Error in this python code [closed] - python

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while True:
print ("Options")
print ("Write 'Quit' if you want to exit")
print ("Write '+'if you want to make an addition")
print ("Write '-' if you want to make a sottration")
print ("Write '*' if you want to make a moltiplication")
print ("Write '/' if you wantto make a division")
user_input == input(":")
if user_input == ("+")
num1 = float(input("Enter a number...")
num2 = float(input("Enter the second number...")
result = str(num1+num2)
print("The result is"+ result)
elif user_input == ("-")
num1 = float(input("Enter a number...")
num2 = float(input("Enter the second number...")
result = str(num1-num2)
print("The result is"+ result)
elif user_input == ("*")
num1 = float(input("Enter a number...")
num2 = float(input("Enter the second number...")
result = str(num1*num2)
print("The result is"+ result)
elif user_input == ("/")
num1 = float(input("Enter a number...")
num2 = float(input("Enter the second number...")
print ("The result is"+ result)
This is the code I have created in python 2.7, but it does not work. I think there's an indentation error. Can you help me?

Fix your indentation and add a colon after each if-statement as the following and change user_input == input(':') to user_input = input(':'):
while True:
print ("Options")
print ("Write 'Quit' if you want to exit")
print ("Write '+'if you want to make an addition")
print ("Write '-' if you want to make a sottration")
print ("Write '*' if you want to make a moltiplication")
print ("Write '/' if you wantto make a division")
user_input = input(":") # fix this line
if user_input == ("+"):
num1 = float(input("Enter a number..."))
num2 = float(input("Enter the second number..."))
result = str(num1+num2)
print("The result is"+ result)
elif user_input == ("-"):
num1 = float(input("Enter a number..."))
num2 = float(input("Enter the second number..."))
result = str(num1-num2)
print("The result is"+ result)
elif user_input == ("*"):
num1 = float(input("Enter a number..."))
num2 = float(input("Enter the second number..."))
result = str(num1*num2)
print("The result is"+ result)
elif user_input == ("/"):
num1 = float(input("Enter a number..."))
num2 = float(input("Enter the second number..."))
result = str(num1/num2)
print ("The result is"+ result)
EDIT:
Below is a better version of your code that fixes few errors, like reading string input, avoid dividing by zero exception and removing float() type casting because in python 2.7 input() already does that for you.
while True:
print("Options")
print("Write 'Quit' if you want to exit")
print("Write '+'if you want to make an addition")
print("Write '-' if you want to make a sottration")
print("Write '*' if you want to make a moltiplication")
print("Write '/' if you wantto make a division")
user_input = raw_input(":")
if user_input == '+':
num1 = input("Enter a number...")
num2 = input("Enter the second number...")
print('The result is {}'.format(num1+num2))
elif user_input == '-':
num1 = input("Enter a number...")
num2 = input("Enter the second number...")
print('The result is {}'.format(num1-num2))
elif user_input == '*':
num1 = input("Enter a number...")
num2 = input("Enter the second number...")
print('The result is {}'.format(num1*num2))
elif user_input == '/':
num1 = input("Enter a number...")
num2 = input("Enter the second number...")
if num2 == 0:
print("Can't divide by zero.")
else:
print("The result is {}".format(num1/num2))
Also as suggested by other users here is an improved version:
while True:
print("Options")
print("Write 'Quit' if you want to exit")
print("Write '+'if you want to make an addition")
print("Write '-' if you want to make a sottration")
print("Write '*' if you want to make a moltiplication")
print("Write '/' if you wantto make a division")
user_input = raw_input(":")
num1 = input("Enter a number...")
num2 = input("Enter the second number...")
if user_input == "+":
result = str(num1+num2)
elif user_input == "-":
result = str(num1-num2)
elif user_input == "*":
result = str(num1*num2)
elif user_input == "/":
if num2 == 0:
result = "Can't divide by zero"
else:
result = str(num1/num2)
print("The result is", result)

Related

Restart Python script at specific point

Ok so I am very new to Python and I recently took on the challenge of creating a very simple calculator.
It works completely fine but I want to add a option to restart and go back to the main menu area rather than restarting the program entirely. How could this be done?
here is the code that i have so far
from math import sqrt
import time
print("Welcome to Calculator")
print(" #1 Add \n #2 Subtract \n #3 Multiply \n #4 Divide \n #5 Square Root")
option = input("Select one #: ")
if option == "1":
print("Addition:")
num1 = input("Enter first Number: ")
num2 = input("Enter Second Number: ")
result = float(num1) + float(num2)
print("The answer is: ", result)
elif option == "2":
print("Subtraction:")
num1 = input("Enter first Number: ")
num2 = input("Enter Second Number: ")
result = float(num1) - float(num2)
print("The answer is: ", result)
elif option == "3":
print("Multiplication:")
num1 = input("Enter first Number: ")
num2 = input("Enter Second Number: ")
result = float(num1) * float(num2)
print("The answer is: ", result)
elif option == "4":
print("Division:")
num1 = input("Enter first Number: ")
num2 = input("Enter Second Number: ")
result = float(num1) / float(num2)
print("The answer is: ", result)
elif option == "5":
print("Square Root:")
num1 = input("Enter Number: ")
result = sqrt(float(num1))
print("The answer is: ", result)
I tried the adding While True to the program but I was not able to figure out how that works.
Wrapping your whole code in a while True loop would work but you need to write an if statement at the end in order to exit the infinite loop. Here's the working code:
from math import sqrt
import time
while True:
print("Welcome to Calculator")
print(" #1 Add \n #2 Subtract \n #3 Multiply \n #4 Divide \n #5 Square Root")
option = input("Select one #: ")
if option == "1":
print("Addition:")
num1 = input("Enter first Number: ")
num2 = input("Enter Second Number: ")
result = float(num1) + float(num2)
print("The answer is: ", result)
elif option == "2":
print("Subtraction:")
num1 = input("Enter first Number: ")
num2 = input("Enter Second Number: ")
result = float(num1) - float(num2)
print("The answer is: ", result)
elif option == "3":
print("Multiplication:")
num1 = input("Enter first Number: ")
num2 = input("Enter Second Number: ")
result = float(num1) * float(num2)
print("The answer is: ", result)
elif option == "4":
print("Division:")
num1 = input("Enter first Number: ")
num2 = input("Enter Second Number: ")
result = float(num1) / float(num2)
print("The answer is: ", result)
elif option == "5":
print("Square Root:")
num1 = input("Enter Number: ")
result = sqrt(float(num1))
print("The answer is: ", result)
restart = input("Do you want to restart the program? (yes/no) ")
if restart.lower() != "yes":
break
You can add while loop like this:
while True:
option = input("Select one #: ")
if option == "1":
print("Addition:")
...
elif option == "5":
print("Square Root:")
num1 = input("Enter Number: ")
result = sqrt(float(num1))
print("The answer is: ", result)

how to make a calculator with a loop until I choose to break

I'm trying to build a calculator with a loop until I choose to break it or end it.
Can you please suggest?
Thank you in advance,
Max
new_operation = input("press enter to make a new operation or type the word exit to finish")
num1 = int(input("Enter a number: "))
op = input("Enter the operator: ")
num2 = int(input("Enter a second number: "))
while new_operation != ("no"):
if op == ("+"):
print (num1 + num2)
elif op == ("-"):
print (num1 - num2)
elif op == ("*"):
print (num1 * num2)
elif op == ("/"):\
print (num1 / num2)
else:
print ("Invalid operation")
new_operation = input("make a new operation")
Your code looks good, but need some tweak to make it "do while" loop kind of implementation.
while True:
num1 = int(input("Enter a number: "))
op = input("Enter the operator: ")
num2 = int(input("Enter a second number: "))
if op == ("+"):
print (num1 + num2)
elif op == ("-"):
print (num1 - num2)
elif op == ("*"):
print (num1 * num2)
elif op == ("/"):\
print (num1 / num2)
else:
print ("Invalid operation")
new_operation = input("press enter to make a new operation or type the word exit to finish")
if(new_operation == ("no")):
break
Some suggestions:
Check your indentation, as commented above. Python is sensitive to that.
Make sure your inputs and outputs are more consistent and useful. Your prompt says I should type exit, but your code requires them to type no...
Your looping structure is a bit broken. This is to be expected for somebody new to coding. One of my favorites for this case is:
print('Welcome to the calculator!')
do_run = True
while do_run:
...
do_run = input('Would you like to continue [y/n]: ')[0].lower() == 'y'

EOFError: EOF when reading a line in a calculator script

I'm trying to program a simple Python calculator but always when I run the code the Atom editor has a problem with reading this line:
while True:
user_input = input(":")
Under this line of code I entered the methods for Python and told it what it should do:
if userinput == "quit":
break
elif userinput == "add":
num1 = float(input("Enter a number"))
num2 = float(input("Enter another number"))
result = str(num1 + num2)
print("The answer is:" + result)
So now when I run this code the Atom editor says that it has a problem with reading this code and it won't ask me for an input as it should.
I think I didn't miss out any code.
This is most likely either mixed tabs and spaces or a missing parenthesis somewhere in your code. also the code has a few mistakes including indentation errors:
while True:
user_input = input(":")
if user_input == "quit":
break
elif user_input == "add":
num1 = float(input("Enter a number"))
num2 = float(input("Enter another number"))
result = str(num1 + num2)
print("The answer is:", result)

My program not showing question or taking inputs in Python

I made this simple Python Maths Quiz Program for some reason sometimes when it is supposed to ask a question it doesn't display the question or allow any input and just says it is incorrect. The problem doesn't happen every time I run the program just sometimes.
import random
def RandomNum():
import random
ran= random.randint(1,10)
return (ran)
def RanOperation():
import random
operation = ['+','-','x']
RanOp = random.choice(operation)
return (RanOp)
stop = False
while stop == False:
Name= input("Hello, what is your name?").title()
print("Hello,", Name, "Welcome to ARITHMETIC QUIZ")
score=0
for i in range(1, 11):
print(str(i)+".")
num1 = RandomNum()
num2 = RandomNum()
operation = RanOperation()
if operation == "+":
ans = num1+num2
elif operation == "-":
if num1 > num2:
ans = num1-num2
elif num2>num1:
ans = num2-num1
elif operation == "x":
ans = num1*num2
if num1 > num2:
num1 = str(num1)
num2 = str(num2)
Answer = int(input((num1+operation+num2+"=")))
elif num2 > num1:
num1 = str(num1)
num2 = str(num2)
Answer = int(input((num2+operation+num1+"=")))
if Answer == ans:
print("Correct!")
score += 1
elif Answer != ans:
print("The correct answer is", ans)
print("Sorry this is incorrect!")
length = int(len(Name))
print("You got", score, "correct out of 10,", Name)
File1 = open('Class_Scores.txt','a')
File1.write("\n %-20s %10d" %(Name , score))
File1.close()
Ask = input("Do you want to continue? Y/N").upper()
if Ask == "N":
stop = True
elif Ask == "Y":
stop = False
Your input() line only runs in two situations:
if num1 > num2:
and
elif num2 > num1:
What happens when num1 and num2 are the same? You won't enter the if block, because num1 > num2 is False; And you won't enter the elif block, because num2 > num1 is also False.
That means the input() won't run at all;
Your code's problem is that you do not always call the input:
if num1 > num2:
num1 = str(num1)
num2 = str(num2)
Answer = int(input((num1+operation+num2+"=")))
elif num2 > num1:
num1 = str(num1)
num2 = str(num2)
Answer = int(input((num2+operation+num1+"=")))
if num1 == num no input is done and the one from before is used (again).
You can solve it by changing one of them to >= or use an additional else: ....
You can shorten/improve your code a lot if you
do not import random multiple times
use a dictionary to decide which function to call (reduces if .. elif .. else
use input validation to avoid crashing on bad input
use string.format() or even better f-strings instead of python 2.7 % formatting
use with open(...) for file operations
structure the code with some more functions
import random
def RanOperation():
return random.choice(['+','-','x'])
def plus():
# get both numbers with one random call
a,b = random.choices(range(1,11),k=2)
return (a,b,a+b)
def minus():
# only operation where a > b matters to not get negative results
# sorting (low to high) and choosing b,a ensures a is at least b or more
# the other operations are cummutative so its better to leave then unsorted
# to train 8x4 as as well as 4x8
b,a = sorted(random.choices(range(1,11),k=2) ) # a > b
return (a,b,a-b)
def mult():
a,b = random.choices(range(1,11),k=2)
return (a,b,a*b)
def get_answer(a,operation,b):
while True:
try:
k = int(input( "{} {} {} = ".format(a,operation,b)))
return k
except Exception:
print("Input a valid number.")
Usage:
# call which function for what ops?
# using mapper["+"]() --> calls the plus() function - this reduces if/else's
mapper = {"-": minus, "+":plus, "x":mult}
while True:
Name= input("Hello, what is your name?").title()
print("Hello,", Name, "Welcome to ARITHMETIC QUIZ")
score=0
for i in range(10):
print(str(i+1)+".")
operation = RanOperation()
a,b,ans = mapper[operation]()
answer = get_answer(a,operation,b)
if answer == ans:
print("Correct!")
score += 1
else:
print("The correct answer is {:>10d}".format(ans))
print("Sorry this is incorrect!")
length = int(len(Name))
print("You got", score, "correct out of 10,", Name)
with open('Class_Scores.txt','a') as File1:
File1.write("\n -{:20s} {:10d}".format(Name , score))
Ask = input("Do you want to continue? Y/N").upper()
if Ask == "N":
break
Output:
Hello, what is your name?Enya
Hello, Enya Welcome to ARITHMETIC QUIZ
1.
10 - 5 = 5
Correct!
2.
8 - 6 = 9
The correct answer is 2
Sorry this is incorrect!
3.
10 - 2 = 8
Correct!
# ...snipp 4-9...
10.
4 - 4 = 0
Correct!
You got 9 correct out of 10, Enya
Do you want to continue? Y/Nn

Simpel Python Calculator - Syntax Error - Indentation errors

I recently started learning Python. I have never coded before, but it seemed like a challenge. The first thing I have made is this calculator. However, I can't seem to get it to work.
while True:
print("Typ 'plus' to add two numbers")
print("Typ 'min' to subtract two numbers")
print("Typ 'multiplication' multiply two numbers")
print("Typ 'division' to divide two numbers")
print("Typ 'end' to abort the program")
user_input = input(": ")
if user_input == "end"
break
elif user_input == "plus":
num1 = float(input("Give a number: "))
num2 = float(input("Give another number: "))
result = str(num1 + num2)
print("The anwser is: " + str(result))
elif user_input == "min":
num1 = float(input("Give a number: "))
num2 = float(input("Give another number: "))
result = str(num1 - num2)
print("The anwser is: " + str(result))
elif user_input == "maal":
num1 = float(input("Give a number:"))
num2 = float(input("Give another number: "))
result = str(num1 * num2)
print("The anwser is: " + str(result))
elif user_input == "deel":
num1 = float(input("Give a number: "))
num2 = float(input("Give another number: "))
result = str(num1 + num2)
print("The anwser is: " + str(result))
else:
print ("I don't understand!")
I know it will probably something stupid, I am still very much learning. Just trying to pickup a new skill instead of bothering my friends who do know how to code.
You missed a colon after an this if statement
if user_input == "end"
break
Should Be:
if user_input == "end":
break

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