I have urls that take a parameter called board_slug. Before getting the template the view will replace the slug if its name is wrong and redirect it. I have already made the code for fixing the slug but do not know how insert the fixed board_slug into the new url. This code is run across multiple views so it has to work with all the following kinds urls:
url(r'^boards/(?P<board_slug>[^/]+)/$', views.BoardView.as_view(), name='board'),
url(r'^/front-thing/boards/(?P<board_slug>[^/]+)/new/$', views.BoardView.as_view(), name='new_board'),
url(r'^boards/(?P<board_slug>[^/]+)/etc...$', views.BoardView.as_view(), name='anything_with_board'),
class BoardView(View):
template_name = 'forums/board.html'
def get(self, request, board_slug):
if wrong:
url = get_django_url
url.board_slug = 'new-slug'
return redirect(url)
else:
return template
Related
Im trying to create a extra view in django admin, on the left navbar. This view will be responsible for uploading a file, which will be parsed in some function (in future i would like to render result of this parsing in admin page). This file wont be saved in database, so there wont be a model. Is there any possibility to add a view to django admin (left navbar) which dont have a model? I was reading a lot, and could find a solution. What i have done for now:
Created a class which inherits from AdminSite. I tried to implement get_app_list method, but variable self._build_app_dict(request) was empty array, and this means, method couldn't find a installed aps. I wanted to add new object to app_list variable, to render it on website.
Tried to override a admin templates, but couldnt render it. I tried to override app_index.html which i put on folder: app_name/templates/admin/app_index.html
Here is my code, which ofc doesnt work:
class MyCustomAdmin(AdminSite):
def get_app_list(self, request):
"""
Return a sorted list of all the installed apps that have been
registered in this site.
"""
app_dict = self._build_app_dict(request)
breakpoint()
app_list = sorted(app_dict.values(), key=lambda x: x['name'].lower())
for app in app_list:
app['models'].sort(key=lambda x: x['name'])
return app_list
def get_urls(self):
from django.conf.urls import url
urls = super(MyCustomAdmin, self).get_urls()
urls += [
url(r'^my_custom_view/$', self.admin_view(MyCustomView.as_view()))
]
return urls
class MyCustomView(View):
template_name = 'admin/app_index.html'
def get(self, request):
print('fefef')
return render(request, self.template_name, {})
def post(self, request):
pass
admin_site = MyCustomAdmin()
admin_site.get_app_list(AdminSite.get_app_list)
I would like to build a system which need to detect which urls the user opened and count the opened times.
There are several different urls shared the same WaitView(TemplateView), so I want to count the numbers for each url when user click it.
I added a dic in the urls and hope it can return the correct url the user opened to the context1 in Waitview.
But I couldn't find a correct way to obtain the correct url, (I tried to use HttpRequest.get_full_path() but it continues error.
"TypeError: get_full_path() missing 1 required positional argument: 'self'")
Moreover, I hope the WaitView could received the correct url and count times and then show the times on the opened page.(need the correct url before render it)
So I wander if you have some suggestions on this.
Really appreciate for your kind help.
# urls.py
'''
urlpatterns = [
re_path('get_times/.+', WaitView.as_view(), {"url": ***CORRECT_URL***})
]
'''
# views.py
'''
class WaitView(TemplateView):
template_name = 'wait.html'
def get_context_data(self, **kwargs):
context1 = kwargs.items()
print(context1)
'''
The request object is stored in the .request attribute of a View. You thus can access it with self.request in the view methods, and you thus can obtain the url with:
class WaitView(TemplateView):
template_name = 'wait.html'
def get_context_data(self, **kwargs):
print(self.request.get_full_path())
return super().get_context_data(**kwargs)
You can use the .build_absolute_uri() method [Django-doc] to generate the absolute URI (so including the protocol, hostname, etc.).
so there is no need to add a parameter to the context.
i have a table which include all users and two columns at the end (Edit,Delete) and i just enabled the delete column, the issue is when i click on the delete icon the record will be deleted but the url will stuck on the delete function even if i used return render(request,'getUsersInfo.html') which is get all records function
Model Name: Users
urls:
from django.urls import path
from django.conf.urls import url
from . import views
urlpatterns = [
path('signup.html',views.signup,name=''),
path('getUsersInfo.html',views.getAllUsers,name=''),
url(r'^deleteUser/(?P<fullname>\D+)/$',views.deleteUser, name='deleteUser'),
# this is how to call a function without parameters url(r'^deleteUser/$',views.deleteUser, name='deleteUser'),
in the same view i have 3 functions (singup "add user", getAllUsers "get all the records to the table,deleteUser)
views:
def getAllUsers(request):
print("getAllUsers")
thesearchValue = ''
if 'SearchValue' in request.GET:
thesearchValue = request.GET['SearchValue']
print(request.GET['SearchValue'])
allUsers = User.objects.filter(fullname__icontains=thesearchValue)#all()
# return render(request,'getUsersInfo.html',{'allUsers':allUsers})
return render(request,'getUsersInfo.html',{'allUsers':allUsers})
else:
print("Empty")
allUsers = User.objects.all()
return render(request,'getUsersInfo.html',{'allUsers':allUsers})
def deleteUser(request,fullname):
print('delete the user')
todelete = User.objects.filter(fullname=fullname)
todelete.delete()
return render(request,'getUsersInfo.html')
Notice that i used return render(request,'getUsersInfo.html') which should call getAllUsers(request): but the url stuck on http://127.0.0.1:8000/deleteUser/John/
Rendering the same template as another view does not mean that you will somehow call other views. A template is nothing more than a tool to specify how to convert context data to a string, that is passed as HTTP response. You can use the same template in multiple views, and a view can render multiple templates.
You can make use of redirect(..) [Django-doc] to return a HTTP redirect response (302):
from django.shortcuts import redirect
def deleteUser(request,fullname):
print('delete the user')
todelete = User.objects.filter(fullname=fullname)
todelete.delete()
return redirect(getAllUsers)
Note: A GET request is not supposed to have side-effects, hence removing
objects when a user makes a GET request, is not compliant with the HTTP
standard. Therefore it might be better to remove a User with a POST request.
I would like to return to a specific page after I edit a record using Django "UpdateView", however this page url needs an argument passed to it as well (see urls.py below). I am pretty sure I need to use "get_absolute_url", which works when I am just redirecting to an unfiltered page, but can't seem to get the syntax to redirect to a filtered page.
Models.py
class DefaultDMLSProcessParams(models.Model):
device = models.ForeignKey(get_user_model(),on_delete=models.CASCADE,)
customerTag = models.CharField(max_length=50,)
processNotes = models.TextField(max_length=300,blank=True,default = "")
def __str__(self):
return str(self.defaultParamDescrip)
def get_absolute_url(self):
#self.object.pk? pass this below somehow?
return reverse('Default_Listview',)
views.py
class defaultUpdateView(LoginRequiredMixin,UpdateView):
model = models.DefaultDMLSProcessParams
fields = ['processNotes','customerTag']
template_name = 'default_edit.html'
login_url = 'login'
urls.py
path('<int:device>', DefaultsListView.as_view(), name='Default_Listview'),
Specify the parameter by args argument of reverse() function
def get_absolute_url(self):
# self.object.pk? pass this below somehow?
return reverse('Default_Listview', args=[self.id, ])
You could find more example in the Official Django doc .
What is wrong with my approach?
When I post new data, I want it to return back to the page with the input fileds empty. But it gives me this error
NoReverseMatch at /school/new-school/
Reverse for 'new-school' with arguments '()' and keyword arguments '{}' not found. 0 pattern(s) tried: []
This is my model. Please note, reverse_lazy was imported
class SchoolList(models.Model):
name = models.CharField(max_length=15, null=False)
def __str__(self):
return '%s' % (self.name)
def get_absolute_url(self):
return reverse_lazy('new-school')
This is my url.py
url(r'^school-list/$', SchoolListtView.as_view(), name='school-list'),
url(r'^new-school/$', CreateSchoolListView.as_view(), name='new-school'),
url(r'^school(?P<pk>\d+)/update/$', SchoolListUpdate.as_view(), name='update-school')
This is my view for create.
class CreateSchoolListView(CreateView):
template_name = 'school\create_form.html'
model = SchoolList
fields = ['name']
This is how I specified the urls in the template.
Create New School
View all Schools
When the page is displayed, I can click the links and it will go to the correct pages. But when I post a data, the it throws the above error. I have been on this for hours and read many of the answers online. It seems mine is a unique case.
Try adding namespace to get_absolute_url().
def get_absolute_url(self):
return reverse_lazy('school:new-school')
Make sure you import your app's urls in your project's urls with namespace like:
url(r'^school/', include('school.urls', namespace="school"))
to use namespace in your templates like this:{% url 'school:new-school' %}
Or remove namespace:
url(r'^school/', include('school.urls'))
to use url without namespace in template:{% url 'new-school' %}
Using get_absolute_url would be a bad approach in this case, since it's an instance method, designed to get url for single model instance.
If you want to add method to model, you should use something like this:
#classmethod
def get_create_url(cls):
return reverse_lazy('school:new-school')