We Keep Coding

Keep asking for numbers and find the average when user enters -1

number = 0
number_list = []
while number != -1:
number = int(input('Enter a number'))
number_list.append(number)
else:
print(sum(number_list)/ len(number_list))
EDIT: Have found a simpler way to get the average of the list but if for example I enter '2' '3' '4' my program calculates the average to be 2 not 3. Unsure of where it's going wrong! Sorry for the confusion

Trying out your code, I did a bit of simplification and also utilized an if statement to break out of the while loop in order to give a timely average. Following is the snippet of code for your evaluation.
number_list = []
def average(mylist):
return sum(mylist)/len(mylist)
while True:
number = int(input('Enter a number: '))
if number == -1:
break
number_list.append(number)
print(average(number_list));
Some points to note.
Instead of associating the else statement with the while loop, I revised the while loop utilizing the Boolean constant "True" and then tested for the value of "-1" in order to break out of the loop.
In the average function, I renamed the list variable to "mylist" so as to not confuse anyone who might analyze the code as list is a word that has significance in Python.
Finally, the return of the average was added to the end of the function. If a return statement is not included in a function, a value of "None" will be returned by a function, which is most likely why you received the error.
Following was a test run from the terminal.
#Dev:~/Python_Programs/Average$ python3 Average.py
Enter a number: 10
Enter a number: 22
Enter a number: 40
Enter a number: -1
24.0
Give that a try and see if it meets the spirit of your project.

converts the resulting list to Type: None
No, it doesn't. You get a ValueError with int() when it cannot parse what is passed.
You can try-except that. And you can just use while True.
Also, your average function doesn't output anything, but if it did, you need to call it with a parameter, not only print the function object...
ex.
from statistics import fmean
def average(data):
return fmean(data)
number_list = []
while True:
x = input('Enter a number')
try:
val = int(x)
if val == -1:
break
number_list.append(val)
except:
break
print(average(number_list))
edit
my program calculates the average to be 2 not 3
Your calculation includes the -1 appended to the list , so you are running 8 / 4 == 2

You don't need to save all the numbers themselves, just save the sum and count.
You should check if the input is a number before trying to convert it to int
total_sum = 0
count = 0
while True:
number = input("Enter a number: ")
if number == '-1':
break
elif not number.isnumeric() and not (number[0] == "-" and number[1:].isnumeric()):
print("Please enter numbers only")
continue
total_sum += int(number)
count += 1
print(total_sum / count)

Determining the two largest numbers from user input

I've been working on a small program to learn more about Python, but I'm stuck on something.
Basically, the user has to input a sequence of positive integers. When a negative number is entered, the program stops and tells the user the two largest integers the user previously inputted. Here is my code:
number = 1
print("Please enter your desired integers. Input a negative number to end. ")
numbers = []
while (number > 0):
number = int(input())
if number < 0:
break
largestInteger = max(numbers)
print(largestInteger)
integers.remove(largestInteger)
largestInteger2 = max(numbers)
print(largestInteger2)

There are two issues with your code:
You need to update the list with the user input for every iteration of the while loop using .append().
integers isn't defined, so you can't call .remove() on it. You should refer to numbers instead.
Here is a code snippet that resolves these issues:
number = 1
print("Please enter your desired integers. Input a negative number to end. ")
numbers = []
while number > 0:
number = int(input())
if number > 0:
numbers.append(number)
largestInteger = max(numbers)
print(largestInteger)
numbers.remove(largestInteger)
largestInteger2 = max(numbers)
print(largestInteger2)

I would build a function that would call itself again if the user enters a number larger or equal to 0, but will break itself and return a list once a user inputs a number smaller than 0. Additionally I would then sort in reverse (largest to smallest) and call only the first 2 items in the list
def user_input():
user_int = int(input('Please enter your desired integers'))
if user_int >= 0:
user_lst.append(user_int)
user_input()
else:
return user_lst
#Create an empty list
user_lst = []
user_input()
user_lst.sort(reverse=True)
user_lst[0:2]

You forgot to append the input number to the numbers list
numbers = []
while (True):
number = int(input())
if number < 0:
break
numbers.append(number)
print("First largest integer: ", end="")
largestInteger = max(numbers)
print(largestInteger)
numbers.remove(largestInteger)
print("Second largest integer: ", end="")
largestInteger2 = max(numbers)
print(largestInteger2)```
The above code will work, according to your **desire**

How to accept user input of a sequence?

I'm new to python and I'm trying to help out a friend with her code. The code receives input from a user until the input is 0, using a while loop. I'm not used to the python syntax, so I'm a little confused as to how to receive user input. I don't know what I'm doing wrong. Here's my code:
sum = 0
number = input()
while number != 0:
number = input()
sum += number
if number == 0:
break

In your example, both while number != 0: and if number == 0: break are controlling when to exit the loop. To avoid repeating yourself, you can just replace the first condition with while True and only keep the break.
Also, you're adding, so it is a good idea to turn the read input (which is a character string) into a number with something like int(input()).
Finally, using a variable name like sum is a bad idea, since this 'shadows' the built-in name sum.
Taking all that together, here's an alternative:
total = 0
while True:
number = int(input())
total += number
if number == 0:
break
print(total)

No need last if, and also make inputs int typed:
sum = 0
number = int(input())
while number != 0:
number = int(input())
sum += number
You can actually do:
number=1
while number!=0:
number = int(input())

# Declare list for all inputs
input_list = []
# start the loop
while True:
# prompt user input
user_input = int(input("Input an element: "))
# print user input
print("Your current input is: ", user_input)
# if user input not equal to 0
if user_input != 0:
# append user input into the list
input_list.append(user_input)
# else stop the loop
else:
break
# sum up all the inputs in the list and print the result out
input_sum = sum(input_list)
print ("The sum is: ", input_sum)
Or
If you don't want to use list.
input_list = 0
while True:
user_input = int(input("Input an element: "))
print("Your current input is: ", user_input)
if user_input != 0:
input_list += user_input
else:
break
print ("The sum is: ", input_list)
Note:
raw_input('Text here') # Python 2.x
input('Text here') # Python 3.x

How to Separate a Range of Odd and Even Numbers Through Searching the Array While Skipping Numbers

I'd like to challenge myself and develop my programming skills. I would like to create a program that asks for the user to enter a range of numbers where odd and even numbers should be separated (preferably through search) and also separated by a specified jump factor.
Also the user should be allowed to choose whether or not they would like to continue. And if so they can repeat the process of entering a new range.
for example when the program is run a sample input would be:
"Please enter the first number in the range": 11
"Please enter the last number in the range": 20
"Please enter the amount you want to jump by": 3
and the program would output:
"Your odd Numbers are": 11,17
"Your even Numbers are": 14,20
"Would you like to enter more numbers(Y/N)":
So far what I have for code is this but am having trouble putting it together and would appreciate some help.
import sys
print("Hello. Please Proceed to Enter a Range of Numbers")
first = int(input("please enter the first number in the range: "))
last = int(input("please enter the last number in the range: "))
jump = int(input("please enter the amount you want to jump by: "))
def mylist(first,last):
print("your first number is: ",first,"your last number is: ",last,"your jump factor is: ",jump)
def binarySearch (target, mylist):
startIndex = 0
endIndex = len(mylist) – 1
found = False
targetIndex = -1
while (not found and startIndex <= endIndex):
midpoint = (startIndex + endIndex) // 2
if (mylist[midpoint] == target):
found = True
targetIndex = midpoint
else:
if(target<mylist[midpoint]):
endIndex=midpoint-1
else:
startIndex=midpoint+1
return targetIndex
print("your odd Numbers are: ")
print("your even Numbers are: ")
input("Would you like to enter more numbers (Y/N)?")
N = sys.exit()
Y = first = int(input("please enter the first number in the range"))
last = int(input("please enter the last number in the range"))
jump = int(input("please enter the amount you want to jump by: "))

question - "So far what I have for code is this but am having trouble putting it together and would appreciate some help."
answer -
As a start, it seems like a good idea to group your inputs and outputs into functions! Then putting it together is a snap!
def get_inputs():
bar = input('foo')
def process_inputs():
bar = bar + 1
def print_outputs():
print(bar)
if '__name__' == '__main__':
get_inputs()
process_inputs()
print_outputs()
You could even toss in something like if input('more? (Y/N):') == 'Y': in a while loop.

Maybe I'm missing something but couldn't you replace your binary search with the following?
>>> list(filter(lambda x: x%2 == 1, range(11, 20 + 1, 3)))
[11, 17]
>>> list(filter(lambda x: x%2 == 0, range(11, 20 + 1, 3)))
[14, 20]

How do i order the numbers a user inputs?

I am basically wondering how i can store the users inputs and put them in order from least to greatest to help them find median mode or range.
from __future__ import division
amtnum = 0
sumofnums = 0
print "Hello, This program will help find the mean of as many numbers as you want."
useramtnum = input("How many numbers will you need to enter: ")#asks user to say how many numbers there are
while amtnum < useramtnum: #Tells program that while the amount of numbers is less than the users input amt of numbers to run.
amtnum = amtnum + 1 #Tells that each time program asks for number add one to amt of numbers
entnum = (int(raw_input("Enter a number:"))) #Asks user for number
sumofnums = entnum + sumofnums #Adds users number to all values
print "The amount of your numbers added up were:", sumofnums
print "The average/mean of your numbers were:", (sumofnums/useramtnum)

put 'em in a list and sort it
mylist = []
while ...
mylist.append(entnum)
mylist.sort()
print mylist

Utilize the basic data structure called a list!
Before your while loop, create a list (aka array)
user_input_list = []
After you get the individual number from the user in the while loop, add the input to the list (in the while loop)
user_input_list.append(entnum)
After the while loop, sort the list (it will sort in place)
user_input_list.sort()
Then the list has every input from the user in sorted order, least to greatest.
To access the last item in the list, use array accessors.
user_input_list[-1]
To access median, utilize the fact you can use the length of the list. Access the length(list)/2 item
user_input_list[int( len(user_input_list) / 2)] #int cast used to remove decimal points

I am by no means a Python expert (as in, this is like my third python program), but I think it's generally easier to call functions, be it in Python or in any other language. It makes code more readable.
These are all basic math functions, so I don't feel I deprived you of knowledge by just writing them. I did, however, leave the range function for you to write. (Since mylist is sorted, I'm sure you can figure it out.)
This allows the user to continually enter numbers and have the mean, median, and mode spit back at them. It doesn't handle non-integer input.
from collections import Counter
from decimal import *
def getMode(l):
data = Counter(l)
mode = data.most_common(1)
print "mode:", mode
def getMean(l):
length = len(l)
total = 0
for x in l:
total = total + x
mean = Decimal(total) / Decimal(length)
print "mean:", mean
def getMedian(l):
median = 0
length = len(l)
if (length % 2 == 0):
median = (l[length/2] + l[length/2 - 1])/2.0
else:
median = l[length/2]
print "median:", median
mylist = []
print "Enter numbers to continually find the mean, median, and mode"
while True:
number = int(raw_input("Enter a number:"))
mylist.append(number)
mylist.sort()
getMean(mylist)
getMedian(mylist)
getMode(mylist)

Solution to solve your problem :
Use a list : More on Lists
Example :
numbers = []
while amount < counter:
...
numbers.append(num)
print sorted(numbers)
You can take a look at modification of your code below.
numbers = []
print "Hello, This program will help find the \
mean of as many numbers as you want."
while True:
try:
counter = input("How many numbers will you need to enter: ")
except:
print "You haven't entered a number."
else:
break
amount = 0
while amount < counter:
try:
num = input("Enter a number: ")
except:
print "You haven't entered a number."
else:
amount += 1
numbers.append(num)
print "The amount of your numbers added up were:", (sum(numbers))
print "The average/mean of your numbers were:", ( (sum(numbers)) / counter)
print "My list not in order:", numbers
print "My list in order:", sorted(numbers)