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Meaning of end='' in the statement print("\t",end='')? [duplicate]
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Closed 4 years ago.
I just started python few days ago, and didn't really understand end =' ' in nested loop. Can anybody explain me this
count=0
for i in range(10):
for j in range(0, i):
print (count, end='')
count +=1
print()
'' is the "empty string" (e.g. nothing). The "end" parameter is what gets printed after the preceding set of variables. The default value of "end" is the newline (i.e. subsequent print statements will begin on a new line). By specifying '', the loop above will literally print out
1
22
333
4444
55555
666666
7777777
88888888
999999999
with each inner loop result on a single line. Without the end='' param, it would get printed out as:
1
2
2
3
3
3
...
9
9
The final print() at the end of the inner loop, just prints a new line.
End is print function keyword argument. The default value of end is \n meaning that after the print statement it will print a new line. If you redefine end, print will output your redefined value after using.
print("123", end="=")
#prints '123='
'' means empty string, so, you wil get output with no delimiters.
The default value of end is \n meaning that after the print statement it will print a new line. So simply stated end is what you want to be printed after the print statement has been executed,
prints an according Count value and stays in the same line. If you left out the end='' each time a newline would be printed
We learn everything by doing, So lets suppose we remove that end="" at the end of the print function. So you code will look like this
count=0
for i in range(10):
for j in range(0, i):
print (count)
count +=1
print()
and the output will be as
1
2
2
3
3
3
...
Now this output may or may not be your desired output depending on where you want to use the code
you may be wondering why this happens when you have not specified python to add a new line, its due to the fact that print function add new line character at the end of the output by default so if you doesnot want that to happen add end="" for the output line end with a empty string or nothing. likewise use end="/t" for tab end="." to end the print statement with a period and so on.
ProTip
use
print()
when ever you want a new line in or out of a loop
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the expected out put was
1 1
2 2
3 3
4 4
5 5
but the output I got is
1
1 2
2 3
3 4
4 5
5
for num in numlist:
print(num)
print(num,end=' ')
I tried to execute this python code in python interpreter and got the wrong output
Every print has an end. Unless you overwrite what print should end in, it ends in a new line. In your first print, you don't overwrite end, so you get a new line. In your second print command, you do overwrite end with a single whitespace.
What you get is this order:
1st print NEWLINE
2nd print SPACE 1st print NEWLINE
2nd print SPACE 1st print NEWLINE
...
You get the exact output you are asking for. I suggest you read the entire Input/Output section of this geeksforgeeks page: https://www.geeksforgeeks.org/taking-input-in-python/?ref=lbp
newline ('\n') is the default end character. Therefore the first call to print() will emit the value of num followed by newline.
In the second print you override the end character with space (' ') so no newline will be emitted.
When you print multiple values, the default separator is a space. This means that you can achieve your objective with:
for num in numlist:
print(num, num)
I'v done a code challenge and one of the extras was write a line of code that prints the previous result (which I have done)
print(str(year)*int(number))
but it also says to put a line break between each returned value.
So for example the var 'year' returns an int and that int gets printed a certain
amount of times depending on what the users input is.
I just can't figure out where the '\n' will go in this line of code.
print(str(year)*int(number))
You could use a simple loop:
for _ in range(number):
print(year)
This will insert the \n by default - as each print is a seperate command and the default end=\n parameter to print applies.
Patrick Haugh beat me by 50sec to use the print-commands parameter sep that lets you specify what to put between printed values:
print(1,2,3,4,sep="\n")
This prints a newline between each of the numbers - by default it prints a single space.
You could put the collected numbers in a list, decomposit the list in its element and print them with a \n seperator:
year = 18
number= 3
print( *[year]*number ,sep="\n")
More can be found in the
print(*objects, sep=' ', end='\n', file=sys.stdout, flush=False) documentation.
You can print a separator character between separate arguments to print that will appear between them instead of a space
print('a', 'b', sep='\n')
We can use argument unpacking to provide number many arguments to print, and separate them with '\n'
year = 2000
number = 5
print(*[year]*number, sep='\n')
prints
2000
2000
2000
2000
2000
I am in an introduction to Anaconda class and I need to write a program to determine how many times a dice roll(s) land on a certain amount of faces. However, I cannot get it to print my answer correctly.
Your problem is your print statement. You try to print a string then something called end then another string, and so forth. I think you want that end to be an end-of-line character.
Instead of printing something like
print("a string" end "another string" end "a third string")
use
print("a string\n" "another string\n" "a third string")
Note that "\n" is the end-of-line character in Python. My code also uses a feature of Python where you can combine string literals by placing them next to each other. Let lets you see the individual lines more clearly. Your code failed because you tried to do this with a string variable, namely end, and you did not even define that variable.
From Python docs: https://docs.python.org/3/library/functions.html#print
print(*objects, sep=’ ‘, end=’\n’, file=sys.stdout, flush=False)
As you can see, the end is one of the parameters for the print() function, and by default, end=’\n’. So to use it correctly, you just have to change the end variable (which may not be directly applicable to your code)
Here are some examples:
>>> for i in range(3):
print(i, end =' ')
0 1 2
>>> for i in range(3):
print(i, end ='')
012
>>> for i in range(3):
print(i) # by default end=\n
0
1
2
>>>
And also, if I am understanding your logic correctly, the same code can be re-written as such.
import random
RollDice = int(input("Number of Rolls:"))
numbers = [0 for _ in range(6)] # array of 6 spaces with int 0
for i in range(RollDice):
Roll = random.randint(1,6)
numbers[Roll-1] += 1 # the array index starts from 0 hence you need Roll-1
plusMinus = "+-----"*6 + "+\n" # since you are repeating this you might want to assign it to a variable
print(plusMinus + "| 1 | 2 | 3 | 4 | 5 | 6 |\n" + "| " + " | ".join(map(str,numbers)) + " |\n" + plusMinus)
P.S. Rather than attaching an image, please copy and paste your code next time, so that we can copy n paste to test.
I am trying to create a for loop where the user inputs a number n and the output provides the range of values from n to n+6. This needs to all be printed in one row and be right aligned with spaces in between value outputs but no space at the end or start of the output.
So far this is what I've come up with:
n=eval(input("Enter the start number: "))
for n in range(n,n+7):
print("{0:>2}".format(n),end=" ")
However, this results in the following output:
-2 -1 0 1 2 3 4 <EOL>
When the output I want needs to look similar but without the space at the end, like so:
-2 -1 0 1 2 3 4<EOL>
How can I add spaces between values without adding an additional space to the final term?
There are 3 recommendations I could make:
use end="" and insert the whitespaces manually
create a string and print after the loop:
s = ""
for n in range(n, n+7):
s+= str(n)+ " "
s = s[:-1] #remove the ending whitespace
print(s)
which I recommend: Using sys.stdout.write instead print:
print only displays the message after a linebreak was printed. So if there is a long calculation in the loop and there is end=" " you will only see the resulr at the end of all calculations. Use sys.stdout instead
for n in range(n, n+7):
if n < n+7:
sys.stdout.write(str(n)+" ")
else:
sys.stdout.write(str(n))
sys.stdour.flush() #flush output to console
Edit: I evolved a bit and this is what I'd use nowadays:
4. message = " ".join(range(n, n+7))
This puts spaces between all elements of a list. You can choose any separation character instead of a space (or multiple characters).
This question already has answers here:
How can I print multiple things on the same line, one at a time?
(18 answers)
Closed last month.
Is it possible to print text on the same line in Python?
For instance, instead of having
1
2
3
I would have
1 2 3
Thanks in advance!
Assuming this is Python 2...
print '1',
print '2',
print '3'
Will output...
1 2 3
The comma (,) tells Python to not print a new line.
Otherwise, if this is Python 3, use the end argument in the print function.
for i in (1, 2, 3):
print(str(i), end=' ') # change end from '\n' (newline) to a space.
Will output...
1 2 3
Removing the newline character from print function.
Because the print function automatically adds a newline character to the string that is passed, you would need to remove it by using the "end=" at the end of a string.
SAMPLE BELOW:
print('Hello')
print('World')
Result below.
Hello
World
SAMPLE Of "end=" being used to remove the "newline" character.
print('Hello', end= ' ')
print('World')
Result below.
Hello World
By adding the ' ' two single quotation marks you create the space between the two words, Hello and World, (Hello' 'World') - I believe this is called a "blank string".
when putting a separator (comma) your problem is easily fixed. But obviously I'm over four years too late.
print(1, 2, 3)