about_pet = input("A sentence about your pet")
multi = "dog", "cat"
if all(multi) in about_pet:
print ("wow, you have one more pets!", " Thanking you reading my
story:) ")
elif "dog" in about_pet:
print ("Ah, a dog.", " Thanking you reading my story:) ")
elif "cat" in about_pet:
print ("Oh, a cat.", " Thanking you reading my story:) ")
i don't know how to search two strings in an input. The above captured is what I had done.
All works on an iterable, it returns true if all items within the iterable are true.
multi = ["dog", "cat"]
if all(m in about_pet for m in multi):
print ("wow, you have one more pets!", " Thanking you reading my story:) ")
you could put an if statement within an if statement so it checks if the sentence contains the word cat first then if it does it goes on check if it also contains the word dog to see if both words are in the string.
about_pet = raw_input("A sentence about your pet")
if "cat" in about_pet:
if "dog"in about_pet:
print "wow, you have one more pets! Thanking you reading my story:) "
elif "dog" in about_pet:
print "Ah, a dog. Thanking you reading my story:) "
elif "cat" in about_pet:
print "Oh, a cat. Thanking you reading my story:) "
I know this might not be the cleverest solution but it is quite easy to understand.
To simplify it you can check them one after another using an and
if "cat" in about_pet and "dog" in about_pet:
or:
if "cat" and "dog" in about_pet:
If you are using Python 2.7.10 ,you also need to use raw_input instead of input as in Python 2.7.10 input only accepts integers and float. And if you're using python 2.7.10(as i am) i don't do my print in brackets as it prints out the brackets sometimes. Also i have a suggestion to add code for when the user says they don't have a pet using an else at the end. Plus you don't have to put sentences in separate speech marks. I hope this helped!
Related
I have a Bad word of list and a Good word to list. My idea was to make a first search for Good words and see which meaning in a letter contains those good word but if that meaning also contains a bad word - then it shouldn't print out the meaning.
etc:
Good word: "Lo", "Yes"
Bad word: "Hate", "Not"
text_roman: "Hello guys. My name is Lo and I hate to code :')"
Meaning: "Hello guys. My name is Lo and I hate to code :')" <-- "Just a joke!!
So meaning if it search for that meaning it should tell us there is a meaning that contains good and then check if it contains Bad word. If it does then we don't want to print out the meaning but if it doesn't contain any bad word then we should print it out.
How I tried to code was:
text_roman = "Hello guys. My name is Lo and I hate to code :')"
good_word = ["Lo", "Yes"]
bad_word = ["Hate", "Not"]
for text in good_word:
if text in text_roman:
print("Yay found word " + text_roman)
for bad_text in bad_word:
if bad_text not in text_roman:
print("Yay no bad words!")
When I tried this, the output gave all the words that contains the bad words aswell unfortunately
I would loop over the bad words first, and skip them. Then, if not skipped, check for a good word
good_word = ["Lo", "Yes"]
bad_word = ["Hate", "Not"]
has_bad = False
for b in bad_word:
if b in text_roman:
has_bad = True
continue
for g in good_word:
if g in text_roman:
print("Yay found word " + g + " in text_roman")
if not has_bad:
print("Yay no bad words!")
Note: in is case sensitive, so "Hate" in "I hate case-sensitivity" will be False
So i wanted to make a little bot that could hold a small conversation with a user. The only problem is that when i type one of the words in the list(being hello or hi) then i get the welcome user message, but if i type something like hello computer it gives me the TESTPHRASE message. Is there something i can put in so that it looks in the sentence of the user input and finds a word in the used list so that it can say the appropriate response.
user_greetings = {"hello", "hi"}
user_input = input("-")
if user_input in user_greetings:
print("Welcome User")
else:
print("TESTPHRASE")
When you apply in to a string and a dictionary, it will test if the entire string is a key. It looks like you want to check for either the first word in the sentence or any word in the sentence being in the dictionary.
In either case, you'd want to split the input on spaces:
words = input('-').split()
If you want to check the first word, proceed almost as before:
if words[0] in user_greetings:
print("Welcome User")
else:
print("TESTPHRASE")
If any of the words should trigger the welcome message, use any and a generator expression:
if any(x in user_greetings for x in words):
print("Welcome User")
else:
print("TESTPHRASE")
I'm getting a syntax error for your code. Try moving else to it's own line. Otherwise, your code works for me.
EDIT:
Reread the question. Your code is checking if "hello computer" is in greetings, which is {'hello', 'hi'}. "hello computer" is not in greetings. You could reverse the search and do
for greeting in user_greetings:
if greeting in user_input:
# print greeting
Otherwise, you need to add "hello computer" to your list of greetings.
Something like this would do it:
greetings = ['hello', 'hi']
input = 'hello computer'.split()
if set(greetings).intersection(set(input)):
print('Welcome')
#Mad Physicist gives a very comprehensive answer for this and I upvoted his answer.
There is another way of doing it if any word will trigger the welcome message, no matter it is capitalized or not.
user_greetings = {"hello", "hi"}
user_input = input("-").split()
# set process control.
greeting = None
for word in user_input:
if word.lower() in user_greetings:
print("Welcome User")
else:
greeting = True
if greeting:
print("TESTPHRASE")
If I ask a question in Python and the answer is chicken, I want to output something related to chicken. And, if the answer is beef I want to output something related to beef, dependent on the answer provided.
How could I structure this? Should I have multiple lists with key words and related answers? Newbie.
I would use a dict of lists:
import random
similar_words = {
'chicken': ['poultry', 'wings'],
'beef': ['cow', 'ground-beef', 'roast-beef', 'steak'],
}
word = raw_input("Enter a word: ").strip()
if word in similar_words:
print random.choice(similar_words[word])
else:
print "Not found!"
See the Python manual on Data Structures for more information. Note that I'm also using random.choice() to select a random item from each list.
Here's the output of it running:
$ python words.py
Enter a word: chicken
poultry
$ python words.py
Enter a word: beef
cow
$
Edit: You were asking in the comments how you could do this if the words were contained inside a whole sentence. Here's one example:
words = raw_input("Enter a word or sentence: ").strip().split()
for word in words:
if word.lower() in similar_words:
print random.choice(similar_words[word.lower()])
else:
print "Not found!"
Here, we're using split() to split the sentence into a list of words. Then we loop through each word, and see if (the lowercase version of) the word exists in our dict, and do the same thing as we did above with a single word.
As a newbie to programming I currently have an exam where I am supposed to submit Python code for a madlibs game. What I am currently missing in my code is the validation of the user input against the word that should appear in the text.
Right now the program is able to take user input and display the full text but I don't know where to put the validation of the user input in my code, especially because I am going through a list of different words. I know that I have to define the variable somewhere to make a check against the user input but I am completely stuck right now.
This is the current working version of my code, i.e. without the attempt of the input validation against the words.
print "Welcome to my first quiz with user input"
print "Lets get cracking straight away"
print
import time
while True:
difficulty_level = raw_input("Which difficulty level would you like? Type EASY, MEDIUM or HARD to continue? ")
if difficulty_level.upper() == "EASY":
time.sleep(1)
print "Here it goes..."
print
time.sleep(1)
print "Here's your text. Should be an easy one. Just fill in the blanks for _Word_ 1-3."
print
print
print "Python is a _Word1_ language that provides constructs intended to enable clear programs on both small and large scale. Python implementation was started in December _Word2_ by Guido von Rossum. The most simple _Word3_ in Python is _Word4_ and normally used at the beginning to tell Python to write 'Hello World' on the screen."
print
# A list of replacement words to be passed in to the play game function.
parts_of_speech1 = ["_Word1_", "_Word2_", "_Word3_", "_Word4_"]
# The following is the text for the easy text..
easy_text = "Python is a _Word1_ language that provides constructs intended to enable clear programs on both small and large scale. Python implementation was started in December _Word2_ by Guido von Rossum. The most simple _Word3_ in Python is _Word4_ and normally used at the beginning to tell Python to write 'Hello World' on the screen."
# Checks if a word in parts_of_speech is a substring of the word passed in.
def word_in_pos_easy(word, parts_of_speech1):
for pos in parts_of_speech1:
if pos in word:
return pos
return None
# Plays a full game of mad_libs. A player is prompted to replace words in the easy text,
# which appear in parts_of_speech with their own words.
def easy_game(easy_text, parts_of_speech1):
replaced = []
easy_text = easy_text.split()
for word in easy_text:
replacement = word_in_pos_easy(word, parts_of_speech1)
if replacement != None:
user_input = raw_input("Type in: " + replacement + " ")
word = word.replace(replacement, user_input)
replaced.append(word)
else:
replaced.append(word)
replaced = " ".join(replaced)
print
time.sleep(1)
print "Ok, lets see your results. Does it make sense?"
print
time.sleep(1)
return replaced
print
time.sleep(1)
print easy_game(easy_text, parts_of_speech1)
# Difficulty Level Medium
if difficulty_level.upper() == "MEDIUM":
time.sleep(1)
print "Good choice. Lets see how much you know about Python"
print
time.sleep(1)
print "Here's your text. It's a tricky one that requires some more knowledge about Python. Just fill in the blanks for _Word_ 1-3."
print
print
print "A string object is _Word1_, i.e. it cannot be modified after it has been created. An important concept in Python and other programming languages is _Word2_. You use them to store a value. To assign a value to a Variable you use the _Word3_ operator. A more versatile data type in Python is _Word4_. They contain items separated by commas and within square brackets. To some extent they are similar to arrays in C."
print
# A list of replacement words to be passed in to the play game function.
parts_of_speech2 = ["_Word1_", "_Word2_", "_Word3_", "_Word4_"]
# The following are some test strings to pass in to the play_game function.
medium_text = "A string object is _Word1_, i.e. it cannot be modified after it has been created. An important concept in Python and other programming languages is _Word2_. You use them to store a value. To assign a value to a Variable you use the _Word3_ operator. A more versatile data type in Python is _Word4_. They contain items separated by commas and within square brackets. To some extent they are similar to arrays in C."
# Checks if a word in parts_of_speech is a substring of the word passed in.
def word_in_pos_medium(word, parts_of_speech2):
for pos in parts_of_speech2:
if pos in word:
return pos
return None
# Plays a full game of mad_libs. A player is prompted to replace words in ml_string,
# which appear in parts_of_speech with their own words.
def medium_game(medium_text, parts_of_speech2):
replaced = []
medium_text = medium_text.split()
for word in medium_text:
replacement = word_in_pos_medium(word, parts_of_speech2)
if replacement != None:
user_input = raw_input("Type in: " + replacement + " ")
word = word.replace(replacement, user_input)
replaced.append(word)
else:
replaced.append(word)
replaced = " ".join(replaced)
print
time.sleep(1)
print "OK, lets see your results. Does it make sense?"
print
time.sleep(1)
return replaced
print
time.sleep(1)
print medium_game(medium_text, parts_of_speech2)
# Difficulty Level Hard
if difficulty_level.upper() == "HARD":
time.sleep(1)
print "Bold move! Here we go. Check out this text. It's a tough one"
print
time.sleep(1)
print "Here's your text. This one requires quite some Python knowledge"
print
print
print "Similar to other programming languages, Python has flow controls. The most known statement is the _Word1_ statement. It can be combined with an else statement and helps to process a logic based on a specific condition. For more repetitive processing one needs to use loops. _Word2_ loops execute a sequence of statements multiple times and abbreviates the code that manages the loop variable._Word3_ loops repeat a statement or group of statements while a given condition is TRUE. It tests the condition before executing the loop body."
print
# A list of replacement words to be passed in to the play game function.
parts_of_speech3 = ["_Word1_", "_Word2_", "_Word3_", "_Word4_"]
# The following are some test strings to pass in to the play_game function.
hard_text = "Similar to other programming languages, Python has flow controls. The most known statement is the _Word1_ statement. It can be combined with an else statement and helps to process a logic based on a specific condition. For more repetitive processing one needs to use loops. _Word2_ loops execute a sequence of statements multiple times and abbreviates the code that manages the loop variable. _Word3_ loops repeat a statement or group of statements while a given condition is TRUE. It tests the _Word4_ before executing the loop body."
# Checks if a word in parts_of_speech is a substring of the word passed in.
def word_in_pos_hard(word, parts_of_speech3):
for pos in parts_of_speech3:
if pos in word:
return pos
return None
# Plays a full game of mad_libs. A player is prompted to replace words in the hard text,
# which appear in parts_of_speech with their own words.
def hard_game(hard_text, parts_of_speech3):
replaced = []
hard_text = hard_text.split()
for word in hard_text:
replacement = word_in_pos_hard(word, parts_of_speech3)
if replacement != None:
user_input = raw_input("Type in: " + replacement + " ")
word = word.replace(replacement, user_input)
replaced.append(word)
else:
replaced.append(word)
replaced = " ".join(replaced)
print
time.sleep(1)
print "OK, lets see your results. Does it make sense?"
print
time.sleep(1)
return replaced
print
print hard_game(hard_text, parts_of_speech3)
else:
print "Sorry, that was not a correct input. Please enter EASY, MEDIUM or HARD to set the difficulty level."
Here's how I would do it:
from random import shuffle
import sys
from time import sleep
# version compatibility shim
if sys.hexversion <= 0x3000000: # Python 2.x
inp = raw_input
else: # Python 3.x
inp = input
def get_word(prompt):
return inp(prompt).strip().lower()
def shuffled(words):
words_copy = list(words)
shuffle(words_copy)
return words_copy
class MadLib:
BLANK = "___"
DELAY = 1
def __init__(self, intros, prompt, words):
self.intros = intros
self.prompt = prompt
self.words = words
self.num_words = len(words)
assert prompt.count(self.BLANK) == self.num_words, "Number of blanks must match number of words!"
def play(self):
# show introduction
for s in self.intros:
sleep(self.DELAY)
print(s, flush=True)
# display madlib with blanks
sleep(self.DELAY)
print(self.prompt)
# get words from user
print("Words available: " + ", ".join(shuffled(self.words)))
gotten = [
get_word("Word {}: ".format(i))
for i in range(1, self.num_words + 1)
]
# evaluate results
num_right = sum(g == w for g,w in zip(gotten, self.words))
if num_right == self.num_words:
print("You did it!")
return True
else:
print("You got {} out of {} words right.".format(num_right, self.num_words))
return False
madlibs = {
"easy":
MadLib(
[
"Here we go...",
"Here's your text. Should be an easy one.",
"Just fill in the blanks!"
],
(
"Python is a ___ language that provides constructs intended to "
"enable clear programs on both small and large scale. "
"Python implementation was started in December ___ by "
"Guido von Rossum. The most basic ___ in Python is ___, "
"often used by beginners to tell Python to display 'Hello "
"World' on the screen."
),
['programming', '1989', 'command', 'print']
),
"medium":
MadLib(
[
"Good choice. Lets see how much you know about Python",
"Here's your text. It's a tricky one that requires some more knowledge about Python.",
"Just fill in the blanks!"
],
(
"A string object is ___, i.e. it cannot be modified after it "
"has been created. An important concept in Python and other "
"programming languages is the ___, used to store a value. "
"To assign a value to you use the ___ operator. A more "
"versatile data type in Python is ___, containing items "
"separated by commas and within square brackets and to "
"some extent they are similar to arrays in C."
),
['immutable', 'variable', 'equals', 'list']
),
"hard":
MadLib(
[
"Bold move! Here we go. Check out this text. It's a tough one!",
"Here's your text. This one requires quite some Python knowledge.",
"Just fill in the blanks!",
"Here's your text:"
],
(
"Similar to other programming languages, Python has flow "
"control commands. The most common is ___ which lets you branch "
"based on a condition. Looping commands like ___ execute "
"statements a given number of times, or ___ repeats statements "
"so long as a condition is True."
),
['if', 'for', 'while']
)
}
def main():
print(
"Welcome to my first quiz with user input!\n"
"Lets get cracking straight away."
)
while True:
choice = get_word("Which difficulty level would you like? [easy, medium, hard] (or just hit Enter to exit) ")
if not choice:
break
elif choice in madlibs:
madlibs[choice].play()
else:
print("Sorry, that was not a recognized option.")
if __name__=="__main__":
main()
What I’d like to is make my code so that if I enter "You are a " plus a complement word (in the list) and or another word like "You are a nice robot" It will print out: "Thank You!"
Here is my code:
complements = ["nice","happy","good","smart","wonderful"]
def chat():
input = raw_input("You: ")
if input in "You are a ":
if input in complements:
print "TIM: Thank you"
else:
print "I don't understand"
chat();
No matter what I do, it automatically goes to the else statement
You have two main problems:
if input in "You are a ": tests whether the whole input is in "You are a ", not whether that phrase is at the start of the input; and
if input in complements tests whether the whole input is in your list, not whether one item from your list is in the input.
Try something like:
def chat(compliments=["nice", "happy", "good", "smart", "wonderful"]):
input = raw_input("YOU: ")
if input.startswith("You are a "):
if any(input[10:].startswith(c) for c in compliments):
print "TIM: Thank you"
This gives me:
>>> chat()
YOU: You are a nice robot
TIM: Thank you