I am working on a program for school, and my homework is to create Letter "A" and the size depends on persons input.
I only worked with loops, print, and input, so I work with what I have.
I tried the following code:
v = eval(input("Enter the size of the Letter: "))
for i in range (v):
print(" " * ((v/2)-i) + i * '*' + ((v/2)-i))
..but I get an error.
Using if statements, my code below seems to work. I am not sure if it is possible without them.
v = eval(input("Enter the size of the Letter: "))
for i in range(1, v, 2):
if i == int(v/2):
middle = i * '*'
else:
middle = '*' + (i-2) * ' ' + '*' if i != 1 else '*'
print(" " * int((v/2)-(i/2)) + middle + int((v/2)-(i/2)) * " ")
Related
Hi everyone, I have an assignment to acquire this shape in Python. I am a beginner, I tried to use nested loops to create this shape but I couldn't. Could someone help? Thanks a lot. (I couldn't copy the output exactly I'm sorry)
I used nested for loops, if and else statements in various ways (for example, I've tried to write stars at the end of a row) but I couldn't get the shape. I am editing the post in order to show you my effort. I am really sorry that my output is really different from the wanted one.
len = int(input("enter an odd number: "))
if len % 2 == 0:
print("enter an odd number")
else:
row = int((len+1) / 2)
for i in range (0,len):
print("#",end="")
print()
for i in range(0,row):
print("*")
print("*", end=" ")
for j in range(1,len):
print("*",end="")
for i in range(0,len):
print("#",end="")
for n = 5
#####
* *
* *
* *
* *
* *
* *
#####
This could be one way of solving it:
if we define n as the sample input, the shape can be divided into 3 steps of length (n//2) each.
Initialization: print('#'*n)
Step 1: for i in range(n//2): print('*'+' '*(n-2)+'*')
Step 2a: create a print_list: print_list = [k*' ' + '*'+ (n-2-2*k)*' ' + '*' + k*' ' for k in range(n//2)]
Step 2b: Now print each line in print_list
Step 3: Then print each line in print_list[::-1]
End: print('#'*n)
Implemented Code:
n = int(input("enter an odd number: "))
if n % 2 == 0:
print("enter an odd number")
else:
print("#"*n)
for i in range(n//2):
print('*'+' '*(n-2)+'*')
print_list = [k * ' ' + '*' + (n - 2 - 2*k) * ' ' + '*' + k * ' 'for k in range(n//2)]
for p in print_list: print(p)
for p in print_list[::-1]: print(p)
print("#"*n)
I am writing a program that calculates the factorial of a number, I am able to display the correct answer, however along with the answer I need the actual calculation to display, I am having trouble with that. So for example, when the user enters 4, I need it to display as:
I have been trying to figure out the right code, but do not know what to do.
Here is the code I have so far
number = int(input("Enter a number to take the factorial of: "))
factorial = 1
for i in range(1, number + 1):
factorial = factorial * i
print (factorial)
Right now, it displays the correct answer, however I need for it to include the equation as well as follows: 4! = 1 x 2 x 3 x 4 = 24
The simplest approach is to construct the string as you are iterating:
equation = str(number) + "! = "
factorial = 1
for i in range(1, number + 1):
factorial = factorial * i
equation += str(i) + "x"
equation = equation[:-1] + " = " + str(factorial)
print(equation)
Note that this method appends an unwanted 'x' after the last factor. This is removed by equation[:-1].
Alternatively, you could append this one-line solution to the end of your code. It uses the join method of the string class to concatenate an array of strings:
print(str(number) + "! = " + "x".join(str(n) for n in range(1, number + 1)) + " = " + str(factorial))
As you loop through the numbers to be multiplied, you can append each number's character to a string containing the equation, e.g ans, and print it at last. At the end of the code, I omitted the last letter because I didn't want an extra 'x' to be displayed.
def fact(number):
num_string=str(number)
factorial = 1
ans=num_string+"!="
for i in range(1, number + 1):
factorial = factorial * i
ans+=str(i)+"x"
ans=ans[:-1]
print(ans)
return factorial
fact(4)
You can append each value to the list and then print the equation using the f-string:
num = 5
l = []
f = 1
for i in range(1, num + 1):
f *= i
l.append(i)
print(f"{num}! = {' x '.join(map(str, l))} = {f}")
# 5! = 1 x 2 x 3 x 4 x 5 = 120
For an assignment I'm suppose to make a triangle using the users input if the characters are equal to an even number. The triangle is suppose to print up to 5 lines in height and the left of it should be the left half of the string and the right side of the triangle should be the right side of the string.
Example of what the triangle is suppose to look like
The problem is I can't figure out how to divide my triangle in half without hard coding it or how to properly display the white space without a loop (were not allowed to in the assignment). Right now if I were to put in "ab" it would return:
aabb
aabbaabb
aabbaabbaabb
aabbaabbaabbaabb
aabbaabbaabbaabbaabb
Instead of:
aabb
aaaabbbb
aaaaaabbbbbb
aaaaaaaabbbbbbbb
aaaaaaaaaabbbbbbbbbb
Here's my code:
#GET Users String
userString = input("Please enter a string with a value of 7 or less characters: ")
#CALCULATE IF userString is less than or equal to 7 and is even
if len(userString) <= 7 and len(userString) % 2 == 0:
print (" " * 5 + userString)
print(" " * 4 + userString * 2)
print(" " * 3 + userString * 3)
print(" " * 2 + userString * 4)
print(" " + userString * 5)
#CALCULATE IF userString is less than 7 but and off
elif len(userString) <=7 and len(userString) % 2 == 1:
print("You are odd")
#CALCULATE IF userString is over 7 characters
else:
print ('The string is too long. \nGood-bye!')
Here's how you can do this:
def print_next(st, index):
if index < 6: # have not reached 5 - print offset and string
offset = 6-index
print ' '*offset+st
index=index+1 # increase counter
print_next((st[0:2]+st[-2:len(st)])*index,index) # recursively go next
print_next('aabb',1) # initial call with index set to 1
I think you can use a stack to save each line so you can easily get a triangle-like output. Also because you can't use loop so my suggestion would be recursive.
public_stack = []
def my_func(original_str, line_count, space_num):
if(line_count == 0):
return
times = line_count * 2
half_length = len(original_str) / 2
left_str = original_str[:half_length] * times
right_str = original_str[half_length:] * times
space_str = ' ' * space_num
complete_str = space_str + left_str + right_str
global public_stack
public_stack.append(complete_str)
space_num += len(original_str)
line_count -= 1
return my_func(original_str,line_count,space_num)
if __name__ == '__main__':
original_str = 'ab'
line_count = 5
space_num = 0
my_func(original_str,line_count,space_num)
global public_stack
for i in range(len(public_stack)):
line = public_stack.pop()
print line
I tried this code with the Python IDE and worked fine. However, a NameError appeared after I compiled the code using pyinstaller or executed the code in Ninja IDE. Any suggestions?
Here is my code. I'm a beginner so please don't judge!
from math import sqrt
while True:
numbers = int(input('Input the total amount of numbers with uncertainties you wish to use: '))
answer = str(input('Type A/a for addition of uncertainties or M/m/D/d for division/multiplication of uncertainties:'))
count = 1
mylist = []
secondlist = []
listsqrnum = []
listsqrun = []
finallist= []
listnum = []
listuncertainty = []
listofanswer1 = ["A","a"]
listofanswer2 = ["d","D","M","m"]
if answer in listofanswer1:
while count <= numbers:
num = float(input('Input uncertainty ' + str(count) + ': '))
count += 1
mylist.append(num)
for i in mylist:
secondlist.append(i ** 2)
x = sqrt(sum(secondlist))
print (x)
elif answer in listofanswer2:
result = float(input("Input resulting value: "))
while count <= numbers:
number = float(input("Input number " + str(count) + ": "))
uncertainty = float(input("Input uncertainty number " +str(count)+ ": "))
listnum.append(number)
listuncertainty.append(uncertainty)
count +=1
for i in listnum:
listsqrnum.append(i ** 2)
for i in listuncertainty:
listsqrun.append(i**2)
for i in range(0,len(listsqrnum)):
finallist.append(listsqrun[i]/listsqrnum[i])
sumofsquare = sum(finallist)
squareroot = sqrt(sumofsquare)
final = result * squareroot
print (final)
else:
print("You have not typed anything or you entered a float")
The error traces back to line 4, saying NameError - 'a' is undefined.
It also indicates same error as other values within the answer list is inputted.
Thank you.
Learning the basics of python and I am running across a problem. I'm sure it is a simple fix. I'm trying to get my program to get 20 different inputs before calculating the min, max, etc.
def main():
number = valueInput()
display(number)
def valueInput():
print("Please enter 20 random numbers")
values = []
for i in range(20):
value1 =(int(input("Enter a random number " + str(i + 1) + ": ")))
values.append(value1)
return values
def display(number):
print("The lowest number is:", min(number))
print("The highest number is:", max(number))
print("The sum of the numbers is:", sum(number))
print("The average number is:", sum(number)/len(number))
main()
I can get it to work by repeating this line:
value1 =(int(input("Enter a random number " + str(i + 1) + ": ")))
to the 20th number but there must be a way that makes it shorter and cleaner. Again I am a beginner so any explanation would be much appreciated.
All you have to do to fix your program is remove four spaces:
def valueInput():
print("Please enter 20 random numbers")
values = []
for i in range(20):
value1 =(int(input("Enter a random number " + str(i + 1) + ": ")))
values.append(value1)
return values
The last line in the block above has been unindented by one level. Instead of returning after the first time through the loop, it lets the loop complete, and then returns the resulting list.
Also you can change your:
values = []
for i in range(20):
value1 =(int(input("Enter a random number " + str(i + 1) + ": ")))
values.append(value1)
return values
part with:
values = [int(input("Enter a random number " + str(x + 1) + ": ")) for x in list(range(20))]
return values
You can check out build in functions