I have the button shown below (image and HTML) and am trying to click it.
Selenium is unable to locate it - I have tried locating by both xpath and by ID.
<input id="wsUpload1" type="file" name="file">
XPATH:
element = driver.find_element_by_xpath('//input[#id="wsUpload1"]')
element.click()
Where am I going wrong?
EDIT: Here is the exception thrown by Selenium:
selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"xpath","selector":"//input[#id="wsUpload1"]"}
Possibilities
Duplicate web element with same id in the page.
Element may be in frame. You need to switch to frame
Trying to access the web element before page is loading.Give some wait time.
Not sure why your button wasn't found, maybe it's because of quotes (although it should show you error in that case), try with driver.find_element_by_xpath(".//input[#id='wsUpload1']") and see if it works. I'm not sure is your button already rendered on the page or you trigger it somehow so it's not there yet?
NoSuchElementException is thrown because your targeted element couldn't be found on that page, it could be that you are on the wrong page, element is not rendered yet so you should wait for it to appear, element could be in some iframe etc etc, it's hard to say when I don't know how your page works.
But if you are trying to upload something you should perform sendKeys() on that button (with path of file which are you trying to upload), not click() on it. This is how selenium upload works.
I have solved it - the driver opens a tab on a side panel and the button is in the tab. There seems to be a few ms delay between clicking the tab and the button appearing so I added a wait until element is clickable and that seems to work.
wait.until(EC.element_to_be_clickable((By.XPATH, "//input[#id='wsUpload1']"))).click()
Related
I am unable to click on Open button, below is the element... getting timeout exception error.. Note: there are multiple open buttons with same class..want to click on 1st one
Open
tried with xpath too(//*[#id="reportHeaderCol4NonMobile"]/div[2]/div[3]/div[3]/fieldset/div[1]/div[1]/div/button[1])
no such element error with xpath
here is thescreenshot of inspect element
Absolute xpath is always fragile, use the below xpath to identify and click.
This will click the first button of your many Open buttons as you have mentioned.
openbutton=wait.until(EC.element_to_be_clickable((By.XPATH,'(//button[text()="Open"])[1]')))
openbutton.click()
python selenium driver:
No thanks
when i open a google page the, there is a small window asking if i want to sign in or not. i want to click on "No thanks" button, which is as shown above.
i have tried these methods so far, but i keep getting errors. None of the following is working.
#self.driver.find_element(By.CSS_SELECTOR, 'button.M6CB1c')
#button=self.driver.find_elements(By.XPATH, '//button')
#abc=self.driver.find_elements(By.NAME, 'ZUkOIc').click()
#self.driver.find_element(By.TAG_NAME, 'button').click()
error message for the 1st line of code:
selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"css selector","selector":".M6CB1c.rr4y5c"}
selenium.common.exceptions.NoSuchElement is caused when the element is not in the page at the current time.
TLDR;
What you're looking for is Explicit Wait in selenium. You need to use WebDriverWait with expected condition element_to_be_clickable.
When we load a page, modern pages tend to load javascript that can often manipulate DOM (html page objects). The proper way to handle this is to wait for the page or the required element to load, and then try to locate it.
The selenium waits section explains this very well with an example.
You should try this :
driver.find_element(By.XPATH, '//button[#id="W0wltc"])
On Python 3.9 and Selenium 4.00
Hi there, I'm currently trying to automate downloading a few things on Chrome. I got the login part and navigating to the page down and it works properly. I'm having issues with the next part which is clicking "export" then "export as csv". I hover over the HTML source code and it highlights the buttons I need to press so I hit "copy XPath" but selenium won't press it and I get this error.
Edit: I cannot share the site as it is locked behind a login and it is not my login to give out; end of edit.
Message: invalid selector: Unable to locate an element with the xpath expression //*[#id="report_nav_menu"]/ul/li[2]/a"
Here's my code
driver = webdriver.Chrome(ChromeDriverManager().install())
driver.get('website')
driver.find_element(By.XPATH, '//*[#id="report_nav_menu"]/ul/li[2]/a').click()
time.sleep(1) # makes sure the page loads
driver.find_element(By.XPATH, '//*[#id="report_nav_menu"]/ul/li[2]/ul/li[6]/a').click()
time.sleep(1000) # to keep the browser open
This the is HTML source code:
Source code
The first highlight in the pic is for the Export button.
Need to click this first
The second highlight shows that it's for the CSV button.
Need to click this second
//class[#elname="zc-navmenuEl/button[2] seems to be an invalid XPath expression.
I can't see this locator used in the code you presented in the question.
Also you didn't share an URL of the page you are working with so I can't determine the correct element locator.
Needing help on this problem. All solutions/suggestions I have researched do not fix it.
Trying to click a button with Selenium. Keep getting these errors.
selenium.common.exceptions.ElementNotInteractableException: Message: element not interactable: [object HTMLButtonElement] has no size and location
and selenium.common.exceptions.ElementNotInteractableException: Message: element not interactable
I am not understanding why this element is not interactable.
play_button = driver.find_element_by_xpath('//*[#id="ppp"]/div/div[2]/div[2]/div[2]/button')
driver.implicitly_wait(10)
ActionChains(driver).move_to_element(play_button).click(play_button).perform()
When printing play_button = <selenium.webdriver.remote.webelement.WebElement (session="ca50b37ee2e4b194b2ad5305e254079f", element="78e35dc3-fef8-4082-a6e4-0a92dfbf2ec6")>
I have tried WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, '//*[#id="ppp"]/div/div[2]/div[2]/div[2]/button'))) but this times out. Element never becomes clickable.
I have tried using the full xpath.
I have tried disabling extensions/maximize window driver options.
The element is not in a frame or anything. It lies in a div that lies in the body.
The element is clickable within Chrome's console.
Any information/suggestions would be helpful.
Thanks.
The button you are trying to click is hidden, not clickable even with JavaScript executor.
You can start video on that page clicking on
driver.find_element_by_css_selector('div.player-poster.clickable').click()
or
driver.find_element_by_css_selector('div.play-wrapper').click()
No need to use ActionChains(driver).move_to_element etc.
Just a simple click.
Just don't forget setting
driver.implicitly_wait(10)
Or using an explicitly wait of expected conditions to make page loaded before accessing the element.
Using full XPath solved this problem for me.
I am trying to automate clicking on the play button of an embedded iframe music player on a webpage, I am coding using python 3 and Selenium to select the element to click.
When the user-agent is changed to replicate a mobile device, a wrapper layer then obscures the button that I can normally click, it asks if I want to listen on the main site or in the browser. I want to listen in the browser, but so far everything I have tried to click the correct element to achieve that, has failed.
I believe I am clicking on the wrong part but cannot find a way to access the correct part.
The inspect window of the browser shows the below for the part of the wrapper I need to click on:
<a class="mobilePrestitial__link sc-font-light" href="#">
Listen in browser
</a>
::before
"
Listen in browser
"
/a>
When I hover over the ::before part it highlights the part in the browser that I believe I need to click, but using right-click to inspect ::before just says 'scroll in view' so I cannot copy whatever the element represents.
My current code is this:
driver.switch_to.default_content()
driver.switch_to.frame(driver.find_element_by_partial_link_text('Listen in browser'))
element = WebDriverWait(driver, 10).until(
EC.element_to_be_clickable((By.XPATH, '//a[#class="mobilePrestitial__link"]'))
)
element.click()
But it errors without a message, I suspect I need to be clicking on the element presented by ::before but cannot figure how to do that.
I found a workaround and solved this by hiding the wrapper overlay using Selenium in python script to make a Javascript call
driver.execute_script('document.getElementsByClassName("mobilePrestitial")[0].style.display=\"none\"')
once the overlay is hidden with the above code, the original button is accessible in the browser