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Rounds integer even with float- python

Below is my code. the issue is in MAIN. The code works as a person trying to buy items into a cart and you can see the total price of those items. They have to enter in the price for each item that they want. If a person inputs a number to two decimal places, it rounds it to the nearest whole number.
import locale
class CashRegister:
def __init__(self):
mself.items = 0
self.price = int(float(0.00))
def addItems(self,price): #keeps track of total number of items in cart
self.price += price
self.items += 1
print(self.price)
def getTotal(self): #returns total price
return self.price
def getCount(self): #return the item count of the cart
return self.items
def clearCart(self): #clears cart for another user or checkout
self.items = 0
self.price = int(float(0.00))
def main():
user_name = input('What is your name?\n') #weclomes user
print("Hello",user_name)
locale.setlocale(locale.LC_ALL, 'en_US')
user_name = CashRegister() #user is using the cash register
while True:
line = input ("Would you like to add another food item to your cart? Choose y or n \n")
if line == "y":
** price = int(float(input("please input the price of the item\n")))
print(price)**
user_name.addItems(price) #user adds prices to cart
elif line == "n":
print("Your total checkout price:", locale.currency(user_name.getTotal()) )
# int(float(locale.currency(user_name.getTotal())))
print("Your total item count", user_name.getCount())
user_name.clearCart() #clears cart for another user/checkout
break
else:
print("Error")
if __name__ == '__main__':
main()
As soon as the person inputs the number, I printed it to see if that's where the problems lies. I'll enter 3.20 but it automatically converts it to 3. I have no idea how to force it to keep those decimals. I even tried printing it with the int/float and it still doesn't work.

The int() function always returns an integer. An integer never has any decimal points. So use only
float(input("please input the price of the item\n"))
instead of
int(float(input("please input the price of the item\n")))

Shopping List Program

I am coding a program that simulates someone making a purchase in a grocery store. I am displaying all the products and the price and I am prompting the user to input all the products they went to buy separated by commas. I want the program to check if the input is in the dictionary of product and add it to the cart with the use of a loop. Before adding it to cart the program needs to check if the input is valid, meaning if the item is in the list of products to buy. When the user selects an item to buy, I want the program to ask the user for the quantity of that item, so how many of the item they want to buy. At the samThen the program will calculate the total of all the products, then calculate the tax value, 24% of the total, and then return a subtotal that includes tax. Here is what I have so far:
def calculatetotal(slist, produce):
# for each item on the shoping list look up the cost & calculate total price
item_price = 0
subtotal = 0
VAT = 0
final_total = 0
basket = {}
for item in slist:
item_price = produce.get(item)
basket[item] = item_price
subtotal = subtotal + item_price
basket["Subtotal"] = subtotal
#calculating VAT
VAT = subtotal * 0.24
basket["VAT"] = VAT
#calculating price with tax
final_total = subtotal + VAT
basket["Total"] = final_total
# print off results
return basket
def main():
# set up grocery list with prices
produce={"Rice":5.00, "Bread":2.00, "Sugar":1.5, "Apple":0.75, "Cereal":3.75, "Gum": 1.00, "Water": 1.75, "Soda": 2.00}
# process input from the user - get a shopping list
item = input("Please enter the items that you want to buy: ")
slist = []
while(item != 'stop'):
if not (item in slist):
slist.append(item)
item = input("Please enter the items that you want to buy: ")
result = calculatetotal(slist, produce)
print(result)
main()
I've gotten most of it, but the small changes that I mentioned above, I can't figure out what to do. I forgot to mention that asking for the quantity of the item and checking if the user input has to be done with a loop. Any input is very much appreciated. Please show the change of code. Thank you in advance.

In this case I would simply go for a while loop
while True:
item = input("Please enter the items that you want to buy: ")
if item == 'Stop':
break
elif item not in produce or item in slist:
# error message or whatever
else:
num = int(input("Enter Quantity"))
# other operations

Print a receipt in Python that doesn't repeat the items

I need to create a function that creates a session that accepts a "clerk's" input data about a customer's orders until the "clerk" enters the string "/". Each line of input consists of two elements: the product code and the quantity. Lines of input are formatted as follows: "{product_code},{quantity}". The function should write a file called receipt.txt that prints a summarized report of the session.
The receipt should provide a summary of all the orders made during the session and the product must only appear once if it has been ordered at least once during the session, even if it has been ordered multiple times. In other words, if a product is ordered multiple times, then it should only have one entry in the receipt that describes the sum of all of the orders made for that product. The products must appear in alphabetical order.
Here is my code right now and it prints a receipt but I don't know how to make the order appear only once and make it alphabetical order. Please help.
EDIT: Added get_property function.
def get_property(code,property):
return products[code][property]
def main():
products = {
"americano":{"name":"Americano","price":150.00},
"brewedcoffee":{"name":"Brewed Coffee","price":110.00},
"cappuccino":{"name":"Cappuccino","price":170.00},
"dalgona":{"name":"Dalgona","price":170.00},
"espresso":{"name":"Espresso","price":140.00},
"frappuccino":{"name":"Frappuccino","price":170.00},
}
orders_list = []
total = 0
while(True):
customer_order = input("Welcome to the CoffeePython POS Terminal.\nPlease enter the Product Code and the Quantity in this format - {Product Code},{Quantity}.\nEnter '/' to quit.\n")
if customer_order == "/":
break
else:
code_quantity_list = customer_order.split(",")
code = code_quantity_list[0]
quantity = code_quantity_list[1]
quantity_int = int(quantity)
if code in products:
subtotal = get_property(code,"price")*quantity_int
total += subtotal
ordered_item = dict([
('code', code),
('qty', quantity_int),
('subtotal', subtotal)
])
orders_list.append(ordered_item)
else:
print("The Product Code that you entered is invalid. Please try again.")
print("==")
print("CODE\t\t\tNAME\t\t\tQUANTITY\t\t\tSUBTOTAL")
for order in orders_list:
order_code = order['code']
order_name = products[order_code]["name"]
order_qty = order['qty']
order_subtotal = order['subtotal']
print(f"{order_code}\t\t{order_name}\t\t{order_qty}\t\t\t\t{order_subtotal}\t\t")
print(f"\nTotal:\t\t\t\t\t\t\t\t\t\t{total}")
print("==")
print("Thank you for ordering. Goodbye.")
main()
Output
==
CODE NAME QUANTITY SUBTOTAL
americano Americano 2 300.0
americano Americano 2 300.0
Total: 600.0
==

To store the orders, I would suggest you to use a dictionary with code as a key, and the price as value.
orders_list = {}
while ...:
orders_list[code] = orders_list.setdefault(code, 0) + subtotal
for product in sorted(orders_list):
subtotal = orders_list[product]
print(f"{product:<10} {subtotal}")

You need to check the saved list in orders_list and then evaluate the existing key. For sort list in the order_list by key in a dict, you can use this reference
How do I sort a list of dictionaries by a value of the dictionary?
I am adding a new method to perform check.
Also, I am not sure about your get_property() method, I changed it a bit.
def check_code(orders_list, code):
codes = []
for i in orders_list:
codes.append(i["code"])
if(code in codes):
return True, codes.index(code)
else:
return False, 0
def main():
products = {
"americano":{"name":"Americano","price":150.00},
"brewedcoffee":{"name":"Brewed Coffee","price":110.00},
"cappuccino":{"name":"Cappuccino","price":170.00},
"dalgona":{"name":"Dalgona","price":170.00},
"espresso":{"name":"Espresso","price":140.00},
"frappuccino":{"name":"Frappuccino","price":170.00},
}
orders_list = []
total = 0
while(True):
customer_order = input("Welcome to the CoffeePython POS Terminal.\nPlease enter the Product Code and the Quantity in this format - {Product Code},{Quantity}.\nEnter '/' to quit.\n")
if customer_order == "/":
break
else:
code_quantity_list = customer_order.split(",")
code = code_quantity_list[0]
quantity = code_quantity_list[1]
quantity_int = int(quantity)
if code in products:
# subtotal = get_property(code,"price")*quantity_int
subtotal = products[code]["price"] *quantity_int
check = check_code(orders_list, code)
if check[0]:
orders_list[check[1]]["subtotal"] += subtotal
orders_list[check[1]]["qty"] += quantity_int
else:
ordered_item = dict([
('code', code),
('qty', quantity_int),
('subtotal', subtotal)
])
orders_list.append(ordered_item)
total += subtotal
else:
print("The Product Code that you entered is invalid. Please try again.")
print("==")
print("CODE\t\t\tNAME\t\t\tQUANTITY\t\t\tSUBTOTAL")
orders_list = sorted(orders_list, key=lambda k: k['code'])
for order in orders_list:
order_code = order['code']
order_name = products[order_code]["name"]
order_qty = order['qty']
order_subtotal = order['subtotal']
print(f"{order_code}\t\t{order_name}\t\t{order_qty}\t\t\t\t{order_subtotal}\t\t")
print(f"\nTotal:\t\t\t\t\t\t\t\t\t\t{total}")
print("==")
print("Thank you for ordering. Goodbye.")
main()

When i test the code the item prints once and i did following:
frappuccino, 1
americano, 2
dalgona, 1
So i cannot reproduce the issue but i dont have the get_properties method either so maybe thats the issue.
As for printing the list in alphabetical order you should look to sort the list before looping and printing the reciept. You will find how you can achieve sort on a list containing dictionaries
here

Input Validation in Python

So my friend and I have been working on this problem for a few days now for our Intro to Python class at our college, but we are a bit stuck due to the fact we didn't spend much time on this topic in class. Our problem is this, "Every product ID must be six characters long and starts with three upper case letters followed by three digits. For example ABE123 and PPL334 are valid product IDs but ABE1.2 and P1L3R4 are not. The auction site has a minimum bid price of 5 dollars and caps bids at 500 dollars. Bids with dollars and cents are acceptable. For example 6.78 is a valid bid. The following code reads in bids from the prompt (keyboard inputs) and loads the product ids and bidding prices into two lists products and bids. Unfortunately the code contains no input validation which is your job to complete." Our teacher gave us the code, we just have to validate the inputs. But it has to be done outside of her code, as in its own function. Here is the code:
`def getbids():
products = []
bids = []
answer = "yes"
while answer == "yes":
productid = input("Enter the productID ")
bid = float(input("Enter the bid for one item "))
products.append(productid)
bids.append(bid)
answer = input("Are there more bids? ")
return products, bids`
Basically, our job is to validate the productid and the bid in separate functions. I have our code here but what we have doesn't work completely and is not correct.
Here is the one for productId:
`def validprod(n):
caps="ABCDEFGHIJKLMNOPQRSTUVWXYZ"
nums="0123456789"
m="Error"
if len(n)!=6:
print("Error, productID must be 6 digits,3 capital letters followed by 3 numbers")
return m
else:
while len(n)==6:
for i in range(3):
if n[i] not in caps or n[i+3] not in nums:
print("Error, productID must be 6 digits,3 capital letters followed by 3 numbers")
return m
else:
return n`
Here is the one for bids:
`def validbid(x,y):
bid="Error"
while x=="Error":
return bid
while x!="Error":
if y>500 or y<5:
print("Error, bid must be between 5 and 500(do not include a dollar sign with your bid).")
return bid
else:
return y`
We know there is probably a much simpler way to do it, we just don't know it.

import re
pid_regex = re.compile(r'^[A-Za-z]{3}\d{3}$')
def is_valid_pid(pid):
if pid_regex.match(pid):
return True
return False
def is_valid_bid(bid):
return bid >= 5 and bid <= 500
def getbids():
products = []
bids = []
answer = "yes"
while answer == "yes":
productid = input("Enter the productID ")
products.append(productid)
bid = float(input("Enter the bid for one item "))
bids.append(bid)
answer = input("Are there more bids? ")
return products, bids
products = dict(zip(*getbids()))
for pid in products:
bid = products[pid]
if not is_valid_pid(pid):
print('PID {} is invalid.'.format(pid))
break
elif not is_valid_bid(bid):
print('PID {} has an invalid bid {}'.format(pid, bid))
break
else:
print('PID {} to bid {} seems OK.'.format(pid, bid))
Note: I needed to fix your getbids() function, because products were not being appended to the products list.
Another note: If you believe I was wrong to provide a complete solution, please let me know. I'm completely open to feedback from the public.

Updating and clearing dictionaries in Python

so I have a question regarding dictionaries in Python.
I'd like to create a dictionary where the user will be prompted with 2 options; either updating the dictionary or clearing the dictionary.
Let me first show you my code:
def myStuff():
food = {'Apple': 0, 'Banana': 0, 'Grapes': 0}
choice = raw_input('Please pick an option:\n1) Update number of food I have\n2) Clear all\n>>')
if choice == str(1):
apple = int(raw_input('How many apples do you want to add?\n>>'))
banana = int(raw_input('How many bananas do you want to add?\n>>'))
grapes = int(raw_input('How many grapes do you want to add?\n>>'))
print 'Updating...'
food['Apple'] = apple
food['Banana'] = banana
food['Grapes'] = grapes
print food
elif choice == str(2):
food['Apple'] = 0
food['Banana'] = 0
food['Grapes'] = 0
print food
else:
return False
myStuff()
Now here's what I'd like to add:
1.The ability for the user to keep updating the dictionary (which means that if someone input 10 apples, the dictionary will store 10 apples and the user will be prompted again to input the number of apples he want to input to update the dictionary).
I'm not really sure how to implement a loop into this.
2, The ability for the user to clear his dictionary after updating it. For example: if someone inputs 10 apples, the loop will ask the user again if he/she would like to clear the dictionary.
It's kind of like a bank where someone deposits money and clears their account if they don't have any money left in there account.

With what you are doing, it might be better to create your own class. You should also have different functions for all of the different actions you wish to do. ie. Update, Clear, Add
class Fruit:
Apple = 0
Banana = 0
Grape = 0
def __repr__(self):
return "You have {self.Apple} apples, {self.Banana} bananas, and {self.Grape} grapes".format(**locals())
def update(self):
while 1:
choice = raw_input('Please pick an option:\n1) Update number of food I have\n2) Clear all\n>>')
if (int(choice) == 1):
self.Add()
elif (int(choice) == 2):
self.Clear()
else:
print "Input not valid"
def Add(self):
self.Apple += int(raw_input('How many apples do you want to add?\n>>'))
self.Banana += int(raw_input('How many bananas do you want to add?\n>>'))
self.Grape += int(raw_input('How many grapes do you want to add?\n>>'))
print self
def Clear(self):
self.Apple = 0
self.Banana = 0
self.Grape = 0
print self
if __name__ == "__main__":
fruit = Fruit()
fruit.update()
You should also look in to using try and except statements to make sure the program does not crash if the wrong input is used. Also you should add in an exit command to exit the program, otherwise this will loop forever. for example. if the user input is "exit" then have a conditional notice it and break.

You can do that this way:
"""
in each loop check the fruit number to see if it is 0 or not.if it
is 0, then this means that you don't want to add fruit from the current
type and skips to the nextFruit.Focus on the code and you realize the other parts.
"""
import string
def myStuff():
food = {'Apples': 0, 'Bananas': 0, 'Grapes': 0}
choice = raw_input('Please pick an option:\n1) Update number of food I have\n2) Clear all\n>>')
fruit = 0
nextFruit = 'Apples'
while True:
if choice == str(1):
fruit = int(raw_input('How many ' + str.lower(nextFruit) + ' do you want to add?\n>>'))
if fruit == 0 and nextFruit == 'Apples':
nextFruit = 'Bananas'
continue
elif fruit == 0 and nextFruit == 'Bananas':
nextFruit = 'Grapes'
continue
elif fruit == 0 and nextFruit == 'Grapes':
print 'Updating...'
print food
choice = raw_input('Please pick an option:\n1) Update number of food I have\n2) Clear all\n>>')
else:
food[nextFruit] += fruit
elif choice == str(2):
food['Apples'] = 0
food['Bananas'] = 0
food['Grapes'] = 0
print 'Updating...'
print food
choice = raw_input('Please pick an option:\n1) Update number of food I have\n2) Clear all\n>>')
else:
print "You've entered a wrong number....try again please:"
print
choice = raw_input('Please pick an option:\n1) Update number of food I have\n2) Clear all\n>>')

For updating in a loop, maybe try something like:
for key in food:
food[key] += int(raw_input('How many %s do you want to add?> ' % key) or 0)
You are already clearing the dictionary by setting the values to zero.

If I understand correctly - you want to keep asking this question repeatedly? In that case, all you need to do is put while True: and indent the block of code you want to repeat, and it will loop through that forever. You probably want to have it from the raw_input (just input in Python 3) to just after the elif - or, if you make food a global variable (so that it doesn't get re-initialised to 0 every time myStuff() is called), you can just do:
while True:
myStuff()