We Keep Coding

Input a message inside a box

I need to create a box with parameters that prints any input the user puts in. I figured that the box should be the length of the string, but I'm stuck with empty code, because I don't know where to start.
It should look like this:

I agree with Daniel Goldfarb comments. Don't look for help without trying.
If you still couldn't get how to do that, then only read my remaining comment.
Just print :
str = string entered
len(str) = string length
+-(len(str) * '-')-+
| str |
+-(len(str) * '-')-+

So hopefully you can learn, don't want to just write the code for you. Basically break it into steps. First you need to accept user input. If you don't know how to do that, try googling, "python accept user input from stdin" or here is one of the results from that search: https://www.pythonforbeginners.com/basics/getting-user-input-from-the-keyboard
Then, as you mentioned, you need the length of the string that was input. You can get that with the len function. Then do the math: It looks like you want "|" and two spaces on each side of the string, giving the length plus 6 ("| " on either side). This new length is what you should make the "+---+" strings. Use the print() function to print out each line. I really don't want to say much more than that because you should exercise your brain to figure it out. If you have a question on how to generate "+---+" of the appropriate length (appropriate number of "-" characters) you can use string concatenation and a loop, or just use the python string constructor (hint: google "construct python string of len repeat characters"). HTH.
One more thing, after looking at your code, in addition to my comment about printing the string itself within the box, I see some minor logic errors in your code (for example, why are you subtracting 2 from the width). THE POINT i want to me here is, if you ware going to break this into multiple small functions (a bit overkill here, but definitely a good idea if you are just learning as it teaches you an important skill) then YOU SHOULD TEST EACH FUNCTION individually to make sure it does what you think and expect it to do. I think you will see your logic errors that way.

Here is the solution, but I recommend to try it out by yourself, breakdown the problem into smaller pieces and start from there.
def format(word):
#It declares all the necessary variables
borders =[]
result = []
# First part of the result--> it gives the two spaces and the "wall"
result.append("| ")
# Second part of the result (the word)
for letter in word:
result.append(letter)
# Third part of the result--> Ends the format
result.append(" |")
#Transforms the list to a string
result = "".join(result)
borders.append("+")
borders.append("--"+"-"*len(word)+"--")
borders.append("+")
borders="".join(borders)
print(borders)
print(result)
print(borders)
sentence = input("Enter a word: ")
format(sentence)

I'm new to Python, and I've found this solution. Maybe is not the best solution, but it works!
test = input()
print("+-", end='')
for i in test:
print("-", end='')
print("-+")
print("| " + test + " |")
print("+-", end='')
for i in test:
print("-", end='')
print("-+")

How to fix this Anagram Scrambler code?

print "YOU HAVE CHOSEN TO REARRANGE YOUR THE WORD THAT YOU ARE ABOUT TO ENTER..."
word = raw_input ("FIRSTLY YOU MUST ENTER A WORD TO BE REARRANGED, ENTER IT HERE:")
character_save = word[1]
def anagram(word):
if len(word)>1:
print str.replace('a','b')
word = str.replace(word[1],word[3])
word= str.replace(word[3], character_save,1)
print word
anagram(word)
I tried to fix this on numerous occasions, the problem with the first time was that it would just replicate characters instead of replacing the positions, the second time I tried to store the position that I was going to replace in a variable but now it mentions that I have only one argument given (when it should be 2).
Would it be easier to do this with a list instead of a string?

The replace message that you are using is called on the string that you want to replace and not on the str type itself.
In your case that is the word parameter that you are providing.
So if you replace the instances of str.replace with word.replace your code will run. However, it doesn't create an anagram yet. The algorithm is still lacking.

Right-to-Left and Left-to-Right printed nicely

I want it to produce the number next to a word so that I can ask the user to select the word by using the corresponding number.
This is my code
alt_words = hlst
loopnum = 8
for i in range(loopnum):
if i < len(alt_words):
print('{0}. {1:<20}'.format((i+1), alt_words[i]), end =' ')
if i == 0:
print('', end=' ')
if i + 9 <= len(alt_words):
print('{0}. {1:<20}'.format((i+9), alt_words[i+8]), end =' ')
if i + 17 <= len(alt_words):
print('{0}. {1:<20}'.format((i+17), alt_words[i+16]), end=' ')
print('\n'+'-'*80)
It produces this
The first number of each line gets printed on the left, but the word on the right, while the rest of the numbers and words get printed RTL. It seems that once python has started printing on a line LTR it can switch to RTL, but not back from RTL to LTR. Note how even the periods are printed to the right of the number for the second set of numbers on each line.
It works perfectly well and looks nice with english words:
I am guessing a work around might involve putting the number after the word, but I figure there must be a better way.

Put a Right-to-Left Embedding character, u'\u202B', at the beginning of each Hebrew word, and a Pop Directional Formatting character, u'\u202C', at the end of each word.
This will set the Hebrew words apart as RTL sections in an otherwise LTR document.
(Note that while this will produce the correct output, you're also dependent on the terminal application in which you're running this script having implemented the Unicode Bidirectional Algorithm correctly.)

See Bi-directional (BiDi) layout implementation in pure python.
Install with:
pip install python-bidi
Example usage:
from bidi.algorithm import get_display
print(get_display('LTR text with RTL text (טקסט לדוגמא) will be printed correctly'))
The following package is also available if you are using Django:
http://pypi.python.org/pypi/django-bidi-utils

Finding specific words in a file

I have to write a program in python where the user is given a menu with four different "word games". There is a file called dictionary.txt and one of the games requires the user to input a) the number of letters in a word and b) a letter to exclude from the words being searched in the dictionary (dictionary.txt has the whole dictionary). Then the program prints the words that follow the user's requirements. My question is how on earth do I open the file and search for words with a certain length in that file. I only have a basic code which only asks the user for inputs. I'm am very new at this please help :(
this is what I have up to the first option. The others are fine and I know how to break the loop but this specific one is really giving me trouble. I have tried everything and I just keep getting errors. Honestly, I only took this class because someone said it would be fun. It is, but recently I've really been falling behind and I have no idea what to do now. This is an intro level course so please be nice I've never done this before until now :(
print
print "Choose Which Game You Want to Play"
print "a) Find words with only one vowel and excluding a specific letter."
print "b) Find words containing all but one of a set of letters."
print "c) Find words containing a specific character string."
print "d) Find words containing state abbreviations."
print "e) Find US state capitals that start with months."
print "q) Quit."
print
choice = raw_input("Enter a choice: ")
choice = choice.lower()
print choice
while choice != "q":
if choice == "a":
#wordlen = word length user is looking for.s
wordlen = raw_input("Please enter the word length you are looking for: ")
wordlen = int(wordlen)
print wordlen
#letterex = letter user wishes to exclude.
letterex = raw_input("Please enter the letter you'd like to exclude: ")
letterex = letterex.lower()
print letterex

Here's what you'd want to do, algorithmically:
Open up your file
Read it line by line, and on each line (assuming each line has one and only one word), check if that word is a) of appropriate length and b) does not contain the excluded character
What sort of control flow would this suggest you use? Think about it.
I'm not sure if you're confused about how to approach this from a problem-solving standpoint or a Python standpoint, but if you're not sure how to do this specifically in Python, here are some helpful links:
The Input and Output section of the official Python tutorial
The len() function, which can be used to get the length of a string, list, set, etc.

To open the file, use open(). You should also read the Python tutorial sec. 7, file input/output.
Open a file and get each line
Assuming your dictionary.txt has each word on a separate line:
opened_file = open('dictionary.txt')
for line in opened_file:
print(line) # Put your code here to run it for each word in the dictionary
Word length:
You can check the length of a string using its str.len() method. See the Python documentation on string methods.
"Bacon, eggs and spam".len() # returns '20' for 20 characters long
Check if a letter is in a word:
Use str.find(), again from the Python sring methods.
Further comments after seeing your code sample:
If you want to print a multi-line prompt, use the heredoc syntax (triple quotes) instead of repeated print() statements.
What happens if, when asked "how many letters long", your user enters bacon sandwich instead of a number? (Your assignment may not specify that you should gracefully handle incorrect user input, but it never hurts to think about it.)

My question is how on earth do I open the file
Use the with statement
with open('dictionary.txt','r') as f:
for line in f:
print line
and search for words with a certain length in that file.
First, decide what is the length of the word you want to search.
Then, read each line of the file that has the words.
Check each word for its length.
If it matches the length you are looking for, add it to a list.

Deleting already printed in Python

For practice, I'm trying to do some stuff in Python. I've decided to make a simple hangman game - I'm not making a GUI. The game would start with a simple input(). Now, I'd like next line to, beside asking for input, to delete the hidden word. I've tried using \b (backspace character), but it's not working. Something like:
word = input("Your word: ")
for i in range(len(word) + 12):
print("\b")
Now, printing the backlash character is supposed to delete the input and "Your word", but it isn't doing anything. If I do this in IDLE I get squares, and I get nothing if I open it by clicking.
How to accomplish this? I'm afraid I wasn't too clear with my question, but I hope you'll see what I meant. :)

\b does not erase the character before the cursor, it simply moves the cursor left one column. If you want text entry without echoing the characters then look at getpass.

I assume the player entering the word wants to be sure they've entered it correctly so you probably want to display the word as they're typing it right?
How about printing enough \ns to move it off the screen when they're done or issue a clear screen command?
You mentioned this was a simple game so a simple solution seems fitting.
[Edit] Here's a simple routine to clear the console on just about any platform (taken from here):
def clearscreen(numlines=100):
"""Clear the console.
numlines is an optional argument used only as a fall-back.
"""
import os
if os.name == "posix":
# Unix/Linux/MacOS/BSD/etc
os.system('clear')
elif os.name in ("nt", "dos", "ce"):
# DOS/Windows
os.system('CLS')
else:
# Fallback for other operating systems.
print '\n' * numlines

word = raw_input("Your word: ")
import sys
sys.stdout.write("\x1b[1A" + 25*" " + "\n")
This will replace the last line printed with 25 spaces.

I think part of your problem is that input is echoing the Enter that terminates your word entry. Your backspaces are on another line, and I don't think they'll back up to the previous line. I seem to recall a SO question about how to prevent that, but I can't find it just now.
Also, I believe print, by default, will output a newline on each call, so each backspace would be on its own line. You can change this by using an end='' argument.
Edit: I found the question I was thinking of, but it doesn't look like there's any help there. You can look at it if you like: Python input that ends without showing a newline