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How can I make a list of last two digits of year plus month

Can I get some help to create a list of days and months in the folowing format:
collection = ['2108', '2109', '2110', '2111', '2112', '2201']
I am trying in this way:
def make_collections(start_date: Date, end_date: Date):
result = []
date = start_date
while True:
if start_date >= end_date:
return result
date = date.strftime('%y%m%d%H%M%S')
result.append(date[:4])
date = (date.strptime(date, '%y%m%d%H%M%S')) + timedelta(days=1)
# test = MakeDataFrame()
# test.run()
if __name__ == '__main__':
start = datetime.now() - timedelta(days=365)
print(make_collections(start, datetime.now()))
But it doesn't work.
I want to give a start date and end date as an argument in function and make a list as I mentioned above with year and month.
Can I get some help to make a a simple function with start and end date as an arguments?
Thanks

I revised your code a little bit, so that the code will print what you expected. I used dateutil.relativedelta module because timedelta provide only day-based delta. dateutil.relativedelta support to calculate month and year differences.
from datetime import datetime, timedelta
from dateutil.relativedelta import relativedelta
def make_collections(start_date, end_date):
result = []
while start_date <= end_date:
result.append(str(start_date.year)[2:] + str(start_date.month).zfill(2))
start_date += relativedelta(months=1)
return result
if __name__ == '__main__':
start = datetime.now() - timedelta(days=365)
print(make_collections(start, datetime.now()))
#['2101', '2102', '2103', '2104', '2105', '2106', '2107', '2108', '2109', '2110', '2111', '2112', '2201']

How do I find what the date will be next Sunday 12 am from now and then add 10 hours to it

I have this code
today = datetime.now().date()
# prints: 2022/1/14
rd = REL.relativedelta(days=1, weekday=REL.SU)
nextSunday = today + rd
#prints : 2022/1/16
How do i add 10 hours to the date so i can get a variable nextSunday_10am that i can substract to the current time
difference = nextSunday_10am - today
and schedule what I need to do

You can do the same thing as suggested by #Dani3le_ more directly with the following:
def getSundayTime(tme: datetime.date) -> datetime:
nxt_sndy = tme + timedelta(days= 6 - tme.weekday())
return datetime.combine(nxt_sndy, datetime.strptime('10:00', '%H:%M').time())
This will compute calculate the next Sunday and set time to 10:00

You can add hours to a DateTime by using datetime.timedelta().
nextSunday += datetime.timedelta(hours=10)
For example:
import datetime
today = datetime.datetime.today()
print("Today is "+str(today))
while today.weekday()+1 != 6: #0 = "Monday", 1 = "Tuesday"...
today += datetime.timedelta(1)
nextSunday = today + datetime.timedelta(hours=10)
print("Next sunday +10hrs will be "+str(nextSunday))

How to replace the day in a date with another date?

I'm trying to replace the day in my if statement for my date but I keep getting this output for my year.
05/15/5 besides 05/15/2020 . Code is below:
today_date = datetime.datetime.now()
date = today_date.date()
formatted_date = datetime.date.strftime(date, "%m/%d/%Y")
mmonth = date.month
myear = date.year
mdate = date.day
if mdate < 7:
m0weekend = formatted_date.replace(str(myear),str(mmonth),1)
else:
m0weekend = formatted_date.replace(str(myear),str(mmonth),15)

it's easier to replace the day before converting to a string:
date = date.replace(day=1)
or, in your case:
if mdate < 7:
m0weekend = date.replace(day=1)
else:
m0weekend = date.replace(day=15)

formatted_date is actually a string.
You are using the str.replace() method not the datetime.date.replace() method.
import datetime
today_date = datetime.datetime.now()
pre_formatted_date = today_date.date()
mmonth = pre_formatted_date.month
myear = pre_formatted_date.year
mdate = pre_formatted_date.day
if mdate < 7:
pre_formatted_date = pre_formatted_date.replace(day=1)
else:
pre_formatted_date = pre_formatted_date.replace(day=15)
print(pre_formatted_date)
formatted_date = pre_formatted_date.strftime("%m/%d/%Y")
print(formatted_date)
Which has the following output:
2020-05-15
05/15/2020

You might get today datetime.date directly from datetime rather than creating datetime.datetime and converting to date. After you have today you might create needed datetime.date and turn it into str, i.e.:
import datetime
today = datetime.date.today()
date = datetime.date(today.year, today.month, 1 if today.day < 7 else 15)
formatted_date = datetime.date.strftime(date, "%m/%d/%Y")
print(formatted_date) # 05/15/2020

Getting dates in python between a past datestamp and the present

Language Python
I am wondering if anyone can help me print out some dates.
i cam trying to create a loop in which i pass in a date say 01/1/2017 and the loop will then output the first and last day in every month between then and the present day.
Example
01/01/2017
31/01/2017
01/02/2017
28/02/2017
etc
Any help will be appreciated

Hope this will help,
Code:
from datetime import date
from dateutil.relativedelta import relativedelta
from calendar import monthrange
d1 = date(2018, 2, 26)
d2 = date.today()
def print_month_day_range(date):
first_day = date.replace(day = 1)
last_day = date.replace(day = monthrange(date.year, date.month)[1])
print (first_day.strftime("%d/%m/%Y"))
print (last_day.strftime("%d/%m/%Y"))
print_month_day_range(d1)
while (d1 < d2):
d1 = d1 + relativedelta(months=1)
print_month_day_range(d1)
Output:
01/02/2018
28/02/2018
01/03/2018
31/03/2018
...
01/07/2018
31/07/2018

you can use calendar module. Below is the code:
import datetime
from calendar import monthrange
strt_date = '01/1/2017'
iter_year = datetime.datetime.strptime(strt_date, '%m/%d/%Y').year
iter_month = datetime.datetime.strptime(strt_date, '%m/%d/%Y').month
cur_year = datetime.datetime.today().year
cur_month = datetime.datetime.today().month
while cur_year > iter_year or (cur_year == iter_year and iter_month <= cur_month):
number_of_days_in_month = monthrange(iter_year, iter_month)[1]
print '/'.join([str(iter_month) , '01', str(iter_year)])
print '/'.join([str(iter_month), str(number_of_days_in_month), str(iter_year)])
if iter_month == 12:
iter_year += 1
iter_month = 1
else:
iter_month += 1

this could work, as long as the first date you give is always the first of the month
from datetime import datetime
from datetime import timedelta
date_string = '01/01/2017'
date = datetime.strptime(date_string, '%d/%m/%Y').date()
today = datetime.now().date()
months = range(1,13)
years = range(date.year, today.year + 1)
for y in years:
for m in months:
new_date = date.replace(month=m, year=y)
last_day = new_date - timedelta(days=1)
if (date < new_date) & (new_date <= today):
print last_day.strftime('%d/%m/%Y')
print new_date.strftime('%d/%m/%Y')
elif (date <= new_date) & (new_date <= today):
print new_date.strftime('%d/%m/%Y')

This code would print the first and last days of all months in a year.
Maybe add some logic to iterate through the years
import datetime
def first_day_of_month(any_day):
first_month = any_day.replace(day=1)
return first_month
def last_day_of_month(any_day):
next_month = any_day.replace(day=28) + datetime.timedelta(days=4)
return next_month - datetime.timedelta(days=next_month.day)
for month in range(1, 13):
print first_day_of_month(datetime.date(2017, month, 1))
print last_day_of_month(datetime.date(2017, month, 1))

Strftime error Python

I'm calling a function to get the calculation for driver revenue but, I keep getting this error:
"line 396, in driver_get_revenue
monthly[month.strftime("%m")] = orders.count() * settings.DRIVER_DELIVERY_PRICE
AttributeError: 'int' object has no attribute 'strftime'"
The function is this:
def driver_get_revenue(request):
driver = JWTAuthentication().authenticate(request)[0].driver
#Returns the difference between date and time.
from datetime import timedelta
revenue = {}
monthly = {}
yearly = {}
today = timezone.now()
month = today.month
year = today.year
#Created a range to calculate the current weekday.
current_weekdays = [today + timedelta(days = i) for i in range(0 - today.weekday(), 7 - today.weekday())]
for day in current_weekdays:
orders = Order.objects.filter(
driver = driver,
status = Order.DELIVERED,
created_at__year = day.year,
created_at__month = day.month,
created_at__day = day.day
)
revenue[day.strftime("%A")] = orders.count() * settings.DRIVER_DELIVERY_PRICE
for day in range(0, 30):
orders = Order.objects.filter(
driver = driver,
status = Order.DELIVERED,
created_at__month = month,
created_at__day = day
)
(Line 396) monthly[month.strftime("%m")] = orders.count() * settings.DRIVER_DELIVERY_PRICE
for month in range(0, 12):
orders = Order.objects.filter(
driver = driver,
status = Order.DELIVERED,
created_at__year = year,
created_at__month = month
)
yearly[year.strftime("%y")] = orders.count() * settings.DRIVER_DELIVERY_PRICE
return JsonResponse({"revenue": revenue,
"month": monthly,
"yearly": yearly})
I'm not exactly sure where I went wrong. I marked line 396 so that you see where the error is. Any help will be greatly appreciated.
Thanks.

When you do this: month = today.month, month becomes an integer. The strftime function works with datetime objects, not with integers.
Therefore, month.strftime("%m") doesn't work.
Try day.strftime("%m") instead, or perhaps just month, depending on your requirements.
If instead you're looking for the month's name, you could do it like this:
today = timezone.now()
month = today.month
month_name = today.strftime("%B") # e.g. December
...
...and use the month_name variable in your code.