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Open Application (such as zoom.us) with Selenium Webdriver

I want to be able to use pure selenium webdriver to open a zoom link in Chrome and then redirect me to the zoom.us application.
When I execute this:
from selenium import webdriver
def main():
driver = webdriver.Chrome()
driver.get("https://zoom.us/j/000-000-000")
main()
I receive a pop-up saying
https://zoom.us wants to open this application.
and I must press a button titled open zoom.us to open the app.
Is there a way to press this pop-up button through selenium. Or, is there some other way to open zoom from chromedriver?
NOTE: I only want to use selenium. I have been able to implement pyautogui to click on the button but that is not what I am looking for.

Solution for Java:
driver.switchTo().alert().accept();
Solution for Python:
driver.switch_to.alert.accept()

There are a lot of duplicated questions regarding this issue. Here is one of them, and it is quite sure that selenium is not capable of achieving such job since it only interacts with the chrome page. I previously encountered this issue as well and here is my solution to it. It might look really unprofessional, but fortunately it works.
The logic of my solution is to change the setting of chrome in order to skip the popup and directly open the application you want. However, the Chrome team has removed this feature in the latter version for some reasons, and we need to get it back manually. Then, we know that everytime when selenium starts to do the thing it opens a new Chrome page with NO customized settings just like the incognito page. Therefore we need to do something to let selenium opened a Chrome page with your customized setting, so that we can make sure that the popup, which we changed manually to skip, can be skipped successfully.
Type the following code in your terminal.
defaults write com.google.Chrome ExternalProtocolDialogShowAlwaysOpenCheckbox -bool true
This enables you to change the setting of skipping popups, which is the feature Chrome team removed.
Restart Chrome,and open the zoom (or whatever application) page to let the popup display. If you do the 1st step correctly you will be able to see there is a checkbox shown next to the "Open Zoom.us" saying if you check it chrome will open this application without asking, that is, to skip the popup for this application.
Now we need to let selenium open the Chrome with our customized setting. To do this, type "chrome://version" in the search tab of your ordinary Chrome (Not automated page opened by selenium). Go to "Profile Path", and copy this path without the last word "default". For example:
/Users/MYNAME/Library/Application Support/Google/Chrome/Default
This is my profile path, but I only copy everything except the last word Default, so this is what I need to copy.
/Users/MYNAME/Library/Application Support/Google/Chrome/
This is for Mac users, but for Windows only the path is different(starts with C:// or something), steps are same.
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.chrome.options import Options
option = Options()
option.add_argument('THE PATH YOU JUST COPIED')
driver = webdriver.Chrome(executable_path='YOUR PATH TO CHROMEDRIVER', options=option)
driver.get("google.com") #Or anything else
We use "options" to let selenium open a page with our customized profile. Now you will see selenium opens a Chrome page with all your account profile, settings, and it just appears like your ordinary chrome page.
Run your code. But before that, remember to quit ALL CHROME sessions manually. For Mac, make sure that there is no dot under Chrome icon indicating that Chrome is not running for any circumstances. THIS STEP IS CRITICAL otherwise selenium will open a chrome page and it just stops there.
Here are all the steps. Again, this solution is vert informal and I personally don't think it is a "solution" to this problem. I will try to figure out a better way of achieving this in the future. But I still posted this as an alternative simply because I guess it might be helpful to some extent for somebody just like me. Hope it works for you, and good luck.

Element not intractable Selenium

I'm trying to make an auto bump program for forums but I can't seem to interact with anything.
import webbrowser
import pyautogui
import time
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
driver = webdriver.Chrome()
driver.get("https://ogusers.com/member.php?action=login")
#Login
inputElement = driver.find_element_by_class_name("textbox")
inputElement.send_keys("xKyle")

Can't really tell where problem lies, you need to say exactly what is happening, let's start with not giving selenium path to ChromeDriver. You need to download it from here, make sure to get driver compatible with your browser verison.
Next give path to it, if you are on windows path will look like:
r"C:\dir\dir\chromedriver.exe'
you need to give 'r' for raw data, otherwise interpreter will think that you are trying to give some weird in-string command like \n for new line
Also try not to search by class name, for 99% of time you want to use Xpath, especially if it's relative. So just click on element, and copy xpath.
For more answers you need to tell exactly what are you trying to do and when it fails :)

how to search for string inside chrome internal pages, using python and\or selenium

I'm trying to write script, that would allow me to search for a string inside Chrome's internal pages (for example: "chrome://help").
is there a simple way to do it, or does it require special tools, (like the Selenium webdriver API)?
i know it's possible to use it for "normal" web pages, but what about "internal" ones?

You can use selenium Webdriver to easily achieve this task, and in this case we will extract the version number of Google Chrome.
Here is the sample code with comments explaining every step:
from selenium import webdriver
# executable path should be the place where chrome driver is on the computer
driver = webdriver.Chrome(executable_path= '/users/user/Downloads/Chromedriver')
# This line tells the driver to go to the help section of chrome
driver.get('chrome://help')
# Because certain elements are stored in another Iframe, you must switch to this particular Iframe which is called 'help' in this case.
driver.switch_to.frame(driver.find_element_by_name('help'))
# retrive the text of the element and store it's text in a variable.
version_string = driver.find_element_by_id('version-container').text
# Now you can easily print it.
print version_string

Chromedriver.exe has stopped working - python

I keep getting this error:
https://sites.google.com/a/chromium.org/chromedriver/help/chromedriver-crashes
I get it when running the command:
python Web.py
However when I go into the file and run the lines 1 by 1, I don't get the error. However I always get the error when the Web.py file has finished. When I run the lines 1 by 1, it's very basic things but i feel like I"m not ending my script correctly.
import selenium
from selenium.webdriver.common.keys import Keys
import time
from selenium import webdriver
driver = webdriver.Chrome()
driver.get('espn.com')
I want the window with espn.com to stay on the screen, not quit when the script has finished.
I'm running this on Python. I can share my setup, maybe that's something I did incorreclty but any help would be appeciated.

You're passing an invalid url.
You need to pass the url like this:
driver.get("http://www.espn.com")
This might work in your browser, but it won't with selenium. Type in "espn.com" in your browser and then copy / paste the url and you'll see that it's actually the above url.
You should also specify the "chromedriver.exe" path.

You are getting this error because you had not installed the chrome driver for selenium on your Machine. Selenium by default provides the driver for Firefox so when you use the webdriver for Firefox, it won't rise any error. To resolve this issue with Chrome you can download the Chrome webdriver from here.
and you can specify the driver as
from selenium import webdriver
d = webdriver.Chrome(executable_path='<your Chrome driver path>')
Adding to what #Pythonista said , it's better if you keep the URL as a raw string than a normal string
driver.get(r'http://www.espn.com')
so that it won't take the slash as an escape sequence in few cases.
Hope it helps.

Try to update chrome and get updated/latest chrome driver, recently chrome made several updates in its driver you can download the last one from the link below:
https://chromedriver.storage.googleapis.com/2.27/chromedriver_win32.zip

Open new tab in Firefox using Selenium WebDriver on Mac

I just installed Selenium Web Driver and tried it out. It works great. My use case can be describe as followed:
Start Firefox on a server with pseudo X server (Xvfb)
New Driver.Firefox() object
Open 10 tabs and load a webpage in each tab
Retrieve the html from all loaded pages
The only step that is not working is step 3. I can not find out how to open new tabs. I found this here on SO : How to open a new tab using Selenium WebDriver with Java? However, I tested this locally (i.e. with visible display) on my Mac for debugging purpose and I saw that the Firefox browser (which was opened when creating the driver object) does not open any tabs when doing as described on the SO thread. So I tried this here:
driver = webdriver.Firefox()
driver.get("https://stackoverflow.com/")
body = driver.find_element_by_tag_name("body")
body.send_keys(Keys.CONTROL + 't')
As I said, it does not work for me. So, how else is it possible to open tabs? I use Selenium 2.39 (pip install selenium) and Python 2.7.

the key combination to open a new tab on OSX is Command+T, so you should use
body.send_keys(Keys.COMMAND + 't')

It's probably slightly more correct to send it to the browser via action chaining since you're not actually typing text; this also makes your code more readable imo
from selenium.webdriver.common.action_chains import ActionChains
from selenium.webdriver.common.keys import Keys
# before correction from DMfll:
# ActionChains(driver).send_keys(Keys.COMMAND, "t").perform()
# correct method
ActionChains(driver).key_down(Keys.COMMAND).send_keys("t").key_up(Keys.COMMAND)‌​‌​.perform()