I'm learning flask through tutorials.Now I stuck on making database file because they just provide unix command to execute that script my question is which command do i use if i want to install that "db_create.py" file from command prompt that i've mention below..I'm running on virtual enviroment with directory project in cmd.
#!flask/bin/python
from migrate.versioning import api
from config import SQLALCHEMY_DATABASE_URI
from config import SQLALCHEMY_MIGRATE_REPO
from app import db
import os.path
db.create_all()
if not os.path.exists(SQLALCHEMY_MIGRATE_REPO):
api.create(SQLALCHEMY_MIGRATE_REPO, 'database repository')
api.version_control(SQLALCHEMY_DATABASE_URI, SQLALCHEMY_MIGRATE_REPO)
else:
api.version_control(SQLALCHEMY_DATABASE_URI, SQLALCHEMY_MIGRATE_REPO,api.version(SQLALCHEMY_MIGRATE_REPO))
I have also install SQLAlchemy.
If it's already specified in the first line the interpreter of this script, then you just have to grant the script the executable permits in order for it to run.
Hence just type the following command, if you are on UNIX-based machine:
sudo chmod +x <path_to_python_script>
And then just execute:
./<path_to_python_script>
Otherwise if you are on a Windows-based machine, move into the folder of the script and just run:
python -m db_create.py
Hope it works!
Related
all
As flask-script document said they are no longer to maintain it,
thus I am trying to use flask cli (Command Line Interface) to activate my flask app.
When I run the following flask cli commands one by one at my terminal, they worked fine for me.
$ export PYTHONPATH=$PWD:flask_api/
$ export FLASK_APP=flask_api/app
$ export FLASK_RUN_PORT=8000
$ flask run
The problem is that it seems not that efficient every time I tried to start my flask app.
so I came up with writing them into a shell scripts (that said run_flask.sh)
the content in run_flask.sh is:
export PYTHONPATH=$PWD:flask_api/
export FLASK_APP=flask_api/app
export FLASK_RUN_PORT=8000
flask run
and I simply run source run_flask.sh
and the result showed and did not start to run flask:
"* Serving Flask app "flask_api/app
* Environment: production
WARNING: This is a development server. Do not use it in a production deployment.
Use a production WSGI server instead.
* Debug mode: off
Usage: flask run [OPTIONS]
".ror: Could not import "src.flask_api.app
I am not sure what's happening,
could any one tell me why flask could not import my flask app while I tried to run it with shell scripts? Great Thanks!
ps. I declare flask app instance in flask_api/base_api/init.py,
and app.py is in flask_api/ folder, app.py would import the app instance from base_api
(I used CentOS7 as the OS)
I have a weird problem with some code I want to run. The code itself should not be the problem since it is downloaded from a Udemy class and not modified:
# coding=utf-8
from flask import Flask, render_template, request
app = Flask(__name__)
#app.route("/")
def hello():
items = ["Apfel", "Birne", "Banane"]
return render_template("start.html", name="Max Mustermann", items=items)
#app.route("/test")
def test():
name = request.args.get("name")
return render_template("test.html", name=name)
I found online that, to start the emulated webserver(?) I have to rund the following temrinal commands before I can see the output:
(base) Christophs-MBP:13-23 chris$ export FLASK_APP=run.py run flask
(base) Christophs-MBP:13-23 chris$ export FLASK_APP=run.py run flask
(base) Christophs-MBP:13-23 chris$ export FLASK_APP=run.py
(base) Christophs-MBP:13-23 chris$ run flask
bash: run: command not found
No reaction to my terminal commands
Basically there is no reaction to the command to start the server(?).It should reply with "Running on 127.0.0.1:5000" as soon as I've run the command once.
If I go to my browser, there is no page when I address http://127.0.0.1:5000. What am I doing wrong? I am pretty new to Python and an absolute rookie regarding the terminal. Not sure if I broke something there, since trying to install pyenv to manage my Python installs better as recommended by a friend does not work either (I cannot update the SDK headers as described on RealPython
What are the export statements?
On Mac, export key=value creates a new (or updates an existing one) environment variable - the tutorial most likely simply asked you to provide one where key is FLASK_APP and value is a path to your app.
To verify it's been saved correctly, you can list the variables by just typing export in the terminal and finding out what's inside each of the environment variables on your system (if you want to only view FLASK_APP you can type export | grep FLASK_APP).
Why do you need FLASK_APP?
When you call flask run in your terminal, you will see the following message:
Error: Could not locate a Flask application. You did not provide the "FLASK_APP" environment variable, and a "wsgi.py" or "app.py"
module was not found in the current directory.
I presume your file is called run.py, therefore none of the conditions are met. You could rename run.py to app.py and simply type flask run in the terminal, but you can also type export FLASK_APP=<path-to-run.py>. It seems the tutorial author decided to do the latter. Keep in mind that if you rename your file to app.py you will need to run flask run within the directory that file lives in. You can change directory in the terminal using cd command.
Why do you get bash: run: command not found?
bash is a language running inside your terminal, and it only knows of a few commands - it is not aware of any run commands. It does however know about flask command once you have installed it on your machine. Within the command's output there is a part which includes a run command:
Commands:
routes Show the routes for the app.
run Run a development server.
shell Run a shell in the app context.
Therefore, what you want to do is type flask run instead of just run in your terminal.
I am trying to use Kubernetes python SDK.
I tried to run the following code:
from kubernetes import client, config
# Configs can be set in Configuration class directly or using helper utility
config.load_kube_config()
v1 = client.CoreV1Api()
print("Listing pods with their IPs:")
ret = v1.list_pod_for_all_namespaces(watch=False)
It failed with lots of errors.
When I run the same code with python from a shell, the same issue.
When I run the same code with sudo python from shell, it works.
I am trying to run PyCharm interperte as root.
Following the instruction from JetBrains, I created a script shell with the name pythonCustomInt.sh that contains:
sudo python
I went to PyCharm settings > Project Interpreter and changed the Base interpreter to /<path>/pythonCutomInt.sh but it writes an error:
Environment location directory is not empty
I am not sure where I need to put the script.
Any idea?
I ran sudo -s and then from the pycharm folder (pycharm-community-2018.1.4/bin) I ran sh ./pycharm.sh and it worked.
I am using Laradock and want to be able to run a python script from my laravel app using Symfony Process. From inside the root on my container I can run "python3 script_name.py arg1" and it runs just fine. pip list shows all modules needed. When I run it from inside Laravel, it tells me:
"import pymysql ImportError: No module named 'pymysql'"
I have used a non-docker Laravel app to do this just fine, using:
$script = storage_path().'/app/script.py';
$process = new Process('python3 '. $script." ".session('division'));
What am I missing?
On *nix make sure that PYTHONPATH is configured correctly for all users or try to set full path to python3.
How to check
At first your php user
php -r "print shell_exec( 'whoami' );" // somebody
When run
su somebody python3 script_name.py arg1
I'd like to create a script (.sh or python, not important) that can do the following:
heroku pg:reset DATABASE_URL
heroku run python manage.py migrate
heroku run python manage.py shell
> from myapp.scenarios import *; reset_demo_data(); exit()
Line 1 to 3 are UNIX commands, but Line 4 is python to be executed in the opened Django shell.
I tried stuff with | and > to "inject" the python code in the command but nothing worked.
I guess it's quite easy to do but I can't figure out how..
Thanks.
I guess the best option would be to write a custom management command.
Your script could then look like:
heroku pg:reset DATABASE_URL
heroku run python manage.py migrate
heroku run python manage.py shell
heroku run python manage.py reset_demo
when the management command is something like:
from django.core.management.base import BaseCommand
from myapp.scenarios import *
class Command(BaseCommand):
def handle(self, *args, **options):
reset_demo_data()
Or you can try this one line solution:
echo "from myapp.scenarios import *; reset_demo_data(); exit()" | python manage.py shell
You can add this line replacing Shell activation line.