How to call back the same window!? PYQT5 - python

I spent all day debugging and stripping my project to fix this issue.
I have a help window(Help_ui class) which should open if the text.txt is not found and the main window(Main class)which has a QTextEdit box which should print "Hello".
The problem is that when I call the Main window from the Help_ui class it doesn't print "Hello", but it does if I call it from the logic.
Why is doing this, does it open another instance of that windows and not the proper window?
from PyQt5 import QtWidgets
import sys
from pathlib import Path
from ui_files import mainWindow
from ui_files import help_ui
text = "Hello"
class Main(QtWidgets.QMainWindow, mainWindow.Ui_mainWindow):
def __init__(self, text):
super().__init__()
self.setupUi(self)
self.mainTextEdit.setText(text)
class Help_ui(QtWidgets.QDialog, help_ui.Ui_help):
def __init__(self):
super().__init__()
self.setupUi(self)
self.close_btn.clicked.connect(self.close)
self.form = Main(None)
self.form.show()
if __name__ == "__main__":
app = QtWidgets.QApplication(sys.argv)
form = Main(text)
my_file = Path("file.txt")
if my_file.is_file():
form.show()
else:
help_window = Help_ui()
help_window.show()
app.exec_()

What happens is that the instance form is different from the instance self.form, in the first you pass as a parameter text, instead in the second None.
Must be change self.form = Main(None) to self.form = Main(text)

Related

Access data from the parent window in a child window in PyQt

I have two windows (App.py and ChildApp.py) and .ui files for both with same name.
App.py:
import sys
from PyQt4 import QtCore, QtGui, uic
from ChildApp import ChildApp
qtCreatorFile = "App.ui" # Enter file here.
Ui_MainWindow, QtBaseClass = uic.loadUiType(qtCreatorFile)
class App(QtGui.QMainWindow, Ui_MainWindow):
def __init__(self):
QtGui.QMainWindow.__init__(self)
Ui_MainWindow.__init__(self)
self.setupUi(self)
self.message = None
self.child_window = ChildApp()
self.pushButton.clicked.connect(self.sendMessage)
def sendMessage(self):
self.message = self.lineEdit.text()
self.child_window.show()
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
window = App()
window.show()
sys.exit(app.exec_())
ChildApp.py:
import sys
from PyQt4 import QtCore, QtGui, uic
qtCreatorFile = "ChildApp.ui" # Enter file here.
Ui_MainWindow, QtBaseClass = uic.loadUiType(qtCreatorFile)
class ChildApp(QtGui.QMainWindow, Ui_MainWindow):
def __init__(self):
QtGui.QMainWindow.__init__(self)
Ui_MainWindow.__init__(self)
self.setupUi(self)
self.pushButton.clicked.connect(self.alertmessage)
def alertmessage(self):
message = "test"
self.label.setText("Message : "+message)
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
window = ChildApp()
window.show()
sys.exit(app.exec_())
In Main.py file I have a variable self.message.
When I click on the button "Do something with text", text in the textbox is assigned to self.message and the child window is opened.
Now in the child window, when I click on button "Show message", the method alertmessage() is called, where it sets message = "text".
This variable message must be assigned to value of self.message from MainApp.py.
Please help
Thank you
Call the child that way:
self.child_window = ChildApp(parent=self)
Define the child app this way:
class ChildApp(QtGui.QMainWindow, Ui_MainWindow):
def __init__(self, parent):
self.parent = parent
you can use the parent variables through self.parent.whatever
It must work, but I wouldn't advise this because you are not supposed to know the fields of the parent form the child.
I don't think you can get local data from the parent. I would do the following:
Use a signal to update the child when the text is changed in the lineEdit:
self.lineEdit.textChanged.connect(self.updateChild)
Add this function in the main window:
def updateChild(self):
self.child_window.setMessage(self.lineEdit.text())
and keep the variable self._message updated in the child window:
def setMessage(self, message):
self._message=message
so that whenever you need this variable, it is up to date

PySide \ PyQt: How to return value to UI after button click?

I am trying to return a path from a browse folder dialog box.
I have tried passing the instance object or even attribute to the call and setting it there:
self.browseBtn.clicked.connect(myExporter.browseFolder(self))
or
self.browseBtn.clicked.connect(myExporter.browseFolder(self.path))
But this doesn't work. It causes the browser dialog to pop open immediately upon load and then once you choose a folder it errors out with : Failed to connect signal clicked().
I have tried to set the clicked call to a return, with no luck:
result = self.browseBtn.clicked.connect(myExporter.browseFolder)
Can someone lead me in the right direction as far as how to return a value, when you are dealing with separate classes handling the UI and logic? Also... is it bad practice to be separating them like this? I know I could probably easily solve this if I threw everything into just one python file, but I figured that is not proper.
Here is my ui file (ui.py):
from PySide import QtCore, QtGui
class Ui_Dialog(object):
def __init__(self):
self.path =""
def setupUi(self, Dialog, myExporter):
Dialog.setObjectName("Dialog")
Dialog.resize(382, 589)
...
.......
.............
.................
self.retranslateUi(Dialog)
self.tabWidget.setCurrentIndex(1)
QtCore.QMetaObject.connectSlotsByName(Dialog)
self.browseBtn.clicked.connect(myExporter.browseFolder)
Here is my exporter file (exporter.py):
class Exporter(object):
def __init__(self):
...
......
def browseFolder(self):
...
.......
do something
...........
return path
Here is my load/test file (loadExporter.py):
import ui as interface
import exporter as exporter
from PySide import QtCore, QtGui
app = QtGui.QApplication.instance()
if app is None:
app = QtGui.QApplication(sys.argv)
Dialog = QtGui.QDialog()
myExporter = exporter.Exporter()
myUI = interface.Ui_Dialog()
myUI.setupUi(Dialog, myExporter)
Dialog.show()
app.exec_()
It's not necessarily bad to have them in separate files. Having a separate file for certain widgets is a good thing especially if those widgets can be reused.
I would have my main file have a QMainWindow class.
class MyWindow(QtGui.QMainWindow):
pass
if __name__ == "__main__":
QtGui.QApplication([])
mywindow = MyWindow()
mywindow.show()
sys.exit(QtGui.qApp.exec_())
Wrapping the app functionality in if __name__ == "__main__" prevents this code from being run when another file tries to import this file.
A signal (self.browserBtn.clicked) calls a callback method. Everything is an object in python.
def my_func():
pass
new_func_name = my_func # my_func can be reassigned like any variable
my_func is an object. self.browseBtn.clicked.connect(my_func) passes my_func as a variable to be called later.
When self.browserBtn.clicked.emit() happens (on user click) it is the same as calling the connected functions my_func(). Other signals may pass values to callback functions self.lineEdit.textChanged.connect(my_func) calls 'my_func(new_text)'
You want your function to call everything for you.
def open_file(filename=None):
"""Open a file."""
# If a filename isn't given ask the user for a file
if filename is None:
filename, ext = QtGUi.QFileDialog.getOpenFileName(None, "Open File", ".../My Documents/")
# You may have to use the ext to make a proper filename
# Open the file
with open(filename, "r") as file:
file.read()
self.browserBtn.clicked.connect(open_file)
Structure
...
import mywidget
class MyWindow(QtGui.QMainWindow):
def __init__(self):
super().__init__()
...
self.show_file = QtGui.QLineEdit()
self.setCentralWidget(self.show_file)
self.exporter = mywidget.Exporter()
self.browserBtn.clicked.connect(self.open_file)
def open_file(self, filename=None):
"""Open a file."""
path = self.exporter.browseFolder()
# Do something with the path
self.show_file.setText(path)
if __name__ == "__main__":
QtGui.QApplication([])
mywindow = MyWindow()
mywindow.show()
sys.exit(QtGui.qApp.exec_())
I don't think I fully understand what you're trying to achieve, but may I suggest the following solution.
exporter.py
# implementation
dialog.py (Main UI)
import PyQt4.QtGui as qg
from exporter import Exporter
class Dialog(qg.QDialog):
def __init__(self):
super().__init__()
self.path = None
self.setup_widgets()
def setup_widgets(self):
self.browse.clicked.connect(self.on_browse_clicked)
def on_browse_clicked(self):
self.path = Exporter().browse_folder()
main.py
import sys
import PyQt4.QtGui as qg
from dialog import Dialog
if __name__ == '__main__':
app = qg.QApplication(sys.argv)
dialog = Dialog()
dialog.show()
sys.exit(app.exec_())
This way you still have three files, but dialog.py imports exporter.py instead of main.py importing both of them.
As for returning values from signals, I don't know; I think signals are voids (do not return values).
Signals pass arguments to slots via their formal parameters. Usually slots have the same or fewer parameters than their signal counterparts'. It's slots that return values.

PyQt lineEdit is empty when called from another script

This is my mainscript which calls some generated UI and defines a few functions:
import uifile
from PyQt5 import QtWidgets
import sys
class App(QtWidgets.QMainWindow, uifile.Ui_MyWindow):
def __init__(self):
super(self.__class__, self).__init__()
self.setupUi(self)
self.btn_clickMe.clicked.connect(self.some_function)
return
def some_function(self):
import otherpyscript
def input_user(self):
user = self.lineEdit_username.text()
return user
def main():
app = QtWidgets.QApplication(sys.argv)
form = App()
form.show()
app.exec_()
if __name__ == '__main__':
main()
This is the other script where I call the function from mainscript:
...
import mainscript
print("The user input from your other script is: " + mainscript.App().input_user())
I'm trying to get mainscript.App().input_user() to not show up as empty (the default for PyQt).
EDIT:
On second thoughts, the right approach depends on how mainscript is used. If it is used as the start-up script, it will not be initially imported, which then complicates things when it comes to accessing its globals later on.
A better approach is to have a very simple start-up script that only has this in it:
# mainscript
if __name__ == '__main__':
from mainmodule import main
main()
The mainmodule would then look like this:
# mainmodule
import sys
from PyQt5 import QtWidgets
import uifile
class App(QtWidgets.QMainWindow, uifile.Ui_MyWindow):
def __init__(self):
super().__init__()
self.setupUi(self)
self.btn_clickMe.clicked.connect(self.some_function)
def some_function(self):
import othermodule
othermodule.print_user()
def input_user(self):
user = self.lineEdit_username.text()
return user
form = None
def main_window():
return form
def main():
global form
app = QtWidgets.QApplication(sys.argv)
form = App()
form.show()
app.exec_()
And othermodule would look like this:
# othermodule
import mainmodule
def print_user():
print("user input: " + mainmodule.main_window().input_user())

PyQt4 signals and slots - QToolButton

In PyQt4 I have a main window which when the settings button is clicked opens the settings dialog
from PyQt4 import QtCore, QtGui
import ui_Design, ui_Settings_Design
class MainDialog(QtGui.QMainWindow, ui_Design.Ui_arbCrunchUI):
def __init__(self, parent=None):
super(MainDialog, self).__init__(parent)
self.setupUi(self)
self.settingsBtn.clicked.connect(lambda: self.showSettings())
def showSettings(self):
dialog = QtGui.QDialog()
dialog.ui = SettingsDialog()
dialog.ui.setupUi(dialog)
dialog.exec_()
The above works and my SettingsDialog is displayed but I cant get the setPageIndex to work
class SettingsDialog(QtGui.QDialog, ui_Settings_Design.Ui_SettingsDialog):
def __init__(self, parent=None):
super(SettingsDialog, self).__init__(parent)
self.setupUi(self)
self.bookSettingsBtn.clicked.connect(self.setPageIndex)
#QtCore.pyqtSlot()
def setPageIndex(self):
print 'selected'
self.settingsStackedWidget.setCurrentIndex(0)
The bookSettingsBtn is a QToolButton
self.bookSettingsBtn = QtGui.QToolButton(self.navigationFrame)
And the settingsStackedWidget is a QStackedWidget
self.settingsStackedWidget = QtGui.QStackedWidget(SettingsDialog)
At this point I am pretty confused on signals and slots and nothing I have read clears this up - if anyone can point out what I am doing wrong above and also potentially direct me to a good (beginners) guide / tutorial on signals and slots it would be greatly appreciated
I would also like to know how to make setPageIndex work as follows:
def setPageIndex(self, selection):
self.settingsStackedWidget.setCurrentIndex(selection)
I'm not sure why you're doing the following, but that's the issue:
def showSettings(self):
dialog = QtGui.QDialog()
dialog.ui = SettingsDialog()
dialog.ui.setupUi(dialog)
dialog.exec_()
SettingsDialog itself is a proper QDialog. You don't need to instantiate another QDialog.
Right now, you're creating an empty QDialog and then populate it with the same ui as SettingsDialog (i.e. setupUi(dialog)), then you show this dialog. But... The signal connection is for SettingsDialog, and the dialog you're showing doesn't have that.
Basically, you don't need that extra QDialog at all. The following should be enough:
def showSettings(self):
dialog = SettingsDialog()
dialog.exec_()
Ok. So here is an example how you pass an argument to a slot
from functools import partial
# here you have a button bookSettingsBtn:
self.bookSettingsBtn = QtGui.QPushButton("settings")
self.bookSettingsBtn.clicked.connect(partial(self.setPageIndex, self.bookSettingsBtn.text()))
#pyqtSlot(str) # this means the function expects 1 string parameter (str, str) 2 string parameters etc.
def setPageIndex(self, selection):
print "you pressed button " + selection
In your case the argument would be an int. Of course you have to get the value from somewhere
and then put it in the partial part as the argument (here I just used the text of the button),
but you can use int, bool etc. Just watch the slot signature.
Here is a tutorial that helped me:
http://zetcode.com/gui/pyqt4/
I hope this helps.
Hey here I have a fully running example (just copy paste it in a python file and run it):
Maybe this helps you. It's a small example but here you see how it works.
from PyQt4.QtCore import *
from PyQt4.QtGui import *
from functools import partial
class MyForm(QMainWindow):
def __init__(self, parent=None):
super(MyForm, self).__init__(parent)
button1 = QPushButton('Button 1')
button2 = QPushButton('Button 2')
button1.clicked.connect(partial(self.on_button, button1.text()))
button2.clicked.connect(partial(self.on_button, button1.text()))
layout = QHBoxLayout()
layout.addWidget(button1)
layout.addWidget(button2)
main_frame = QWidget()
main_frame.setLayout(layout)
self.setCentralWidget(main_frame)
#pyqtSlot(str)
def on_button(self, n):
print "Text of button is: " + str(n)
if __name__ == "__main__":
import sys
app = QApplication(sys.argv)
form = MyForm()
form.show()
app.exec_()
So I dont really understand why but changing the way the settingsDialog is called from the MainWindow has fixed my problem. I guess the parent window needed to be specified??:
class MainDialog(QtGui.QMainWindow, ui_Design.Ui_arbCrunchUI):
....
def showSettings(self):
self.settingsDialog = QtGui.QDialog(self)
self.settingsDialog.ui = SettingsDialog(self)
self.settingsDialog.ui.show()
class SettingsDialog(QtGui.QDialog, ui_Settings_Design.Ui_SettingsDialog):
def __init__(self, parent=None):
super(SettingsDialog, self).__init__(parent)
self.setupUi(self)
self.bookSettingsBtn.clicked.connect(partial(self.setPageIndex, 1))
#QtCore.pyqtSlot(int)
def setPageIndex(self, selection):
self.settingsStackedWidget.setCurrentIndex(selection)

How to connect a signal from the controller in PyQt4? (iOS like MVC structure in PyQt4)

Why doesn't the following example work?
from PyQt4 import QtGui
import sys
class TestView(QtGui.QWidget):
def __init__(self):
super(TestView, self).__init__()
self.initUI()
def initUI(self):
self.btn = QtGui.QPushButton('Button', self)
self.btn.resize(self.btn.sizeHint())
self.btn.move(50, 50)
class TestViewController():
def __init__(self, view):
view.btn.clicked.connect(self.buttonClicked)
view.show()
def buttonClicked(self):
print 'clicked'
def main():
app = QtGui.QApplication(sys.argv)
view = TestView()
TestViewController(view)
app.exec_()
if __name__ == '__main__':
main()
The example is supposed to represent an MVC structure (like the one in Figure 4 -- without the Model) where the controller (TestViewController) receives a reference to the view (TestView) and connects the clicked signal from the view's button view.btn to its function self.buttonClicked.
I'm sure the line view.btn.clicked.connect(self.buttonClicked) is executed but, apparently, it has no effect. Does anyone knows how to solve that?
Update (awful solution):
In the example, if I replace the line
view.btn.clicked.connect(self.buttonClicked)
with
view.clicked = self.clicked
view.btn.clicked.connect(view.clicked)
it works. I'm still not happy with that.
The reason it is not working is because the controller class is being garbage collected before you can ever click anything for it.
When you set view.clicked = self.clicked, what you're actually doing is making one of the objects from the controller persist on the view object so it never gets cleaned up - which isn't really the solution.
If you store your controller to a variable, it will protect it from collection.
So if you change your code above to read:
ctrl = TestViewController(view)
You'll be all set.
That being said - what exactly you are trying to do here, I am not sure...it seems you're trying to setup an MVC system for Qt - but Qt already has a pretty good system for that using the Qt Designer to separate the interface components into UI (view/template) files from controller logic (QWidget subclasses). Again, I don't know what you are trying to do and this may be a dumb down version of it, but I'd recommend making it all one class like so:
from PyQt4 import QtGui
import sys
class TestView(QtGui.QWidget):
def __init__(self):
super(TestView, self).__init__()
self.initUI()
def initUI(self):
self.btn = QtGui.QPushButton('Button', self)
self.btn.resize(self.btn.sizeHint())
self.btn.move(50, 50)
self.btn.clicked.connect(self.buttonClicked)
def buttonClicked(self):
print 'clicked'
def main():
app = QtGui.QApplication(sys.argv)
view = TestView()
view.show()
app.exec_()
if __name__ == '__main__':
main()
Edit: Clarifying the MVC of Qt
So this above example doesn't actually load the ui dynamically and create a controller/view separation. Its a bit hard to show on here. Best to work through some Qt/Designer based examples/tutorials - I have one here http://bitesofcode.blogspot.com/2011/10/introduction-to-designer.html but many can be found online.
The short answer is, your loadUi method can be replace with a PyQt4.uic dynamic load (and there are a number of different ways to set that up) such that your code ultimately reads something like this:
from PyQt4 import QtGui
import PyQt4.uic
import sys
class TestController(QtGui.QWidget):
def __init__(self):
super(TestController, self).__init__()
# load view
uifile = '/path/to/some/widget.ui'
PyQt4.uic.loadUi(uifile, self)
# create connections (assuming there is a widget called 'btn' that is loaded)
self.btn.clicked.connect(self.buttonClicked)
def buttonClicked(self):
print 'clicked'
def main():
app = QtGui.QApplication(sys.argv)
view = TestController()
view.show()
app.exec_()
if __name__ == '__main__':
main()
Edit 2: Storing UI references
If it is easier to visualize this concept, you Can also store a reference to the generated UI object:
from PyQt4 import QtGui
import PyQt4.uic
import sys
class TestController(QtGui.QWidget):
def __init__(self):
super(TestController, self).__init__()
# load a view from an external template
uifile = '/path/to/some/widget.ui'
self.ui = PyQt4.uic.loadUi(uifile, self)
# create connections (assuming there is a widget called 'btn' that is loaded)
self.ui.btn.clicked.connect(self.buttonClicked)
def buttonClicked(self):
print 'clicked'
def main():
app = QtGui.QApplication(sys.argv)
view = TestController()
view.show()
app.exec_()
if __name__ == '__main__':
main()

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