THEANO_FLAGS: Command not found - python

My settings of .theanorc file is device = gpu0, but I want to know if I can run one program with gpu0, and run another with gpu1, I tried THEANO_FLAGS='device=gpu1' python myscript.py but it raised THEANO_FLAGS: Command not found.

just add these 2 lines in the script:
import os
os.environ["THEANO_FLAGS"] = "device=gpu1"

THEANO_FLAGS='device=gpu1' python myscript.py is working for me.
Are you sure you have no space character after THEANO_FLAGS, like this: THEANO_FLAGS ='device=gpu1' python myscript.py.
This would raise the THEANO_FLAGS: Command not found

Related

Shell command not found in python script

I source a dotcshrc file in my python script with :os.system(‘/bin/csh dotcshrc’) and it works,but when I want to use the command I have just put into the env by the source command,like os.system(‘ikvalidate mycase ‘),linux complaints:command not found.
But when I do it all by hand,everything go well.
Where is problem?
If you have a command in linux like ls and you want to use it in your python code do like this:
import os
ls = lambda : os.system('ls')
# This effectively turns that command into a python function.
ls() # skadoosh!
Output is :
FileManip.py Oscar
MySafety PROJECT DOCS
GooSpace Pg Admin
l1_2014 PlatformMavenRepo
l1_2015 R
l1_201617 R64
l2_2014 Resources
os.system runs each command in its own isolated environment. If you are sourcing something in an os.system call, subsequent calls will not see that because they are starting with a fresh shell environment. If you have dependencies like the above, you might be able to combine it into one call:
os.system(‘/bin/csh "dotcshrc; ikvalidate mycase"’)

Python script doesn't print output in command prompt

I need some advice with a Python script. I'm still new and learned it by myself. I found the script on Google. After I retype it, it doesn't print the result in the console. How can the result of the script be shown in the console? Details as below:
C:\Python27>test1.py af8978b1797b72acfff9595a5a2a373ec3d9106d
C:\Python27>
After I press enter, nothing happens. Should the result be shown or not?
Here's the code that I retyped:
#!/usr/bin/python
#coding: ascii
import requests
import sys
import re
url = 'http://hashtoolkit.com/reverse-hash?hash='
try:
hash = sys.argv[1]
except:
print ("usage: python "+sys.argv[0]+" hash")
sys.exit()
http = request.get(url+hash)
content = http.content
cracked = re.findall("<span title=\*decrypted (md5|sha1|sha384|sha512) hash\*>(.*)</span>", content) # expression regular
print ("\n\tAlgoritmo: "+cracked[0][0])
print ("\tPassword Cracked: "+cracked[0][1])
The first line in your script is called a Shebang line.
A Shebang line tells the script to run the Python interpreter from that location.
The shebang line you provided is a Linux system path, but it looks from the path you are executing Python from, that you are running on Windows.
You can do one of two things here to fix that:
Remove the Shebange Line.
Remove the first line from your script.
Execute the script using python test1.py COMMAND_LINE_ARGUMENTS
Modify Your Shebang line.
Change the first line of your script from !/usr/bin/python to
#!python (This is assuming that python is in your systems PATH variable.)`
Execute the script using test1.py COMMAND_LINE_ARGUMENTS
Also, you are trying to import the requests module that is not installed in the standard library.
If you haven't installed this yet, you can do so by going to your Python install directory and go to the scripts folder.
Hold shift and right click and go Open command window here
Type pip install requests and hit enter.
After that you should be good to go, execute the script by navigating to it and type test.py COMMAND_LINE_ARGUMENT
If a Python script doesn't have the shebang line:
python test.py COMMAND_LINE_ARGUMENT
you need to run your script using python. try:
C:\Python27>python test1.py af8978b1797b72acfff9595a5a2a373ec3d9106d

Executable .py file with shebang path to which python gives error, command not found

I have a self-installed python in my user directory in a corporate UNIX SUSE computer (no sudo privilege):
which python
<user>/bin/python/Python-3.6.1/python
I have an executable (chmod 777) sample.py file with this line at the top of the file:
#!<user>/bin/python/Python-3.6.1/python
I can execute the file like this:
python sample.py
But when I run it by itself I get an error:
/full/path/sample.py
/full/path/sample.py: Command not found
I have no idea why it's not working. I'm discombobulated as what might be going wrong since the file is executable, the python path is correct, and the file executes if I put a python command in the front. What am I missing?
EDIT:
I tried putting this on top of the file:
#!/usr/bin/env python
Now, I get this error:
: No such file or directory
I tried this to make sure my env is correct
which env
/usr/bin/env
EDIT2:
Yes, I can run the script fine using the shebang command like this:
<user>/bin/python/Python-3.6.1/python /full/path/sample.py
Your file has DOS line endings (CR+LF). It works if you run python sample.py but doesn't work if you run ./sample.py. Recode the file so it has Unix line endings (pure LF at the end of every line).
Try using #!/usr/bin/env python as described in this post. Let the OS do the work.

Get Exceptions from popen in python

I executed this code in python: (test.py)
from subprocess import Popen
p = Popen("file.bat").wait()
Here is file.bat:
#echo off
start c:\python27\python.exe C:\Test\p1.py %*
start c:\python27\python.exe C:\Test\p2.py %*
pause
Here is p1.py:
This line is error
print "Hello word"
p2.py is not interesting
I want to know the exception(not only compiling error) in p1.py by running test.py?
How can I do this?
Thanks!
Here's how I got it working:
test.py
from subprocess import Popen
p = Popen(["./file.sh"]).wait()
Make sure to add the [] around file, as well as the ./. You can also add arguments, like so:
["./file.sh", "someArg"]
Note that I am not on Windows, but this fixed it on Ubuntu. Please comment if you are still having issues
EDIT:
I think the real solution is: Using subprocess to run Python script on Windows
This way you can run a python script from python, while still using Popen

Python encountering unexpected ')` in very short program

Python is seeing some problem with how I am opening a file with the code below
if __name__ == "__main__":
fileName = sys.argv[1]
with open(fileName, 'r') as f:
for line in f:
print line
It is producing the error
./search.py: line 3: syntax error near unexpected token `('
./search.py: line 3: ` with open(fileName, 'r') as f:'
Am I missing an import? What could be the cause of this?
EDIT: OS - CentOS, Python version 2.6.6
Not sure how I installed, I am running an image from a .edu openstack site. Not sure of the distribution, binaries, ...
You must add import sys in order to use sys.argv. Check this out.
I have tried this:
chmod u+x yourfile.py
./yourfile.py
and it gives me:
./jd.py: line 4: syntax error near unexpected token `('
./jd.py: line 4: ` with open(fileName, 'r') as f:'
If you are doing ./search.py file then add at the beginnig of your file #!/usr/bin/env python. Otherwise, use python file.py input
The problem is that you aren't running your program with Python at all! When you do ./script (assuming that script is a text script, and not a binary program), the system will look for a line at the top of the file beginning with the sequence #!. If it finds that line, the rest of the line will be used as the interpreter of that script: the program which runs the script. If it doesn't find that line, the system defaults to /bin/sh.
So, basically, by omitting the magic line #!/usr/bin/python at the top of your script, the system will run your Python script using sh, which will produce all sorts of incorrect results.
The solution, then, is to add the line #!/usr/bin/python (or an equivalent line, like #!/usr/bin/env python) to the top of your Python script so that your system will run it using Python. Alternately, you can also always run your program using python search.py, instead of using ./search.py.
(Note that, on Linux, filename extensions like .py mean almost nothing to the system. Thus, even though it ends with .py, Linux will just execute it as if you wrote /bin/sh search.py).
Either:
the first line of search.py should be a #! comment specifying the path to locate the python executable, usually [#!/usr/bin/env python](Why do people write #!/usr/bin/env python on the first line of a Python script?
on-the-first-line-of-a-python-script). Usually this is #!/usr/env/bin python . Don't use a hardpath e.g. #/opt/local/bin/python2.7
or else you can invoke as python yourfile.py <yourargs> ...
PREVIOUS: If import sys fails, post more of your file please.
Maybe your install is messed up.
Can you import anything else successfully, e.g. import re?
What are your platform, OS and Python version? How did you install? source? binaries? distribution? which ones, from where?

Categories