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How should I write a recursive function that returns multiple values? [closed]

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I want the output to be a tuple including the sum the the product.
For example the list [1,2,3,4] should output (10,24). I can get the sum and product individually but cannot get both at the same time. Here's what I have so far:
def sum_product(aList):
if len(aList) == 1:
return aList[0]
result = sum_product(aList[1:])
return (result + aList[0], result*aList[0])
sum_product([1,2,3,4])
Help is greatly appreciated

Your mistake was that you return different types. In the end of recursion you return int, but in general return a tuple. I changed your code, so now it works.
def sum_product(aList):
if len(aList) == 1:
return aList[0], aList[0] #list[0] for sum and list[0] for product
result = sum_product(aList[1:])
return (result[0] + aList[0], result[1] * aList[0])

I am Wrote this python code but every time it's give me wrong answer [closed]

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I have wrote this Code for calculates the product of the first natural numbers, but it showing answer 1 every time. I don't where i did mistake?? Can you please help me find out my mistake in this code..
num = 10
i = 0
prod = 1
while i<=num:
i = i+1
prod*prod*i
print(prod)

The problem seems to be on the line prod*prod*i. The product needs to be accumulated and for this it should be exchanged for prod*=i.
The new snippet is:
num = 10
i = 0
prod = 1
while i<=num:
print(i)
i = i+1
prod*=i
print(prod)

Instead of prod*prod*i write prod=prod*i

Here we first take the input of the number of terms.Then we iterate the for loop and multiply the value of x with the initial value(=1).Then we assign the new value to p.
n=int(input('Terms: ')) #specifing the limit
p=1
for x in range(1,n+1):
p=p*x
print(p)

Reverse of a list of list in Python [closed]

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Closed 4 years ago.
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I have been trying to horizontally reverse the matrix in Python.
input 1 0
1 0
output 0 1
0 1
Here is the code...
class Reversedmat(object):
def __list_oflist__(self,mat)
rows = len(mat)
columns = len(mat[0])
for i in range(0, len(mat)):
reversed_mat = ""
for j in range(0, len(mat[i])):
reversed_mat += str(mat[i][j]) + "\t" ## this is where im
print(reverse(reversed_mat))
if __name__ == "__main__":
mat =[[1,0],[1,0]]
print(Reversedmat().__list_oflist__(mat))
I have been trying to do this in Python, but I was not able to achieve. Any help is much appreciated! Thanks

A simple solution:
def reversemat(mat):
return [row[::-1] for row in mat]
print(reversemat([[1,0],[1,0]]))
# [[0, 1], [0, 1]]
besides, you have returned nothing from your function, so you will get None from your second print.

Why do I get None as a result [closed]

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Closed 7 years ago.
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I have the following script:
import math
scores = [3.0,1.0,0.1]
sum = 0
i=0
j=0
for s in scores:
sum = sum + math.exp(scores[i])
i=i+1
def myFunction(x):
math.exp(x)/sum
for s2 in scores:
print(myFunction(scores[j]))
j=j+1
But, the output I get is:
None
None
None
Why is that? How can I retrieve the correct values?
Thanks.

You forgot to return.
def myFunction(x):
return math.exp(x)/sum

print(myFunction(scores[j]))
Here you try to print something. But myFunction doesn't return anything to print.
You can use,
def myFunction(x):
return math.exp(x)/sum
This will solve the problem.

Python Function Codecademy [closed]

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I'm trying to cube the number in this function, but Codecademy says it isn't returning the right result. Could anyone help?
def cube(number):
return number**number
def by_three(number):
if number % 3==0:
return cube(number)
else:
return False

Because it is not a cube. Cube is: number ** 3

Given your cube function, you are doing
n^n
for example, given n = 4, what you are really doing is 4*4*4*4
And it work only on 3 or it's multiple, given the line
if number % 3==0:

In case you are interested in one liner of this function check this out:
def by_three(number):
return number ** 3 if number % 3 == 0 else False
If you are interested in how this is done check ternary operator in python