show forms for model who can have multiple instance - python

I am creating a simple project which is about creating a resume by user. In resume, a user can have multiple experience, educational background and etc. That is why I have created the following table where experience, educational background, skills are foreignkey to the resume table.
class Resume(models.Model):
applicant = models.OneToOneField(User, on_delete=models.CASCADE)
name = models.CharField(max_length=100, blank=False, null=False, help_text="Full Name")
slug = models.SlugField(max_length=50, unique=True)
designation = models.CharField(max_length=200, blank=True, null=True)
city = models.CharField(max_length=100, blank=True, null=True)
def __str__(self):
return self.name
class Education(models.Model):
resume = models.ForeignKey(Resume, related_name='education')
name = models.CharField(max_length=100, blank=False, null=False, help_text="Name of an institution")
course = models.CharField(max_length=200, blank=False, null=False, help_text="Name of a course")
description = models.CharField(max_length=400, blank=True, null=True)
start_date = models.DateField()
end_date = models.DateField()
class Experience(models.Model):
resume = models.ForeignKey(Resume, related_name='experience')
designation = models.CharField(max_length=100, blank=True, null=True)
company = models.CharField(max_length=100, blank=True, null=True)
description=models.CharField(max_length=400, blank=True, null=True)
start_date = models.DateField()
end_date = models.DateField()
class Skill(models.Model):
resume=models.ForeignKey(Resume, related_name="skills")
name = models.CharField(max_length=100, blank=True, null=True, help_text="Name of the skill")
class Meta:
verbose_name='Skill'
verbose_name_plural='Skills'
def __str__(self):
return self.name
Now for such situation, do I have to create a ResumeForm, EducationForm, ExperienceForm etc and create an Education, Experience and Skill formset or
I have to do something else. I do not have clear idea on how to move forward now for developing form with such
relation where Education, Skill can have multiple instance. Can anyone guide me, please?

Well the question is unclear but following with your idea you have 2 options:
First you can have existing values in Education, Experience, Skill. Then in the view you have a checkbox to add education, experience, skill.
Second you can add education, experience, skill creating a modelForm for each one and then passing the resume, It is not necessary use formset here

Related

user Checkout and guest checkout: best way to use both in Django

Actually I need suggestion about best practice to handle guest checkout and customer checkout.
I have a scenario that 1 order can have multipul products (which is not problem). My order table is like
class Orders(models.Model):
customer= models.ForeignKey(Customer, on_delete=models.CASCADE)
order_number = models.AutoField(primary_key=True)
total_amount = models.DecimalField(max_digits=10, decimal_places=2)
ordertime = models.DateTimeField(auto_now_add=True)
order_status = models.CharField(max_length=50)
is_placed = models.BooleanField(default=False)
and then it is linked to product table like this
class OrderProduct(models.Model):
order=models.ForeignKey(Orders, on_delete=models.CASCADE)
activity = models.ForeignKey(ActivityOrganizer, on_delete=models.CASCADE)
participants=models.IntegerField(default=0)
totalPrice=models.DecimalField(max_digits=10, decimal_places=2)
checkIn = models.DateField()
language = models.CharField(max_length=50, null=False, blank=False)
And my Customer Table is
class Customer(models.Model):
customerProfile = models.OneToOneField(User, on_delete=models.CASCADE)
first_name=models.CharField(max_length=50, null=False, blank=False)
last_name=models.CharField(max_length=50, null=False, blank=False)
email=models.CharField(max_length=50, null=False, blank=False)
mobile_number=models.CharField(max_length=50, null=False, blank=False)
profile_image=models.ImageField(null=True, upload_to='CustomerProfile')
is_customer=models.BooleanField(default=False)
city=models.CharField(max_length=50, null=True, blank=True)
gender=models.CharField(max_length=50, null=True, blank=True)
verification_key = models.CharField(max_length=100, null=True, blank=True)
def __str__(self):
return str(self.first_name)
Now I want to Enable guest checkouts aswell . then Should I use existing tables of order by allowing Foregin key Null ? Or I should make seprate order tables for this ? What will be best way ?
Based off the information you've presented, I'd make Customer.customerProfile nullable and have it set to None for guest checkouts.

How to write a self referencing Django Model?

I have a Django model "Inspection" which has:
InspectionID (PK)
PartID
SiteID
Date
Comment
Report
Signiture
I want to be able to have a one to many relationship between the inspection ID and date. So one ID can have inspections at many dates. How would I do this? I currently have the following:
class Inspection(models.Model):
InspectionID = models.IntegerField(primary_key=True, unique=True)
PartID = models.ForeignKey('Part', on_delete=models.CASCADE)
SiteID = models.ForeignKey('Site', on_delete=models.CASCADE)
Date = models.DateField(auto_now=False, auto_now_add=False)
Comment = models.CharField(max_length=255, blank=True)
Report = models.FileField(upload_to='docs', null=True, blank=True)
Signiture = models.CharField(max_length=255, blank=True)
I thought about using models.ForeignKey but I really don't know how to implement that properly in this situation.
I want to be able to have a one to many relationship between the inspection ID and date.
You create an extra model, like:
class InspectionDate(models.Model):
inspection = models.ForeignKey(
Inspection,
on_delete=models.CASCADE,
related_name='inspectiondates'
)
date = models.DateField()
You thus can create InspectionDates for a given Inspection.
Or if you want to add extra data, it might be better to define an InspectionGroup model:
class InspectionGroup(models.Model):
pass
class Inspection(models.Model):
id = models.AutoField(primary_key=True, unique=True, db_column='InspectionId')
inspectiongroup = models.ForeignKey(InspectionGroup, on_delete=models.CASCADE, db_column='InspectionGroupId')
part = models.ForeignKey('Part', on_delete=models.CASCADE, db_column='PartId')
site = models.ForeignKey('Site', on_delete=models.CASCADE, db_column='SiteId')
date = models.DateField(db_column='Date')
comment = models.CharField(max_length=255, blank=True, db_column='CommentId')
report = models.FileField(upload_to='docs', null=True, blank=True, db_column='ReportId')
signiture = models.CharField(max_length=255, blank=True, db_column='Signature')
Note: the name of attributes are normally written in snake_case [wiki], not in PerlCase or camelCase.
you may store 'self Foriegnkey' as
class Inspection(models.Model):
InspectionID = models.IntegerField(primary_key=True, unique=True)
PartID = models.ForeignKey('Part', on_delete=models.CASCADE)
SiteID = models.ForeignKey('Site', on_delete=models.CASCADE)
Date = models.DateField(auto_now=False, auto_now_add=False)
Comment = models.CharField(max_length=255, blank=True)
Report = models.FileField(upload_to='docs', null=True, blank=True)
Signiture = models.CharField(max_length=255, blank=True)
inspection_id = models.ForeignKey('self', null=True, blank=True)

referral by company's product specific and company specific

I am thinking of creating a referral and reward app where a user will list his/her company with the product they have. A company can use referral program by product specific or just in whole(could not name it properly). For example, I have listed my company called ABC Company and I have a product like smartphone, smart Tvs, Laptops. I would like to market for my company by just saying refer me to 10 people and get something in return(this is non-product specific) or I should be able to market my specific product let's say when user goes to the abc phone XI and there will be refer this phone and get the same phone in return if you refer to more than 50 or if more than 10 then 10% discount etc. This is just an example to demonstrate my project.
For now I created the model for Company, Product(with nested category), referral. But I have no idea on how should i be able to keep the referral based on above example like product specific or based on full company.
Here is what I have done
class Product(models.Model):
"""
product model
"""
name = models.CharField(max_length=100, blank=True)
company = models.ForeignKey(Company, blank=False, null=False, on_delete=models.CASCADE)
category = TreeForeignKey('Category', null=True, blank=True, db_index=True, on_delete=models.CASCADE)
image = models.FileField(upload_to='/company/', max_length=100, blank=True, null=True)
description = models.TextField(blank=True, null=True)
stocks = models.IntegerField(default=0, blank=True)
class Company(models.Model):
"""
company model
"""
name = models.CharField(max_length=150, blank=False, null=False)
domain = models.URLField(blank=False, null=False)
email = models.EmailField()
description = models.TextField(blank=True)
pan_number = models.CharField(max_length=100, blank=False, null=False)
industry = models.CharField(max_length=150, blank=False, null=False)
class Join(models.Model):
"""
Join Model
"""
email = models.EmailField()
friend = models.ForeignKey("self", related_name='referral', null=True, blank=True, on_delete=models.CASCADE)
ref_id = models.CharField(max_length=120, default='ABC', unique=True)
count_added = models.ForeignKey("self", null=True, related_name='count', blank=True, on_delete=models.CASCADE)
ip_address = models.CharField(max_length=120, default='ABC')
timestamp = models.DateTimeField(auto_now_add=True, auto_now=False)
updated = models.DateTimeField(auto_now_add=False, auto_now=True)
def __str__(self):
return '{}'.format(self.email)

Is a self-join on a model in a django app an acceptable pattern?

Apologies if this question is too subjective.
If you are planning to close this question: please comment with a suggestion for a more appropriate place to post.
I'm super new to django and python, and I'm building a test app that keeps track of employees and who their managers are.
I would like to set up the domain model so that there there is only one list of employees, any of which can be managers, and all of which can be managed by any other employee who is designated a manager.
To achieve this, I did a self-join on the Employee model and have an "is_manager" flag to keep track of who is a manager and who isn't (see model below).
Is an acceptable pattern?
I'm worried it violates a design principle I'm not considering and there's some hairy trap that I'm walking into as a noob.
Thank you very much for your time.
models.py for the app:
class OrganizationTitle(models.Model):
def __str__(self):
return "{}".format(self.organization_title_name)
organization_title_name = models.CharField(max_length=150, unique=True)
class ClassificationTitle(models.Model):
def __str__(self):
return "{}".format(self.classification_title_name)
classification_title_name = models.CharField(max_length=150, unique=True)
class WorkingTitle(models.Model):
def __str__(self):
return "{}".format(self.working_title_name)
working_title_name = models.CharField(max_length=150, unique=True)
class Category(models.Model):
def __str__(self):
return "{}".format(self.category_name)
category_name = models.CharField(max_length=150, unique=True)
class Department(models.Model):
def __str__(self):
return "{}".format(self.department_name)
department_name = models.CharField(max_length=150, unique=True)
class Employee(models.Model):
first_name = models.CharField(max_length=150)
last_name = models.CharField(max_length=150)
org_title = models.ForeignKey(OrganizationTitle, blank=True, null=True, on_delete=models.SET_NULL)
manager = models.ForeignKey('self', null=True, blank=True, on_delete=models.SET_NULL)
manager_email = models.EmailField(max_length=50, blank=True, null=True)
hire_date = models.DateField(blank=True, null=True)
classification_title = models.ForeignKey(ClassificationTitle, blank=True, null=True, on_delete=models.SET_NULL)
working_title = models.ForeignKey(WorkingTitle, blank=True, null=True, on_delete=models.SET_NULL)
email_address = models.EmailField(max_length=250, blank=False, unique=True,
error_messages={'unique': 'An account with this email exist.',
'required': 'Please provide an email address.'})
category = models.ForeignKey(Category, blank=True, null=True, on_delete=models.SET_NULL)
is_substitute = models.BooleanField(default=False)
department = models.ForeignKey(Department, blank=True, null=True, on_delete=models.SET_NULL)
is_active = models.BooleanField(default=True)
is_manager = models.BooleanField(default=False)
class Meta:
ordering = ('is_active', 'last_name',)
def __str__(self):
return "{}".format(self.first_name + ' ' + self.last_name)
That's perfectly fine.
I would recommend you to specify the related_name to keep your code more explicit:
manager = models.ForeignKey(..., related_name="managed_employees")
so then you can do something like:
bob.managed_employees.all()
Also, there are 2 things I would change (not your question but still regarding the models):
1.The manager_email field is redundant. I would remove it. You already have that information at tom.manager.email_address for example.
2.There are many fields that I would simply rename to name. For example:
class OrganizationTitle(models.Model):
def __str__(self):
return u"{}".format(self.name)
name = models.CharField(max_length=150, unique=True)
No need to call it organization_title_name. That's consistent with the first_name field (not employee_first_name).
Yes, this is an acceptable pattern. This is called a "recursive relationship", or "self referential foreign keys" and is a very common usecase in realworld applications.
Here is django's example supporting this usecase

create custom role in django to employees

I have created a role model for Employee so that employee will be assigned to control
the overall app based on his/her role. I mean if the role of employee is given can_create_only, then the employee should be able to create inventory, orders, items etc and if employee is given can_create_edit_and_delete, then the employee would be like one of the admin and etc. For this I have designed the model as below but I want to know what is the best way to handle such and why?
Should I go with middleware or decorator way? Can anyone give me an example, please?
class Role(models.Model):
name = models.CharField(max_length=100, blank=False, null=False)
class Meta:
verbose_name = 'Role'
verbose_name_plural = 'Roles'
class Employee(models.Model):
office = models.ForeignKey(
OfficeSetup, blank=False, null=False, on_delete=models.CASCADE)
name = models.CharField(max_length=150, blank=False, null=False)
designation = models.ForeignKey(Designation, blank=False, null=False)
section = models.ForeignKey(DepartmentSetup, blank=True, null=True)
phone_number = models.CharField(max_length=150, blank=True, null=True)
mobile_number = models.CharField(max_length=150, blank=True, null=True)
email = models.EmailField(max_length=150, blank=False, null=False)
gender = models.CharField(
max_length=4, choices=GENDER, blank=True, null=True)
role = models.ForeignKey(Role, blank=True, null=True)
username = models.CharField(max_length=100, blank=False, null=False)
password = models.CharField(max_length=100, blank=False, null=False)
avatar = models.ImageField(
null=True, blank=True, upload_to=upload_employee_image_path)
class Meta:
verbose_name = 'Employee'
verbose_name_plural = 'Employees'
def __str__(self):
return self.name
When creating an employee by admin, the username, password and email, the admin provides will create a new user instance along with the employee
Django comes with Groups and permissions which provides all most everything you are looking for.
This may help you - How do I use Django groups and permissions?
Django documentation - https://docs.djangoproject.com/en/1.11/topics/auth/

Categories