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I'm wondering if there is some built in function in python that will change whatever the sign of an integer is to its opposite.
example of what I'm looking for:
num = 1
num2 = -2
# where flip() is a hypothetical function
flip(num)
flip(num2)
print(num)
print(num2)
>>> -1
>>> 2
I know how to create my own function to do this, but it seems there may be a built-in, or some short hand way to go about it.
So this was actually way more simple than I was trying to make it.
num1 = 1
num1 = -num1
print(num1)
>>> -1
num1 = -num1
print(num1)
>>> 1
Two negatives equal a positive
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does anyone know why I can't subtract a variable from another variable if both are defined as numbers?
A = 100
B = int(input("Amount? "))
A - B
print(A)
This is a very simplified version of what it actually is but still the same concept, I am quite new to coding so sorry if this is really dumb of me to ask. Thanks :)
Replace A - B to A = A - B or use the shorthand notation A -= B which is the same as the first alternative.
You are never assigning the value to A.
Here is the corrected code:
A = 100
B = int(input("Amount? "))
A = A - B #Issue was here
print(A)
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i can not get My python code to work it does not replay after i give a answer
Weight = input("Weight: ")
lbsorkg = input("(L)bs or (K)g: ")
if lbsorkg.upper == "K":
FinalPounds = float(Weight) * 2.205
print(f"You are {FinalPounds} pounds")
And I get this
Weight: 12
(L)bs or (K)g: k
Please help me slove this issue
the problem is with the strings' attribute upper, which is not a simple attribute but an instance function.
You must call it, like this:
>>> "k".upper()
'K'
In your case, you should call lbsorkg.upper(), like this:
if lbsorkg.upper() == 'K':
...
I don't understand what's wrong with this.
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I encountered a floating point problem when dealing with flow:
a = "0.0003"
b = pow(10, 4)
c = int(float(a) * b)) // int so i don't want the decimal places behind
i got the following result 2.9999999999999996 which is wrong
I also tried decimal:
c = int(Decimal(a) * Decimal(pow(10, 4)))
but still got the wrong result 2.999999999999999737189393390
Expected result is 3
In Javascript we can use bignumber.js
Is there a way i can avoid this kind of problem in python? maybe some library like in javascript
Thanks
Make sure a is the string, not the float. Then it should work.
int(Decimal('0.0003') * pow(10, 4))
# returns 3
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i want to detect when the program sees the value 26, i have a function that looks like this
val = 26
for n in range (0,101):
if n in val:
print(n,"is the value i am looking for")
break
else:
print(n)
I keep getting this error:
TypeError: argument of type 'int' is not iterable
What is wrong with this function
n in val checks whether the value n is in the iterable val. The correct check here is n == val
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def kaka(name):
r=''
for ch in name:
r=r+ch*3
return r
Output:
>>> kaka('Mississippi')
>>> 'MMMiiissssssiiissssssiiippppppiii'
But for this code:
def kaka(name):
for ch in name:
r=''
r=r+ch*3
return r
I am getting output as: iii
That's because in your second code you're re-assigning r back to the empty string ''. Thus you only get the final character multiplied 3 times (which for Mississippi is i).
You are getting 2 different outputs because in the first code you are initialising the value of r i.e r = '' outside the for loop and in the second program you are initialising value of r inside the for loop.