I am currently a new student learning python. This is my first real experience doing much computer coding. For my project I must create a fill in the blank quiz with three different levels of difficulty. Once the user chooses a difficulty the game should print a different paragraph based on the difficulty. Each section of the game works fine but I am having trouble creating the "difficulty chooser." No matter the difficulty I choose, the game rolls through the easy, medium, and the hard level in order and then crashes.
Below I have included the introductory text and the difficulty chooser. I would love some help. I am sure there are really obvious things I don't see. Thank you!
def introduction():
print '''Welcome to Kevin's European Geography Quizzes.
Test your knowledge of European geography. \n'''
difficulty = raw_input('''Do you want to play an easy, medium, or hard game?
Please type the number 1 for easy, 2 for medium, or 3 for hard.\n''' )
game_chooser(difficulty)
def game_chooser(difficulty):
cursor = 0
difficulty_choice = [easy_game(), medium_game(), hard_game()]
#each element of the above list links to a procedure and starts one of the
#mini-games.
while cursor < len(difficulty_choice):
if difficulty != cursor:
cursor += 1
else:
difficulty_choice[cursor]
break
You can do with if else if you only want to print something but if you have separate code block for each level then define a function for each level and use this pattern :
You can define the function blocks and call them basis on user input something like:
# define the function blocks
def hard():
print ("Hard mode code goes here.\n")
def medium():
print ("medium mode code goes here\n")
def easy():
print ("easy mode code goes here\n")
def lazy():
print ("i don't want to play\n")
# Now map the function to user input
difficulty_choice = {0 : hard,
1 : medium,
4 : lazy,
9 : easy,
}
user_input=int(input("which mode do you want to choose : \n press 0 for hard \n press 1 for medium \n press 4 for lazy \n press 9 for easy "))
difficulty_choice[user_input]()
Then invocation of function block will be:
difficulty_choice[num]()
Add a conditional for the input.
if difficulty == 'easy':
print("here is an easy game")
elif difficulty == 'medium':
print('here is a medium game')
elif difficulty == 'hard':
print('here is hard')
else:
print('Please enter valid input (easy, medium, hard)')
Under each if statement put your game code.
The reason your code goes through all the difficulties is because of this line:
difficulty_choice = [easy_game(), medium_game(), hard_game()]
When Python sees something like easy_game(), it calls the easy_game function and replaces it with the result. You don't want to call the function yet though, so you can take off the parenthesis to store just the function instead:
difficulty_choice = [easy_game, medium_game, hard_game]
This will mean you have to call the function after you take it out of the array.
As for the crash, when you use raw_input() you get a string back. That means when you type in the 1 to decide for an easy game, you get the character 1, which is represented by the number 49. That's why your code goes through everything and crashes: Your 1 is really a 49. In fact, if you type 1 < '1' into the interpreter, you'll get True back.
To fix that, you can pass the result of raw_input() to the int() function, which will parse it and give you the proper integer (or throw an exception if it can't be parsed). The last line of introduction would then look like game_chooser(int(difficulty)).
You could also skip most of the code of game_chooser by just indexing into the array (that's what they're for, after all):
def game_chooser(difficulty):
# the lack of parens here means you get the function itself, not what it returns
difficulty_choice = [easy_game, medium_game, hard_game]
#each element of the above list links to a procedure and starts one of the
#mini-games.
# note the parens to actually call the retrieved function now
difficulty_choice[difficulty]()
Related
I'm working on a choose-your-own-adventure game in Python to try to learn how to code. I might be doing this entirely wrong, but I thought rather than just nesting if-elif-else statements endlessly, I could write some sort of function that would be a template for all choices in the game.
My ideas was to have every decision in a given scene to generate two lists - choices and outcomes. The "multitemplate" function would then load the choose and outcomes lists, present the options to the player, take in the answer, and call the correct function for the outcome given.
My issue is that the outcome list is a list of functions, which Python doesn't seem to like. It says I've not defined the functions properly, but when I define my outcome functions before calling "multitemplate", it just prints them first.
Here's my code:
#Function to allow the adventurer to make choices
def refusal():
print("You stop at the roadsign you passed on your way into town. There are only two directions - towards Tarroway, or towards Angion, the town from whence you came.")
def guards():
print("The guards stop you.")
def theinn():
print("You follow the joyful chatter down the deserted street. Its source is a squat, one story building. A sign above the door reads \"The Forked Tongue\"")
choose = ["I walk towards the merry sounds.", "I turn on my heels and head back where I came from.","I stay where I am and watch the night quietly."]
outcome = [theinn(), refusal(), guards()]
def multitemplate(choose,outcome):
global mychoice
global carryon
for x in range(len(choose)):
print (f"{x+1}) " + choose[x], end="\n")
mychoice = (input())-1
while True:
if (mychoice) in range(len(choose)):
carryon = True
outcome[mychoice]
carrion()
else:
print("Please enter the number of the choice you wish to make.")
carryon = False
mychoice = int((input()))-1
I'd appreciate any input on how this should work properly, or if I'm going down a completely blind alley here.
Thanks!
This thing is hard to post code and context inside of.
#This is a menu driven multiplication game. i am attemtping to save the high
#score in a file named multiplication_game.txt...
def single_player():
in_file = open('multiplication_game.txt', 'r')
highest_times_selection = int(in_file.readline())
print('\n____now lets see how u do on the times tables____')
correct = 0
missed = 0
times_selection = int(input(
'\nPlease enter a times time table integer to practice: '))
#This simple generates the multiplation questions and checks for right or
#wrong.
for number in range(0,11):
print(times_selection, 'x' , number, '=')
user_answer=int(input('answer: '))
correct_answer = times_selection * number
if user_answer == correct_answer:
correct+=1
else:
missed+=1
#This is where if its a perfect score and a high times table than the
#previous saved score it should be opened and the new score saved in the
#text document.
if missed == 0 and times_selection > highest_times_selection :
output_file = open('multiplication_game.txt', 'w')
name = input('You have the highest Score!!\n enter your name: ')
output_file.write(str(times_selection)+ '\n')
output_file.write(name + '\n')
else:
print('you missed ', missed, 'and got', correct,'correct\n')
output_file.close()
Try to define output_file = None before any assignment of it.
Tip: before your last if-else condition.
This looks like homework, so I don't want to give you the answer but rather lead you to it.
Take a look at your if/else for your high score table, and walk through your code twice, taking a different branch (different part of the if/else) each time you reach this spot. Write down the variable names on paper as you define them, starting over with a new sheet of paper each time you walk through. If you access a variable, check it off on your list. If you try to access a variable that's not on your list, it's the same as python saying local variable referenced before assignment -- you're trying to access it before you've defined it.
Hope this helps, both in figuring out your problem and learning how to debug in the future.
Current assignment is building a basic text adventure. I'm having trouble with the following code. The current assignment uses only functions, and that is the way the rules of the assignment state it must be done.
def make_selections(response):
repeat = True
while repeat == True:
selection = raw_input('-> ')
for i, v in enumerate(response):
i +=1 # adds 1 to the index to make list indices correlate to a regular 1,2,3 style list
if selection == i:
print v[1]
else:
print "There's an error man, what are you doing?!?!?"
firstResponse = 'You chose option one.'
secondResponse = 'You chose option two.'
thirdResponse = 'You chose option three.'
responses = [(0, firstResponse), (1, secondResponse),( 0, thirdResponse)]
make_selections(responses)
My intention in that code is to make it so if the user selects a 1, it will return firstResponse, if the user selects 2 it will return secondResponse, etc.
I am basically just bug testing the code to make sure it produces the appropriate response, hence the "Error man..." string, but for some reason it just loops through the error message without printing the appropriate response string. Why is this?
I know that this code is enumerating the list of tuples and I can call them properly, as I can change the code to the following and get the expected output:
for i, v in enumerate(response):
i += 1 # adds 1 to the index to make list indices correlate to a regular 1,2,3 style list
print i, v
Also, two quick asides before anyone asks:
I know there is currently no way to get out of this while loop. I'm just making sure each part of my code works before I move on to the next part. Which brings me to the point of the tuples.
When I get the code working, a 0 will produce the response message and loop again, asking the user to make a different selection, whereas a 1 will produce the appropriate response, break out of the loop, and move on to the next 'room' in the story... this way I can have as many 'rooms' for as long of a story as I want, the player does not have to 'die' each time they make an incorrect selection, and each 'room' can have any arbitrary amount of options and possible responses to choose from and I don't need to keep writing separate loops for each room.
There are a few problems here.
First, there's no good reason to iterate through all the numbers just to see if one of them matches selection; you already know that will be true if 1 <= selection <= len(response), and you can then just do response[selection-1] to get the v. (If you know anything about dicts, you might be able to see an even more convenient way to write this whole thing… but if not, don't worry about it.)
But if you really want to do this exhaustive search, you shouldn't print out There is an error man after any mismatch, because then you're always going to print it at least twice. Instead, you want to only print it if all of them failed to match. You can do this by keeping track of a "matched" flag, or by using a break and an else: clause on your for loop, whichever seems simpler, but you have to do something. See break and continue Statements, and else Clauses on Loops in the tutorial for more details.
But the biggest problem is that raw_input returns a string, and there's no way a string is ever going to be equal to a number. For example, try '1' == 1 in your interactive interpreter, and it'll say False. So, what you need to do is convert the user's input into a number so you can compare it. You can do that like this:
try:
selection = int(selection)
except ValueError:
print "That's not a number!"
continue
Seems like this is a job for dictionaries in python. Not sure if your assignment allows this, but here's my code:
def make_selections(response):
selection = raw_input('-> ')
print response.get(selection, err_msg)
resp_dict = {
'1':'You chose option one.',
'2':'You chose option two.',
'3':'You chose option three.'
}
err_msg = 'Sorry, you must pick one of these choices: %s'%sorted(resp_dict.keys())
make_selections(resp_dict)
The problem is that you are comparing a string to an integer. Selection is raw input, so it comes in as a str. Convert it to an int and it will evaluate as you expect.
You can check the type of a variable by using type(var). For example, print type(selection) after you take the input will return type 'str'.
def make_selections(response):
repeat = True
while repeat == True:
selection = raw_input('-> ')
for i, v in enumerate(response):
i +=1 # adds 1 to the index to make list indices correlate to a regular 1,2,3 style list
if int(selection) == i:
print v[1]
else:
print "There's an error man, what are you doing?!?!?"
I've been set the task to design a small game which includes a text file which is 'encrypted' and a 'decrypted' version of the text file. The user is shown the 'encrypted' list (which has been read in and appended to an array) with some clues e.g. A = # (I'm using a dictionary to store possible values of the symbols.)
My problem is: I have created the whole game but i have added an option to my menu to allow the End-User to compare the words they have substituted in with the 'decrypted' list (also read into an array) to see if they have completed the game.
I have tried the following code and have tested the game through to me being 100% sure the words were identical and the Python Shell printed "Sorry! Try Again!"
Here's The Code:
def compareFiles():
for eachLine in range(len(rsef)):
if rsef[eachLine] == rssf[eachLine]:
print("Congratulations! Puzzle Solved!")
else:
print("Sorry! Try Again!")
secMenu()
For Context:
secMenu() is my menu
rsef is my 'encrypted' array
rssf is the 'decrypted' array which i want to compare to.
EDIT:
Which Option Would You Like To Choose?
Option Number: 1
--------------------------------
1. View The Encrypted Words With Some Clues.
A+/084&"
A3MANA+
8N203:
,1$&
!-MN
.A7&33&
AMA71N
&-&641'2
A))85
9&330M
This is the Sorted List:
Which Option Would You Like To Choose?
Option Number: 5
ACQUIRED
ALMANAC
INSULT
JOKE
HYMN
GAZELLE
AMAZON
EYEBROWS
AFFIX
VELLUM
Here's to check if all items in both lists are identical:
def compareFiles():
if rsef == rssf:
print("Congratulations! Puzzle Solved!")
else:
print("Sorry! Try Again!")
secMenu()
If you insist on looping, the one below :)
def compareFiles():
for eachLine in range(len(rsef)):
if rsef[eachLine] != rssf[eachLine]:
print("Sorry! Try Again!")
secMenu()
return 0 #exit the function, use this if you need it.
print("Congratulations! Puzzle Solved!")
I am learning how to code in Python and using the IDLE, I have put in this code, however when I hit F5, nothing happens... no output occurs.
Is this due to maybe the fact that the code I have put in doesn't need an output? Or maybe I am saving it wrongly. Would love to know the reason as it is slightly upsetting.
X = "X" #This is to indicate one piece of the game
O = "O" #this is to indicate another piece of the game
EMPTY = "" # an empty square on the board.
TIE = "TIE" #represents a tie game
NUM_SQUARES = "9" #number of squares on the board
def display_instruct(): #this is a function with the name display_instruct.
"""display game instructions."""
print \
""" Welcome to the greatest challenge of all time: Tic-tac toe. This would be a showdown betweene your human brain
and my silcon processor You will mkae your move known by entering a number
0 | 1 | 2
---------
3 | 4 | 5
---------
6 | 7 |8
Prepare yourself, human. The ultimate battle is about to begin. \n """
def ask_yes__no(question):
"""Ask a yes or no question"""
response = None
while response not in ("y", "n"):
response = raw_input(question).lower()
return response
#this produces a function. It receives a question and thenn responds with an answer which is either yes or not
def ask_number(question, low, high):
"""Ask for a number within the range"""
response = None
while response not in range(low, high):
response - int(raw_input(question))
return response
#remember that when defining the functions, you have to put in colons. The user recieves a question and then has to give an answer.
def pieces():
"""Determine if player or computer goes first""" #docstrings are used to name the functions.
go_first = ask_yes_no("Do you requre the first move?y/n: ")
if go_first == "y": #important to have two equal signs because you are giving a variable a name. Notice that one function callled another.
print "\n Then take the first move, you will need it."
human = X
computer = 0
else:
print "\n Your bravery will beyour undoing .... I will go first."
computer = X
human = O
return computer, human
You need to define and call a main function
def main():
display_instruct()
#the rest of the code
if __name__ == "__main__":
main()
The reason your code doesn't run is because what you have is function definitions
def func() ...
and value assignments
x=5
To actually run something you will either need to define a main function that takes all the things you have defined and combines them in a meaningful way or append to the bottom of the code something similar to what you would write in the main function.