exclude(visible=False).annotate(search=vector)\
.filter(search__icontains =search)
This other answer might be helpful.

MongoAlchemy regex return nothing

I'm testing MongoAlchemy for a project and I've to search user by name.
I'm trying to make a regex but query result is always empty.
I tried two methods :
import re
users = User.query.filter({"name":re.compile("/a/", re.IGNORECASE)}).all()
And :
users = User.query.filter(User.name.regex('/a/', ignore_case=True)).all()
Even if I use a very general regex like /.*/, the result is always empty.
Thank you.

In python regular expressions are not defined using /regexp/, this is javascript syntax.
The proper way to initialize regular expressions would be:
re.compile(r".*", re.IGNORECASE)
So you should use:
users = User.query.filter({"name": re.compile(r".*", re.IGNORECASE)}).all()

Output list of links grouped by extension or base URL - built on regex using python.

Working on this assignment for a while now. The regex is not particularly difficult, but I don't quite follow how to get the output they want
Your program should:
Read the html of a webpage (which has been stored as textfile);
Extract all the domains referred to and list all the full http addresses related to these domains;
Extract all the resource types referred to and list all the full http * addresses related to these resource types.
Please solve the task using regular expressions and re functions/methods. I suggest using ‘finditer’ and ‘groups’ (there might be other possibilities). Please do not use string functions where re is better suited."
The output is supposed to look like this
www.fairfaxmedia.co.nz
http://www.fairfaxmedia.co.nz
www.essentialmums.co.nz
http://www.essentialmums.co.nz/
http://www.essentialmums.co.nz/
http://www.essentialmums.co.nz/
www.nzfishingnews.co.nz
http://www.nzfishingnews.co.nz/
www.nzlifeandleisure.co.nz
http://www.nzlifeandleisure.co.nz/
www.weatherzone.co.nz
http://www.weatherzone.co.nz/
www.azdirect.co.nz
http://www.azdirect.co.nz/
i.stuff.co.nz
http://i.stuff.co.nz/
ico
http://static.stuff.co.nz/781/3251781.ico
zip
http://static2.stuff.co.nz/1392867595/static/jwplayer/skin/Modieus.zip
mp4
http://file2.stuff.co.nz/1394587586/272/9819272.mp4
I really need help with how to filter stuff out so the output shows up like that?

create list of tuples (keyword, url)
sort it according to keyword
using itertools.groupby group per keyword
for each keyword, print keyword and then all urls (these to be printed indentend).

Pattern matching Twitter Streaming API

I'm trying to insert into a dictionary certain values from the Streaming API. One of these is the value of the term that is used in the filter method using track=keyword. I've written some code but on the print statement I get an "Encountered Exception: 'term'" error. This is my partial code:
for term in setTerms:
a = re.compile(term, re.IGNORECASE)
if re.search(a, status.text):
message['term'] = term
else:
pass
print message['text'], message['term']
This is the filter code:
setTerms = ['BBC','XFactor','Obama']
streamer.filter(track = setTerms)
It matches the string, but I also need to be able to match all instances eg. BBC should also match with #BBC, #BBC or BBC1 etc.
So my question how would i get a term in setTerms eg BBC to match all these instances in if re.search(term, status.text)?
Thanks

Have you tried putting all your search terms into a single expression?
i.e. setTerms = '(BBC)|(XFactor)|(Obama)', then seeing if it matches the whole piece string (not just individual word?