I have four python functions that I am using to send mail. If the program does one thing, it mails a set of results to a multiple recipients, if it does another thing, a separate function mails the results to one recipient.
def smail(to,sub,body):
addr_from = 'alert#example.com'
msg = MIMEMultipart()
msg['From'] = addr_from
msg['To'] = to
msg['Subject'] = sub
msg.attach(body)
s = smtplib.SMTP('webmail.example.com')
s.sendmail(addr_from, [to], msg.as_string())
s.quit()
def email_format2(results):
text = ""
text += 'The following applications in <environment> are non-compliant\n'
text += '<br>'
text += 'Here are there names and locations. Please inform the developer.'
text += '<br>'
text += '<br>'
table = pd.DataFrame.from_records(results)
table_str = table.to_html()
text += "%s" % table_str
return text
def mail_results_aq(results):
body = email_format2(results)
msg = MIMEText(body, 'html')
sub = "Placeholder subject"
to = 'email1#example.com, email2#example.com, email3#example.com'
smail(to, sub, msg)
def mail_results_prd(results):
body = email_format2(results)
msg = MIMEText(body, 'html')
sub = "Placeholder subject"
to = 'email4#example.com'
smail(to, sub, msg)
The mail_results_aq function will only email results to the first recipient (email1#example.com).
In other questions similar to this one, I've seen a the recipients being entered into a list i.e
import smtplib
from email.mime.text import MIMEText
s = smtplib.SMTP('smtp.uk.xensource.com')
s.set_debuglevel(1)
msg = MIMEText("""body""")
sender = 'me#example.com'
recipients = ['john.doe#example.com', 'john.smith#example.co.uk']
msg['Subject'] = "subject line"
msg['From'] = sender
msg['To'] = ", ".join(recipients)
s.sendmail(sender, recipients, msg.as_string())
However, this use case only seems to work when used in the same function. How can I implement this feature across the four functions I have above?
Thanks in advance!
Related
I would like to loop through a list and display each item on a separate line in my email.
The code works fine if I set body = "Just a string"
mylist = [first line,second line,third line,fourth line]
fromaddr = "EMAIL"
toaddr = "EMAIL"
msg = MIMEMultipart()
msg['From'] = fromaddr
msg['To'] = toaddr
msg['Subject'] = "EMAIL SUBJECT"
body = mylist
msg.attach(MIMEText(body, 'plain'))
server = smtplib.SMTP('smtp.gmail.com', 587)
server.ehlo()
server.starttls()
server.ehlo()
server.login("EMAIL", "PASSWORD")
text = msg.as_string()
server.sendmail(fromaddr, toaddr, text)
I tried just making body = to mylist just to see how it looked currently but I get the following error: _text.encode('us-ascii')
AttributeError: 'list' object has no attribute 'encode'
What I would like ultimately is the body of the email to look this (when I receive the email):
first line
second line
third line
fourth line
Thanks to Michael Butscher for the push in the right direction.
This does the job.
body = "\r\n".join(mylist)
I am making a script which checks a website for auctions interested for me. If it finds an interested link, it adds this link to listalink with listalink.append(link). When I am sending an email I have this error:
AttributeError: 'list' object has no attribute 'encode'.
import smtplib
from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText
# listalink example:
listalink = ["http://www.google.pl", "http://www.facebook.com", "http://amazon.com"]
def email_sender():
fromaddr = "test_e_mail#wp.pl"
toaddr = "myemail#gmail.com"
msg = MIMEMultipart()
msg['From'] = fromaddr
msg['To'] = toaddr
msg['Subject'] = "NEW INTERESTED AUCTIONS"
body = listalink
msg.attach(MIMEText(body, 'plain'))
server_ssl = smtplib.SMTP_SSL("smtp.wp.pl", 465)
server_ssl.ehlo()
server_ssl.login("test_e_mail#wp.pl", "password")
text = msg.as_string()
server_ssl.sendmail(fromaddr, toaddr, text)
server_ssl.close()
print 'E-mail sent'
the error occurs because you add list to email's body (the body must be str):
body = listalink
Solution:
listalink = ["http://www.google.pl", "http://www.facebook.com", "http://amazon.com"]
listalink = " ".join(listalink)
I am working on a python script to send email to my customer with a survey. I will send only one email with all my customers's emails in the BCC field so that I do not need to loop through all the emails. Everything works fine when I tested sending emails to my company's coleagues and also when I sent to my personal email, but whenever I send to a gmail account, the BCC field appears to not be hidden and show all the emails. I found this post Email Bcc recipients not hidden using Python smtplib and tried that solution as well, but as I am using a html body email, the emails were shown inside the body. Can anyone help me on this one?
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.image import MIMEImage
def send_survey_mail():
template_path = 'template.html'
background_path = 'image.png'
button_path = 'image2.png'
try:
body = open(template_path, 'r')
msg = MIMEMultipart()
msg['Subject'] = 'Customer Survey'
msg['To'] = ', '.join(['myemail#domain.com.br', 'myemail2#domain.com'])
msg['From'] = 'mycompany#mycompany.com.br'
msg['Bcc'] = 'customer#domain.com'
text = MIMEText(body.read(), 'html')
msg.attach(text)
fp = open(background_path, 'rb')
img = MIMEImage(fp.read())
fp.close()
fp2 = open(button_path, 'rb')
img2 = MIMEImage(fp2.read())
fp2.close()
img.add_header('Content-ID', '<image1>')
msg.attach(img)
img2.add_header('Content-ID', '<image2>')
msg.attach(img2)
s = smtplib.SMTP('smtpserver')
s.sendmail('mycompany#mycompany.com.br',
['myemail#domain.com.br', 'myemail2#domain.com', 'customer#domain.com'],
msg.as_string())
s.quit()
except Exception as ex:
raise ex
send_survey_mail()
I removed the following line from the code and tried again. Now the email is not sent to my customer's Gmail email.
msg['Bcc'] = 'customer#gmail.com'
Just do not mention bcc mails in msg['To'] or msg['Cc']. Do it only in server.sendmail()
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.base import MIMEBase
from email import encoders
from_addr = "your#mail.com"
to_addr = ["to#mail.com", "to2#mail.com"]
msg = MIMEMultipart()
msg['From'] = from_addr
msg['To'] = to_addr
msg['Subject'] = "SUBJECT"
body = "BODY"
msg.attach(MIMEText(body, 'plain'))
filename = "FILE.pdf"
attachment = open('/home/FILE.pdf', "rb")
part = MIMEBase('application', 'octet-stream')
part.set_payload((attachment).read())
encoders.encode_base64(part)
part.add_header('Content-Disposition', "attachment; filename= %s" % filename)
msg.attach(part)
server = smtplib.SMTP('.....', 587)
server.starttls()
server.login(from_addr, 'yourpass')
text = msg.as_string()
server.sendmail(from_addr, to_addr + [bcc#mail.com], text)
server.quit()
Did you try not to define the msg['BCC'] field? Setting this field forces it to be included. It is sufficient that the BCC email address is in the sendmail command's destination address list. Take a look at this question.
MAIL_FROM = default#server.com
MAIL_DL = default#server.com
def send(to, cc, bcc, subject, text, html):
message = MIMEMultipart("alternative")
message["Subject"] = subject
message["From"] = MAIL_FROM
message["To"] = to
message["Cc"] = cc + "," + MAIL_DL
if html is not None:
body = MIMEText(html, "html")
else:
body = MIMEText(text)
message.attach(body)
server = smtplib.SMTP(MAIL_SERVER)
server.set_debuglevel(1)
server.sendmail(MAIL_DL, to.split(",") + bcc.split(","), message.as_string())
server.quit()
return {
"to": to,
"cc": cc,
"bcc": bcc,
"subject": subject,
"text": text,
"html": html,
}
I searched about this quite a lot, but could not fix the issue in my script. So finally, I decided to post it here.
Here's the code snippet:
fromaddr = "someValidAddress#xyz.com"
cc = ['SomeEmailAlias#xyz.com']
toaddr = ""
msg = MIMEMultipart()
toaddrlist = list(toaddr.split(',')) #As sendmail() accepts the list of recipients only in list form.
toaddrlist += (cc,)
msg['From'] = fromaddr
msg['To'] = toaddr
msg['Cc'] = ', '.join(cc)
msg['Date'] = formatdate(localtime=True)
msgHtml = MIMEText(html, 'html')
msg.attach(msgHtml)
msg['Subject'] = "Test mail"
server = "someMailServer.xyz.com"
smtp = smtplib.SMTP(server, 25)
smtp.sendmail(fromaddr, toaddrlist, msg.as_string())
smtp.close() #Close the SMTP server connection.
I'm aware and I've ensured that msg['To'] accepts a string value (toaddr), whereas toaddrlist in sendmail() should be a list.
Catch: If I remove the line toaddrlist += (cc,), then the mail does not get delivered twice to the recipients in "To" field, but the mail does not get delivered to the Cc alias.
Please help.
When the line toaddrlist += (cc,) is evaluated, the value of toaddrlist in your case is :
["", ["SomeEmailAlias#xyz.com"]]
and it's wrong because toaddrlist must be a list of strings not a list containing some lists.
So the solution is to change :
toaddrlist += (cc,)
to
toaddrlist += cc
or the recommended form (the pythonic way) :
toaddrlist.extend(cc)
I'm having big time problems with this issue-- another question on SO that didn't solve it is here: Send Raw Email (with attachment) to Multiple Recipients
My code (that works) is simple:
def send_amazon_email_with_attachment(html, subject, now, pre):
dummy = 'test#example.com'
recipients = ['test1#exampl.ecom', 'test2#example.com', 'test3#example.com']
connS3 = S3Connection('IDENTIFICATION','PASSWORD')
b = connS3.get_bucket('BUCKET_NAME')
key = b.get_key('FILE_NAME.pdf')
temp = key.get_contents_as_string()
msg = MIMEMultipart('alternative')
msg['Subject'] = subject
msg['From'] = 'My Name <test#example.com>'
msg.preamble = 'Multipart message.\n'
part1 = MIMEText(u"Attached is the report", 'plain')
part2 = MIMEText(html, 'html')
msg.attach(part1)
msg.attach(part2)
part = MIMEApplication(temp) #read binary
part.add_header('Content-Disposition', 'attachment', filename='FILE_NAME.pdf')
msg.attach(part)
conn = boto.ses.connect_to_region('us-east-1', aws_access_key_id='AUTH_ID', aws_secret_access_key='AUTH_PW')
for recipient in recipients:
print recipient
msg['To'] = recipient
result = conn.send_raw_email(msg.as_string(), source=msg['From'], destinations=recipient)
but, there's a caveat... this is looping for each recipient. Any variation of this does not work. Passing a list to msg['Bcc'] or msg['BCC'] will return an error that the list can't be stripped (same exact error as the posted question). Passing a string separated by commas gives an Amazon SES issue saying 'Illegal Email' in the returned XML. Because I only get an error from Amazon in specific situations, I'm led to believe this is an error with the program before it hits their API call.
Any MIMEMultipart experts have some ideas?
Basically you need to specify the email recipients in 2 different places using 2 different formats.
def send_amazon_email_with_attachment(html, subject, now, pre):
dummy = 'test#example.com'
recipients = ['test1#exampl.ecom', 'test2#example.com', 'test3#example.com']
connS3 = S3Connection('IDENTIFICATION','PASSWORD')
b = connS3.get_bucket('BUCKET_NAME')
key = b.get_key('FILE_NAME.pdf')
temp = key.get_contents_as_string()
msg = MIMEMultipart('alternative')
msg['Subject'] = subject
msg['From'] = 'My Name <test#example.com>'
msg['To'] = ', '.join(recipients)
msg.preamble = 'Multipart message.\n'
part1 = MIMEText(u"Attached is the report", 'plain')
part2 = MIMEText(html, 'html')
msg.attach(part1)
msg.attach(part2)
part = MIMEApplication(temp) #read binary
part.add_header('Content-Disposition', 'attachment', filename='FILE_NAME.pdf')
msg.attach(part)
conn = boto.ses.connect_to_region('us-east-1', aws_access_key_id='AUTH_ID', aws_secret_access_key='AUTH_PW')
result = conn.send_raw_email(msg.as_string(), source=msg['From'], destinations=recipients)
msg['To'] = ', '.join(recipients) isn't working for me (throws encoding error). Simply comment that line and your 'destinations' in "send_raw_email" should contain a list. That will work like a charm.