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NOT NULL constraint when creating a new user in django

I created a Django API to create a new user. However, when I try to create a user I get the error message:
IntegrityError at /api/v1/users/register/ NOT NULL constraint failed: accounts_user.user_id
This is what I have in models.py
from django.db import models
from django.contrib.auth.models import User
from django.db.models.signals import post_save
from django.dispatch import receiver
class User(models.Model):
user = models.OneToOneField(User, on_delete=models.CASCADE)
name = models.CharField(max_length=100, blank=True)
location = models.CharField(max_length=100, blank=True)
password = models.CharField(max_length=32)
email = models.EmailField(max_length=150)
signup_confirmation = models.BooleanField(default=False)
def __str__(self):
return self.user.username
#receiver(post_save, sender=User)
def update_profile_signal(sender, instance, created, **kwargs):
if created:
User.objects.create(user=instance)
instance.profile.save()
In serializers.py
from rest_framework import serializers
from .models import User
class UserSerializer(serializers.HyperlinkedModelSerializer):
class Meta:
model = User
fields = ('user_id', 'name', 'location', 'password', 'email', 'signup_confirmation')
and my views.py
from rest_framework import viewsets
from .serializers import UserSerializer
from .models import User
from rest_framework.decorators import action
from .forms import SignUpForm
from .tokens import account_activation_token
class UserViewSet(viewsets.ModelViewSet):
queryset = User.objects.all().order_by('name')
serializer_class = UserSerializer
#action (detail=True, methods=['post'])
def register(self, request):
print(request)
Any ideas on what I can do to resolve this error

As John wrote in a comment:
Here you have a problem: fields = ('user_id',...).
I also advise you to change your User model. If you don't need separating (I suppose you don't), it is way better to create your User with inheritance directly from AbstractUser instead of creating in fact doubled User models.
from django.contrib.auth.models import AbstractUser
class User(AbstractUser):
...
In this way you will already have username, password and email, but you can add anything else in same model, instead of using user.user etc.

query data from one model, filter from another

I would like to display values from one table, but filter these values based on a value from another table.
for example: I want to display values from data/models.py that are filtered by the customer_tag in the CustomUser table (accounts/models.py).
These are related tables, but I can't figure out the right syntax to filter this view.
Any ideas? Or is this not possible with my current schema..
data/views.py
from django.views.generic import ListView, DetailView
from django.views.generic.edit import UpdateView, DeleteView, CreateView
from django.urls import reverse_lazy
from .models import Data
from django.contrib.auth.mixins import LoginRequiredMixin
from rest_framework import generics
from .models import Data
from accounts.models import CustomUser
from .serializers import DataSerializer
from .permissions import IsAuthorOrReadOnly
class DataListView(LoginRequiredMixin,ListView):
queryset = Data.objects.all()
context = {
"object_list": queryset
}
template_name = 'data_list.html'
login_url = 'login'
accounts/models.py
from django.db import models
from django.contrib.auth.models import AbstractUser
class CustomUser(AbstractUser):
customer_Tag = models.CharField(max_length=50,)
isAdmin = models.BooleanField(default = False,)
notifications = models.BooleanField(default = True,)
deviceSerial= models.CharField(max_length=50,)
machineName= models.CharField(max_length=50,default="ESP1",)
machineDescription = models.CharField(max_length=200,)
class Customer(models.Model):
customerTag= models.CharField(max_length=50,)
customerName = models.CharField(max_length=50,)
mainContact = models.CharField(max_length=100,default='',)
Address = models.CharField(max_length=100,default='',)
city = models.CharField(max_length=100,default='',)
website = models.URLField(max_length=100,default='',)
phone = models.IntegerField(default=0,)
def __str__(self):
return self.customerName
data/models.py
from django.db import models
from django.conf import settings
from django.contrib.auth import get_user_model
class Data(models.Model):
author = models.ForeignKey(get_user_model(),on_delete=models.CASCADE,)
tempData= models.CharField(max_length=50,blank=True,)
humidData= models.CharField(max_length=50,blank=True,)
def __str__(self):
return str(self.author)

It's all in the docs: https://docs.djangoproject.com/en/2.1/topics/db/queries/#lookups-that-span-relationships
Fields of related models are queried using double underscores __ in a filter.
In your case you need to override get_queryset method of your DataListView class to return a filtered queryset:
class DataListView(LoginRequiredMixin,ListView):
...
def get_queryset(self):
return self.queryset.filter(author__customerTag=self.request.user.customerTag)

I think you are looking for the key__field argument of the filter query if I understood you correctly. So in your case it would be something like,
Data.objects.filter(author__customer_tag='tag-you-are-looking-for') # double underscores after author
Hope this answers your question!

Django view not saving to model

I have a view I am calling when a user clicks a button on the site, it pulls JSON data(from the Coinbase API) and converts it to a string and should save the string pulled to the current user's account.
Whenever they click the button it will pull the string, but nothing is saved to the account, which is the issue.
views.py
from django.shortcuts import render
from django.http import HttpResponse
from django.contrib.auth.decorators import login_required
from ico_login.models import UserAddress
from coinbase.wallet.client import Client
#login_required()
def generate_address_btc(request, *args, **kwargs):
client = Client('api', 'key')
r = client.get_addresses('account_id')
address = r['data'][0]['address']
request.user.address = str(address)
request.user.save()
return HttpResponse(address)
models.py
from django.db import models
from django.contrib.auth.models import User
class UserAddress(models.Model):
user = models.OneToOneField(User, on_delete=models.CASCADE)
address = models.CharField(max_length=300, default=' ')
urls.py
from django.contrib import admin
from django.urls import path, include
from ico_details import views
urlpatterns = [
path('create_address/', views.generate_address_btc, name='generate')
]

In your view you write request.user.address = ..., so you add the attribute address to a User object. As far as I read your code, this is not what you want. You would like to put str(address) into the field address of the object UserAddress related to the User object from request.user, right?!
So, here are the suggested edits to do so:
models.py
from django.db import models
from django.contrib.auth.models import User
class UserAddress(models.Model):
# next line changed
user = models.OneToOneField(User, on_delete=models.CASCADE, related_name='user_address')
address = models.CharField(max_length=300, default=' ')
views.py
from django.shortcuts import render
from django.http import HttpResponse
from django.contrib.auth.decorators import login_required
from ico_login.models import UserAddress
from coinbase.wallet.client import Client
#login_required()
def generate_address_btc(request, *args, **kwargs):
client = Client('api', 'key')
r = client.get_addresses('account_id')
address = r['data'][0]['address']
# next 2 lines changed
request.user.user_address.address = str(address)
request.user.user_address.save()
return HttpResponse(address)
Hope that helped and happy coding!

Trouble accessing object

I've been working on an issue all day and am at my wits end. I have two models with a manytomany relationship (bookmark, and boomark group). I am trying to access the bookmarks accosiated with the bookgroup in my view. When print the context to take a peak I get None returned. I've pasted the code below in a gist...any help would be so greatly appreciated.
models.py
# -*- coding: utf-8 -*-
from __future__ import unicode_literals
from itertools import chain
import datetime
import hashlib
from django.db import models
from django.urls import reverse
from django.contrib.auth.models import AbstractBaseUser, BaseUserManager, PermissionsMixin
from django_mysql.models import JSONField, Model
from django.template.loader import render_to_string
from django.core.mail import send_mail
from django.utils import timezone
from django.conf import settings
class Bookmark(models.Model):
user = models.ForeignKey(User, on_delete=models.CASCADE)
resource = models.ForeignKey("Resource", on_delete=models.CASCADE, related_name="bookmarks")
bookmark_groups = models.ManyToManyField("BookmarkGroup")
# meta
created_at = models.DateTimeField(auto_now_add=True)
modified_at = models.DateTimeField(auto_now=True)
class Meta:
unique_together = ('user', 'resource',)
ordering = ('resource',)
def __str__(self):
return "{} | {}".format(self.user, self.resource)
class BookmarkGroup(models.Model):
name = models.CharField(max_length=50)
slug = models.SlugField(null=False, unique=True)
bmark = models.ManyToManyField(Bookmark)
def __str__(self):
return self.name
views.py
from __future__ import unicode_literals
import json
from django.shortcuts import render, get_list_or_404
from django.http import JsonResponse
from django.views import View
from django.views.generic import DetailView
from app.serializers import BookmarkGroupSerializer
from app.models import Resource,Bookmark,ResourceShare,PrivateNote,BookmarkGroup
from app.views.resources import get_enriched_resources
class BookmarkGroupView(DetailView):
model = BookmarkGroup
def get_context_data(self, **kwargs):
context = super(BookmarkGroupView, self).get_context_data(**kwargs)
print(context['object'].bmark.resource)
return context

The key here is ManyToMany relationship, but you are trying to access it like a single object.
context['object'].bmark.all()[0].resource
OR
context['object'].bmark.first().resource
UPDATED:
With emptiness check
try:
resourse = context['object'].bmark.all()[0].resource
except:
resourse = None
OR
bmarks = context['object'].bmark.all()
resourse = bmarks[0].resource if bmarks else None

Django Rest Framework 3.4 foreign key serialization and upload image file

every one, I am working the project (use django 1.8 ) have a ForeignKey, and I have to upload image file through the api,but I just fail to do it,,can any one tell me how to do it,thank you.
within the models.py there is a class Upload(models.Model): it has the ForeignKey thing = models.ForeignKey(ProductsTbl, related_name="uploads") to class ProductsTbl(models.Model):
models.py
class ProductsTbl(models.Model):
......
model_number = models.CharField()
name = models.CharField(max_length=255, blank=True, null=True)
material = models.CharField(max_length=255, blank=True, null=True)
.......
def __unicode__(self):
return self.name
def save(self, *args, **kwargs):
''' On save, update timestamps '''
if not self.id:
self.created = timezone.now()
return super(ProductsTbl, self).save(*args, **kwargs)
def get_image_path(instance, filename):
return '/'.join(['thing_images', instance.thing.slug, filename])
class Upload(models.Model):
thing = models.ForeignKey(ProductsTbl, related_name="uploads")
image = models.ImageField(upload_to=get_image_path, verbose_name='Image')
..........
api/serializers.py
from rest_framework import serializers
from ..models import *
from django.contrib.auth.models import User
from django.contrib.auth import get_user_model
UserModel = get_user_model()
class ProductsTblSerializer(serializers.ModelSerializer):
class Meta:
model = ProductsTbl
fields = ('model_number','name','material',)
class UploadSerializer(serializers.ModelSerializer):
ProductsTbl = serializers.CharField(source='ProductsTbl.id')
class Meta:
model = Upload
fields = ('thing','image')
........
api/urls.py
from django.conf.urls import url, include
from . import views
urlpatterns = [
url(r'^productsTbls/$', views.ProductsTblListView.as_view(), name='productsTbls_list'),
url(r'^productsTbls/(?P<pk>\d+)/$', views.ProductsTblDetailView.as_view(), name='productsTbls_detail'),
url(r'^Upload/(?P<pk>\d+)/$', views.UploadDetailView.as_view(), name='Upload_Detail'),
......
]
api/views.py
from rest_framework import generics
from ..models import *
from .serializers import ProductsTblSerializer,UploadSerializer,UserSerializer
from django.contrib.auth.decorators import login_required
from django.http import Http404, HttpResponse
from django.shortcuts import render, redirect
from rest_framework.renderers import JSONRenderer
from rest_framework.parsers import JSONParser
from django.views.decorators.csrf import csrf_exempt
from django.forms import modelformset_factory
from django.template.defaultfilters import slugify
from rest_framework import permissions
from rest_framework.generics import CreateAPIView
from django.contrib.auth import get_user_model
from rest_framework.permissions import AllowAny
class ProductsTblListView(generics.ListCreateAPIView):
queryset = ProductsTbl.objects.order_by('-created')
serializer_class = ProductsTblSerializer
class ProductsTblDetailView(generics.RetrieveUpdateDestroyAPIView):
queryset = ProductsTbl.objects.all()
serializer_class = ProductsTblSerializer
class UploadDetailView(generics.RetrieveUpdateDestroyAPIView):
queryset = Upload.objects.all()
serializer_class = UploadSerializer
......
settings.py
........
REST_FRAMEWORK = {
'DEFAULT_PERMISSION_CLASSES': [
'rest_framework.permissions.AllowAny',
#'rest_framework.permissions.DjangoModelPermissionsOrAnonReadOnly'
]
}
.......
when I try to upload image through PUT , I just seeing {"detail":"Not found."}