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How to Default Value in a Form from another Form in Django

I have two forms, one CreateOrderForm and one CreateManifestForm. Submitting CreateOrderForm renders CreateManifestForm.
There is an input in CreateOrderForm 'reference' which is user entered but then should default into the 'reference field of CreateManifestForm. I seem to be unable to figure out how to pass that value from form to form
FORMS.PY
class CreateOrderForm(forms.ModelForm):
class Meta:
model = Orders
fields = ('reference', 'ultimate_consignee', 'ship_to', 'vessel', 'booking_no', 'POL',....)
class CreateManifestForm(forms.ModelForm):
class Meta:
model = Manifests
fields = ('reference', 'cases', 'description', 'count')
VIEWS.PY
def add_order(request):
if request.method == "POST":
form = CreateOrderForm(request.POST)
if form.is_valid():
form.save()
return redirect('add_manifest')
else:
form = CreateOrderForm()
return render(request, 'add_order.html', {'form': form})
def add_manifest(request):
if request.method == "POST":
form = CreateManifestForm(request.POST)
if form.is_valid():
form.save()
return redirect('add_manifest')
form = CreateManifestForm()
manifests = Manifests.objects.all()
context = {
'form': form,
'manifests': manifests,
}
return render(request, 'add_manifest.html', context)
As you can see there is a field in each form for 'reference' I would like to user enter it in CreateOrderForm and pass that value to default when creating the manifest. Any help is greatly appreciated and thank you in advance.

There is a solution that you can try:
make the add_manifest URL have a Parameter like
path('add-manifest/<int:reference_id>/', name='add_manifest`)
and in your View update:
return redirect('add_manifest') # in add_order function
to:
return redirect('add_manifest', kwargs={'reference_id': form.reference})
now in the add_manifest View you can access the Reference from:
request.resolver_match.kwargs.get('reference_id')

How to create a unique reference for the result each time?

In general, I make a page on the site. The meaning is this: a person comes in, loads an xml file, selects several parameters, and outputs the result. I did not find how to handle the xml file at once. So I upload its file with the parameters to the database, and then redirect us to the page with the result. Everything works fine, but there is a problem. I have not figured out how to create a unique link for the result each time. Now I have one link for the results and it just shows the last one ...
views.py of uploader
def upload_file(request):
if request.method == 'POST':
form = DocumentForm(request.POST, request.FILES)
if form.is_valid():
form.save()
return redirect('lessons:index')
else:
form = DocumentForm()
return render(request, 'templates/upload/upload.html', {'form': form})
downloader
views.py of handler
def lessons_view(request):
a = keker()
return render(request, 'templates/lessons/ocenki.html', {'ocenki': a})
keker if handler function

Try code like this (python 3.6):
# models.py
class Document(Model):
...
reference = CharField(max_length=128, db_index=True, null=False)
...
# forms.py
import secrets
...
class DocumentForm(ModelForm):
...
def save(self, commit=True):
self.instance.reference = secrets.token_hex(128)
return super().save(commit)
# views.py
...
def upload_file(request):
if request.method == 'POST':
form = DocumentForm(request.POST, request.FILES)
if form.is_valid():
form.save()
return redirect('lessons:index', kwargs=dict(reference=form.instance.reference))
else:
form = DocumentForm()
return render(request, 'templates/upload/upload.html', {'form': form})
...
def lessons_view(request, reference):
a = keker(reference)
return render(request, 'templates/lessons/ocenki.html', {'ocenki': a})
# urls.py
...
url(r'^/(?P<reference>\w+)/$', 'index', name='index'),
...

django - how to redirect page after save modelform

I want to redirtect page, after saving modelform. when i pushed save button, page redirecte, but no any things saved.
def channelAdd(request):
if request.method == 'POST':
form = ChannelForm(request.POST)
if form.is_valid():
channelid = form.cleaned_data['channelid']
form.save()
return HttpResponseRedirect(reverse('updateChannelInfo', args=[channelid]))
else:
form = ChannelForm()
return render(request, 'web/channelAdd.html', {'form':form})

This will get you closer to the solution. I'm not positive if you have 'updateChannelInfo' as the name in urls.py (so please double-check that). I think the complexity here is getting the correct channelId to be sent
def channelAdd(request):
if request.method == 'POST':
form = ChannelForm(request.POST)
if form.is_valid():
channelid = form.cleaned_data['channelid']
form.save()
return HttpResponseRedirect(reverse('updateChannelInfo', args = [self.object.id])))
else:
form = ChannelForm()
return render(request, 'web/channelAdd.html', {'form':form})
If you are willing to share your urls.py and forms.py files, this would help with getting the correct names into arguments
Another way I have had success with the dynamic direct after form submission is to use
def add_channel (request):
if request.method == 'POST':
form = ChannelForm(request.POST)
if form.is_valid():
channel.save()
return HttpResponseRedirect(reverse('channel_detail', args=[channel.id]))
else:
form = ChannelForm()
return render(request, 'channel_example.html', {'form': form})

Edit your view like this,
if form.is_valid():
form.save()
return redirect('updateChannelInfo', channelId=self.object.id)

Form validation failing in Django

Im trying to get a form to validate with a Charfield but using the Select widget.
Here is my view.py code:
def mpld3plot(request):
form = PlotlyPlotForm()
form.fields['plot_file'].widget.choices = own_funcs.uploaded_files(string=False)
if request.method == 'POST':
print(form.is_valid())
if form.is_valid():
return HttpResponseRedirect('/mpld3')
else:
pass
else:
pass
return render(request, 'evert/plot.html', {'plottype': 'MPLD3',
'form': form})
Below is my forms.py code:
class Mpld3PlotForm(forms.Form):
plot_file = forms.CharField(widget=forms.Select(choices=[('', 'a'), ('', 'b')]))
The form does not validate on submit. I update the choices dynamically based on uploaded files. Any help would be appreciated.

Turns out I did not pass the request object to the form.
The view.py file should look like the following:
def mpld3plot(request):
form = PlotlyPlotForm(request.POST)
form.fields['plot_file'].widget.choices = own_funcs.uploaded_files(string=False)
if request.method == 'POST':
print(form.is_valid())
if form.is_valid():
return HttpResponseRedirect('/mpld3')
else:
pass
else:
pass
return render(request, 'evert/plot.html', {'plottype': 'MPLD3',
'form': form})

How to update a form attribute from view code in django

I have a page for updating a user profile in my django project. The view code looks like this:
#login_required
def updateProfile(request, user_id):
if request.method == 'POST':
form = UserProfileForm(request.POST)
if form.is_valid():
form.user_id = user_id
form.save(commit=True)
return index(request)
else:
profile, created = UserProfile.objects.get_or_create(user_id = self.user_id) # don't know if this will actually work.
profile_form = UserProfileForm(profile)
context = {
'user' : request.user,
'form' : profile_form
}
return render(request, 'myapp/profile.html', context)
My form looks like this:
class UserProfileForm(forms.ModelForm):
class Meta:
model = UserProfile
fields = ['age', 'skill_level']
My user profile looks like this:
class UserProfile(models.Model):
user = models.ForeignKey(User, unique=True)
age = models.IntegerField(default=18)
skill_level = models.ForeignKey(SkillLevel)
When this gets posted to, we receive what appears to be a valid user_id along with a valid form. In the UserProfileForm form we do not include user_id so that when it renders the user cannot decide to swap that out. Instead, the user_id gets posted back as a separate parameter (as I type this out, I realize it's kind of weird..). I want to save the UserProfile encapsulated by UserProfileForm to the database on post, so I give it a user_id and try to call .save(commit=True) on it, which returns "Column 'user_id' cannot be null".
My question is simple, how can I get that underlying UserProfile object saved from the form data with the information at hand?

Standard Django form handling idiom in case like that is
#login_required
def updateProfile(request, user_id):
if request.method == 'POST':
form = UserProfileForm(request.POST)
if form.is_valid():
obj = form.save(commit=False) # Get just object, but don't save yet
obj.user = request.user # set user (or user_id)
obj.save() # Save object
return index(request)
else:
profile, created = UserProfile.objects.get_or_create(user_id = self.user_id) # don't know if this will actually work.
profile_form = UserProfileForm(profile)
context = {
'user' : request.user,
'form' : profile_form
}
return render(request, 'myapp/profile.html', context)
Note that form data is not in fields, so form.my_field = 123 won't work - form data is parsed to form.cleaned_data dictionary where form.save() reads it.

use the request.user for userProfile user, do this way
#login_required
def updateProfile(request, user_id):
if request.method == 'POST':
form = UserProfileForm(request.POST)
form.user = request.user
if form.is_valid():
form.save(commit=True)
return index(request)
else:
profile, created = UserProfile.objects.get_or_create(user = request.user) # don't know if this will actually work.
profile_form = UserProfileForm(instance=profile)
context = {
'user' : request.user,
'form' : profile_form
}
return render(request, 'myapp/profile.html', context)