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Webscraping Live data

I am currently trying to scrape live stock market data from the yahoo finance page.
I am using bs4. My current issue is that whenever I run my script, it does not update properly to reflect the current price of the stock.
If anybody has any advice on how to change that it would be appreciated.
import requests
from bs4 import BeautifulSoup
while True:
page = requests.get("https://nz.finance.yahoo.com/quote/NZDUSD=X?p=NZDUSD=X")
soup = BeautifulSoup(page.text, "html.parser")
price = soup.find("div", {"class": "My(6px) Pos(r) smartphone_Mt(6px)"}).find("span").text
print(price)

NOT POSSIBLE WITH BS4 ALONE
This website particularly uses JavaScript to update the page and urlib etc. just parses the html content of the page not Java Script or AJAX content.
PhantomJs or Selenium Web Browser provide a more mechanized browser that often can run the JavaScript codes enabling dynamic websites. Try Using this :)
Using Selenium It can be done as:
from selenium import webdriver #its the library
import time
from selenium.webdriver.common.keys import Keys
from bs4 import BeautifulSoup as soup
#it Says that we are going to Use chrome browser
chrome_options = webdriver.ChromeOptions()
#hiding the Chrome Browser
chrome_options.add_argument("--headless")
#Initiating Chrome with all properties we need (in this case we use no specific properties
driver = webdriver.Chrome(chrome_options=chrome_options,executable_path='C:/Users/shary/Downloads/chromedriver.exe')
#URL We need to open
url = 'https://nz.finance.yahoo.com/quote/NZDUSD=X?p=NZDUSD=X'
#Starting Our Browser
driver = webdriver.Chrome()
#Accessing the url .. this will open the page just as you open in Chrome etc.
driver.get(url)
while 1:
#it will get you the html content repeatedly .. So you can get the changing price
html = driver.page_source
page_soup = soup(html,features="lxml")
price = page_soup.find("div", {"class": "D(ib) Mend(20px)"}).text
print(price)
time.sleep(5)
Note the Best Comments But Hope this you will understand it :) Else Watch a youtube tutorial to get proper idea what a Selenium Bot does
Hope This will Help. Its working perfect for me :) Accept This Answer if it helps you

Can't get all titles from a list with Python WebScraping

I'm practicing web scraping with Python atm and I found a problem, I wanted to scrape one website that has a list of anime that I watched before but when I try to scrape it (via requests or selenium) it only gets around 30 of 110 anime names from the page.
Here is my code with selenium:
from selenium import webdriver
from bs4 import BeautifulSoup
browser = webdriver.Firefox()
browser.get("https://anilist.co/user/Agusmaris/animelist/Completed")
data = BeautifulSoup(browser.page_source, 'lxml')
for title in data.find_all(class_="title"):
print(title.getText())
And when I run it, the page source only shows up until an anime called 'Golden time' when there are like 70 or more left that are in the page.
Thanks
Edit: Code that works now thanks to 'supputuri':
from selenium import webdriver
from bs4 import BeautifulSoup
import time
driver = webdriver.Firefox()
driver.get("https://anilist.co/user/Agusmaris/animelist/Completed")
time.sleep(3)
footer = driver.find_element_by_css_selector("div.footer")
preY = 0
print(str(footer))
while footer.rect['y'] != preY:
preY = footer.rect['y']
footer.location_once_scrolled_into_view
print('loading')
html = driver.page_source
soup = BeautifulSoup(html, 'lxml')
for title in soup.find_all(class_="title"):
print(title.getText())
driver.close()
driver.quit()
ret = input()

Here is the solution.
Make sure to add import time
driver.get("https://anilist.co/user/Agusmaris/animelist/Completed")
time.sleep(3)
footer =driver.find_element_by_css_selector("div.footer")
preY =0
while footer.rect['y']!=preY:
preY = footer.rect['y']
footer.location_once_scrolled_into_view
time.sleep(1)
print(str(driver.page_source))
This will iterate until all the anime is loaded and then gets the page source.
Let us know if this was helpful.

So, this is the jist of what I get when I load the page source:
AniListwindow.al_token = 'E1lPa1kzYco5hbdwT3GAMg3OG0rj47Gy5kF0PUmH';Sorry, AniList requires Javascript.Please enable Javascript or http://outdatedbrowser.com>upgrade to a modern web browser.Sorry, AniList requires a modern browser.Please http://outdatedbrowser.com>upgrade to a newer web browser.
Since I know damn well that Javascript is enabled and my Chrome version is fully up to date, and the URL listed takes one to a nonsecure website to "download" a new version of your browser, I think this is a spam site. Not sure if you were aware of that when posting so I won't flag as such, but I wanted you and others who come across this to be aware.

Web scraping when scrolling down is needed

I want to scrape, e.g., the title of the first 200 questions under the web page https://www.quora.com/topic/Stack-Overflow-4/all_questions. And I tried the following code:
import requests
from bs4 import BeautifulSoup
url = "https://www.quora.com/topic/Stack-Overflow-4/all_questions"
print("url")
print(url)
r = requests.get(url) # HTTP request
print("r")
print(r)
html_doc = r.text # Extracts the html
print("html_doc")
print(html_doc)
soup = BeautifulSoup(html_doc, 'lxml') # Create a BeautifulSoup object
print("soup")
print(soup)
It gave me a text https://pastebin.com/9dSPzAyX. If we search href='/, we can see that the html does contain title of some questions. However, the problem is that the number is not enough; actually on the web page, a user needs to manually scroll down to trigger extra load.
Does anyone know how I could mimic "scrolling down" by the program to load more content of the page?

Infinite scrolls on a webpage is based on the Javascript functionality. Therefore, to find out what URL we need to access and what parameters to use, we need to either thoroughly study the JS code working inside the page or, and preferably, examine the requests that the browser does when you scroll down the page. We can study requests using the Developer Tools.
See example for quora
the more you scroll down, the more requests generated. so now your requests will be done to that url instead of normal url but keep in mind to send correct headers and playload.
other easier solution will be by using selenium

Couldn't find a response using request. But you can use Selenium. First printed out the number of questions at first load, then send the End key to mimic scrolling down. You can see number of questions went from 20 to 40 after sending the End key.
I used driver.implicitly wait for 5 seconds before loading the DOM again in case the script load to fast before the DOM was loaded. You can improve by using EC with selenium.
The page loads 20 questions per scroll. So if you are looking to scrape 100 questions, then you need to send the End key 5 times.
To use the code below you need to install chromedriver.
http://chromedriver.chromium.org/downloads
from selenium import webdriver
from selenium.webdriver.chrome.options import Options
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
CHROMEDRIVER_PATH = ""
CHROME_PATH = ""
WINDOW_SIZE = "1920,1080"
chrome_options = Options()
# chrome_options.add_argument("--headless")
chrome_options.add_argument("--window-size=%s" % WINDOW_SIZE)
chrome_options.binary_location = CHROME_PATH
prefs = {'profile.managed_default_content_settings.images':2}
chrome_options.add_experimental_option("prefs", prefs)
url = "https://www.quora.com/topic/Stack-Overflow-4/all_questions"
def scrape(url, times):
if not url.startswith('http'):
raise Exception('URLs need to start with "http"')
driver = webdriver.Chrome(
executable_path=CHROMEDRIVER_PATH,
chrome_options=chrome_options
)
driver.get(url)
counter = 1
while counter <= times:
q_list = driver.find_element_by_class_name('TopicAllQuestionsList')
questions = [x for x in q_list.find_elements_by_xpath('//div[#class="pagedlist_item"]')]
q_len = len(questions)
print(q_len)
html = driver.find_element_by_tag_name('html')
html.send_keys(Keys.END)
wait = WebDriverWait(driver, 5)
time.sleep(5)
questions2 = [x for x in q_list.find_elements_by_xpath('//div[#class="pagedlist_item"]')]
print(len(questions2))
counter += 1
driver.close()
if __name__ == '__main__':
scrape(url, 5)

I recommend using selenium rather than bs.
selenium can control browser and parsing. like scroll down, click button, etc…
this example is for scroll down for get all liker user in instagram.
https://stackoverflow.com/a/54882356/5611675

If the content only loads on "scrolling down", this probably means that the page is using Javascript to dynamically load the content.
You can try using a web client such as PhantomJS to load the page and execute the javascript in it, and simulate the scroll by injecting some JS such as document.body.scrollTop = sY; (Simulate scroll event using Javascript).

scrape website traffic from semrush using beautiful soup python

I'm trying to scrape website traffic from semrush.com.
my current code using BeautifulSoup is:
from bs4 import BeautifulSoup, BeautifulStoneSoup
import urllib
import json
req = urllib.request.Request('https://www.semrush.com/info/burton.com', headers={'User-Agent':'Magic Browser'})
response = urllib.request.urlopen(req)
raw_data = response.read()
response.close()
soup = BeautifulSoup(raw_data)
I've been trying data = soup.findAll("a", {"href":"/info/burton.com+(by+organic)"}) or data = soup.findAll("span", {"class":"sem-report-counter"}) without much luck.
I can see the numbers on the webpage that I would like to get. Is there a way to pull this information off? I'm not seeing it in the html I pull.

I went the extra mile and set up a working example of how you can use selenium to scrape that page. Install selenium and try it out!
from selenium import webdriver
from selenium.webdriver.chrome.options import Options
url = 'https://www.semrush.com/info/burton.com' #your url
options = Options() #set up options
options.add_argument('--headless') #add --headless mode to options
driver = webdriver.Chrome(executable_path='/opt/ChromeDriver/chromedriver',
chrome_options=options)
#note: executable_path will depend on where your chromedriver.exe is located
driver.get(url) #get response
driver.implicitly_wait(1) #wait to load content
elements = driver.find_elements_by_xpath(xpath='//a[#href="/info/burton.com+(by+organic)"]') #grab that stuff you wanted?
for e in elements: print(e.get_attribute('text').strip()) #print text fields
driver.quit() #close the driver when you're done
Output that I see in my terminal:
356K
6.5K
59.3K
$usd305K
Organic keywords
Organic
Top Organic Keywords
View full report
Organic Position Distribution

Open a page programmatically in python

Can you extract the VIN number from this webpage?
I tried urllib2.build_opener, requests, and mechanize. I provided user-agent as well, but none of them could see the VIN.
opener = urllib2.build_opener()
opener.addheaders = [('User-agent',('Mozilla/5.0 (Macintosh; Intel Mac OS X 10_6_7) ' 'AppleWebKit/535.1 (KHTML, like Gecko) ' 'Chrome/13.0.782.13 Safari/535.1'))]
page = opener.open(link)
soup = BeautifulSoup(page)
table = soup.find('dd', attrs = {'class': 'tip_vehicleStats'})
vin = table.contents[0]
print vin

That page has much of the information loaded and displayed with Javascript (probably through Ajax calls), most likely as a direct protection against scraping. To scrape this you therefore either need to use a browser that runs Javascript, and control it remotely, or write the scraper itself in javascript, or you need to deconstruct the site and figure out exactly what it loads with Javascript and how, and see if you can duplicate these calls.

You can use browser automation tools for the purpose.
For example this simple selenium script can do your work.
from selenium import webdriver
from bs4 import BeautifulSoup
link = "https://www.iaai.com/Vehicles/VehicleDetails.aspx?auctionID=14712591&itemID=15775059&RowNumber=0"
browser = webdriver.Firefox()
browser.get(link)
page = browser.page_source
soup = BeautifulSoup(page)
table = soup.find('dd', attrs = {'class': 'tip_vehicleStats'})
vin = table.contents.span.contents[0]
print vin
BTW, table.contents[0] prints the entire span, including the span tags.
table.contents.span.contents[0] prints only the VIN no.

You could use selenium, which calls a browser. This works for me :
from selenium import webdriver
from selenium.common.exceptions import NoSuchElementException
from selenium.webdriver.common.keys import Keys
import time
# See: http://stackoverflow.com/questions/20242794/open-a-page-programatically-in-python
browser = webdriver.Firefox() # Get local session of firefox
browser.get("https://www.iaai.com/Vehicles/VehicleDetails.aspx?auctionID=14712591&itemID=15775059&RowNumber=0") # Load page
time.sleep(0.5) # Let the page load
# Search for a tag "span" with an attribute "id" which contains "ctl00_ContentPlaceHolder1_VINc_VINLabel"
e=browser.find_element_by_xpath("//span[contains(#id,'ctl00_ContentPlaceHolder1_VINc_VINLabel')]")
e.text
# Works for me : u'4JGBF7BE9BA648275'
browser.close()

You do not have to use Selenium.
Just make an additional get request:
import requests
stock_number = '123456789' # located at VEHICLE INFORMATION
url = 'https://www.clearvin.com/ads/iaai/check?stockNumber={}&vin='.format(stock_number)
vin = requests.get(url).json()['car']['vin']