I have a simple three line script that converts a string to a datetime in Python.
from datetime import datetime
mydate='Feb-22-1732'
print(datetime.strptime(mydate,'%b-%dd-%Y'))
But when I run this code, I get an error saying:
ValueError: time data 'Feb-22-1732' does not match format '%b-%dd-%Y'
Can you please help me understand what am I doing wrong here?
Thanks in advance.
You don't need to repeat d two times - %d handles two-digit days by definition:
%d - Day of the month as a zero-padded decimal number.
print(datetime.strptime(mydate,'%b-%d-%Y'))
Related
I need python code for 'YYYY-MM-DD HH24:MI:SS.FF' format .
The result would be like this '2019-07-27 12:07:00.0'
sample code that I tried:
from datetime import datetime as dt
from datetime import timedelta
timestamp=(dt.now() - timedelta(1)).strftime('%Y-%m-%d %HH24:%MI:%SS.%FF')
Output:2019-09-05 10H24:31I:57S.2019-09-05F
Results should looks like 2019-09-05 10:31:57.0
Your format string just needs to be adapted - Python takes a single character to tell about the correct output - your repeated characters don't work like that.
Here is a corrected code example:
from datetime import datetime as dt
from datetime import timedelta
timestamp=(dt.now() - timedelta(1)).strftime('%Y-%m-%d %H:%M:%S.%f')
As you can see, I just removed some characters and wrote f in lowercase. The format characters that you chose already include padding and 24-hour format.
Example output: '2019-09-05 12:27:45.416157'
For a full list of format characters, please check the linked python documentation.
According to this documentation, you should use the following format:
timestamp=(dt.now() - timedelta(1)).strftime('%Y-%m-%d %H:%M:%S.%f')
I am trying to find the correct time format for this time string for the Python time module:
'2019-01-25T06:59:36.8081116Z'
I tried this '%Y-%m-%dT%H:%M:%SZ' and many variants and can't get it right.
Link to the documentation:
https://docs.python.org/2/library/time.html
This might help
import datetime
curtime = datetime.datetime.now()
curtime.strftime("%Y-%m-%dT%H:%M:%S.%fZ")
couldn't figure out how to get 7 decimal places. Maybe your string ends with '6Z' instead of 'Z'?
I am converting the datetime into time. My JSON datetime format is "2017-01-02T19:00:07.9181202Z". I have placed my code below:
from datetime import datetime
date_format = datetime.strptime('2017-01-02T19:00:07.9181202Z', '%Y-%m-%dT%H:%M:%S.%fZ')
time = date_format.strftime("%I:%M %p")
print(time)
Error message as below:
After that I read this python date-time document. It says that microsecond digit should be 6. But, JSON date-time microsecond has 7 digit.
Message from Python document:
%f is an extension to the set of format characters in the C standard
(but implemented separately in datetime objects, and therefore always
available). When used with the strptime() method, the %f directive
accepts from one to six digits and zero pads on the right.
I need result like 07:00 PM format. Is there any alternative method?
Thanks in advance.
If you're sure that the input will always be like that, you can just remove the extra digit before passing that string to strptime:
date_format = datetime.strptime('2017-01-02T19:00:07.9181202Z'[:-2] + 'Z', '%Y-%m-%dT%H:%M:%S.%fZ')
This is dirty, but gives the idea - remove the last two characters (the extra digit and "Z"), re-add the "Z".
This question already has answers here:
Python 2.7 how parse a date with format 2014-05-01 18:10:38-04:00 [duplicate]
(2 answers)
Closed 6 years ago.
I am receiving a json that prints time data '2016-04-15T02:19:17+00:00' I I cant seem to figure out the format of this unicode string.
I need to find a difference in time between then and now. The first step in that is to convert the string to structured format and Iam not able to find the format
fmt='"%Y-%m-%d %H:%M:%S %Z'
#fmt='%Y-%m-%d %H:%M:%S.%f'
print datetime.datetime.strptime(result_json['alert_time'], fmt)
I keep getting exception that it is not the same format
time data '2016-04-15T02:19:17+00:00' does not match format '"%Y-%m-%d %H:%M:%S %Z'
There are a few problems with your format. First, it has a double quote " in it. Second, you need to include the T between the date and the time. Third, the timezone offset is not standard. Here is code that will work:
print datetime.datetime.strptime('2016-04-15T02:19:17', '%Y-%m-%dT%H:%M:%S')
If your alert_time is always in GMT, you can just trim the timezone off before calling strptime.
The answer by Brent is the safer and faster option rather than having things going on under the hood. But the amount of times I've had datetime as a frustrating bottleneck not associated with the main problem I wanted to test out, I will also point out that dateparser here has not yet been wrong for me and will take a huge range of inputs.
import dateparser
import datetime
date = '2016-04-15T02:19:17+00:00'
date_parser_format = dateparser.parse(date)
datetime_format = datetime.datetime.strptime('2016-04-15T02:19:17', '%Y-%m-%dT%H:%M:%S')
print date_parser_format
print datetime_format
I have a time String like this：
07/01/2015-14:31:58.520
I use this command line to convert it:
import time
timeStr = "07/01/2015-14:31:58.520"
time.strptime(timeStr,'%d/%m/%y-%H:%M:%S.%f')
But this returns:
ValueError: time data '07/01/2015-14:31:58.520' does not match format
'%d/%m/%y-%H:%M:S.%f'
My python version is 2.7.7
%y denotes a 2 digit year, but your string has a 4 digit year. Use %Y (capital Y) to denote a 4 digit year. See the docs for more information.
time.strptime(timeStr, '%d/%m/%Y-%H:%M:%S.%f')
Note that datetime.strptime may be more useful, as it will return a full datetime object rather than a tuple. The format syntax is essentially the same.
It should have been capital Y for year (%Y in place of %y)
time.strptime(timeStr,'%d/%m/%Y-%H:%M:%S.%f')
You need to use %Y instead of %y
time.strptime(timeStr,'%d/%m/%Y-%H:%M:%S.%f')
To get a datetime object, use python-dateutil
To install
pip install python-dateutil
Then
t = "07/01/2015-14:31:58.520"
from dateutil import parser
>>>parser.parse(t)
datetime.datetime(2015, 7, 1, 14, 31, 58, 520000)
tim = parser.parse(t)
>>>str(tim.date())
'2015-07-01'
All operations to datetime objects is possible.
the time.strptime syntax %d/%m/%y-%H:%M:%S.%f is incorrect, it should be
"%d/%m/%Y-%H:%M:%S.%f"
where the only difference is that %y has become %Y. The reason is because from the docs %y is without century number ( [00,99] ), whereas %Y is with century number, which is the syntax you use with "2015"
Tested and functinal in python 2.7.5 and 3.4.1
Edit: Zero answers when I started typing this, 6 answers by time of post, sorry about that!
Edit #2: datetime.strptime functions similarly, so if you want to use that as well, you can!