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Python - setting arbitrary contour xy-ratio

I am reading the following discussion:
setting axis scale in matplotlib contour plot
From the discussion above, to get arbitrary ratio, we could use
plt.figure(figsize=(8,2))
# ...
plt.tight_layout()
However, this setting is for figure not for contourf.
I used the above codes in my codes
import matplotlib.pyplot as plt
from matplotlib import cm
import numpy as np
import pandas as pd
import math
rm = pd.read_excel("test_3d.xlsx", header = None)
# find min values of noise
rec = np.shape(rm)
# grid
X = np.arange(1,rec[1]+1,1)
Y = np.arange(1,rec[0]+1,1)
x , y = np.meshgrid(X,Y)
# plots
plt.clf()
con = plt.contourf(x,y,rm, cmap=cm.jet)
plt.figure(figsize=(8,2))
plt.tight_layout()
plt.title('2457MHz')
plt.show()
The result I got is
The ratio of bottom plot is what I want; however, I use plt.figure(figsize=(8,2)), which is not for contourf. Therefore, I did not get the correct result.
Is there any way that I can plot arbitrary ratio for contourf?

Instead of setting the figsize, use Axes.set_aspect to change the aspect ratio of the contour plot's Axes:
fig, ax = plt.subplots()
ax.contourf(x, y, rm, cmap='viridis')
ax.set_aspect(0.25)
If you prefer to stick with the plt syntax, access the Axes using plt.gca:
plt.contourf(x, y, rm, cmap='viridis')
plt.gca().set_aspect(0.25)

Remove line through points in matplotlib plot

I have the following matplotlib snippet:
fig, ax = plt.subplots(figsize=(6,6))
values = np.random.normal(loc=0, scale=1, size=10)
ax.plot(range(10), values, 'r^', markersize=15, alpha=0.4);
which produces
as planned.
I'd like to make the line invisible where it overlaps with the points so that the points look more joined by the line rather than lying on top of the line. It is possible to do this by either making the line invisible where they overlap or to create a new line object that simply links the points rather than traces them?
To be explicit, I do not want the entire line removed, just the sections that overlap with the points.

It is in general hard to let the lines stop at the edges of the markers. The reason is that lines are defined in data coordinates, while the markers are defined in points.
A workaround would be to hide the lines where the markers are. We may think of a three layer system. The lowest layer (zorder=1) contains the lines, just as they are. The layer above contains markers of the same shape and size as those which are to be shown. Yet they would be colored in the same color as the background (usually white). The topmost layer contains the markers as desired.
import matplotlib.pyplot as plt
import numpy as np; np.random.seed(42)
fig, ax = plt.subplots(figsize=(6,5))
def plot_hidden_lines(x,y, ax = None, ms=15, color="r",
marker="^", alpha=0.4,**kwargs):
if not ax: ax=plt.gca()
ax.scatter(x,y, c=color, s=ms**2, marker=marker, alpha=alpha, zorder=3)
ax.scatter(x,y, c="w", s=ms**2, marker=marker, alpha=1, zorder=2)
ax.plot(x,y, color=color, zorder=1,alpha=alpha,**kwargs)
values1 = np.random.normal(loc=0, scale=1, size=10)
values2 = np.random.normal(loc=0, scale=1, size=10)
x = np.arange(len(values1))
plot_hidden_lines(x,values1)
plot_hidden_lines(x,values2, color="indigo", ms=20, marker="s")
plt.show()

I think the best way to go about it is to overlay the triangles over the lines:
import matplotlib.pyplot as plt
import numpy as np
values = np.random.normal(loc=0, scale=1, size=10)
plt.plot( range(10), values, marker='^', markerfacecolor='red', markersize=15, color='red', linewidth=2)
plt.show()
The program outputs:
If you really want the see through aspect, I suggest you somehow calculate where the lines overlap with the markers and only draw the lines inbetween:
import numpy as np
import matplotlib.pyplot as plt
values = np.random.normal(loc= 0, scale=1, size=10)
for i in range(9):
start_coordinate, end_coordinate = some_function(values[i], values[i+1])
plt.plot([i, i+1], [start_coordinate, end_coordinate], *whatever_other_arguments)
plt.scatter(range(10), values, *whatever_other_arguments)
plt.show()
The hard part here is of course calculating these coordinates (if you want to zoom in this won't work), but honestly, given the difficulty of this question, I think you won't find anything much better...

No color when I make python scatter color plot using third variable to define color

I try to make colorful scatter plot using third variable to define color. It is simple to use the following code:
plt.scatter(mH, mA, s=1, c=mHc)
plt.colorbar()
plt.show()
But I do not have many choices to modify the frame of the plot. I am trying the following code to make colorful scatter plot, at the same time I try to optimize the frame of the plot:
import numpy as np
import math
from matplotlib import rcParams
import matplotlib.pyplot as plt
from matplotlib.ticker import AutoMinorLocator
fig, ax = plt.subplots()
cax = ax.scatter(mH,mA,s=0.5,c=mHc) ### mH, mA, mHC are the dataset
fig.colorbar(cax)
minor_locator1 = AutoMinorLocator(6)
minor_locator2 = AutoMinorLocator(6)
ax.xaxis.set_minor_locator(minor_locator1)
ax.yaxis.set_minor_locator(minor_locator2)
ax.tick_params('both', length=10, width=2, which='major')
ax.tick_params('both', length=5, width=2, which='minor')
ax.set_xlabel(r'$m_H$')
ax.set_ylabel(r'$m_A$')
ax.set_xticks([300,600,900,1200,1500])
ax.set_yticks([300,600,900,1200,1500])
plt.savefig('mH_mA.png',bbox_inches='tight')
plt.show()
But the plot I got is black-white. It looks like the problem lies in the marker size argument, but I do not have much idea how to correct it. I want to have smaller marker size. Anyone can offer me some idea to approach this issue. Thanks.

size=0.5 is extremely small - probably all you are seeing is the marker outlines. I would suggest you increase the size a bit, and perhaps pass edgecolors="none" to turn off the marker edge stroke:
import numpy as np
from matplotlib import pyplot as plt
n = 10000
x, y = np.random.randn(2, n)
z = -(x**2 + y**2)**0.5
fig, ax = plt.subplots(1, 1)
ax.scatter(x, y, s=5, c=z, cmap="jet", edgecolors="none")
You might also want to experiment with making the points semi-transparent using the alpha= parameter:
ax.scatter(x, y, s=20, c=z, alpha=0.1, cmap="jet", edgecolors="none")
It can be difficult to get scatter plots to look nice when you have such a massive number of overlapping points. I would be tempted to plot your data as a 2D histogram or contour plot instead, or perhaps even a combination of a scatter plot and a contour plot:
density, xe, ye = np.histogram2d(x, y, bins=20, normed=True)
ax.hold(True)
ax.scatter(x, y, s=5, c=z, cmap="jet", edgecolors="none")
ax.contour(0.5*(xe[:-1] + xe[1:]), 0.5*(ye[:-1] + ye[1:]), density,
colors='k')

Adding y=x to a matplotlib scatter plot if I haven't kept track of all the data points that went in

Here's some code that does scatter plot of a number of different series using matplotlib and then adds the line y=x:
import numpy as np, matplotlib.pyplot as plt, matplotlib.cm as cm, pylab
nseries = 10
colors = cm.rainbow(np.linspace(0, 1, nseries))
all_x = []
all_y = []
for i in range(nseries):
x = np.random.random(12)+i/10.0
y = np.random.random(12)+i/5.0
plt.scatter(x, y, color=colors[i])
all_x.extend(x)
all_y.extend(y)
# Could I somehow do the next part (add identity_line) if I haven't been keeping track of all the x and y values I've seen?
identity_line = np.linspace(max(min(all_x), min(all_y)),
min(max(all_x), max(all_y)))
plt.plot(identity_line, identity_line, color="black", linestyle="dashed", linewidth=3.0)
plt.show()
In order to achieve this I've had to keep track of all the x and y values that went into the scatter plot so that I know where identity_line should start and end. Is there a way I can get y=x to show up even if I don't have a list of all the points that I plotted? I would think that something in matplotlib can give me a list of all the points after the fact, but I haven't been able to figure out how to get that list.

You don't need to know anything about your data per se. You can get away with what your matplotlib Axes object will tell you about the data.
See below:
import numpy as np
import matplotlib.pyplot as plt
# random data
N = 37
x = np.random.normal(loc=3.5, scale=1.25, size=N)
y = np.random.normal(loc=3.4, scale=1.5, size=N)
c = x**2 + y**2
# now sort it just to make it look like it's related
x.sort()
y.sort()
fig, ax = plt.subplots()
ax.scatter(x, y, s=25, c=c, cmap=plt.cm.coolwarm, zorder=10)
Here's the good part:
lims = [
np.min([ax.get_xlim(), ax.get_ylim()]), # min of both axes
np.max([ax.get_xlim(), ax.get_ylim()]), # max of both axes
]
# now plot both limits against eachother
ax.plot(lims, lims, 'k-', alpha=0.75, zorder=0)
ax.set_aspect('equal')
ax.set_xlim(lims)
ax.set_ylim(lims)
fig.savefig('/Users/paul/Desktop/so.png', dpi=300)
Et voilà

In one line:
ax.plot([0,1],[0,1], transform=ax.transAxes)
No need to modify the xlim or ylim.

Starting with matplotlib 3.3 this has been made very simple with the axline method which only needs a point and a slope. To plot x=y:
ax.axline((0, 0), slope=1)
You don't need to look at your data to use this because the point you specify (i.e. here (0,0)) doesn't actually need to be in your data or plotting range.

If you set scalex and scaley to False, it saves a bit of bookkeeping. This is what I have been using lately to overlay y=x:
xpoints = ypoints = plt.xlim()
plt.plot(xpoints, ypoints, linestyle='--', color='k', lw=3, scalex=False, scaley=False)
or if you've got an axis:
xpoints = ypoints = ax.get_xlim()
ax.plot(xpoints, ypoints, linestyle='--', color='k', lw=3, scalex=False, scaley=False)
Of course, this won't give you a square aspect ratio. If you care about that, go with Paul H's solution.

Add second axis to polar plot

I try to plot two polar plots in one figure. See code below:
fig = super(PlotWindPowerDensity, self).get_figure()
rect = [0.1, 0.1, 0.8, 0.8]
ax = WindSpeedDirectionAxes(fig, rect)
self.values_dict = collections.OrderedDict(sorted(self.values_dict.items()))
values = self.values_dict.items()
di, wpd = zip(*values)
wpd = np.array(wpd).astype(np.double)
wpdmask = np.isfinite(wpd)
theta = self.radar_factory(int(len(wpd)))
# spider plot
ax.plot(theta[wpdmask], wpd[wpdmask], color = 'b', alpha = 0.5)
ax.fill(theta[wpdmask], wpd[wpdmask], facecolor = 'b', alpha = 0.5)
# bar plot
ax.plot_bar(table=self.table, sectors=self.sectors, speedbins=self.wpdbins, option='wind_power_density', colorfn=get_sequential_colors)
fig.add_axes(ax)
return fig
The length of the bar is the data base (how many sampling points for this sector). The colors of the bars show the frequency of certain value bins (eg. 2.5-5 m/s) in the correspondent sector (blue: low, red: high). The blue spider plot shows the mean value for each sector.
In the shown figure, the values of each plot are similar, but this is rare. I need to assign the second plot to another axis and show this axis in another direction.
EDIT:
After the nice answer of Joe, i get the result of the figure.
That's almost everything i wanted to achieve. But there are some points i wasn't able to figure out.
The plot is made for dynamicly changing data bases. Therefore i need a dynamic way to get the same location of the circles. Till now I solve it with:
start, end = ax2.get_ylim()
ax2.yaxis.set_ticks(np.arange(0, end, end / len(ax.yaxis.get_ticklocs())))
means: for second axis i alter the ticks in order to fit the ticklocs to the one's of first axis.
In most cases i get some decimal places, but i don't want that, because it corrupts the clearness of the plot. Is there a way to solve this problem more smartly?
The ytics (the radial one's) range from 0 to the next-to-last circle. How can i achieve that the values range from the first circle to the very last (the border)? The same like for the first axis.

So, as I understand it, you want to display data with very different magnitudes on the same polar plot. Basically you're asking how to do something similar to twinx for polar axes.
As an example to illustrate the problem, it would be nice to display the green series on the plot below at a different scale than the blue series, while keeping them on the same polar axes for easy comparison.:
import numpy as np
import matplotlib.pyplot as plt
numpoints = 30
theta = np.linspace(0, 2*np.pi, numpoints)
r1 = np.random.random(numpoints)
r2 = 5 * np.random.random(numpoints)
params = dict(projection='polar', theta_direction=-1, theta_offset=np.pi/2)
fig, ax = plt.subplots(subplot_kw=params)
ax.fill_between(theta, r2, color='blue', alpha=0.5)
ax.fill_between(theta, r1, color='green', alpha=0.5)
plt.show()
However, ax.twinx() doesn't work for polar plots.
It is possible to work around this, but it's not very straight-forward. Here's an example:
import numpy as np
import matplotlib.pyplot as plt
def main():
numpoints = 30
theta = np.linspace(0, 2*np.pi, numpoints)
r1 = np.random.random(numpoints)
r2 = 5 * np.random.random(numpoints)
params = dict(projection='polar', theta_direction=-1, theta_offset=np.pi/2)
fig, ax = plt.subplots(subplot_kw=params)
ax2 = polar_twin(ax)
ax.fill_between(theta, r2, color='blue', alpha=0.5)
ax2.fill_between(theta, r1, color='green', alpha=0.5)
plt.show()
def polar_twin(ax):
ax2 = ax.figure.add_axes(ax.get_position(), projection='polar',
label='twin', frameon=False,
theta_direction=ax.get_theta_direction(),
theta_offset=ax.get_theta_offset())
ax2.xaxis.set_visible(False)
# There should be a method for this, but there isn't... Pull request?
ax2._r_label_position._t = (22.5 + 180, 0.0)
ax2._r_label_position.invalidate()
# Ensure that original axes tick labels are on top of plots in twinned axes
for label in ax.get_yticklabels():
ax.figure.texts.append(label)
return ax2
main()
That does what we want, but it looks fairly bad at first. One improvement would be to the tick labels to correspond to what we're plotting:
plt.setp(ax2.get_yticklabels(), color='darkgreen')
plt.setp(ax.get_yticklabels(), color='darkblue')
However, we still have the double-grids, which are rather confusing. One easy way around this is to manually set the r-limits (and/or r-ticks) such that the grids will fall on top of each other. Alternately, you could write a custom locator to do this automatically. Let's stick with the simple approach here:
ax.set_rlim([0, 5])
ax2.set_rlim([0, 1])
Caveat: Because shared axes don't work for polar plots, the implmentation I have above will have problems with anything that changes the position of the original axes. For example, adding a colorbar to the figure will cause all sorts of problems. It's possible to work around this, but I've left that part out. If you need it, let me know, and I'll add an example.
At any rate, here's the full, stand-alone code to generate the final figure:
import numpy as np
import matplotlib.pyplot as plt
np.random.seed(1977)
def main():
numpoints = 30
theta = np.linspace(0, 2*np.pi, numpoints)
r1 = np.random.random(numpoints)
r2 = 5 * np.random.random(numpoints)
params = dict(projection='polar', theta_direction=-1, theta_offset=np.pi/2)
fig, ax = plt.subplots(subplot_kw=params)
ax2 = polar_twin(ax)
ax.fill_between(theta, r2, color='blue', alpha=0.5)
ax2.fill_between(theta, r1, color='green', alpha=0.5)
plt.setp(ax2.get_yticklabels(), color='darkgreen')
plt.setp(ax.get_yticklabels(), color='darkblue')
ax.set_ylim([0, 5])
ax2.set_ylim([0, 1])
plt.show()
def polar_twin(ax):
ax2 = ax.figure.add_axes(ax.get_position(), projection='polar',
label='twin', frameon=False,
theta_direction=ax.get_theta_direction(),
theta_offset=ax.get_theta_offset())
ax2.xaxis.set_visible(False)
# There should be a method for this, but there isn't... Pull request?
ax2._r_label_position._t = (22.5 + 180, 0.0)
ax2._r_label_position.invalidate()
# Bit of a hack to ensure that the original axes tick labels are on top of
# whatever is plotted in the twinned axes. Tick labels will be drawn twice.
for label in ax.get_yticklabels():
ax.figure.texts.append(label)
return ax2
if __name__ == '__main__':
main()

Just to add onto #JoeKington 's (great) answer, I found that the "hack to ensure that the original axes tick labels are on top of whatever is plotted in the twinned axes" didn't work for me so as an alternative I've used:
from matplotlib.ticker import MaxNLocator
#Match the tick point locations by setting the same number of ticks in the
# 2nd axis as the first
ax2.yaxis.set_major_locator(MaxNLocator(nbins=len(ax1.get_yticks())))
#Set the last tick as the plot limit
ax2.set_ylim(0, ax2.get_yticks()[-1])
#Remove the tick label at zero
ax2.yaxis.get_major_ticks()[0].label1.set_visible(False)