As a newbie to django, I'm having an insanely difficult time figuring out how to upload a folder to the site directory with django. Let me give some context. I'm making a sort of blog. In this blog, I store details on an article in the database, such as headline, author, etc... Then, I write the article in word, save it as an html document, and upload the file to django. All of this can be done through the builtin admin page. But the reason I need to upload an entire folder is because if I use images in my article, Word places them inside a folder with the same name as the article and appends '.fld' to the folder name. Let's say I save an article as 'test.html'. It saves that file and any other files it needs in a folder named 'test.fld' right next to the html file. If I could upload the article and folder along with it, it would make life a lot easier. That being said, the django documentation for uploading multiple files sucks. I was wondering if anyone could give me clearer explanation on how to do this. And if possible, how to upload an entire folder.
Related
I want to create the file(.wav) by django and let it be downloaded by user.
Currently I create the file under /myproj/static directory.
However it is mixed with the other jpg/img files, so,, it's not good design?
then, I read the document about /myproj/media directory but it is said used for user upload files.
So,,, how is the good directory design for server created file?
Should I create such as /myproj/create_wav?
but how can user access this url in template?
Thank you for any idea or helps.
According to Django's documentation,
By default, Django stores files locally, using the MEDIA_ROOT and MEDIA_URL settings. (...) However, Django provides ways to write custom file storage systems that allow you to completely customize where and how Django stores files.
So, in OP's shoes I'd simply use the media folder, since that's used not only for user uploads but also for user downloads.
I'm making an app which gets data from a csv file and generates a graph using it. All files contains the same structure. I've decided I'm not going to store the files, because of server prices. I'm going to use heroku for now to host this app. It's a Django app. I'm wondering how I could only open the file and extract the data of it using django. I've thought about creating a model and save each file content on it. How can I do this? Is this the best option for my case?
I'll assume you're using Django 1.9 (if not, please update your question to reflect your version of Django).
First, using the HTML <form> tag, you'll want to include enctype="multipart/form-data" as an attribute.
Assuming you'll name your <input> tag as myFile (<form name="myFile">), in your view, simply extract the file from request.FILES:
def my_file_upload(request):
if request.method == 'POST':
myFile = request.FILES.get('myFile')
# At this point, myFile is an instance of UploadedFile, see
# https://docs.djangoproject.com/en/1.9/ref/files/uploads/ for details
Read up on uploaded files in the Django documentation to see the caveats associated with this approach.
My django application has a file uploader which uploads to a specific location in my local system.
It redirects to a new html page which shows successful message after upload is done.
Once the file is uploaded I need to do some processing of csv files.
I have a python code which does the processing.
Now my question is, where do I put the python file in the django project and how do i call it to be run once the upload is done?
Any help is appreciable
Thanks in advance
You can place it anywhere you like, it's just Python. Maybe in a csv_processing.py if it fits in a single module, or as a completely independent library if it's more. Django doesn't have an opinion on this.
The best way to run it is by doing it asynchronously using Celery.
Make sure the file is within a python package, you do this by adding init.py to the directory, documentation here. In accordance to Django convention; you would place the file within the app that needs to use it, or within another app you would name utils, documentation here.
Question:
I need the file to be run completely after the application uploads the file.
Answer:
new = Storage()
new.file = request.FILES['file']
new.save()
Now we have the database id. (When file object saved into database it emits the id).
originalObj = Storage.objects.get(pk=new.id)
Now you can import the csv file and do modification here.
I am creating an application in django where I want to upload multiple file from django admin. I also want these files to be associated with a particular user in my database. for e.g a pdf file will have a file names as 'john.pdf', 'matt.pdf', 'alice.pdf' and I want to upload all these files at once from django admin and each file should be associated with particular user, so if user john logs in he can see pdf 'john.pdf' in his profile page.
I am new to django and web programming and I have been banging my head for a couple of days but I just cannot find the right logic to implement such a code.
I have looked in these resources but I still cannot really find an answer
How to upload multiple file in django admin models
How to upload through django admin.
I am using django with mysql database. I highly appreciate and thank anyone in advance who could help me out with this problem. (hoping not to get downvoted too much)
Ok so I found out a solution but I still don't know if thats the best solution there. What I did was to add path of my pdf files in MySQL database and add attributes to those paths. I wrote a script in python to add those files to MySQL database. My script listed all the files in the directory, where the files were stored and added them to the database. From these attributes I could retrieve those paths. As these are just paths to static files I had to save them in the static folder for django to access and display them and the rest was simple.
I currently have a django app which generates PDFs and saves them to a specific directory. From the admin interface I want to have some way to view the list of files within that directory (similar to models.FilePathField()), but also be able to download them. I realize that django was never intended to actually serve files, and I have been tinkering with django-sendfile, as a possible option. It just doesn't seem like there is any way to create a dynamic list of files other than with FilePathField (which I don't believe can suite my purposes).
Would this project fit your needs? http://code.google.com/p/django-filebrowser/
I ended up realizing that I was going about the problem in a more complicated manner than was necessary. Using two separate views trivializes the issue. I was just under the impression that the admin interface would include such a basic feature.
What I did was create a download_list view to display the files in the directory, and a download_file view which uses django-sendfile to serve the file to the end-user. Download_file simply parses through the directory with listdir(), checks if the extension is valid and sends the complete file path to the download_file function (after the user selects one).
Are the files in a directory that is served by your webserver? If all you want to do is list and download the files, it may be easier just to have a link to the directory with all the files in it and let the webserver take care of listing and serving the files. I understand this may not be the ideal solution for you, but it does avoid having Django serve static files, which is a task best left to the webserver.