We Keep Coding

Confused about how the return works in python [closed]

Closed. This question needs debugging details. It is not currently accepting answers.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Closed 1 year ago.
Improve this question
The program runs and the function works but I am not able to see my docCountryList in the output. Can someone tell me why?
I have this code
def ViewByCountry(docID,user_selection):
docCountryList=[]
for x in jfile:
if x.get('subject_doc_id') == docID:
docCountryList.append(x['visitor_country'])
if user_selection == '2a':
x = []
y = []
#Insert countries and number of occurences in two seperate lists
for k,v in Counter(docCountryList).items():
x.append(k)
y.append(v)
plt.title('Countries of Viewers')
plt.bar(range(len(y)), y, align='center')
plt.xticks(range(len(y)), x, size='small')
plt.show()
return docCountryList
and in my main
from program import ViewByCountry
# Press the green button in the gutter to run the script.
if __name__ == '__main__':
docID = input("Enter required document ID: ")
user_selection = input("Enter selection")
ViewByCountry(docID,user_selection)

You never print out the value of docCountryList, so try this:
print(ViewByCountry(docID,user_selection))
This will print out the value.
You can do this as well:
lst = ViewByCountry(docID,user_selection)
print(lst)

In your main you can change to myView = ViewByCountry(docID,user_selection) and then add print(myView). This saves the list created by your function to a variable to be printed or used later.

How to have a function feed another function's input [closed]

Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 2 years ago.
Improve this question
I'm making a hangman game and testing how different letter picking algorithms fare, but to do this, the guessing algorithm function has to feed a letter into the hangman function's input('Select a letter').
How do you make it so that a function detects when another function is waiting for an input ?

Assuming you are doing input() in a loop inside your hangman function, you could switch that to a yield and let an external function drive input as needed. In this example I have a hangman function that uses yield to get data. Now its a generator and driving function can use next and the generator's .send method to pump data into it.
def hangman(chances=5):
for i in range(chances):
letter = yield "prompt"
if letter == "quit":
yield "quit"
return
print("letter", letter)
# do all the things
solved = False
if solved:
yield "solved"
yield "failed"
def command_line_prompt_hangman():
feeder = hangman()
state = next(feeder)
while state == "prompt":
state = feeder.send(input("Next letter: "))
def test():
# after years of testing the best algorithm is
test = ['a', 'b', 'c', 'd', 'e', 'f']
feeder = hangman()
assert next(feeder) == "prompt"
for count, letter in enumerate(test, 1):
state = feeder.send(letter)
if state == "solved":
print("did it in ", count, "tries")
break
if state == "failed":
print("exceeded count")
break
command_line_prompt_hangman()
test()

Instead of using the input function, write a custom function to pull an output from whatever algorithm you are using. That would look something like this:
user_input = algo_obj.get_input(game_state)
In this case, algo_obj would be an object storing the current state of the algorithm/generator (if such a state exists, otherwise you can just call the function normally). game_state would be some representation of the game's current state (available letters, the word-form -- ie. blanks & letters).
You can then feed user_input to your Hangman function.

This should be as simple as:
Define both functions.
Pass one function return value to the other one as argument.
This can be done by using input() as according to this
e.g. Define the functions
def first_function():
input_variable = input("Please enter some data")
return input_variable
def second_function(a):
print(a) # Do some calculations here
And use them:
second_function(first_function())
I wouldn't say that this is necessarily the best way to go about but it solves Your problem. If You would like to receive a more detailed answer please provide code samples.

Trying to make a dice rolling script in python [closed]

Closed. This question needs debugging details. It is not currently accepting answers.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Closed 4 years ago.
Improve this question
I'm getting a vague syntax error with the print int(rollval) on line 15.
from random import randint
roll == 0
def diceroll(roll):
def dicenum(userdicenum):
userdicenum = int(raw_input("How many dice would you like to roll?"))
return userdicenum
def dicesides(userdiceside):
userdiceside = int(raw_input("How many sides for each die?"))
return userdiceside
for rollval in range(1,userdicenum):
rollval = randint(1,userdiceside)
print int(rollval)
roll = roll + rollval
return roll
print roll

from random import randint
def diceroll():
def dicenum():
userdicenum = int(input("How many dice would you like to roll?"))
return userdicenum
def dicesides():
userdiceside = int(input("How many sides for each die?"))
return userdiceside
roll = 0
dicesida = dicesides() # so you dont have to re type it =)
for rollval in range(dicenum()):
rollval = randint(1,dicesida)
print(int(rollval))
roll = roll + rollval
return roll
print(diceroll())
is this what you want?

One difference between Python3 and Python2 is that in Python3, the print statement is a function in Python3, but a keyword in Python2. The fact that it is a function means that you have to use it like any other function, which is by putting the arguments within parenthesis.
Use print(int(rollval))
You should also have a look at the second line. roll == 0 should probably be roll = 0. And as mentioned in comments, you should also not use raw_input in Python3. Use input.

Need a code to allow the user to restart my python quiz at any time [closed]

Closed. This question needs debugging details. It is not currently accepting answers.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Closed 5 years ago.
Improve this question
I would like to know how I could allow my code to let the user restart the quiz at any time throughout the program however, I have no idea how to do this from scratch. It preferably needs to be fairly simple. Would it be easiest doing it as an if statement and if so what would I put in it? I tried this:
while True:
# main program
while True:
answer = raw_input('Run again? (y/n): ')
if answer in ('y', 'n'):
break
print 'Invalid input.'
if answer == 'y':
continue
else:
print 'Goodbye'
break

breaking your problem down into parts is the first step
# 1. ask a question and validate the response
def ask_question(prompt,possible_choices):
while True:
result = raw_input(prompt)
if result in possible_choices:
return result
print "Invalid Response Please Enter One Of:",possible_choices
# 2. run a whole quiz (ask all our questions)
def do_quiz():
answers = []
for question_text in questions_list:
answer = ask_question(question_text,['a','b','c','d','quit','restart')
if answer == "restart":
return False
# instead of returning false we could also simply call recursively
# return do_quiz()
elif answer == "quit":
print "Adios muchacho"
sys.exit(0)
else:
answers.append(answer)
return answers
# 3. play forever (or atleast until the user wants to quit...)
while True:
results = do_quiz()
if not results:
print "Lets Start Over!!"
continue
else:
check_answers(results)
if raw_input("Play again?")[0].lower() == "n":
print "Goodbye!"
sys.exit(1)

Newbie query about conditional statements [closed]

Closed. This question needs debugging details. It is not currently accepting answers.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Closed 6 years ago.
Improve this question
I'm learning Python and can't work out why the following doesn't work.
Can anyone advise? code below
thanks
# Make sure that the_flying_circus() returns True
print "What is your number?"
num = input()
print "What is bla?"
bla = input()
def the_flying_circus():
if num ==4 and bla=="bla": # Start coding here!
return True
print "Well done!"
# Don't forget to indent
# the code inside this block!
elif num == 2 or bla== zog:
print "OK"
# Keep going here.
# You'll want to add the else statement, too!
else:
print "Bad luck!"
the_flying_circus()

The return True is probably not what you want to have on the top of the if block. Try removing it.

The only condition that will return True is num==4 and bla=='bla'. Otherwise, the return value is None. However, 'Well done!' will never be printed since the return statement occurs first.

Couple of things...
1) return True should be moved to the end of the function (as mentioned by others)
2) watch how you collect input... use raw_input for your string, use input for the number.
This works for me:
def the_flying_circus():
if a==4 and b=='bla':
print "Well done!"
elif a==2 or b=="zog":
print "OK"
else:
print "Bad luck!"
return 1
a = input("What is your number? ")
b = raw_input("What is bla? ")
the_flying_circus()