How Can I Suppress Warnings in Python Module CppHeaderParser - python

How Do I Change the Value of a Variable or Function in a Foreign Module?
I have a C++ header file that I need to parse. I'm using CppHeaderParser. Sadly, the header generates a lot of warnings that I'd like to suppress. The header in question is maintained by someone else, so I can't just fix it and be done.
CppHeaderParser doesn't include a configurable way to suppress warnings, but it is controlled by a variable and a function in the module
# Controls warning_print
print_warnings = 1
...
def warning_print(arg):
if print_warnings: print(("[%4d] %s"%(inspect.currentframe().f_back.f_lineno, arg)))
In my script, I tried changing the value of print_warnings:
import CppHeaderParser
CppHeaderParser.print_warnings = 0
cpp_info = CppHeaderParser.CppHeader(my_h_file)
But this had no effect.
How do I set a variable in a different module such that a class defined in that module will see it?
In my case, I might also like to redefine warning_print to examine the warnings and skip only the specific warnings I wish to ignore. I encountered the same problem as setting print_warnings. The assignment "worked" but had no effect, as if the code in CppHeaderParser wasn't looking at the values I set.
Note: I have worked around the problem by making a temp copy of the header file, correcting the problems, but I consider this a fragile solution.
Update: I was able to completely and unintelligently suppress all the warnings with:
CppHeaderParser.CppHeaderParser.print_warnings = 0

I've looked the source. The problem with your method is that in CppHeaderParser file there are import with *:
from .CppHeaderParser import *
So you need to change the way you import CppHeaderParser class:
from CppHeaderParser import CppHeaderParser
It should work.
Finally, just try this:
from CppHeaderParser import CppHeaderParser
CppHeaderParser.print_warnings = 0
cpp_info = CppHeaderParser.CppHeader(my_h_file)
The reason of such a behaviour is that from statement creates the copy of variable from imported module but not an alias. I will try to explain it on a simple example. Let's suppose we have some module named import_test with the following contents:
foo = "Init value"
def f():
print(foo)
Then execute the following code:
>> from import_test import *
>> f()
Init value
>> foo = "Updated value"
>> f()
Init value
The reason is that you change the copy of variable foo so the actual value of import_test.foo variable is not changed.
But we have a different behaviour when we import the module itself:
>> import import_test
>> import_test.f()
Init value
>> import_test.foo = "Updated value"
>> import_test.f()
Updated value
So in the case of CppHeaderParser package when you make import CppHeaderParser the code inside CppHeaderParser.__init__ is executed. And python interpreter creates a copy of warnings_print variable inside a CppHeaderParser. But to change the behaviour of a print_warning function you have to change the value of CppHeaderParser.CppHeaderParser.warnings_print.

Try monkey patching:
import CppHeaderParser
def my_silent_warning_print(arg):
pass
CppHeaderParser.warning_print = my_silent_warning_print

Related

accessing and changing module level variable [duplicate]

I've run into a bit of a wall importing modules in a Python script. I'll do my best to describe the error, why I run into it, and why I'm tying this particular approach to solve my problem (which I will describe in a second):
Let's suppose I have a module in which I've defined some utility functions/classes, which refer to entities defined in the namespace into which this auxiliary module will be imported (let "a" be such an entity):
module1:
def f():
print a
And then I have the main program, where "a" is defined, into which I want to import those utilities:
import module1
a=3
module1.f()
Executing the program will trigger the following error:
Traceback (most recent call last):
File "Z:\Python\main.py", line 10, in <module>
module1.f()
File "Z:\Python\module1.py", line 3, in f
print a
NameError: global name 'a' is not defined
Similar questions have been asked in the past (two days ago, d'uh) and several solutions have been suggested, however I don't really think these fit my requirements. Here's my particular context:
I'm trying to make a Python program which connects to a MySQL database server and displays/modifies data with a GUI. For cleanliness sake, I've defined the bunch of auxiliary/utility MySQL-related functions in a separate file. However they all have a common variable, which I had originally defined inside the utilities module, and which is the cursor object from MySQLdb module.
I later realised that the cursor object (which is used to communicate with the db server) should be defined in the main module, so that both the main module and anything that is imported into it can access that object.
End result would be something like this:
utilities_module.py:
def utility_1(args):
code which references a variable named "cur"
def utility_n(args):
etcetera
And my main module:
program.py:
import MySQLdb, Tkinter
db=MySQLdb.connect(#blahblah) ; cur=db.cursor() #cur is defined!
from utilities_module import *
And then, as soon as I try to call any of the utilities functions, it triggers the aforementioned "global name not defined" error.
A particular suggestion was to have a "from program import cur" statement in the utilities file, such as this:
utilities_module.py:
from program import cur
#rest of function definitions
program.py:
import Tkinter, MySQLdb
db=MySQLdb.connect(#blahblah) ; cur=db.cursor() #cur is defined!
from utilities_module import *
But that's cyclic import or something like that and, bottom line, it crashes too. So my question is:
How in hell can I make the "cur" object, defined in the main module, visible to those auxiliary functions which are imported into it?
Thanks for your time and my deepest apologies if the solution has been posted elsewhere. I just can't find the answer myself and I've got no more tricks in my book.
Globals in Python are global to a module, not across all modules. (Many people are confused by this, because in, say, C, a global is the same across all implementation files unless you explicitly make it static.)
There are different ways to solve this, depending on your actual use case.
Before even going down this path, ask yourself whether this really needs to be global. Maybe you really want a class, with f as an instance method, rather than just a free function? Then you could do something like this:
import module1
thingy1 = module1.Thingy(a=3)
thingy1.f()
If you really do want a global, but it's just there to be used by module1, set it in that module.
import module1
module1.a=3
module1.f()
On the other hand, if a is shared by a whole lot of modules, put it somewhere else, and have everyone import it:
import shared_stuff
import module1
shared_stuff.a = 3
module1.f()
… and, in module1.py:
import shared_stuff
def f():
print shared_stuff.a
Don't use a from import unless the variable is intended to be a constant. from shared_stuff import a would create a new a variable initialized to whatever shared_stuff.a referred to at the time of the import, and this new a variable would not be affected by assignments to shared_stuff.a.
Or, in the rare case that you really do need it to be truly global everywhere, like a builtin, add it to the builtin module. The exact details differ between Python 2.x and 3.x. In 3.x, it works like this:
import builtins
import module1
builtins.a = 3
module1.f()
As a workaround, you could consider setting environment variables in the outer layer, like this.
main.py:
import os
os.environ['MYVAL'] = str(myintvariable)
mymodule.py:
import os
myval = None
if 'MYVAL' in os.environ:
myval = os.environ['MYVAL']
As an extra precaution, handle the case when MYVAL is not defined inside the module.
This post is just an observation for Python behaviour I encountered. Maybe the advices you read above don't work for you if you made the same thing I did below.
Namely, I have a module which contains global/shared variables (as suggested above):
#sharedstuff.py
globaltimes_randomnode=[]
globalist_randomnode=[]
Then I had the main module which imports the shared stuff with:
import sharedstuff as shared
and some other modules that actually populated these arrays. These are called by the main module. When exiting these other modules I can clearly see that the arrays are populated. But when reading them back in the main module, they were empty. This was rather strange for me (well, I am new to Python). However, when I change the way I import the sharedstuff.py in the main module to:
from globals import *
it worked (the arrays were populated).
Just sayin'
A function uses the globals of the module it's defined in. Instead of setting a = 3, for example, you should be setting module1.a = 3. So, if you want cur available as a global in utilities_module, set utilities_module.cur.
A better solution: don't use globals. Pass the variables you need into the functions that need it, or create a class to bundle all the data together, and pass it when initializing the instance.
The easiest solution to this particular problem would have been to add another function within the module that would have stored the cursor in a variable global to the module. Then all the other functions could use it as well.
module1:
cursor = None
def setCursor(cur):
global cursor
cursor = cur
def method(some, args):
global cursor
do_stuff(cursor, some, args)
main program:
import module1
cursor = get_a_cursor()
module1.setCursor(cursor)
module1.method()
Since globals are module specific, you can add the following function to all imported modules, and then use it to:
Add singular variables (in dictionary format) as globals for those
Transfer your main module globals to it
.
addglobals = lambda x: globals().update(x)
Then all you need to pass on current globals is:
import module
module.addglobals(globals())
Since I haven't seen it in the answers above, I thought I would add my simple workaround, which is just to add a global_dict argument to the function requiring the calling module's globals, and then pass the dict into the function when calling; e.g:
# external_module
def imported_function(global_dict=None):
print(global_dict["a"])
# calling_module
a = 12
from external_module import imported_function
imported_function(global_dict=globals())
>>> 12
The OOP way of doing this would be to make your module a class instead of a set of unbound methods. Then you could use __init__ or a setter method to set the variables from the caller for use in the module methods.
Update
To test the theory, I created a module and put it on pypi. It all worked perfectly.
pip install superglobals
Short answer
This works fine in Python 2 or 3:
import inspect
def superglobals():
_globals = dict(inspect.getmembers(
inspect.stack()[len(inspect.stack()) - 1][0]))["f_globals"]
return _globals
save as superglobals.py and employ in another module thusly:
from superglobals import *
superglobals()['var'] = value
Extended Answer
You can add some extra functions to make things more attractive.
def superglobals():
_globals = dict(inspect.getmembers(
inspect.stack()[len(inspect.stack()) - 1][0]))["f_globals"]
return _globals
def getglobal(key, default=None):
"""
getglobal(key[, default]) -> value
Return the value for key if key is in the global dictionary, else default.
"""
_globals = dict(inspect.getmembers(
inspect.stack()[len(inspect.stack()) - 1][0]))["f_globals"]
return _globals.get(key, default)
def setglobal(key, value):
_globals = superglobals()
_globals[key] = value
def defaultglobal(key, value):
"""
defaultglobal(key, value)
Set the value of global variable `key` if it is not otherwise st
"""
_globals = superglobals()
if key not in _globals:
_globals[key] = value
Then use thusly:
from superglobals import *
setglobal('test', 123)
defaultglobal('test', 456)
assert(getglobal('test') == 123)
Justification
The "python purity league" answers that litter this question are perfectly correct, but in some environments (such as IDAPython) which is basically single threaded with a large globally instantiated API, it just doesn't matter as much.
It's still bad form and a bad practice to encourage, but sometimes it's just easier. Especially when the code you are writing isn't going to have a very long life.

How does importing 1 function only that depends on another work?

What if we have a module that contains two functions and we import only one of them, will the other work?For instance:
file test.py
def a(x):print(x)
def b():a(12)
At the interpreter:
from test import b
b()
It prints 12.How is this possible?Please pardon my bad formatting that's my first question :).
Technically there is no such thing as importing a single name from a module; the entire module is imported and then one or more names are copied to the local namespace. Your import is roughly the equivalent of:
import test
b = test.b
del test
Except that at no point is test ever actually in the local namespace (and subsequently is not actually deleted).

Module namespace initialisation before execution

I'm trying to dynamically update code during runtime by reloading modules using importlib.reload. However, I need a specific module variable to be set before the module's code is executed. I could easily set it as an attribute after reloading but each module would have already executed its code (e.g., defined its default arguments).
A simple example:
# module.py
def do():
try:
print(a)
except NameError:
print('failed')
# main.py
import module
module.do() # prints failed
module.a = 'succeeded'
module.do() # prints succeeded
The desired pseudocode:
import_module_without_executing_code module
module.initialise(a = 'succeeded')
module.do()
Is there a way to control module namespace initialisation (like with classes using metaclasses)?
It's not usually a good idea to use reload other than for interactive debugging. For example, it can easily create situations where two objects of type module.A are not the same type.
What you want is execfile. Pass a globals dictionary (you don't need an explicit locals dictionary) to keep each execution isolated; anything you store in it ahead of time acts exactly like the "pre-set" variables you want. If you do want to have a "real" module interface change, you can have a wrapper module that calls (or just holds as an attribute) the most recently loaded function from your changing file.
Of course, since you're using Python 3, you'll have to use one of the replacements for execfile.
Strictly speaking, I don't believe there is a way to do what you're describing in Python natively. However, assuming you own the module you're trying to import, a common approach with Python modules that need some initializing input is to use an init function.
If all you need is some internal variables to be set, like a in you example above, that's easy: just declare some module-global variables and set them in your init function:
Demo: https://repl.it/MyK0
Module:
## mymodule.py
a = None
def do():
print(a)
def init(_a):
global a
a = _a
Main:
## main.py
import mymodule
mymodule.init(123)
mymodule.do()
mymodule.init('foo')
mymodule.do()
Output:
123
foo
Where things can get trickier is if you need to actually redefine some functions because some dynamic internal something is dependent on the input you give. Here's one solution, borrowed from https://stackoverflow.com/a/1676860. Basically, the idea is to grab a reference to the current module by using the magic variable __name__ to index into the system module dictionary, sys.modules, and then define or overwrite the functions that need it. We can define the functions locally as inner functions, then add them to the module:
Demo: https://repl.it/MyHT/2
Module:
## mymodule.py
import sys
def init(a):
current_module = sys.modules[__name__]
def _do():
try:
print(a)
except NameError:
print('failed')
current_module.do = _do

executing python code from string loaded into a module

I found the following code snippet that I can't seem to make work for my scenario (or any scenario at all):
def load(code):
# Delete all local variables
globals()['code'] = code
del locals()['code']
# Run the code
exec(globals()['code'])
# Delete any global variables we've added
del globals()['load']
del globals()['code']
# Copy k so we can use it
if 'k' in locals():
globals()['k'] = locals()['k']
del locals()['k']
# Copy the rest of the variables
for k in locals().keys():
globals()[k] = locals()[k]
I created a file called "dynamic_module" and put this code in it, which I then used to try to execute the following code which is a placeholder for some dynamically created string I would like to execute.
import random
import datetime
class MyClass(object):
def main(self, a, b):
r = random.Random(datetime.datetime.now().microsecond)
a = r.randint(a, b)
return a
Then I tried executing the following:
import dynamic_module
dynamic_module.load(code_string)
return_value = dynamic_module.MyClass().main(1,100)
When this runs it should return a random number between 1 and 100. However, I can't seem to get the initial snippet I found to work for even the simplest of code strings. I think part of my confusion in doing this is that I may misunderstand how globals and locals work and therefore how to properly fix the problems I'm encountering. I need the code string to use its own imports and variables and not have access to the ones where it is being run from, which is the reason I am going through this somewhat over-complicated method.
You should not be using the code you found. It is has several big problems, not least that most of it doesn't actually do anything (locals() is a proxy, deleting from it has no effect on the actual locals, it puts any code you execute in the same shared globals, etc.)
Use the accepted answer in that post instead; recast as a function that becomes:
import sys, imp
def load_module_from_string(code, name='dynamic_module')
module = imp.new_module(name)
exec(code, mymodule.__dict__)
return module
then just use that:
dynamic_module = load_module_from_string(code_string)
return_value = dynamic_module.MyClass().main(1, 100)
The function produces a new, clean module object.
In general, this is not how you should dynamically import and use external modules. You should be using __import__ within your function to do this. Here's a simple example that worked for me:
plt = __import__('matplotlib.pyplot', fromlist = ['plt'])
plt.plot(np.arange(5), np.arange(5))
plt.show()
I imagine that for your specific application (loading from code string) it would be much easier to save the dynamically generated code string to a file (in a folder containing an __init__.py file) and then to call it using __import__. Then you could access all variables and functions of the code as parts of the imported module.
Unless I'm missing something?

Injecting Locals into Dynamically Loaded Modules Before Execution

I'm trying to build a sort of script system in python that will allow small snippets of code to be selected and executed at runtime inside python.
Essentially I want to be able to load a small python file like
for i in Foo: #not in a function.
print i
Where somewhere else in the program I assign what Foo will be. As if Foo served as a function argument to the entire loaded python file instead of a single function
So somewhere else
FooToPass = GetAFoo ()
TempModule = __import__ ("TheSnippit",<Somehow put {'Foo' : FooToPass} in the locals>)
It is considered bad style to have code with side effects at module level. If you want your module to do something, put that code in a function, make Foo a parameter of this function and call it with the desired value.
Python's import mechanism does not allow to preinitialise a module namespace. If you want to do this anyway (which is, in my opinion, confusing and unnecessary), you have to fiddle around with details of the import mechanism. Example implementation (untested):
import imp
import sys
def my_import(module_name, globals):
if module_name in sys.modules:
return sys.modules[module_name]
module = imp.new_module(module_name)
vars(module).update(globals)
f, module.__file__, options = imp.find_module(module_name)
exec f.read() in vars(module)
f.close()
sys.modules[module_name] = module
return module

Categories