I use this method to send file to remote server:
def runSendArchive(host, port, username, password, remote_directory, archive):
try:
s = paramiko.SSHClient()
s.set_missing_host_key_policy(paramiko.AutoAddPolicy())
s.connect(host, username, password, port)
sftp = s.open_sftp()
sftp.put(archive, remote_directory)
print "3 - The file was uploaded via SSH!"
except (BadHostKeyException, AuthenticationException, SSHException, socket.error) as e:
print "4 - Error! The file was not uploaded: ", e
It returns me an exception:
except (BadHostKeyException, AuthenticationException, SSHException, socket.error) as e: NameError: global name
'BadHostKeyException' is not defined
How to use this library right?
Now I get the following error:
File "run.py", line 65, in runSendArchive
sftp.put(archive, remote_directory)
File "C:\Python27\lib\site-packages\paramiko\sftp_client.py", line 721, in put
return self.putfo(fl, remotepath, file_size, callback, confirm)
File "C:\Python27\lib\site-packages\paramiko\sftp_client.py", line 677, in putfo
with self.file(remotepath, 'wb') as fr:
File "C:\Python27\lib\site-packages\paramiko\sftp_client.py", line 338, in open
t, msg = self._request(CMD_OPEN, filename, imode, attrblock)
File "C:\Python27\lib\site-packages\paramiko\sftp_client.py", line 774, in _request
return self._read_response(num)
File "C:\Python27\lib\site-packages\paramiko\sftp_client.py", line 826, in _read_response
self._convert_status(msg)
File "C:\Python27\lib\site-packages\paramiko\sftp_client.py", line 859, in _convert_status
raise IOError(text)
IOError: Failure
65 line is sftp.put(archive, remote_directory)
Judging from the line
paramiko.SSHClient()
you are calling import paramiko
Since BadHostKeyException is in paramiko.ssh_exception, you need to add an
from paramiko.ssh_exception import BadHostKeyException, AuthenticationException, SSHException
See http://docs.paramiko.org/en/2.3/api/ssh_exception.html
paramiko.ssh_exception.BadHostKeyException
paramiko.ssh_exception.AuthenticationException
paramiko.ssh_exception.SSHException
reside in that module.
For your example code snippet you would need to add the following before the runSendArchive function
import socket
import paramiko
from paramiko.ssh_exception import BadHostKeyException, AuthenticationException, SSHException
Related
This question already has an answer here:
Uploading file via Paramiko SFTP not working
(1 answer)
Closed 2 years ago.
I want to upload a file to a SFTP server using Paramiko, but I don't seem to get it right.
I thought I got the respective error cause of the file path '/' witch is the root on the server but I didn't get anywhare.
I keep getting this error:
File "c:\python\whitelistBot\whitelistBot.py", line 63, in on_message
sftp_client.put('C:/python/whitelistBot/whitelist1.json', '/')
File "C:\python\whitelistBot\lib\site-packages\paramiko\sftp_client.py", line 759, in put
return self.putfo(fl, remotepath, file_size, callback, confirm)
File "C:\python\whitelistBot\lib\site-packages\paramiko\sftp_client.py", line 714, in putfo
with self.file(remotepath, "wb") as fr:
File "C:\python\whitelistBot\lib\site-packages\paramiko\sftp_client.py", line 372, in open
t, msg = self._request(CMD_OPEN, filename, imode, attrblock)
File "C:\python\whitelistBot\lib\site-packages\paramiko\sftp_client.py", line 813, in _request
return self._read_response(num)
File "C:\python\whitelistBot\lib\site-packages\paramiko\sftp_client.py", line 865, in _read_response
self._convert_status(msg)
File "C:\python\whitelistBot\lib\site-packages\paramiko\sftp_client.py", line 898, in _convert_status
raise IOError(text)
OSError: Operation Unsupported
The code I'm running:
import paramiko
FTP_HOST = "********"
FTP_USER = "********"
FTP_PASS = "********"
FTP_PORT = ****
ssh_client = paramiko.SSHClient()
ssh_client.set_missing_host_key_policy(paramiko.AutoAddPolicy())
ssh_client.connect(hostname= FTP_HOST, username=FTP_USER, password=FTP_PASS, port=FTP_PORT)
sftp_client = ssh_client.open_sftp()
sftp_client.put('C:/python/whitelistBot/whitelist1.json', '/')
sftp_client.close()
ssh_client.close()
EDIT: I changed the directory where to put the file to "/home/container" cause that's what they told me in the site but except for the fact that I don't get that error message, the file does not appear on the server
Looks like I had to specify the name of the file '/whitelist1.json' like so:
sftp_client.put('C:/python/whitelistBot/whitelist1.json', '/whitelist1.json') # don't know why but yeah
import paramiko
from socket import error as socket_error
import os
server =['10.10.0.1','10.10.0.2']
path='/home/test/'
for hostname in server:
try:
ssh_remote =paramiko.SSHClient()
ssh_remote.set_missing_host_key_policy(paramiko.AutoAddPolicy())
privatekeyfile = os.path.expanduser('~/.ssh/id')
mykey = paramiko.RSAKey.from_private_key_file(privatekeyfile, password='test123')
ssh_remote.connect(hostname, username = 'test1', pkey = mykey)
sftp=ssh_remote.open_sftp()
for i in sftp.listdir(path):
info = sftp.stat(i)
print info.st_size
except paramiko.SSHException as sshException:
print "Unable to establish SSH connection:{0}".format(hostname)
except socket_error as socket_err:
print "Unable to connect connection refused"
This is my code. I tried to get file size of remote server files. But below error was throwing. Can some please guide on this?
Error
Traceback (most recent call last):
File "<stdin>", line 15, in <module>
File "/usr/lib/python2.6/site-packages/paramiko/sftp_client.py", line 337, in stat
t, msg = self._request(CMD_STAT, path)
File "/usr/lib/python2.6/site-packages/paramiko/sftp_client.py", line 624, in _request
return self._read_response(num)
File "/usr/lib/python2.6/site-packages/paramiko/sftp_client.py", line 671, in _read_response
self._convert_status(msg)
File "/usr/lib/python2.6/site-packages/paramiko/sftp_client.py", line 697, in _convert_status
raise IOError(errno.ENOENT, text)
IOError: [Errno 2] No such file
SFTPClient.listdir returns file names only, not a full path. So to use the filename in another API, you have to add a path:
for i in sftp.listdir(path):
info = sftp.stat(path + "/" + i)
print info.st_size
Though that's inefficient. Paramiko knows the size already, you are just throwing the information away by using SFTPClient.listdir instead of SFTPClient.listdir_attr (listdir calls listdir_attr internally).
for i in sftp.listdir_attr(path):
print i.st_size
I'm a newb at python, so please excuse the hack job I created in order to transfer the contents of a folder into an ssh server.
The problem is that it works great in my test server, but as soon as run it against the actual server that I need to upload files for I receive the error below, and I'm not sure what it means.
I've googled it, but I can't figure it out, please help.
Thanks.
import paramiko
import glob
import os
from shutil import move
host = "192.168.1.87" #hard-coded
port = 22
password ="passwd" #hard-coded
username = "administator" #hard-coded
remotepath ='' #hard-coded
localpath = 'D:\\PH/PH_PROD\\PowerConnectInterf1_WINS\\bin\\data\\Sheex\\bc\\945\\'
#build filename array
os.chdir("D:/PH/PH_PROD/PowerConnectInterf1_WINS/bin/data/Sheex/bc/945")
filelist=[]
for files in glob.glob( "2016*" ):
f = open(files, 'r')
filelist.append(f.name)
f.close()
if (len(filelist)>0):
transport = paramiko.Transport((host, port))
transport.connect(username=username, password=password)
sftp = paramiko.SFTPClient.from_transport(transport)
for s in filelist:
#print remotepath+s
sftp.put(localpath+s,remotepath+s)
#os.rename(localpath+s,localpath+"945back/"+s)
sftp.close()
transport.close()
#print 'Upload done.'
Error:
D:\Scripts>python mysftp.py
Traceback (most recent call last):
File "mysftp.py", line 37, in <module>
sftp.put(localpath+s,remotepath+s)
File "C:\Python27\lib\site-packages\paramiko\sftp_client.py", line 676, in put
return self.putfo(fl, remotepath, file_size, callback, confirm)
File "C:\Python27\lib\site-packages\paramiko\sftp_client.py", line 634, in put
fo
with self.file(remotepath, 'wb') as fr:
File "C:\Python27\lib\site-packages\paramiko\sftp_client.py", line 327, in ope
n
t, msg = self._request(CMD_OPEN, filename, imode, attrblock)
File "C:\Python27\lib\site-packages\paramiko\sftp_client.py", line 730, in _re
quest
return self._read_response(num)
File "C:\Python27\lib\site-packages\paramiko\sftp_client.py", line 781, in _re
ad_response
self._convert_status(msg)
File "C:\Python27\lib\site-packages\paramiko\sftp_client.py", line 807, in _co
nvert_status
raise IOError(errno.ENOENT, text)
IOError: [Errno 2] Invalid file ID
It sounds like the path you are writing on the server doesn't exist. You should check and create if doesn't exist.
I'm coding a script to check a FTP directory and download the new files. This is part of the code:
from ftplib import FTP
import os
ftp = FTP(ftp_lance)
ftp.login(login, password)
ftp.cwd('xxxxxx')
FTP_list = ftp.nlst()
lista_diferenca = [file for file in FTP_list if file not in local_list]
for file in lista_diferenca:
local_filename = os.path.join(cache, file)
ftp.retrbinary('REST ' + file, open(local_filename, 'wb').write)
When I run it, I get this error message:
Traceback (most recent call last):
File "D:\Scripts\Istari\Radagast\Radagast.py", line 44, in <module>
ftp.retrbinary('REST tabela14_pag5.pdf', open(local_filename, 'wb').write)
File "D:\Portable Python 2.7.6.1\App\lib\ftplib.py", line 414, in retrbinary
conn = self.transfercmd(cmd, rest)
File "D:\Portable Python 2.7.6.1\App\lib\ftplib.py", line 376, in transfercmd
return self.ntransfercmd(cmd, rest)[0]
File "D:\Portable Python 2.7.6.1\App\lib\ftplib.py", line 339, in ntransfercmd
resp = self.sendcmd(cmd)
File "D:\Portable Python 2.7.6.1\App\lib\ftplib.py", line 249, in sendcmd
return self.getresp()
File "D:\Portable Python 2.7.6.1\App\lib\ftplib.py", line 224, in getresp
raise error_perm, resp
error_perm: 501 Bad parameter. Numeric value required
I check several sites searching for this kind of error and find nothing. It seems that my retrbinaty is broken, but the arguments looks right (first the 'Rest' + file, and then the callback function).
Some idea about my error?
You need to specify the FTP command RETR, not REST:
ftp.retrbinary('RETR ' + file, open(local_filename, 'wb').write)
I've installed and written the following Paramiko which is unable to put the file. It is easily able to 'get' a file and execute ls commands on it.
#set username & password
username='runaway'
password='runaway'
port=22
source= '/Unzip.sh'
destination ='/var/mpx/www/http'
#SFTP
client.load_system_host_keys()
print " hostname =%s \n username=%s \n password=%s \n" (hostname,username,password)
t = paramiko.Transport((hostname, port))
t.connect(username=username,password=password)
sftp = paramiko.SFTPClient.from_transport(t)
sftp.put(source,destination)
#sftp.close()
#t.close()
Using a 'put' command gives the following error & stack trace -
File "upload_file.py", line 84, in ?
sftp.put(source,destination)
File "/usr/lib/python2.4/site-packages/paramiko/sftp_client.py", line 522, in put
fr = self.file(remotepath, 'wb')
File "/usr/lib/python2.4/site-packages/paramiko/sftp_client.py", line 221, in open
t, msg = self._request(CMD_OPEN, filename, imode, attrblock)
File "/usr/lib/python2.4/site-packages/paramiko/sftp_client.py", line 572, in _request
return self._read_response(num)
File "/usr/lib/python2.4/site-packages/paramiko/sftp_client.py", line 619, in _read_response
self._convert_status(msg)
File "/usr/lib/python2.4/site-packages/paramiko/sftp_client.py", line 649, in _convert_status
raise IOError(text)
IOError: Failure
How do I overcome this?
The solution seemed very funny to me!
source= '/Unzip.sh'
destination ='/var/mpx/www/http/Unzip.sh'
Just modified the destination path to include the file name as well.
Didn't expect some error like this coming from a Python package.
This also occurs in 2.0.2 when you try to sftp.mkdir('/exists'):
Traceback (most recent call last):
...
File "/usr/local/lib/python2.7/site-packages/paramiko/sftp_client.py", line 380, in mkdir
self._request(CMD_MKDIR, path, attr)
File "/usr/local/lib/python2.7/site-packages/paramiko/sftp_client.py", line 730, in _request
return self._read_response(num)
File "/usr/local/lib/python2.7/site-packages/paramiko/sftp_client.py", line 781, in _read_response
self._convert_status(msg)
File "/usr/local/lib/python2.7/site-packages/paramiko/sftp_client.py", line 811, in _convert_status
raise IOError(text)
IOError: Failure
This was my Python 2.7.9 fix:
try:
sftp.mkdir(remote_dir)
except IOError:
logging.debug('%s already exists.', remote_dir)