I am trying to check if today's date < date downloaded from text file online. Here is my code :
import datetime
import requests
URL = "http://directlinktotextfile.com/text.txt"
result = requests.get(URL)
today = datetime.datetime.now().date()
Url_date = result.text
Url_date.strip()
Url_date = datetime.date(Url_date)
if today < Url_date :
print "Today is less than future date"
raw_input()
else:
print "Today is greater than or = to future date"
raw_input()
The result that comes back is just this : 2018,02,14. I use .strip() in case there might be blank spaces or extra lines. I've printed out result.text after strip() and it shows the correct details. Why is it that I can't check if today < Url_date. It works fine if I enter manually a date into datetime.date(2018,02,14), but when I'm downloading the string it won't work. Any suggestions?
You pass string to datetime.date() which should be each an integer.
Url_list = []
Url_list = Url_date.split(",")
yr = int(Url_list[0])
mn = int(Url_list[1])
d = int(Url_list[2])
Now pass these integers to datetime.date
Url_date = datetime.date(yr, mn, d)
The arguments you pass to datetime.date(arg1, arg2, arg3) are not strings as a whole. When you pass it from url, what you are actually doing is
datetime.date("2018,2,14")
Note that you are passing only one string argument and not 3 different integers. You should split the date string using comma and then convert each into integers and then pass them as arguments to datetime.date.
Here is what your code is trying to do :
Url_date = datetime.date("2018,02,14")
But he wants to have:
Url_date = datetime.date(2018,02,14)
Do
Url_date.split(',') # Result: ['2018','02','14']
And then convert all the string in the array in integers
It should be ok :)
Use strptime:
import datetime
today = datetime.datetime.now().date()
parsed = datetime.datetime.strptime("2018,02,14", "%Y,%m,%d").date()
print(today < parsed) # True
Related
I'm trying to parse dates from a textfile, but executing the scripts throws incorrect data format, when the format is correct.
The file is a .txt file with the following structure
2018/02/15 05:00:13 - somestring - anotherstring
2018/02/15 05:00:14 - somestring - anotherstring
2018/02/15 05:00:15 - somestring - anotherstring
... etc
The script gets the file divided in lines, and each line is divided on fields, of which one field is a date and time. I divided the date and the time in two separate fields, the time gets converted ok so the problem is in the date.
This is what I get on execution:
ValueError: time data "b'2018/02/15" does not match format '%Y/%m/%d'
I noticed it prints the string with a "b" in front of it, which if I'm not mistaken it means it's a byte literal. I've tried using "decode("utf-8")" on it, but it throw's exception as "string" has no method decode.
#the file is in one long string as I get it from a 'cat' bash command via ssh
file = str(stdout.read()) #reads the cat into a long string
strings = file.split("\\n") #splits the string into lines
for string in strings:
fields = string.split(" - ")
if len(fields) >= 3:
#dates.append(datetime.strptime(campos[0],"%Y/%m/%d %H:%M:%S")) #Wrong format
datentime = fields[0].split()
dates.append(datetime.strptime(datentime[0],"%Y/%m/%d")) #Wrong format
print(datentime[1])
dates.append(datetime.strptime(datentime[1],"%H:%M:%S")) #WORKS
I can't figure out why that is happening to you with the code you gave so I can't offer a fix for that but I tried testing on it and this worked for me:
datetime.strptime(str(datentime[0])[2,:-1], "%Y/%m/%d")
It removes the B and ' from the string, if you still have problems with that, please post how you got that string, maybe there was some error on the way.
use try and except:
import datetime
def convertDate(d):
strptime = datetime.datetime.strptime
try:
return strptime(d, "%Y/%m/%d")
except TypeError:
return strptime(d.decode("utf-8"), "%Y/%m/%d")
print(convertDate(b'2018/02/15'))
print(convertDate('2018/02/15'))
I need convert number to time.
For example:
I need to convert 1230 to 12:30 or 0730 to 07:30.
How to convert a number to time in python?
We can create a function that takes a string and returns the time.
This can all be done in one line by slicing the string up to the minutes (done with [:2]) and then concatenating a ':' and finally concatenating the minutes with [2:].
def getTime(t):
return t[:2] + ':' + t[2:]
and some tests to show it works:
>>> getTime("1230")
'12:30'
>>> getTime("0730")
'07:30'
>>> getTime("1512")
'15:12'
Note how the function cannot take an integer and convert this to a string, as otherwise entries with leading zeros would fail. E.g. 0730 wouldn't work.
Yes, to answer #AbhishtaGatya, this could be written using a lambda function, but doing so wouldn't be advisable. However:
getTime = lambda t: t[:2] + ':' + t[2:]
works just the same as above.
You can insert ":" to the index 2
val = 1230
new= ([str(i) for i in str(val)])
new.insert(2,":")
print(''.join(new))
output:
12:30
Assuming the input is a string, you can do this:
number_str = '0730'
time_str = number_str[:2] + ':' + number_str[2:]
print(time_str) # Output: '07:30'
If you are sure that you only have 4 digits as strings one way is
new = '%s:%s'%(string[:2], string[2:])
Recommended is however to use the datetime handling within python
datetime.
from datetime import datetime
t1="1205"
t2="0605PM"
#%I - 12 hour format
print t1,(datetime.strptime(t1,"%I%M")).strftime("%I:%M")
print t2,(datetime.strptime(t2,"%I%M%p")).strftime("%I:%M")
#%H - 24 hour format
print t1,(datetime.strptime(t1,"%I%M")).strftime("%H:%M")
print t2,(datetime.strptime(t2,"%I%M%p")).strftime("%H:%M")
All of these require 4 digits for your time. This code will add a zero to the front if there are 3 digits. It will check for invalid times.
def conv_num_time(time):
num_str = ('{:04}'.format(time))
time_str = num_str[:2] + ':' + num_str[2:]
if int(num_str[:2])>23 or int(num_str[2:])>59:
print("Invalid time")
else:
print(time_str)
user_time = int(input(': '))
conv_num_time(user_time)
I am writing to write something where there are two variables that are formatted in datetime format. The way the user may input their date and time may have the letter "Z" at the end of it. For example:
"2008-01-01T00:00:01Z"
The user may or may not enter in the "Z" at the end so I want to do something that makes either format acceptable. Here's what I have:
import datetime
b = datetime.datetime.strptime("2008-01-01T00:00:01Z", "%Y-%m-%dT%H:%M:%S")
c = datetime.datetime.strptime("2008-05-01T23:59:00Z", "%Y-%m-%dT%H:%M:%S")
def startTime(b):
try:
datetime.datetime.strptime(b, "%Y-%m-%dT%H:%M:%S")
except:
print "Error: start time is invalid."
def endTime(c):
try:
datetime.datetime.strptime(c, "%Y-%m-%dT%H:%M:%S")
except:
print "Error: end time is invalid."
How about just manually removing the Z if it is there?
user_in = raw_input("Please enter a date")
if user_in.endswith('Z'): user_in = user_in[:-1]
rstrip can remove the Z for you if it exists, and leave the string alone otherwise:
>>> "2008-05-01T23:59:00Z".rstrip("Z")
'2008-05-01T23:59:00'
>>> "2008-05-01T23:59:00".rstrip("Z")
'2008-05-01T23:59:00'
So if you have a date s in string format,
date = datetime.datetime.strptime(s.rstrip("Z"), "%Y-%m-%dT%H:%M:%S")
will handle both cases.
I need a function to generate datafile names with a suffix which must be the current date and time.
I want for the date Feb, 18 2014 15:02 something like this:
data_201402181502.txt
But this is that I get: data_2014218152.txt
My code...
import time
prefix_file = 'data'
tempus = time.localtime(time.time())
suffix = str(tempus.tm_year)+str(tempus.tm_mon)+str(tempus.tm_mday)+
str(tempus.tm_hour)+str(tempus.tm_min)
name_file = prefix_file + '_' + suffix + '.txt'
You can use time.strftime for this, which handles padding leading zeros e.g. on the month:
from time import strftime
name_file = "{0}_{1}.txt".format(prefix_file,
strftime("%Y%m%d%H%M"))
If you simply turn an integer to a string using str, it will not have the leading zero: str(2) == '2'. You can, however, specify this using the str.format syntax: "{0:02d}".format(2) == '02'.
Looks like you want
date.strftime(format)
The format string will allow you to control the output of strftime, try something like:
"%b-%d-%y"
From http://docs.python.org/2/library/datetime.html
Using str.format with datetime.datetime object:
>>> import datetime
>>> '{}_{:%Y%m%d%H%M}.txt'.format('filename', datetime.datetime.now())
'filename_201402182313.txt'
i am writing a script in python that searches for strings and suposedly does different things when encounters strings.
import re, datetime
from datetime import *
f = open(raw_input('Name of file to search: ')
strToSearch = ''
for line in f:
strToSearch += line
patFinder = re.compile('\d{2}\/\d{2}\/\d{4}\sA\d{3}\sB\d{3}')
findPat1 = re.findall(patFinder, strToSearch)
# search only dates
datFinder = re.compile('\d{2}\/\d{2}\/\d{4}')
findDat = re.findall(datFinder, strToSearch)
nowDate = date.today()
fileLst = open('cels.txt', 'w')
ntrdLst = open('not_ready.txt', 'w')
for i in findPat1:
for Date in findDat:
Date = datetime.strptime(Date, '%d/%m/%Y')
Date = Date.date()
endDate = Date + timedelta(days=731)
if endDate < nowDate:
fileLst.write(i)
else:
ntrdLst.write(i)
f.close()
fileLst.close()
ntrdLst.close()
toClose = raw_input('File was modified, press enter to close: ')
so basically it searches for a string with dates and numbers and then same list but only dates, converts the dates, adds 2 years to each and compares, if the date surpass today's date, goes to the ntrdLst, if not, to fileLst.
My problem is that it writes the same list (i) multiple times and doesn't do the sorting.
i am fearly new to python and programming so i am asking for your help. thanks in advance
edit: -----------------
the normal output was this (without the date and if statement)
27/01/2009 A448 B448
22/10/2001 A434 B434
06/09/2007 A825 B825
06/09/2007 A434 B434
06/05/2010 A826 B826
what i would like is if i had a date that is after date.today() say like 27/01/2016 to write to another file and what i keep getting is the script printing this list 30x times or doesn't take to account the if statement.
(sorry, the if was indeed indented the last loop, i went wrong while putting it in here)
You're computing endDate in a loop, once for each date... but not doing anything with it in the loop. So, after the loop is over, you have the very last endDate, and you use only that one to decide which file to write to.
I'm not sure what your logic is supposed to be, but I'm pretty sure you want to put the if statement with the writes inside the inner loop.
If you do that, then if you have, say, 100 pattern matches and 25 dates, you'll end up writing 2500 strings--some to one file, some to the other. Is that what you wanted?
SOLVED
i gave it a little (A LOT) of thought about it and just got all together in one piece. i knew that there too many for loops but now i got it. Thanks anyway to you whom have reached a helping hand to me. I leave the code for anyone having a similar problem.
nowDate = date.today()
for line in sourceFile:
s = re.compile('(\d{2}\/\d{2}\/\d{4})\s(C\d{3}\sS\d{3})')
s1 = re.search(s, line)
if s1:
date = s1.group(1)
date = datetime.strptime(date, '%d/%m/%Y')
date = date.date()
endDate = date + timedelta(days=731)
if endDate <= nowDate:
fileLst.write(s1.group())
fileLst.write('\n')
else:
print ('not ready: ', date.strftime('%d-%m-%Y'))
ntrdLst.write(s1.group(1))
ntrdLst.write('\n')