I have been working on some code that will grab emergency incident information from a service called PulsePoint. It works with software built into computer controlled dispatch centers.
This is an app that empowers citizen heroes that are CPR trained to help before a first resonder arrives on scene. I'm merely using it to get other emergency incidents.
I reversed-engineered there app as they have no documentation on how to make your own requests. Because of this i have knowingly left in the api key and auth info because its in plain text in the Android manifest file.
I will definitely make a python module eventually for interfacing with this service, for now its just messy.
Anyhow, sorry for that long boring intro.
My real question is, how can i simplify this function so that it looks and runs a bit cleaner in making a timed request and returning a json object that can be used through subscripts?
import requests, time, json
def getjsonobject(agency):
startsecond = time.strftime("%S")
url = REDACTED
body = []
currentagency = requests.get(url=url, verify=False, stream=True, auth=requests.auth.HTTPBasicAuth(REDACTED, REDCATED), timeout = 13)
for chunk in currentagency.iter_content(1024):
body.append(chunk)
if(int(startsecond) + 5 < int(time.strftime("%S"))): #Shitty internet proof, with timeout above
raise Exception("Server sent to much data")
jsonstringforagency = str(b''.join(body))[2:][:-1] #Removes charecters that define the response body so that the next line doesnt error
currentagencyjson = json.loads(jsonstringforagency) #Loads response as decodable JSON
return currentagencyjson
currentincidents = getjsonobject("lafdw")
for inci in currentincidents["incidents"]["active"]:
print(inci["FullDisplayAddress"])
Requests handles acquiring the body data, checking for json, and parsing the json for you automatically, and since you're giving the timeout arg I don't think you need separate timeout handling. Request also handles constructing the URL for get requests, so you can put your query information into a dictionary, which is much nicer. Combining those changes and removing unused imports gives you this:
import requests
params = dict(both=1,
minimal=1,
apikey=REDACTED)
url = REDACTED
def getjsonobject(agency):
myParams = dict(params, agency=agency)
return requests.get(url, verify=False, params=myParams, stream=True,
auth=requests.auth.HTTPBasicAuth(REDACTED, REDACTED),
timeout = 13).json()
Which gives the same output for me.
Related
I am trying to run my csv data thru "https://rxnav.nlm.nih.gov/REST/interaction" to identify any drug interactions using python. What else do I need in order to have the program be ready?
I got 200 when print status_code is that mean my code is up and ready?
import requests
response = requests.get("https://rxnav.nlm.nih.gov/REST/interaction")
print(response.status_code)
Here's how you'd hit this API, using requests and the details in their example:
import requests
uri = "https://rxnav.nlm.nih.gov/REST/interaction/interaction.json"
params = {'rxcui': 341248}
r = requests.get(uri, params)
Now you can check that r.status_code is 200, and get at the result of the request. For example:
r.json()
As you may realize, this returns a Python dictionary.
The general idea is that requsts.get() takes the base URL, followed by the query parameters, given as a dictionary. What you get back depends on the API endpoint you're querying, and/or on the parameters. In this, it's giving you JSON. Others might give you text (see r.text for this representation), or bytes (r.content).
I am communicating with an API using HTTP.client in Python 3.6.2.
In order to upload a file it requires a three stage process.
I have managed to talk successfully using POST methods and the server returns data as I expect.
However, the stage that requires the actual file to be uploaded is a PUT method - and I cannot figure out how to syntax the code to include a pointer to the actual file on my storage - the file is an mp4 video file.
Here is a snippet of the code with my noob annotations :)
#define connection as HTTPS and define URL
uploadstep2 = http.client.HTTPSConnection("grabyo-prod.s3-accelerate.amazonaws.com")
#define headers
headers = {
'accept': "application/json",
'content-type': "application/x-www-form-urlencoded"
}
#define the structure of the request and send it.
#Here it is a PUT request to the unique URL as defined above with the correct file and headers.
uploadstep2.request("PUT", myUniqueUploadUrl, body="C:\Test.mp4", headers=headers)
#get the response from the server
uploadstep2response = uploadstep2.getresponse()
#read the data from the response and put to a usable variable
step2responsedata = uploadstep2response.read()
The response I am getting back at this stage is an
"Error 400 Bad Request - Could not obtain the file information."
I am certain this relates to the body="C:\Test.mp4" section of the code.
Can you please advise how I can correctly reference a file within the PUT method?
Thanks in advance
uploadstep2.request("PUT", myUniqueUploadUrl, body="C:\Test.mp4", headers=headers)
will put the actual string "C:\Test.mp4" in the body of your request, not the content of the file named "C:\Test.mp4" as you expect.
You need to open the file, read it's content then pass it as body. Or to stream it, but AFAIK http.client does not support that, and since your file seems to be a video, it is potentially huge and will use plenty of RAM for no good reason.
My suggestion would be to use requests, which is a way better lib to do this kind of things:
import requests
with open(r'C:\Test.mp4'), 'rb') as finput:
response = requests.put('https://grabyo-prod.s3-accelerate.amazonaws.com/youruploadpath', data=finput)
print(response.json())
I do not know if it is useful for you, but you can try to send a POST request with requests module :
import requests
url = ""
data = {'title':'metadata','timeDuration':120}
mp3_f = open('/path/your_file.mp3', 'rb')
files = {'messageFile': mp3_f}
req = requests.post(url, files=files, json=data)
print (req.status_code)
print (req.content)
Hope it helps .
Trying to send pageview hit using Measurement Protocol to Google Analytics, Universal property (using Python's Requests library to make HTTP request)
import requests
endpoint = 'https://www.google-analytics.com/collect'
payload = {'v':'1'
,'tid':'UA-XXXXXX-Y'
,'t':'pageview'
,'dl': 'http%3A%2F%2Fvibhorj.com%2Ftest1%2Fpath2'
,'cid':'928534239.3492469166'
}
r = requests.post(url = endpoint, data = payload)
r.status_code is returned as 200 (OK), but still can't see the hit in Real Time reports or in standard report
also tried GET request:
requests.post(url = endpoint, params = payload)
(same result: status_code returned in 200 OK but still no data in GA reports)
any help, pointers will be highly appreciated
[SOLVED!]:
Apparently I notice User-Agent is mandatory to set. Following code worked for me
r = requests.post(url = endpoint, data = dic2
, headers={'User-Agent': 'My User Agent 1.0'})
To enable to see the Python hits on the tool you have yo uncheck the option of "Exclude all hits from known bots and spiders". Also check the filter if you are not excluding this data in others ways.
Also, it's highly recommended to add the parameter title ("&dt"), this parameter is used on the Report "User Explorer" or in other "reports of behavior section" is not mandatory but you can expect undesired issues with the tool.
Greetings
I am using an api which takes html code as input.Lets say it is accesible at http://10.21.2.80:8000/Application/validate_content.php
validate_content.php
$html_data = trim(urldecode($_POST['html'])); // html is key
validate($html_data)
access.py
I am sending a request to this api using python requests like
import requests
openfile = open('file.txt')
html_data = openfile.read()
openfile.close()
url = http://10.21.2.80:8000/Application/validate_content.php?id=12&offset=10
response = requests.post(url,data={'html':html_data})
validate() checks weather html code follows 508 compliance rules or not. If it follows the rules then it returns PASS, else it returns the errors in the code.
When I am making request using POSTMAN, the API is giving right response(Validating and returning errors). But with python code it is always returning PASS.
I don't know what went wrong. Can anyone suggest me the right way to do it.
A while ago, I made a python function which took a URL of an image and passed it to Imgur's API v2. Since I've been notified that the v2 API is going to be deprecated, I've attempted to make it using API v3.
As they say in the Imgur API documentation:
[Sending] an authorization header with your client_id along with your requests [...] also works if you'd like to upload images anonymously (without the image being tied to an account). This lets us know which application is accessing the API.**
Authorization: Client-ID YOURCLIENTID
It's unclear to me (especially with the italics they put) whether they mean that the header should be {'Authorization': 'Client-ID ' + clientID}, or {'Authorization: Client-ID ': clientID}, or {'Authorization:', 'Client-ID ' + clientID}, or some other variation...
Either way, I tried and this is what I got (using Python 2.7.3):
def sideLoad(imgURL):
img = urllib.quote_plus(imgURL)
req = urllib2.Request('https://api.imgur.com/3/image',
urllib.urlencode([('image', img),
('key', clientSecret)]))
req.add_header('Authorization', 'Client-ID ' + clientID)
response = urllib2.urlopen(req)
return response.geturl()
This seems to me like it does everything Imgur wants me to do: I've got the right endpoint, passing data to urllib2.Request makes it a POST request according to the Python docs, I'm passing the image parameter with the form-encoded URL, I also tried giving it my client secret as a POST parameter since I got an error saying I need an ID (even though there is no mention of the need for me to use my client secret anywhere in the relevant documentation). I add the Authorization header and it seems to be the right form, so... why am I getting an Error 400: Bad Request?
Side-question: I might be able to debug it myself if I could see the actual error Imgur returns, but because it returns an erroneous HTTP status, Python dies and gives me one of those nauseating stack traces. Is there any way I could have Python stop whining and give me the error message JSON that I know Imgur returns?
Well, I'll be damned. I tried taking out the encoding functions and just straight up forming the string, and I got it to work. I guess Imgur's API expects the non-form-encoded URL?
Oh... or was it because I used both quote_plus() and url_encode(), encoding the URL twice? That seems even more likely...
This is my working solution, at long last, for something that took me a day when I thought it'd take an hour at most:
def sideLoad(imgURL):
img = urllib.quote_plus(imgURL)
req = urllib2.Request('https://api.imgur.com/3/image', 'image=' + img)
req.add_header('Authorization', 'Client-ID ' + clientID)
response = urllib2.urlopen(req)
response = json.loads(response.read())
return str(response[u'data'][u'link'])
It's not a final version, mind you, it still lacks some testing (I'll see whether I can get rid of quote_plus(), or if it's perhaps preferable to use url_encode alone) as well as error handling (especially for big gifs, the most frequent case of failure).
I hope this helps! I searched all over Google, Imgur and Stack Overflow and the information about anonymous usage of APIv3 were confusing (and drowned in a sea of utterly horrifying OAuth2 stuff).
In python 3.4 using urllib I was able to do it like this:
import urllib.request
import json
opener = urllib.request.build_opener()
opener.addheaders = [("Authorization", "Client-ID"+ yourClientId)]
jsonStr = opener.open("https://api.imgur.com/3/image/"+pictureId).read().decode("utf-8")
jsonObj = json.loads(jsonStr)
#jsonObj is a python dictionary of the imgur json response.