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Beginner question regard basic loop and totaling positive inputs [closed]

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print("Welcome to the number program")
number=input("Please give me a number \n")
number=int(number)
total_number=0
entries=0
while number>0:
total_number=total_number+number
print(total_number)
number=input("Please give me another number! \n")
number=int(number)
entries= int(entries)+1
if number < 0 :
print("Sorry, this value needs to be positive. Please enter a
different number.")
if number == -999:
print(total_number)
print(entries)
print(total_number/entries)
I'm in a beginners programming class, and the book is not very helpful at times. I'm trying to write a basic program that takes positive numbers, totals them, and averages them out at the end. Also rejects negative numbers, and asks if -999 is entered I print the average of all entries, amount of entries, and the value tally. Any advice or tips I can learn from to improve it would be helpful. Thanks!
The program runs ok, it just doesn't write out some things I wanted

From what you wrote and the comments in your code I am guessing that you want the program to continue running and asking for input if you enter a non-positive number. In that case I would rewrite it as:
print("Welcome to the number program")
total_number = 0
entries = 0
while True:
number = input("Please give me a number \n")
number = int(number)
if number == -999:
break
if number <= 0:
print("Sorry, this value needs to be positive. Please enter a different number.")
continue
total_number = total_number + number
entries += 1
print(total_number)
print(total_number)
print(entries)
print(total_number / entries)
Also, you can increment numbers with entries += 1

In most cases you should NOT create variables first, however this case you should. Create number = 0, tally = 0 and total_number = 0 first
Accept your first number inside your while loop and handle all of the logic in there as well.
Your while loop should continue to loop until the final condition is met which seems to be number == -999
Should tally be incremented if you enter a negative number? I assume not. What about a 0? Wrap the increment for tally and the addition to total_number in an if number > -1: condition. Use an if else to check for number == -999, and an else for handling invalid entries.
Finally, move your print statements outside of your while loop. It also doesn't need a condition around it because now, if you've exited your while loop, that condition has been satisfied.
Final note here, and this is just a nice to know/have and purely syntactic sugar, MOST languages support abbreviated incrementing. Theres a better word for it, but the gist is simply this.
total_number += number
# is exactly the same as
total_number = total_number + number
# but way nicer to read and write :)
print("Welcome to the number program")
number = 0
total_number = 0
entries = 0
while number != -999:
number = input("Please enter a number! \n")
number = int(number)
if number >= 0
total_number += number
entries += 1
print("Current sum: " + total_number)
elif number == -999:
break
else
print("Sorry, this value needs to be positive.")
print("Sum of entries: "+str(total_number))
print("Number of entries: " + str(entries))
print("Average entry: " +str(total_number/entries))

I have rewritten your code. But I am not sure what the goal was. Anyways, if the value were ever to be under 0 the loop would have been exited and a new value would have never been accepted from an input.
Also some things I have written more elegant.
print("Welcome to the number program")
number=int(input("Please give me a number \n"))
total_number=0
entries=0
while number > 0:
total_number += number
print(total_number)
number = int(input("Please give me another number! \n"))
entries += 1
if number == -999:
print(total_number)
print(entries)
print(total_number/entries)
break
elif number < 0:
number = input("Sorry, this value needs to be positive. Please enter a different number!")

Number guessing game will not print the right phrase

I am extremely new to python and this is one of the first things I have tried. There are 3 criteria that I want this game to meet. First is to use the number 0-10 and guess the number 3 which it does correctly. Next is 0-25 when 11 is chosen. This also works correctly.
However this last part has been giving me trouble. When picking from 0-50, it should guess 1 which it does. It should also print the "I'm out of guesses" line when another input is placed as it cannot go higher than one now. What am I doing wrong here?
import random
import math
smaller = int(input("Enter the smaller number: "))
larger = int(input("Enter the larger number: "))
maxTry = math.log(larger - smaller)
count = 0
guess = int((smaller+larger)/2)
while count != maxTry:
count += 1
guess = int((smaller+larger)/2)
print("Your number is ", guess)
help = input("Enter =, <, or >: ")
if help == ">":
smaller = guess +1
elif help == "<":
larger = guess -1
elif help == "=":
print("Hooray, I've got it in", count, "tries")
break
elif count == maxTry:
print("I'm out of guesses, and you cheated")
break

Your maxTry is a log so it is not an integer, therefore it can never be equal to count.
You can either use an int for maxTry (cast it to int maxTry = int(math.log(larger - smaller))) or compute it with something different than log that will return an int.
Alternatively, your condition could be count > maxTry instead of equal. It would actually be a bit better conceptually.
Note: you should not use capital letters in variable names in python but all lowercase with _ max_try. It is only a convention though so won't affect your program directly. You can find more info on conventions in the PEP8 documentation

Python input control loop

Python beginner here. Practicing user input control.
Trying to make user input loop to the beginning if anything but a whole number between 1 and 10 is used. Been trying for hours, tried using Try and Except commands but couldn't do it correctly. What am i doing wrong? Thank you.
Edit:
Thank you very much for your help everyone, however the problem is still not solved (but very close!) I'm trying to figure out how to loop back to the beginning if anything BUT a whole number is typed. Agent Biscuit (above) gave a great answer for floating numbers, but any word or letter that is typed still produces an error. I´m trying to understand how to loop when anything random (except whole numbers between 1 and 10) is typed. None of the above examples produced corrcct results. Thank you for your help
while True:
print("Enter a number between 1 and 10")
number = int(input())
if (number > 0) and (number < 10):
print("Thank you, the end.")
break
else number != (> 0 and < 10):
print("It has to be a whole number between 1 and 10.")
print("Please try again:")

I have identified some problems.
First, the input statement you are using would just raise an error if a float value is entered, because the int at the start requires all elements of the input to be a number, and . is not a number.
Second; your else statement. else is just left as else:, and takes no arguments or parameters afterwards.
Now, how to check if the number is not whole? Try this:
while True:
print("Enter a number between 1 and 10")
number = float(input())
if (number > 0) and (number < 10) and (round(number)==number):
print("Thank you, the end.")
break
else:
print("It has to be a whole number between 1 and 10.")
print("Please try again:")
This accepts a float value, but only accepts it if it is equal to a whole number, hence the (round(number)==number).
Hope that answers your question.

First of all, you can't use a condition in a else statement. Also, you need to use or operator instead of and if one of the conditions is acceptable.
So, your code needs to be like this
while True:
print("Enter a number between 1 and 10")
number = int(input())
if (number > 0) and (number < 10):
print("Thank you, the end.")
break
elif number < 0 or number >10:
print("It has to be a whole number between 1 and 10.")
print("Please try again:")

Thanks to ack (above) for pointing me to a useful link. By studying another thread, I found the solution. It may not be perfect code, but it works 100%:
while True:
try:
print("Enter a number between 1 and 10")
number = float(input())
if (number > 0) and (number < 10) and (round(number)==number):
print("Thank you, the end.")
break
else:
print("\n")
print("It has to be a whole number between 1 and 10.")
print("Please try again:")
print("\n")
continue
except ValueError:
print("It has to be a whole number between 1 and 10.")
print("Please try again:")
print("\n")

creating a python program which ask the user for a number - even odd

I am new to python and I am taking a summer online class to learn python.
Unfortunately, our professor doesn't really do much. We had an assignment that wanted us to make a program (python) which asks the user for a number and it determines whether that number is even or odd. The program needs to keep asking the user for the input until the user hit zero. Well, I actually turned in a code that doesn't work and I got a 100% on my assignment. Needless to say our professor is lazy and really doesn't help much. For my own knowledge I want to know the correct way to do this!!! Here is what I have/had. I am so embarrassed because I know if probably very easy!
counter = 1
num = 1
while num != 0:
counter = counter + 1
num=int(input("Enter number:"))
while num % 2 == 0:
print ("Even", num)
else:
print ("Odd", num)

There are a couple of problems with your code:
You never use counter, even though you defined it.
You have an unnecessary nested while loop. If the number the user inputs is even, then you're code will continue to run the while loop forever.
You are incorrectly using the else clause that is available with while loops. See this post for more details.
Here is the corrected code:
while True:
# Get a number from the user.
number = int(input('enter a number: '))
# If the number is zero, then break from the while loop
# so the program can end.
if number == 0:
break
# Test if the number given is even. If so, let the
# user know the number was even.
if number % 2 == 0:
print('The number', number, 'is even')
# Otherwise, we know the number is odd. Let the user know this.
else:
print('The number', number, 'is odd')
Note that I opted above to use an infinite loop, test if the user input is zero inside of the loop, and then break, rather than testing for this condition in the loop head. In my opinion this is cleaner, but both are functionally equivalent.

You already have the part that continues until the user quits with a 0 entry. Inside that loop, all you need is a simple if:
while num != 0:
num=int(input("Enter number:"))
if num % 2 == 0:
print ("Even", num)
else:
print ("Odd", num)
I left out the counter increment; I'm not sure why that's in the program, since you never use it.

Use input() and If its only number specific input you can use int(input()) or use an If/else statement to check

Your code wasn't indented and you need to use if condition with else and not while
counter = 1
num = 1
while num != 0:
counter = counter + 1
num = int(input("Enter number:"))
if num % 2 == 0:
print ("Even", num)
else:
print ("Odd", num)
Sample Run
Enter number:1
Odd 1
Enter number:2
Even 2
Enter number:3
Odd 3
Enter number:4
Even 4
Enter number:5
Odd 5
Enter number:6
Even 6
Enter number:0
Even 0

Being told I have an infinite loop, but I'm unsure how to fix it. (Python Coding Course)

I'm currently in a python coding class and this is an assignment. I apparently have an infinite loop somewhere in my code, yet I can't seem to find it.
num = int(input("Enter a number: "))
factorial = 1
# check if the number is negative, positive or zero
if num < 0:
print("Sorry, factorial does not exist for negative numbers")
elif num == 0:
print("The factorial of 0 is 1")
else:
for i in range(1,num + 1):
factorial = factorial*i
print("The factorial of",num,"is",factorial)
# At this point the program should take your now factorial and give you the fibonacci sequence
# takes your factorial and makes it the fibonacci
nterms = factorial
# first two terms
n1 = 0
n2 = 1
count = 2
# check if the number of terms is valid
if nterms <= 0:
print("Plese enter a positive integer")
elif nterms == 1:
print("Fibonacci sequence:")
print(n1)
else:
print("Fibonacci sequence:")
print(n1,",",n2,end=', ')
while count < nterms:
nth = n1 + n2
print(nth,end=' , ')
# update values
n1 = n2
n2 = nth
count += 1
I've used both the debugging tool and attempted to find the problem myself by running the programming and attempting various break sequences but I'm just not grasping it.

There is no infinite loop in your code, both loops will finish in finite time. What is happening is that your teacher, without looking at your code, has discovered that the finite time is very, very long and mistaken this for an infinite loop.
The reason it's taking so long is that you have misunderstood the question - "I was asked to make a program that took an integer and gave me said factorial of an integer. Then give the Fibonacci sequence of the integer" - means find the factorial and Fibonacci sequence of the same integer rather than feeding the first result into the second. Simply replace the line nterms = factorial with the line nterms = num to fix the problem.
(See comments on question for additional information used in this answer)

First, you already know what a loop is and how it works. You should review the loop in your code and make sure any variable used is defined. Since this is an assignment, this is the best I can do for you, to be honest your problem is already solved.
Maybe try enclosing your code in a function with arguments/input-variables, this way your code might run smoother and better. Hope this helps.