How to rewrite the Django model save method? - python

How to rewrite the Django model save method?
class Message(models.Model):
"""
message
"""
message_num = models.CharField(default=getMessageNum, max_length=16)
title = models.CharField(max_length=64)
content = models.CharField(max_length=1024)
def save(self, force_insert=False, force_update=False, using=None,
update_fields=None):
# I want send email there
pass
I mean, in the Django model, if I create instance success, I want to call a function, such as send a email in the function.
I find in the Django model have a save method. I am not sure whether should write other code, because there are so many params.
I mean whether I only should care about my send email logic?

When you override the save method, you still have to make sure that the it actually saves the instance. You can do that by simply calling the parent class' save via super:
class Message(models.Model):
# ...
def save(self, *args, **kwargs):
# this will take care of the saving
super(Message, self).save(*args, **kwargs)
# do email stuff
# better handle ecxeptions well or the saving might be rolled back
You can also connect the mail sending to the post_save (or pre_save, depending on your logic) signal. Whether you want to separate one orm the other in that way depends on how closely the two actions are linked and a bit on your taste.
Overriding save gives you the option to intervene in the saving process, e.g. you can change the value of fields based on whether the mail sending was successful or not save the instance at all.

The solution to what you want to do is to use Django Signals. By using Signals you can hook code to when a model is created and saved without having to rewrite the save method, that keep the separation of code and logic in a much nicer way, obviously the model does not need to know about the emails for example.
An example of how to use Signals would be to simply do the following:
from django.db.models.signals import pre_save
from django.dispatch import receiver
from myapp.models import MyModel
#receiver(pre_save, sender=MyModel)
def my_handler(sender, **kwargs):
# Code to execute whenever MyModel is saved...
If you still want to override the save() method you can use the Python super() method to do so (docs).
class MyModel(models.Model):
def save(self, *args, **kwargs):
# This will call the parent method that you are overriding
# so it will save your instance with the default behavior.
super(MyModel, self).save(*args, **kwargs)
# Then we add whatever extra code we want, e.g. send email...
Messenger.send_email()

You need to activate signal once your message is saved. That means, when your message is saved, django will issue signal as follows:
from django.db.models.signals import post_save
from django.dispatch import receiver
class Message(models.Model):
# fields...
# method for sending email
#receiver(post_save, sender=Message, dispatch_uid="send_email")
def send_email(sender, instance, **kwargs):
# your email send logic here..
You can put your signals in signals.py file inside your app folder and make sure to import that in your application config file as follows:
message/apps.py
from django.apps import AppConfig
class MyAppConfig(AppConfig):
name = 'message'
def ready(self):
import message.signals
And update init file as follows:
message/__init__.py
default_app_config = 'message.apps.MyAppConfig'

Related

How to only perform action once instance created?

My code:
def save(self, *args, **kwargs):
<My_CODE>
if <having_register>:
<send_email_to_admin>
but this function will work when I run an update instance ( The 'force_insert' and 'force_update' parameters can be used to insist that the "save" must be an SQL insert or update )
so if I just want to send an email to admin only once having a new registration? Any way to check the request method or prevent force_insert in this case?
You can check the value of the pk:
def save(self, *args, **kwargs):
<My_CODE>
if self.pk is None:
<send_email_to_admin>
Otherwise you could send the email in the view after having called save.
Another way you can solve this is by using django signals, and use the post_save signal and check the created parameter. A good example for django signals could be this one here, it shows the setup needed for django signals to work.
from django.db.models.signals import post_save
from django.dispatch import receiver
from yourApp.models import yourModel
#receiver(post_save, sender=yourModel)
def new_instance_created(sender, instance, created, **kwargs):
if created:
<send_email_to_admin>

How to create an immutable copy of the django model in python?

I want to create an immutable copy of the model instance, such that the user be able to access the details of the model, including its attributes, but not the save and the delete methods.
The use case is that there are two repos accessing the django model, where one is supposed to have a writable access to the model, while another should only have a readable access to it.
I have been researching ways of doing this. One way, I could think is the readable repo gets the model instance with a wrapper, which is a class containing the model instance as a private variable.
class ModelA(models.Model):
field1=models.CharField(max_length=11)
class ModelWrapper:
def __init__(self,instance):
self.__instance=instance
def __getattr__(self,name):
self.__instance.__getattr__(name)
The obvious problem with this approach is that the user can access the instance from the wrapper instance:
# model_wrapper is the wrapper created around the instance. Then
# model_wrapper._ModelWrapper__instance refers to the ModelA instance. Thus
instance = model_wrapper._ModelWrapper__instance
instance.field2="changed"
instance.save()
Thus, he would be able to update the value. Is there a way to restrict this behaviour?
Try overriding the models save and delete in webapp where you want to restrict that:
class ModelA(models.Model):
field1=models.CharField(max_length=11)
def save(self, *args, **kwargs):
return # Or raise an exception if needed
def delete(self, *args, **kwargs):
return # Or raise an exception if needed
If you are using update or delete on a queryset you might also need a pre_save and pre_delete signal:
from django.db.models.signals import pre_delete
#receiver(pre_delete, sender=ModelA)
def pre_delete_handler(sender, instance, *args, **kwargs):
raise Exception('Cannot delete')
Edit: Looks like querysets don't send the pre_save/post_save signal so that cannot be used there, the delete signals are emitted though.
class ModelA(models.Model):
field1=models.CharField(max_length=11)
class ModelWrapper:
def __init__(self, instance):
self.__instance=instance
# Delete unwanted attributes
delattr(self.__instance, 'save')
delattr(self.__instance, 'delete')
def __getattr__(self,name):
self.__instance.__getattr__(name)

How to trigger an action after model and related m2m (groups) fields are saved?

How to do something after a Django user model save, including related changes to m2m fields like django.contrib.auth.models.Group?
Situation
I have a custom Django user model and want to trigger some actions after a user instance is - with related changes such as m2m group memberships - successfully saved to the database.
The use case here is a Wagtail CMS where I create ProfilePages for each user instance. Depending of the group memberships of the user instance, I need to do something.
Problem
In a custom model save() method, I'm not able to reference the changed group memberships, as m2m's are saved after the saving of the user instance. Even if running my custom function after the super().save() call, new group memberships are not yet available.
But I need to get the new group memberships in order to do something depending of the new groups for that user.
What I've tried
[✘] Custom model save()
# file: users/models.py
class CustomUser(AbstractUser):
super().save(*args, **kwargs)
do_something()
[✘] Signal post_save
As the above simple save() method did not do the trick, I tried the post_save signal of the user model:
# file users/signals.py
#receiver(post_save, sender=get_user_model())
def handle_profilepage(sender, instance, created, **kwargs):
action = 'created' if created else 'updated'
do_something()
... but even here I always get the "old" values from the group membership back.
[✔] Signal: m2m_changed
I learnt that there is a m2m_changed signal with which I could monitor changes of the Users.groups(.through) table.
My following implementation did what I need:
#receiver(m2m_changed, sender=User.groups.through)
def user_groups_changed_handler(sender, instance, **kwargs):
USER_GROUPS = instance.groups.values_list('name', flat=True)
if set(USER_GROUPS) & set(settings.PROFILE_GROUPS):
do_something_because_some_groups_match()
else:
do_something_else()
My whishlist
I would happily stay away from signals if there is a chance to solve this problem in the models save() method - but I'm stuck...
You asked after the dark magic. Tell me, what are you willing to sacrifice to avoid using signals? Would you embrace a greater evil? What if I were to suggest that you could start a new thread and sleep for a few seconds until you thought that the m2m relations were probably saved before doing anything?
from threading import Thread
from time import sleep
# file: users/models.py
class CustomUser(AbstractUser):
super().save(*args, **kwargs)
def do_something(obj):
sleep(3)
# stuff
thread = Thread(target = do_something, args = [self], daemon=True)
thread.start()

Django EventLog: Passing in current user

I am trying to add logging to my Django app using EventLog. I followed an example online but not sure how to pass in the user that makes the changes. The example shows it as user=self.user. Obviously this wouldn't work in my case as it doesn't refer to anything in my model
models.py
class Client(models.Model):
name = models.CharField(max_length=50)
....
def save(self, *args, **kwargs):
# Initial Save
if not self.pk:
log(user=self.user, action='ADD_CLIENT',
extra={'id': self.id})
else:
log(user=self.user, action='UPDATED_CLIENT',
extra={'id': self.id})
super(Client, self).save(*args, **kwargs)
The save method will only know what has been passed into it, this will normally not include the request which is where you would get the current user (request.user).
You should instead add logging in the view which is calling the save method.
user = request.user

How to use Django model inheritance with signals?

I have a few model inheritance levels in Django:
class WorkAttachment(models.Model):
""" Abstract class that holds all fields that are required in each attachment """
work = models.ForeignKey(Work)
added = models.DateTimeField(default=datetime.datetime.now)
views = models.IntegerField(default=0)
class Meta:
abstract = True
class WorkAttachmentFileBased(WorkAttachment):
""" Another base class, but for file based attachments """
description = models.CharField(max_length=500, blank=True)
size = models.IntegerField(verbose_name=_('size in bytes'))
class Meta:
abstract = True
class WorkAttachmentPicture(WorkAttachmentFileBased):
""" Picture attached to work """
image = models.ImageField(upload_to='works/images', width_field='width', height_field='height')
width = models.IntegerField()
height = models.IntegerField()
There are many different models inherited from WorkAttachmentFileBased and WorkAttachment. I want to create a signal, which would update an attachment_count field for parent work, when attachment is created. It would be logical, to think that signal made for parent sender (WorkAttachment) would run for all inherited models too, but it does not. Here is my code:
#receiver(post_save, sender=WorkAttachment, dispatch_uid="att_post_save")
def update_attachment_count_on_save(sender, instance, **kwargs):
""" Update file count for work when attachment was saved."""
instance.work.attachment_count += 1
instance.work.save()
Is there a way to make this signal work for all models inherited from WorkAttachment?
Python 2.7, Django 1.4 pre-alpha
P.S. I've tried one of the solutions I found on the net, but it did not work for me.
You could register the connection handler without sender specified. And filter the needed models inside it.
from django.db.models.signals import post_save
from django.dispatch import receiver
#receiver(post_save)
def my_handler(sender, **kwargs):
# Returns false if 'sender' is NOT a subclass of AbstractModel
if not issubclass(sender, AbstractModel):
return
...
Ref: https://groups.google.com/d/msg/django-users/E_u9pHIkiI0/YgzA1p8XaSMJ
The simplest solution is to not restrict on the sender, but to check in the signal handler whether the respective instance is a subclass:
#receiver(post_save)
def update_attachment_count_on_save(sender, instance, **kwargs):
if isinstance(instance, WorkAttachment):
...
However, this may incur a significant performance overhead as every time any model is saved, the above function is called.
I think I've found the most Django-way of doing this: Recent versions of Django suggest to connect signal handlers in a file called signals.py. Here's the necessary wiring code:
your_app/__init__.py:
default_app_config = 'your_app.apps.YourAppConfig'
your_app/apps.py:
import django.apps
class YourAppConfig(django.apps.AppConfig):
name = 'your_app'
def ready(self):
import your_app.signals
your_app/signals.py:
def get_subclasses(cls):
result = [cls]
classes_to_inspect = [cls]
while classes_to_inspect:
class_to_inspect = classes_to_inspect.pop()
for subclass in class_to_inspect.__subclasses__():
if subclass not in result:
result.append(subclass)
classes_to_inspect.append(subclass)
return result
def update_attachment_count_on_save(sender, instance, **kwargs):
instance.work.attachment_count += 1
instance.work.save()
for subclass in get_subclasses(WorkAttachment):
post_save.connect(update_attachment_count_on_save, subclass)
I think this works for all subclasses, because they will all be loaded by the time YourAppConfig.ready is called (and thus signals is imported).
You could try something like:
model_classes = [WorkAttachment, WorkAttachmentFileBased, WorkAttachmentPicture, ...]
def update_attachment_count_on_save(sender, instance, **kwargs):
instance.work.attachment_count += 1
instance.work.save()
for model_class in model_classes:
post_save.connect(update_attachment_count_on_save,
sender=model_class,
dispatch_uid="att_post_save_"+model_class.__name__)
(Disclaimer: I have not tested the above)
I just did this using python's (relatively) new __init_subclass__ method:
from django.db import models
def perform_on_save(*args, **kw):
print("Doing something important after saving.")
class ParentClass(models.Model):
class Meta:
abstract = True
#classmethod
def __init_subclass__(cls, **kwargs):
super().__init_subclass__(**kwargs)
models.signals.post_save.connect(perform_on_save, sender=cls)
class MySubclass(ParentClass):
pass # signal automatically gets connected.
This requires django 2.1 and python 3.6 or better. Note that the #classmethod line seems to be required when working with the django model and associated metaclass even though it's not required according to the official python docs.
post_save.connect(my_handler, ParentClass)
# connect all subclasses of base content item too
for subclass in ParentClass.__subclasses__():
post_save.connect(my_handler, subclass)
have a nice day!
Michael Herrmann's solution is definitively the most Django-way of doing this.
And yes it works for all subclasses as they are loaded at the ready() call.
I would like to contribute with the documentation references :
In practice, signal handlers are usually defined in a signals submodule of the application they relate to. Signal receivers are connected in the ready() method of your application configuration class. If you’re using the receiver() decorator, simply import the signals submodule inside ready().
https://docs.djangoproject.com/en/dev/topics/signals/#connecting-receiver-functions
And add a warning :
The ready() method may be executed more than once during testing, so you may want to guard your signals from duplication, especially if you’re planning to send them within tests.
https://docs.djangoproject.com/en/dev/topics/signals/#connecting-receiver-functions
So you might want to prevent duplicate signals with a dispatch_uid parameter on the connect function.
post_save.connect(my_callback, dispatch_uid="my_unique_identifier")
In this context I'll do :
for subclass in get_subclasses(WorkAttachment):
post_save.connect(update_attachment_count_on_save, subclass, dispatch_uid=subclass.__name__)
https://docs.djangoproject.com/en/dev/topics/signals/#preventing-duplicate-signals
This solution resolves the problem when not all modules imported into memory.
def inherited_receiver(signal, sender, **kwargs):
"""
Decorator connect receivers and all receiver's subclasses to signals.
#inherited_receiver(post_save, sender=MyModel)
def signal_receiver(sender, **kwargs):
...
"""
parent_cls = sender
def wrapper(func):
def childs_receiver(sender, **kw):
"""
the receiver detect that func will execute for child
(and same parent) classes only.
"""
child_cls = sender
if issubclass(child_cls, parent_cls):
func(sender=child_cls, **kw)
signal.connect(childs_receiver, **kwargs)
return childs_receiver
return wrapper
It's also possible to use content types to discover subclasses - assuming you have the base class and subclasses packaged in the same app. Something like this would work:
from django.contrib.contenttypes.models import ContentType
content_types = ContentType.objects.filter(app_label="your_app")
for content_type in content_types:
model = content_type.model_class()
post_save.connect(update_attachment_count_on_save, sender=model)
In addition to #clwainwright answer, I configured his answer to instead work for the m2m_changed signal. I had to post it as an answer for the code formatting to make sense:
#classmethod
def __init_subclass__(cls, **kwargs):
super().__init_subclass__(**kwargs)
for m2m_field in cls._meta.many_to_many:
if hasattr(cls, m2m_field.attname) and hasattr(getattr(cls, m2m_field.attname), 'through'):
models.signals.m2m_changed.connect(m2m_changed_receiver, weak=False, sender=getattr(cls, m2m_field.attname).through)
It does a couple of checks to ensure it doesn't break if anything changes in future Django versions.

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