I have a functioning curl request:
curl --form "bio[0]=#images/12345.jpg" --form "bio[1]=#images/6789.jpg" --form "Verify=Verfiy" http://192.45.35.89/test.php
that I'm trying to convert to python requests:
requests.post('http://192.45.35.89/test.php', data = {
'bio' : [
('12345.jpg', open('images/12345.jpg', 'rb'), 'image/png'),
('6789.jpg', open('images/6789.jpg', 'rb'), 'image/png')
],
'Verify' : 'Verify'
})
The python version of the request yields a server error about "files not found or not accessible".
Am I correctly transforming the curl request to python requests? Any pointer would be greatly appreciated.
You need to send the files in a files dictionary to send the data as multipart/form-data as curl does:
requests.post('http://192.45.35.89/test.php',
files = {
'bio[0]' : ('12345.jpg', open('images/12345.jpg', 'rb'), 'image/png'),
'bio[1]' : ('6789.jpg', open('images/6789.jpg', 'rb'), 'image/png')
},
data = {'Verify' : 'Verify'})
Reference: POST a Multipart-Encoded File
Related
I'm doign an app with the Spotify API. My problem is I'm trying to get an access_token but It's not working. In the docs it says i need to send the body encoded as application/x-www-form-urlencoded so I search a little bit and It should work just setting request_body as a dictionary.
This is the code of my function:
def get_access_token(self):
auth_code, code_verifier = self.get_auth_code()
endpoint = "https://accounts.spotify.com/api/token"
# as docs said data should be encoded as application/x-www-form-urlencoded
# as internet says i just need to send it as a dictionary. However it's not working
request_body = {
"client_id": f"{self.client_ID}",
"grant_type": "authorization_code",
"code": f"{auth_code}",
"redirect_uri": f"{self.redirect_uri}",
"code_verifier": f"{code_verifier}"
}
response = requests.post(endpoint, data=request_body)
print(response)
The response I'm getting is always <Response [400]>
Here are the docs, step 4 https://developer.spotify.com/documentation/general/guides/authorization-guide/#authorization-code-flow-with-proof-key-for-code-exchange-pkce
NOTE: I tryed executing this as a curl and it works fine I'm not sure what I'm doing wrong in the python code
here's the command:
curl -d client_id={self.client_ID} -d grant_type=authorization_code -d code={auth_code} -d redirect_uri={self.redirect_uri} -d code_verifier={code_verifier} https://accounts.spotify.com/api/token
You can specify the request type in the request header.
headers = {'Content-Type': 'application/x-www-form-urlencoded'}
response = requests.post(endpoint, data=request_body, headers=headers)
print(response)
i am trying to convert a curl method into a python POST request.
Here is the curl command:
curl --location --request POST 'https://global.kaleyra.com/api/v4/' --form 'file=#/home/user/Desktop/TWP_MD565041.pdf' --form 'method=wa' --form 'api_key=A3d51xxxxxxxxxxxxxxxxxxxxxxxxxx' --form 'from=971xxxxxxxxxx' --form 'body={
"to":"9198xxxxxxxx",
"type": "document", "document" : {"caption" : ""},
"callback":""
}' --form 'format=json'
And here is the python request ia tried:
payload = {
"method": "wa",
"api_key": "A3dxxxxxxxxxxxxxxxx",
"body": '{"to":'+str(user_number)+',"type": "document"}',
'from': '971xxxxxxxx',
'format':'json',
"file":open("/home/user/Desktop/TWP_MD565041.pdf","rb")}
r = requests.post(url=api_url,headers={}, files=payload)
getting error:
b'{"status":"A401B","message":"Method Not Found"}'
Then i changed request like this:
r = requests.post(url=api_url,headers={}, files=json.dumps(payload))
Now am getting an error:
TypeError: Object of type 'BufferedReader' is not JSON serializable
And i tried this,
with open("/home/user/Desktop/TWP_MD565041.pdf",'rb') as f:
r = session.post(url=api_url,headers=headers, data=json.dumps(payload),files={"file":f})
Then i an getting an error:
ValueError: Data must not be a string.
How can i resolve this?
1) Requests will serialize the JSON for you. Drop the json.dumps method and use the raw payload.
2) I suggest sending the file as such. The with statement is used for larger atomic manipulations, and you really don't need to keep the file open while performing API I/O. Therefore, use the following method, as the file stream is implicitly closed after interpretation.
r = session.post(
url = api_url,
headers = headers,
data = payload,
files = {'file': open('file.pdf','rb')}
)
It would be a great help if somebody helps me to understand how the following command can be executed using python:
curl -X POST https://insights-collector.newrelic.com/v1/accounts/YOUR_ACCOUNT_ID/events -H "Content-Type: application/json" -H "X-Insert-Key: YOUR_KEY_HERE" -d '{"eventType":"Custom Event Name", "attribute1": "value"}'
SQL query results need to be converted to JSON format and need to be pushed to new relic using the above command.
try doing this
import requests
headers = {
'Content-Type': 'application/json',
'X-Insert-Key': 'YOUR_KEY_HERE',
}
data = '{"eventType":"Custom Event Name", "attribute1": "value"}'
response = requests.post('https://insights-collector.newrelic.com/v1/accounts/YOUR_ACCOUNT_ID/events', headers=headers, data=data)
I have go server that unmarshals the json it receives it.
It works when I do it using the curl but fails in case of python.
Go server Unmarshal code:
type Data struct {
Namespace string `json:"namespace"`
ContainerId string `json:"containerId"`
}
func notify(w http.ResponseWriter, r *http.Request) {
decoder := json.NewDecoder(r.Body)
var data Data
err := decoder.Decode(&data)
if err != nil {
glog.Errorf("Failed to decode the request json %s \n", err.Error())
return
}
...
}
If I Do curl command it works without complaining:
curl -i -H "Accept: application/json" -H "Content-Type:application/json" -X POST --data '{"namespace": "default", "containerId": "2f7c58d399f2dc35fa1be2abea19301c8e74973ddd72f55a778babf01db5ac26"}' http://mysvc:8080/notify
but if I do the same thing with Python it complains:
jsonPrep['containerId'] = "2f7c58d399f2dc35fa1be2abea19301c8e74973ddd72f55a778babf01db5ac26"
jsonPrep['namespace'] = "default"
headers = {'Content-type': 'application/json', 'Accept': 'application/json'}
r = requests.post('http://mysvc:8080/notify', json=json.dumps(jsonPrep), headers=headers)
the go server complains :
E1026 15:49:48.974117 1 main.go:59] Failed to decode the request json json: cannot unmarshal string into Go value of type main.Data
I don't see what is different when I do curl vs rest query in python.
Can anyone help me identify the issue?
The json argument to requests.post() is for passing a value that has not had json.dumps() called on it yet. requests calls json.dumps() on the json argument itself, so because you're passing json=json.dumps(jsonPrep), jsonPrep will end up being JSONified twice, which is not what you want.
Either use data:
requests.post(..., data=json.dumps(jsonPrep), ...)
or get rid of the json.dumps():
requests.post(..., json=jsonPrep, ...)
I am currently trying to integrate Stripe Connect and have come across the flowing CURl POST request:
curl https://connect.stripe.com/oauth/token \
-d client_secret=SECRET_CODE \
-d code="{AUTHORIZATION_CODE}" \
-d grant_type=authorization_code
However I am very new to CURL and have been doing some research and trying to use the requests package to do it. This is what my current code looks like:
data = '{"client_secret": "%s", "code": "%s", "grant_type": "authorization_code"}' % (SECRET_KEY, AUTHORIZATION_CODE)
response = requests.post('https://connect.stripe.com/oauth/token', json=data)
However this always returns a response code 400. I have no idea where I am going wrong and any guidance would be thoroughly appreciated.
The error is because you are passing your data as string, instead json param of requests.post call expects it to be dict. Your code should be:
import requests
data = {
"client_secret": SECRET_KEY,
"code": AUTHORIZATION_CODE,
"grant_type": "authorization_code"
}
response = requests.post('https://connect.stripe.com/oauth/token', json=data)
Take a look at request library's More complicated POST requests document.