Hello I have some json api output data that I am trying to restructure/reformat. Here is a sample of the output:
{
"playergamelogs: {
"gamelogs": [
{
"game" : {
"date" : "2016-10-13"
"id" : "32637},
"player": {
"ID": "4419"},
"team" : {
"id" : "16},
"stats" : {
"minutes": "10"}
},
{
"game": {
"date" : "2016-10-17"
"id" : "33737},
"player": {
"ID": "4419"},
"team" : {
"id" : "16
},
"stats" : {
"minutes": "10"
What I would like to do is group the data by player id (or name). For example:
`{
"playerlogs" : [
{
"player" : {
"ID" : "4419"
"team" : {
"id" : "16"
},
"gamelogs" : [
{
"game" : {}
"game" : {}
}
}
"player" : {
....
}
}`
The best way that I can think to accomplish this is nested for loops using dict.items() and if statements to match the appropriate player ID's. I am having trouble with the most efficient way to go about restructuring. I am fairly new to python and any help is greatly appreciated.
Instead of hardcoding your transformation logic into python code I suggest to check MongoDB. It is a JSON based document database and you can create such queries with it.
Here is a very simple example:
https://docs.mongodb.com/manual/aggregation/
Your data is more complex, but player is similar to cust_id and game to amount in the example.
Here is how I was able solve my initial question and reformat the original data:
for i in range(0,len(dataedit)):
playerID = dataedit[i]["player"]["ID"]
if not any(p.get('player',{}).get('ID',{}) == playerID for p in playerlog):
playerlog.append({})
playerlog[x]["player"] = dataedit[i]["player"]
x+=1
gameID = dataedit[i]["game"]["id"]
playerlog[x-1]["player"]["game" + gameID] = dataedit[i]["game"]
playerlog[x-1]["player"]["game" + gameID]["stats"] = dataedit[i]["stats"]
playerlog[x-1]["player"]["game" + gameID]["team"] = dataedit[i]["team"]
As I am still learning, I would love to get feedback/comments on how to improve.
Related
"data": {
"0": {
"name": "test",
"tag": "123"
},
"1": {
"name": "test123",
"tag": "456"
lets say having this example data above and i wanted to get the tag value of 456 but need to make sure the "name" has test123 value compared in a search. how should i loop this dict?
def test():
response = requests.get(data_above)
data_dict = json.loads(response.text)
# need to loop here to get the tag value of 456 and assigned it in variable but is from searching to make sure i have "name" test123 is found. is more towards dynamic
The data structure in the original question is incomplete. Making an assumption about how it really looks then this would work:
mydict = [{"data": {
"0": {
"name": "test",
"tag": "123"
},
"1": {
"name": "test123",
"tag": "456"}
}
}]
for v in mydict[0]['data'].values():
if v['name'] == 'test123':
print(v['tag'])
searched_name = "test123"
for v in myDict["data"]:
if v["name"] == searched_name:
tag = v["tag"]
expected outcome:
tag variable will hold value of 456 now
this is working for me. i might be posting my question wrongly but thanks to anyone who tried to helped me. Certainly some gave me idea in how to loop it
You can use [“the item name”] for calling it
like:
dict = {“data” : {
“0” : {
“name” : “test”,
“tag” : “123”
},
“1” : {
“name” : “test123”,
“tag” : “456”
}
}
#searching
for val in mydict:
#scan for each level
if val == “test”:
print(“i found”)
else:
for i in mydict[val]:
if i == “test”:
print(“i found”)
else:
for item in mydict[val][i]:
res = mydict[val][i][item]
if res == “test”:
print(“I found it in final step!”)
I am using Python and MongoEngine to try and query the below Document in MongoDB.
I need a query to efficiently get the Documents only when they contain Embedded Documents 'Keywords' that match the following criteria:
Keywords Filtered where the Property 'SFR' is LTE '100000'
SUM the filtered keywords
Return the parent documents where SUM of the keywords matching the criteria is Greater than '9'
Example structure:
{
"_id" : ObjectId("5eae60e4055ef0e717f06a50"),
"registered_data" : ISODate("2020-05-03T16:12:51.999+0000"),
"UniqueName" : "SomeUniqueNameHere",
"keywords" : [
{
"keyword" : "carport",
"search_volume" : NumberInt(10532),
"sfr" : NumberInt(20127),
"percent_contribution" : 6.47,
"competing_product_count" : NumberInt(997),
"avg_review_count" : NumberInt(143),
"avg_review_score" : 4.05,
"avg_price" : 331.77,
"exact_ppc_bid" : 3.44,
"broad_ppc_bid" : 2.98,
"exact_hsa_bid" : 8.33,
"broad_hsa_bid" : 9.29
},
{
"keyword" : "party tent",
"search_volume" : NumberInt(6944),
"sfr" : NumberInt(35970),
"percent_contribution" : 4.27,
"competing_product_count" : NumberInt(2000),
"avg_review_count" : NumberInt(216),
"avg_review_score" : 3.72,
"avg_price" : 210.16,
"exact_ppc_bid" : 1.13,
"broad_ppc_bid" : 0.55,
"exact_hsa_bid" : 9.66,
"broad_hsa_bid" : 8.29
}
]
}
From the research I have been doing, I believe an Aggregate type query might do what I am attempting.
Unfortunately, being new to MongoDB / MongoEngine I am struggling to figure out how to structure the query and have failed in finding an example similar to what I am attempting to do (RED FLAG RIGHT????).
I did find an example of a aggregate but unsure how to structure my criteria in it, maybe something like this is getting close but does not work.
pipeline = [
{
"$lte": {
"$sum" : {
"keywords" : {
"$lte": {
"keyword": 100000
}
}
}: 9
}
}
]
data = product.objects().aggregate(pipeline)
Any guidance would be greatly appreciated.
Thanks,
Ben
you can try something like this
db.collection.aggregate([
{
$project: { // the first project to filter the keywords array
registered_data: 1,
UniqueName: 1,
keywords: {
$filter: {
input: "$keywords",
as: "item",
cond: {
$lte: [
"$$item.sfr",
100000
]
}
}
}
}
},
{
$project: { // the second project to get the length of the keywords array
registered_data: 1,
UniqueName: 1,
keywords: 1,
keywordsLength: {
$size: "$keywords"
}
}
},
{
$match: { // then do the match
keywordsLength: {
$gte: 9
}
}
}
])
you can test it here Mongo Playground
hope it helps
Note, I used sfr property only from the keywords array for simplicity
I have below sample data in JSON format :
project_cost_details is my database result set after querying.
{
"1": {
"amount": 0,
"breakdown": [
{
"amount": 169857,
"id": 4,
"name": "SampleData",
"parent_id": "1"
}
],
"id": 1,
"name": "ABC PR"
}
}
Here is full json : https://jsoneditoronline.org/?id=2ce7ab19af6f420397b07b939674f49c
Expected output :https://jsoneditoronline.org/?id=56a47e6f8e424fe8ac58c5e0732168d7
I have this sample JSON which i created using loops in code. But i am stuck at how to convert this to expected JSON format. I am getting sequential changes, need to convert to tree like or nested JSON format.
Trying in Python :
project_cost = {}
for cost in project_cost_details:
if cost.get('Parent_Cost_Type_ID'):
project_id = str(cost.get('Project_ID'))
parent_cost_type_id = str(cost.get('Parent_Cost_Type_ID'))
if project_id not in project_cost:
project_cost[project_id] = {}
if "breakdown" not in project_cost[project_id]:
project_cost[project_id]["breakdown"] = []
if 'amount' not in project_cost[project_id]:
project_cost[project_id]['amount'] = 0
project_cost[project_id]['name'] = cost.get('Title')
project_cost[project_id]['id'] = cost.get('Project_ID')
if parent_cost_type_id == cost.get('Cost_Type_ID'):
project_cost[project_id]['amount'] += int(cost.get('Amount'))
#if parent_cost_type_id is None:
project_cost[project_id]["breakdown"].append(
{
'amount': int(cost.get('Amount')),
'name': cost.get('Name'),
'parent_id': parent_cost_type_id,
'id' : cost.get('Cost_Type_ID')
}
)
from this i am getting sample JSON. It will be good if get in this code only desired format.
Also tried this solution mention here : https://adiyatmubarak.wordpress.com/2015/10/05/group-list-of-dictionary-data-by-particular-key-in-python/
I got approach to convert sample JSON to expected JSON :
data = [
{ "name" : "ABC", "parent":"DEF", },
{ "name" : "DEF", "parent":"null" },
{ "name" : "new_name", "parent":"ABC" },
{ "name" : "new_name2", "parent":"ABC" },
{ "name" : "Foo", "parent":"DEF"},
{ "name" : "Bar", "parent":"null"},
{ "name" : "Chandani", "parent":"new_name", "relation": "rel", "depth": 3 },
{ "name" : "Chandani333", "parent":"new_name", "relation": "rel", "depth": 3 }
]
result = {x.get("name"):x for x in data}
#print(result)
tree = [];
for a in data:
#print(a)
if a.get("parent") in result:
parent = result[a.get("parent")]
else:
parent = ""
if parent:
if "children" not in parent:
parent["children"] = []
parent["children"].append(a)
else:
tree.append(a)
Reference help : http://jsfiddle.net/9FqKS/ this is a JavaScript solution i converted to Python
It seems that you want to get a list of values from a dictionary.
result = [value for key, value in project_cost_details.items()]
I must be really slow because I spent a whole day googling and trying to write Python code to simply list the "code" values only so my output will be Service1, Service2, Service2. I have extracted json values before from complex json or dict structure. But now I must have hit a mental block.
This is my json structure.
myjson='''
{
"formatVersion" : "ABC",
"publicationDate" : "2017-10-06",
"offers" : {
"Service1" : {
"code" : "Service1",
"version" : "1a1a1a1a",
"index" : "1c1c1c1c1c1c1"
},
"Service2" : {
"code" : "Service2",
"version" : "2a2a2a2a2",
"index" : "2c2c2c2c2c2"
},
"Service3" : {
"code" : "Service4",
"version" : "3a3a3a3a3a",
"index" : "3c3c3c3c3c3"
}
}
}
'''
#convert above string to json
somejson = json.loads(myjson)
print(somejson["offers"]) # I tried so many variations to no avail.
Or, if you want the "code" stuffs :
>>> [s['code'] for s in somejson['offers'].values()]
['Service1', 'Service2', 'Service4']
somejson["offers"] is a dictionary. It seems you want to print its keys.
In Python 2:
print(somejson["offers"].keys())
In Python 3:
print([x for x in somejson["offers"].keys()])
In Python 3 you must use the list comprehension because in Python 3 keys() is a 'view', not a list.
This should probably do the trick , if you are not certain about the number of Services in the json.
import json
myjson='''
{
"formatVersion" : "ABC",
"publicationDate" : "2017-10-06",
"offers" : {
"Service1" : {
"code" : "Service1",
"version" : "1a1a1a1a",
"index" : "1c1c1c1c1c1c1"
},
"Service2" : {
"code" : "Service2",
"version" : "2a2a2a2a2",
"index" : "2c2c2c2c2c2"
},
"Service3" : {
"code" : "Service4",
"version" : "3a3a3a3a3a",
"index" : "3c3c3c3c3c3"
}
}
}
'''
#convert above string to json
somejson = json.loads(myjson)
#Without knowing the Services:
offers = somejson["offers"]
keys = offers.keys()
for service in keys:
print(somejson["offers"][service]["code"])
I want to count all elements which occur in somekey in an MongoDB collection.
The current code looks at all elements in somekey as a whole.
from pymongo import Connection
con = Connection()
db = con.database
collection = db.collection
from bson.code import Code
reducer = Code("""
function(obj, prev){
prev.count++;
}
""")
from bson.son import SON
results = collection.group(key={"somekey":1}, condition={}, initial={"count": 0}, reduce=reducer)
for doc in results:
print doc
However, I want that it counts all elements which occur in any document with somekey.
Here is an anticipated example. The MongoDB has the following documents.
{ "_id" : 1, “somekey" : [“AB", “CD"], "someotherkey" : "X" }
{ "_id" : 2, “somekey" : [“AB", “XY”], "someotherkey" : "Y" }
The result should provide an by count ordered list with:
count: 2 "AB"
count: 1 "CD"
count: 1 "XY"
The .group() method will not work on elements that are arrays, and the closest similar thing would be mapReduce where you have more control over the emitted keys.
But really the better fit here is the aggregation framework. It is implemented in native code as does not use JavaScript interpreter processing as the other methods there do.
You wont be getting an "ordered list" from MongoDB responses, but you get a similar document result:
results = collection.aggregate([
# Unwind the array
{ "$unwind": "somekey" },
# Group the results and count
{ "$group": {
"_id": "$somekey",
"count": { "$sum": 1 }
}}
])
Gives you something like:
{ "_id": "AB", "count": 2 }
{ "_id": "CD", "count": 1 }
{ "_id": "XY", "count": 1 }