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I have tried to use the max code but it printed out the largest number not the variable name.
a=3
b=4
c=7
d=6
e=8
max(a,b,c,d,e)
this is the code I've tried but it printed 8 instead of e.
forgot to add that my values for a b c etc came from a loop so im not suppose to know their values myself...
You need to use a dictionary or a named tuple to do something like that.
>>> my_list = {'a': 1, 'b': 2, 'c': 3}
>>> max(my_list, key=my_list.get)
'c'
Let me know if there are any other methods.
Try this
dct={'a':3 ,'b':4 ,'c':7 ,'d':6 ,'e':8}
for i, j in dct.iteritems():
if j == max(dct.values()):
print i
From this question, there seems to be a way to retrieve the name of your variable (see caveat below before using):
a = 3
b = 4
c = 7
d = 6
e = 8
m = max(a, b, c, d, e)
for k, v in list(locals().items()):
if v is m:
v_as_str = k
break
v_as_str
output:
'e'
Caveat:
This may work if you can be sure that there are no other (unrelated) variables with the same value as the max of a to e
somewhere in your code, and appearing earlier in the locals.
Thanks to #D.Everhard & #asongtoruin in the comments
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Anyone pls help me in program to find out sum of elements in matrix using for loop.
This is my code.
a = [[1,2,3],[1,2,3],[1,2,3]]
total = 0
sha = np.shape(a)
for i in range(sha[0]):
for j in range(sha[1]):
total= total+a[i,j]
return total
Simply use sum
a = [[1,2,3],[1,2,3],[1,2,3]]
sum([sum(i) for i in a])
As it is nested list (list inside a list) you can refer to the following
a=[[1,2],[2,3],[4,5]]
total=0
for i in a:
total+=sum(i)
print(total)
a = [[1,2,3],[1,2,3],[1,2,3]]
Sum = 0
sha = np.shape(a)
for r in range(len(sha)):
for c in range(len(sha)):
sum = sum + a[r][c]
print(Sum)
Sum is looped and calculated for r->row and c-> column
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I am creating a function that takes any quantity of numbers, and tell you what is the max value or if there is a tie for largest. I am wondering what I could do to simplify what I have.
def max_num(*args):
nums = []
nums_1 = []
nums.append(args)
i = 0
while i < len(nums[0]):
nums_1.append(nums[0][i])
i += 1
c = max(nums_1)
nums_1.remove(c)
if c in nums_1:
print("It's a tie!")
else:
print(c)
max_num(-10, 0, 10, 10)
So when I initially make a list with the arguments given, it gives me a tuple inside the list. This is why I create a new list to dissect the tuple into separate values. I have the feeling that wasn't necessary, and that there is a much simpler way to do this. Any advice would be great.
Just get the max, and count how many times it appears in your data:
def max_num(*args):
maxi = max(args)
if args.count(maxi) == 1:
print(maxi)
else:
print('Tie')
max_num(2, 5, 1)
#5
max_num(2, 5, 1, 5)
#Tie
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I am having trouble solving the following question,
Q: Given a string find out the total sum of all the numbers.
Values are as A-1, B-10, C-100, D-1000, E-10000.
Ex. DDBC. Answer is 1000+1000+10+100 = 2110.
There are lots of ways to go about this.
Here's one idea:
Make a lookup that maps letters to the their values. Something like:
import string
lookup = {s: 10**i for i,s in enumerate(string.ascii_uppercase)}
Lookup will be a dictionary like:
{
'A': 1,
'B': 10,
'C': 100,
'D': 1000,
'E': 10000,
'F': 100000,
...
}
With that you can use a comprehension and take the sum:
>> s = "DDBC"
>> sum(lookup[l] for l in s)
2110
This, of course, assumes your string is all uppercase, like the example you posted.
just deduce the power of 10 by the position of the letter:
s = "DDBC"
result = sum(10**(ord(c)-ord('A')) for c in s)
result: 2110
You can filter out lowercase letters & other chars easily, but that complexifies a little bit:
result = sum(10**(ord(c.upper())-ord('A')) for c in s if c.isalpha())
Try searching the string, and every instance of that letter occurring causes you to add to total.
For instance:
total = 0
input_string = input()
for i in len(input_string):
if input_string[i] == "A":
total += 1
and then you can repeat that for the other instances of the other characters.
Hope I helped!
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cc = input('Input the number: ')
b = str(cc)
c = []
for digit in b:
c.append (int(digit))
csort = c.sort(key=int)
c == csort #??
I need to say True or False if the number is in ascending order or not.
My code do not print True or False, why?
You should not use key=int in c.sort(key=int) as c is already a list of ints due to you creating it via c.append(int(digit)).
However the key issue is that c.sort() is in-place and as such returns None, instead use sorted which returns a sorted list:
csort = sorted(c)
And then you can print the boolean result of the comparsion via:
print c == csort
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I have a list which includes infinite an unknown number of elements (I don't have control on the length of the list or the type of values)
a = [x, y, z ...]
where x = 1, y = 9, z = 'Hello' ...
And I would like to loop over list "a" and print all the elements' names and values.
I hope if I can implement something like that:
for i in a:
print i $i
I would like to have output as:
x 1
y 9
z Hello
from itertools import cycle # an infinite repeating set
my_infinite = cycle(["a","b","c"])
a=1,b=4,c=99
for val in my_infinite:
print val, globals()[val]
maybe ... its aweful and hackey but it might work
Something like this:
import string
for a, b in zip(string.ascii_lowercase, xrange(1, 27)):
print a, b
You should use a dictionary:
a = {'x': 1, 'y': 2}
for i in a:
print i, a[i]