Python failing to create symlinks - python

I'm trying to use python to make symbolic links. When I try to use os.symlink I get a WinError 5 "Access is denied" error, but if I try to create the same symlink using mklink, it works fine. (I'm running this as an administrator, and have the 'Create symbolic links' privilege.)
I then to use subprocess.call to call mklink directly with the proper arguments and such, and it runs without any errors, yet when it's finished the symlinks have not been created.
When I try to use Popen to run the command I get a 'system cannot find the file specified' error even though the directory is there.
This is on Windows Server 2008.
def createStudentFolders(studentList):
grad_year = input("Please enter the year of graduation for the class of students being created (i.e. 2016): ")
for student in studentList:
student = student.replace(" ","") # Gets rid of the white space in the name
studentPath = 'cpwd/{}'.format(student)
try:
os.mkdir(studentPath)
except:
pass
print(studentPath)
proc = Popen("icacls {} /inheritance:e /grant STUDENT\{}:(OI)(CI)F /T".format(studentPath, student))
classFolder = "students/ClassOf{}".format(grad_year)
try:
os.mkdir(classFolder)
except:
pass
os.symlink('{}/{}'.format(classFolder, student), studentPath, target_is_directory=True)
print("Done")
def main():
newStudentsLoc = "newStudents.txt"
studentList = readStudentsToList(newStudentsLoc)
createStudentFolders(studentList)
main()
input("Pausing")
File resides in Z:\
inside that are
cpwd\<student folders>
students\ClassOf<Year>\<symlinks to student folders go here>
I've tried using absolute paths as well with no luck.

Related

Python subprocess.run can't find /bin/sh in chroot

(First off, apologies for the roughness of this question's writing-- would love any constructive feedback.)
Ok what I'm doing is a bit involved-- I'm trying to make a Python script that executes Bash scripts that each compile a component of a Linux From Scratch (LFS) system. I'm following the LFS 11.2 book pretty closely (but not 100%, although I've been very careful to check where my deviations break things. If you're familiar with LFS, this is a deviation that breaks things).
Basically, my script builds a bunch of tools (bash, tar, xz, make, gcc, binutils) with a cross compiler, and tells their build systems to install them into a directory lfs/temp-tools. Then the script calls os.chroot('lfs') to chroot into the lfs directory, and immediately resets all the environment variables (most importantly PATH) with:
os.environ = {"PATH" : "/usr/bin:/usr/sbin:/temp-tools/bin", ...other trivial stuff like HOME...}
But after the chroot, my calls of
subprocess.run([f"{build_script_path} >{log_file_path} 2>&1"], shell=True)
are failing with FileNotFoundError: [Errno 2] No such file or directory: '/bin/sh', even though
bin/sh in the chroot directory is a sym link to bash
there's a perfectly good copy of bash in /temp-tools/bin
calling print(os.environ) after the python chroot shows /temp-tools/bin is in PATH
I thought maybe subprocess.run is stuck using the old environment variables, before I reset them upon entering the chroot, but adding env=os.environ to subprocess.run does not help. :/ I'm stuck for now
For context if it helps, here is where the subprocess.run call gets made:
def vanilla_build(target_name, src_dir_name=None):
def f():
nonlocal src_dir_name
if src_dir_name == None:
src_dir_name = target_name
tarball_path = find_tarball(src_dir_name)
src_dir_path = tarball_path.split(".tar")[0]
if "tcl" in src_dir_path:
src_dir_path = src_dir_path.rsplit("-",1)[0]
snap1 = lfs_dir_snapshot()
os.chdir(os.environ["LFS"] + "srcs/")
subprocess.run(["tar", "-xf", tarball_path], check=True, env=os.environ)
os.chdir(src_dir_path)
build_script_path = f"{os.environ['LFS']}root/build-scripts/{target_name.replace('_','-')}.sh"
log_file_path = f"{os.environ['LFS']}logs/{target_name}"
####### The main call #######
proc = subprocess.run([f"{build_script_path} >{log_file_path} 2>&1"],
shell=True, env=os.environ)
subprocess.run(["rm", "-rf", src_dir_path], check=True)
if proc.returncode != 0:
red_print(build_script_path + " failed!")
return
tracked_file_record_path = f"{os.environ['LFS']}logs/tracked/{target_name}"
with open(tracked_file_record_path, 'w') as f:
new_files = lfs_dir_snapshot() - snap1
f.writelines('\n'.join(new_files))
f.__name__ = "build_" + target_name
return f
And how I enter the chroot:
def enter_chroot():
os.chdir(os.environ["LFS"])
os.chroot(os.environ["LFS"])
os.environ = {"HOME" : "/root",
"TERM" : os.environ["TERM"],
"PATH" : "/usr/bin:/usr/sbin:/temp-tools/bin",
"LFS" : '/'}
Thank you! In the meantime I'm going to chop away as much code as possible to isolate the problem to either understand whatever I'm not getting or rewrite this question to be less context specific

how to pass a python variable into a bash script function

I have searched and searched and searched but have not found and answer to my particular situation, or if I had I don't know how to implement it. I'm trying to create a script using python and bash to automate my project creation process. Whereas I would run the testing.py "as it is called now because I'm testing" with 1 command line argument which would be the name of the project folder, then it would ask "where I would like to create the project" with two options for paths to store the project and store the path using an if statement into the path variable. then I would like to pass that variable in the bash script to navigate to it and create the project directory there. here is what I have so far:
so the command that I would run is like:
python testing.py newProject
in the .test.sh
#!/bin/bash
function testing() {
cd
desktop
python testing.py $1
}
and in the testing.py
import sys
import os
school = "/Users/albert/Open/Microverse/"
personal = "/Users/albert/Open/code/Projects/"
path = " "
userInput = input("What type of project would you like to create? Personal or School? ")
if userInput.lower() == "personal":
path = personal
elif userInput.lower() == "school":
path = school
def testing():
folderName = str(sys.argv[1])
os.makedirs(path + str(folderName))
print(folderName)
if __name__ == "__main__":
testing()
Use "$1" instead of $1 as shown below
python testing.py "$1"
You have to run your bash function like this
testing $1
The whole script
#!/bin/bash
function testing() {
cd
desktop
python test.py $1
}
testing $1
And change input() to raw_input() in your python part. Input() function returns will actually evaluate the input string and try to run it as Python code. And if i try to input Personal this give me an error
What type of project would you like to create? Personal or School? Personal
Traceback (most recent call last):
File "test.py", line 9, in <module>
userInput = input("What type of project would you like to create? Personal or School? ")
File "<string>", line 1, in <module>
NameError: name 'Personal' is not defined
And if you input personal than userInput will be /Users/albert/Open/code/Projects/ wich is not wat you want right?
I'm guessing desktop is not actually a valid command, and that you really want
testing () {
cd ~/Desktop
python test.py "$1"
]
A better design might be to not force all projects to be created inside your desktop folder, though.
testing () {
python ~/Desktop/test.py "$1"
}
will let you run the script in any directory.
A still better design would be to give the script a proper shebang, mark it executable, call it testing, and save it in your PATH; then you don't need a shell function at all.
A different and IMHO more usable approach would be to allow the user to specify "personal" or "school" as part of the command line, instead of forcing the script to use interactive input. Requiring interactive I/O makes the script harder to use as a building block in further automation, and robs the user of the ability to use the shell's history and completion features.
The following refactoring hard-codes a very crude option parser, and uses a dict to map the project type to a specific folder name.
#!/usr/bin/env python3
import sys
import os
paths = {
"school": "/Users/albert/Open/Microverse/"
"personal": "/Users/albert/Open/code/Projects/"
}
def makeproject(type, folder):
os.makedirs(os.path.join(path, folder))
def gettype():
while True:
userInput = input("What type of project would you like to create? Personal or School? ")
if userInput in paths:
return paths[userInput]
print("Not a valid option: {} -- try again".format(userInput))
def testing():
idx = 1
if sys.argv[idx] == "--school":
type = paths["school"]
idx = 1
elif sys.argv[idx] == "--personal":
type = paths["personal"
idx = 2
else:
type = gettype()
folderName = sys.argv[idx]
makeproject(type, folderName)
print(folderName)
if __name__ == "__main__":
testing()
Notice that sys.argv and the value returned by input are already strings; there is no need to call str() on them.

Copying a file in python : Permission denied [duplicate]

I want my Python script to copy files on Vista. When I run it from a normal cmd.exe window, no errors are generated, yet the files are NOT copied. If I run cmd.exe "as administator" and then run my script, it works fine.
This makes sense since User Account Control (UAC) normally prevents many file system actions.
Is there a way I can, from within a Python script, invoke a UAC elevation request (those dialogs that say something like "such and such app needs admin access, is this OK?")
If that's not possible, is there a way my script can at least detect that it is not elevated so it can fail gracefully?
As of 2017, an easy method to achieve this is the following:
import ctypes, sys
def is_admin():
try:
return ctypes.windll.shell32.IsUserAnAdmin()
except:
return False
if is_admin():
# Code of your program here
else:
# Re-run the program with admin rights
ctypes.windll.shell32.ShellExecuteW(None, "runas", sys.executable, " ".join(sys.argv), None, 1)
If you are using Python 2.x, then you should replace the last line for:
ctypes.windll.shell32.ShellExecuteW(None, u"runas", unicode(sys.executable), unicode(" ".join(sys.argv)), None, 1)
Also note that if you converted you python script into an executable file (using tools like py2exe, cx_freeze, pyinstaller) then you should use sys.argv[1:] instead of sys.argv in the fourth parameter.
Some of the advantages here are:
No external libraries required. It only uses ctypes and sys from standard library.
Works on both Python 2 and Python 3.
There is no need to modify the file resources nor creating a manifest file.
If you don't add code below if/else statement, the code won't ever be executed twice.
You can get the return value of the API call in the last line and take an action if it fails (code <= 32). Check possible return values here.
You can change the display method of the spawned process modifying the sixth parameter.
Documentation for the underlying ShellExecute call is here.
It took me a little while to get dguaraglia's answer working, so in the interest of saving others time, here's what I did to implement this idea:
import os
import sys
import win32com.shell.shell as shell
ASADMIN = 'asadmin'
if sys.argv[-1] != ASADMIN:
script = os.path.abspath(sys.argv[0])
params = ' '.join([script] + sys.argv[1:] + [ASADMIN])
shell.ShellExecuteEx(lpVerb='runas', lpFile=sys.executable, lpParameters=params)
sys.exit(0)
It seems there's no way to elevate the application privileges for a while for you to perform a particular task. Windows needs to know at the start of the program whether the application requires certain privileges, and will ask the user to confirm when the application performs any tasks that need those privileges. There are two ways to do this:
Write a manifest file that tells Windows the application might require some privileges
Run the application with elevated privileges from inside another program
This two articles explain in much more detail how this works.
What I'd do, if you don't want to write a nasty ctypes wrapper for the CreateElevatedProcess API, is use the ShellExecuteEx trick explained in the Code Project article (Pywin32 comes with a wrapper for ShellExecute). How? Something like this:
When your program starts, it checks if it has Administrator privileges, if it doesn't it runs itself using the ShellExecute trick and exits immediately, if it does, it performs the task at hand.
As you describe your program as a "script", I suppose that's enough for your needs.
Cheers.
Just adding this answer in case others are directed here by Google Search as I was.
I used the elevate module in my Python script and the script executed with Administrator Privileges in Windows 10.
https://pypi.org/project/elevate/
The following example builds on MARTIN DE LA FUENTE SAAVEDRA's excellent work and accepted answer. In particular, two enumerations are introduced. The first allows for easy specification of how an elevated program is to be opened, and the second helps when errors need to be easily identified. Please note that if you want all command line arguments passed to the new process, sys.argv[0] should probably be replaced with a function call: subprocess.list2cmdline(sys.argv).
#! /usr/bin/env python3
import ctypes
import enum
import subprocess
import sys
# Reference:
# msdn.microsoft.com/en-us/library/windows/desktop/bb762153(v=vs.85).aspx
# noinspection SpellCheckingInspection
class SW(enum.IntEnum):
HIDE = 0
MAXIMIZE = 3
MINIMIZE = 6
RESTORE = 9
SHOW = 5
SHOWDEFAULT = 10
SHOWMAXIMIZED = 3
SHOWMINIMIZED = 2
SHOWMINNOACTIVE = 7
SHOWNA = 8
SHOWNOACTIVATE = 4
SHOWNORMAL = 1
class ERROR(enum.IntEnum):
ZERO = 0
FILE_NOT_FOUND = 2
PATH_NOT_FOUND = 3
BAD_FORMAT = 11
ACCESS_DENIED = 5
ASSOC_INCOMPLETE = 27
DDE_BUSY = 30
DDE_FAIL = 29
DDE_TIMEOUT = 28
DLL_NOT_FOUND = 32
NO_ASSOC = 31
OOM = 8
SHARE = 26
def bootstrap():
if ctypes.windll.shell32.IsUserAnAdmin():
main()
else:
# noinspection SpellCheckingInspection
hinstance = ctypes.windll.shell32.ShellExecuteW(
None,
'runas',
sys.executable,
subprocess.list2cmdline(sys.argv),
None,
SW.SHOWNORMAL
)
if hinstance <= 32:
raise RuntimeError(ERROR(hinstance))
def main():
# Your Code Here
print(input('Echo: '))
if __name__ == '__main__':
bootstrap()
Recognizing this question was asked years ago, I think a more elegant solution is offered on github by frmdstryr using his module pywinutils:
Excerpt:
import pythoncom
from win32com.shell import shell,shellcon
def copy(src,dst,flags=shellcon.FOF_NOCONFIRMATION):
""" Copy files using the built in Windows File copy dialog
Requires absolute paths. Does NOT create root destination folder if it doesn't exist.
Overwrites and is recursive by default
#see http://msdn.microsoft.com/en-us/library/bb775799(v=vs.85).aspx for flags available
"""
# #see IFileOperation
pfo = pythoncom.CoCreateInstance(shell.CLSID_FileOperation,None,pythoncom.CLSCTX_ALL,shell.IID_IFileOperation)
# Respond with Yes to All for any dialog
# #see http://msdn.microsoft.com/en-us/library/bb775799(v=vs.85).aspx
pfo.SetOperationFlags(flags)
# Set the destionation folder
dst = shell.SHCreateItemFromParsingName(dst,None,shell.IID_IShellItem)
if type(src) not in (tuple,list):
src = (src,)
for f in src:
item = shell.SHCreateItemFromParsingName(f,None,shell.IID_IShellItem)
pfo.CopyItem(item,dst) # Schedule an operation to be performed
# #see http://msdn.microsoft.com/en-us/library/bb775780(v=vs.85).aspx
success = pfo.PerformOperations()
# #see sdn.microsoft.com/en-us/library/bb775769(v=vs.85).aspx
aborted = pfo.GetAnyOperationsAborted()
return success is None and not aborted
This utilizes the COM interface and automatically indicates that admin privileges are needed with the familiar dialog prompt that you would see if you were copying into a directory where admin privileges are required and also provides the typical file progress dialog during the copy operation.
This may not completely answer your question but you could also try using the Elevate Command Powertoy in order to run the script with elevated UAC privileges.
http://technet.microsoft.com/en-us/magazine/2008.06.elevation.aspx
I think if you use it it would look like 'elevate python yourscript.py'
You can make a shortcut somewhere and as the target use:
python yourscript.py
then under properties and advanced select run as administrator.
When the user executes the shortcut it will ask them to elevate the application.
A variation on Jorenko's work above allows the elevated process to use the same console (but see my comment below):
def spawn_as_administrator():
""" Spawn ourself with administrator rights and wait for new process to exit
Make the new process use the same console as the old one.
Raise Exception() if we could not get a handle for the new re-run the process
Raise pywintypes.error() if we could not re-spawn
Return the exit code of the new process,
or return None if already running the second admin process. """
#pylint: disable=no-name-in-module,import-error
import win32event, win32api, win32process
import win32com.shell.shell as shell
if '--admin' in sys.argv:
return None
script = os.path.abspath(sys.argv[0])
params = ' '.join([script] + sys.argv[1:] + ['--admin'])
SEE_MASK_NO_CONSOLE = 0x00008000
SEE_MASK_NOCLOSE_PROCESS = 0x00000040
process = shell.ShellExecuteEx(lpVerb='runas', lpFile=sys.executable, lpParameters=params, fMask=SEE_MASK_NO_CONSOLE|SEE_MASK_NOCLOSE_PROCESS)
hProcess = process['hProcess']
if not hProcess:
raise Exception("Could not identify administrator process to install drivers")
# It is necessary to wait for the elevated process or else
# stdin lines are shared between 2 processes: they get one line each
INFINITE = -1
win32event.WaitForSingleObject(hProcess, INFINITE)
exitcode = win32process.GetExitCodeProcess(hProcess)
win32api.CloseHandle(hProcess)
return exitcode
This is mostly an upgrade to Jorenko's answer, that allows to use parameters with spaces in Windows, but should also work fairly well on Linux :)
Also, will work with cx_freeze or py2exe since we don't use __file__ but sys.argv[0] as executable
[EDIT]
Disclaimer: The code in this post is outdated.
I have published the elevation code as a python package.
Install with pip install command_runner
Usage:
from command_runner.elevate import elevate
def main():
"""My main function that should be elevated"""
print("Who's the administrator, now ?")
if __name__ == '__main__':
elevate(main)
[/EDIT]
import sys,ctypes,platform
def is_admin():
try:
return ctypes.windll.shell32.IsUserAnAdmin()
except:
raise False
if __name__ == '__main__':
if platform.system() == "Windows":
if is_admin():
main(sys.argv[1:])
else:
# Re-run the program with admin rights, don't use __file__ since py2exe won't know about it
# Use sys.argv[0] as script path and sys.argv[1:] as arguments, join them as lpstr, quoting each parameter or spaces will divide parameters
lpParameters = ""
# Litteraly quote all parameters which get unquoted when passed to python
for i, item in enumerate(sys.argv[0:]):
lpParameters += '"' + item + '" '
try:
ctypes.windll.shell32.ShellExecuteW(None, "runas", sys.executable, lpParameters , None, 1)
except:
sys.exit(1)
else:
main(sys.argv[1:])
For one-liners, put the code to where you need UAC.
Request UAC, if failed, keep running:
import ctypes, sys
ctypes.windll.shell32.IsUserAnAdmin() or ctypes.windll.shell32.ShellExecuteW(
None, "runas", sys.executable, " ".join(sys.argv), None, 1) > 32 and exit()
Request UAC, if failed, exit:
import ctypes, sys
ctypes.windll.shell32.IsUserAnAdmin() or (ctypes.windll.shell32.ShellExecuteW(
None, "runas", sys.executable, " ".join(sys.argv), None, 1) > 32, exit())
Function style:
# Created by BaiJiFeiLong#gmail.com at 2022/6/24
import ctypes
import sys
def request_uac_or_skip():
ctypes.windll.shell32.IsUserAnAdmin() or ctypes.windll.shell32.ShellExecuteW(
None, "runas", sys.executable, " ".join(sys.argv), None, 1) > 32 and sys.exit()
def request_uac_or_exit():
ctypes.windll.shell32.IsUserAnAdmin() or (ctypes.windll.shell32.ShellExecuteW(
None, "runas", sys.executable, " ".join(sys.argv), None, 1) > 32, sys.exit())
If your script always requires an Administrator's privileges then:
runas /user:Administrator "python your_script.py"

How to get linux screen title from command line

How can I fetch the title of a screen session from the command line?
I came up with a very small and simple python script with pexpect to do it.
It is handy in multiuser environments where some host is reserved and status is written to screen title by user.
It works for me, feel free to make it better.
In order to fetch specific session title, you need to modify the script and call for correct session.
If you run this through remote connection as local script (through SSH for example), remember to set export TERM=xterm before execution.
try:
import pexpect
import sys
child=pexpect.spawn('screen -x')
child.sendcontrol('a');
child.send('A');
i = child.expect('Set window.*')
child.sendcontrol('c');
child.sendcontrol('a');
child.send('d');
TITLE=str(child.after)
TITLE_P=TITLE.split('7m')
if str(TITLE_P[-1]) == '':
print 'Title not found'
else:
print str(TITLE_P[-1])
except:
print 'Could not check screen Title'

Request UAC elevation from within a Python script?

I want my Python script to copy files on Vista. When I run it from a normal cmd.exe window, no errors are generated, yet the files are NOT copied. If I run cmd.exe "as administator" and then run my script, it works fine.
This makes sense since User Account Control (UAC) normally prevents many file system actions.
Is there a way I can, from within a Python script, invoke a UAC elevation request (those dialogs that say something like "such and such app needs admin access, is this OK?")
If that's not possible, is there a way my script can at least detect that it is not elevated so it can fail gracefully?
As of 2017, an easy method to achieve this is the following:
import ctypes, sys
def is_admin():
try:
return ctypes.windll.shell32.IsUserAnAdmin()
except:
return False
if is_admin():
# Code of your program here
else:
# Re-run the program with admin rights
ctypes.windll.shell32.ShellExecuteW(None, "runas", sys.executable, " ".join(sys.argv), None, 1)
If you are using Python 2.x, then you should replace the last line for:
ctypes.windll.shell32.ShellExecuteW(None, u"runas", unicode(sys.executable), unicode(" ".join(sys.argv)), None, 1)
Also note that if you converted you python script into an executable file (using tools like py2exe, cx_freeze, pyinstaller) then you should use sys.argv[1:] instead of sys.argv in the fourth parameter.
Some of the advantages here are:
No external libraries required. It only uses ctypes and sys from standard library.
Works on both Python 2 and Python 3.
There is no need to modify the file resources nor creating a manifest file.
If you don't add code below if/else statement, the code won't ever be executed twice.
You can get the return value of the API call in the last line and take an action if it fails (code <= 32). Check possible return values here.
You can change the display method of the spawned process modifying the sixth parameter.
Documentation for the underlying ShellExecute call is here.
It took me a little while to get dguaraglia's answer working, so in the interest of saving others time, here's what I did to implement this idea:
import os
import sys
import win32com.shell.shell as shell
ASADMIN = 'asadmin'
if sys.argv[-1] != ASADMIN:
script = os.path.abspath(sys.argv[0])
params = ' '.join([script] + sys.argv[1:] + [ASADMIN])
shell.ShellExecuteEx(lpVerb='runas', lpFile=sys.executable, lpParameters=params)
sys.exit(0)
It seems there's no way to elevate the application privileges for a while for you to perform a particular task. Windows needs to know at the start of the program whether the application requires certain privileges, and will ask the user to confirm when the application performs any tasks that need those privileges. There are two ways to do this:
Write a manifest file that tells Windows the application might require some privileges
Run the application with elevated privileges from inside another program
This two articles explain in much more detail how this works.
What I'd do, if you don't want to write a nasty ctypes wrapper for the CreateElevatedProcess API, is use the ShellExecuteEx trick explained in the Code Project article (Pywin32 comes with a wrapper for ShellExecute). How? Something like this:
When your program starts, it checks if it has Administrator privileges, if it doesn't it runs itself using the ShellExecute trick and exits immediately, if it does, it performs the task at hand.
As you describe your program as a "script", I suppose that's enough for your needs.
Cheers.
Just adding this answer in case others are directed here by Google Search as I was.
I used the elevate module in my Python script and the script executed with Administrator Privileges in Windows 10.
https://pypi.org/project/elevate/
The following example builds on MARTIN DE LA FUENTE SAAVEDRA's excellent work and accepted answer. In particular, two enumerations are introduced. The first allows for easy specification of how an elevated program is to be opened, and the second helps when errors need to be easily identified. Please note that if you want all command line arguments passed to the new process, sys.argv[0] should probably be replaced with a function call: subprocess.list2cmdline(sys.argv).
#! /usr/bin/env python3
import ctypes
import enum
import subprocess
import sys
# Reference:
# msdn.microsoft.com/en-us/library/windows/desktop/bb762153(v=vs.85).aspx
# noinspection SpellCheckingInspection
class SW(enum.IntEnum):
HIDE = 0
MAXIMIZE = 3
MINIMIZE = 6
RESTORE = 9
SHOW = 5
SHOWDEFAULT = 10
SHOWMAXIMIZED = 3
SHOWMINIMIZED = 2
SHOWMINNOACTIVE = 7
SHOWNA = 8
SHOWNOACTIVATE = 4
SHOWNORMAL = 1
class ERROR(enum.IntEnum):
ZERO = 0
FILE_NOT_FOUND = 2
PATH_NOT_FOUND = 3
BAD_FORMAT = 11
ACCESS_DENIED = 5
ASSOC_INCOMPLETE = 27
DDE_BUSY = 30
DDE_FAIL = 29
DDE_TIMEOUT = 28
DLL_NOT_FOUND = 32
NO_ASSOC = 31
OOM = 8
SHARE = 26
def bootstrap():
if ctypes.windll.shell32.IsUserAnAdmin():
main()
else:
# noinspection SpellCheckingInspection
hinstance = ctypes.windll.shell32.ShellExecuteW(
None,
'runas',
sys.executable,
subprocess.list2cmdline(sys.argv),
None,
SW.SHOWNORMAL
)
if hinstance <= 32:
raise RuntimeError(ERROR(hinstance))
def main():
# Your Code Here
print(input('Echo: '))
if __name__ == '__main__':
bootstrap()
Recognizing this question was asked years ago, I think a more elegant solution is offered on github by frmdstryr using his module pywinutils:
Excerpt:
import pythoncom
from win32com.shell import shell,shellcon
def copy(src,dst,flags=shellcon.FOF_NOCONFIRMATION):
""" Copy files using the built in Windows File copy dialog
Requires absolute paths. Does NOT create root destination folder if it doesn't exist.
Overwrites and is recursive by default
#see http://msdn.microsoft.com/en-us/library/bb775799(v=vs.85).aspx for flags available
"""
# #see IFileOperation
pfo = pythoncom.CoCreateInstance(shell.CLSID_FileOperation,None,pythoncom.CLSCTX_ALL,shell.IID_IFileOperation)
# Respond with Yes to All for any dialog
# #see http://msdn.microsoft.com/en-us/library/bb775799(v=vs.85).aspx
pfo.SetOperationFlags(flags)
# Set the destionation folder
dst = shell.SHCreateItemFromParsingName(dst,None,shell.IID_IShellItem)
if type(src) not in (tuple,list):
src = (src,)
for f in src:
item = shell.SHCreateItemFromParsingName(f,None,shell.IID_IShellItem)
pfo.CopyItem(item,dst) # Schedule an operation to be performed
# #see http://msdn.microsoft.com/en-us/library/bb775780(v=vs.85).aspx
success = pfo.PerformOperations()
# #see sdn.microsoft.com/en-us/library/bb775769(v=vs.85).aspx
aborted = pfo.GetAnyOperationsAborted()
return success is None and not aborted
This utilizes the COM interface and automatically indicates that admin privileges are needed with the familiar dialog prompt that you would see if you were copying into a directory where admin privileges are required and also provides the typical file progress dialog during the copy operation.
This may not completely answer your question but you could also try using the Elevate Command Powertoy in order to run the script with elevated UAC privileges.
http://technet.microsoft.com/en-us/magazine/2008.06.elevation.aspx
I think if you use it it would look like 'elevate python yourscript.py'
You can make a shortcut somewhere and as the target use:
python yourscript.py
then under properties and advanced select run as administrator.
When the user executes the shortcut it will ask them to elevate the application.
A variation on Jorenko's work above allows the elevated process to use the same console (but see my comment below):
def spawn_as_administrator():
""" Spawn ourself with administrator rights and wait for new process to exit
Make the new process use the same console as the old one.
Raise Exception() if we could not get a handle for the new re-run the process
Raise pywintypes.error() if we could not re-spawn
Return the exit code of the new process,
or return None if already running the second admin process. """
#pylint: disable=no-name-in-module,import-error
import win32event, win32api, win32process
import win32com.shell.shell as shell
if '--admin' in sys.argv:
return None
script = os.path.abspath(sys.argv[0])
params = ' '.join([script] + sys.argv[1:] + ['--admin'])
SEE_MASK_NO_CONSOLE = 0x00008000
SEE_MASK_NOCLOSE_PROCESS = 0x00000040
process = shell.ShellExecuteEx(lpVerb='runas', lpFile=sys.executable, lpParameters=params, fMask=SEE_MASK_NO_CONSOLE|SEE_MASK_NOCLOSE_PROCESS)
hProcess = process['hProcess']
if not hProcess:
raise Exception("Could not identify administrator process to install drivers")
# It is necessary to wait for the elevated process or else
# stdin lines are shared between 2 processes: they get one line each
INFINITE = -1
win32event.WaitForSingleObject(hProcess, INFINITE)
exitcode = win32process.GetExitCodeProcess(hProcess)
win32api.CloseHandle(hProcess)
return exitcode
This is mostly an upgrade to Jorenko's answer, that allows to use parameters with spaces in Windows, but should also work fairly well on Linux :)
Also, will work with cx_freeze or py2exe since we don't use __file__ but sys.argv[0] as executable
[EDIT]
Disclaimer: The code in this post is outdated.
I have published the elevation code as a python package.
Install with pip install command_runner
Usage:
from command_runner.elevate import elevate
def main():
"""My main function that should be elevated"""
print("Who's the administrator, now ?")
if __name__ == '__main__':
elevate(main)
[/EDIT]
import sys,ctypes,platform
def is_admin():
try:
return ctypes.windll.shell32.IsUserAnAdmin()
except:
raise False
if __name__ == '__main__':
if platform.system() == "Windows":
if is_admin():
main(sys.argv[1:])
else:
# Re-run the program with admin rights, don't use __file__ since py2exe won't know about it
# Use sys.argv[0] as script path and sys.argv[1:] as arguments, join them as lpstr, quoting each parameter or spaces will divide parameters
lpParameters = ""
# Litteraly quote all parameters which get unquoted when passed to python
for i, item in enumerate(sys.argv[0:]):
lpParameters += '"' + item + '" '
try:
ctypes.windll.shell32.ShellExecuteW(None, "runas", sys.executable, lpParameters , None, 1)
except:
sys.exit(1)
else:
main(sys.argv[1:])
For one-liners, put the code to where you need UAC.
Request UAC, if failed, keep running:
import ctypes, sys
ctypes.windll.shell32.IsUserAnAdmin() or ctypes.windll.shell32.ShellExecuteW(
None, "runas", sys.executable, " ".join(sys.argv), None, 1) > 32 and exit()
Request UAC, if failed, exit:
import ctypes, sys
ctypes.windll.shell32.IsUserAnAdmin() or (ctypes.windll.shell32.ShellExecuteW(
None, "runas", sys.executable, " ".join(sys.argv), None, 1) > 32, exit())
Function style:
# Created by BaiJiFeiLong#gmail.com at 2022/6/24
import ctypes
import sys
def request_uac_or_skip():
ctypes.windll.shell32.IsUserAnAdmin() or ctypes.windll.shell32.ShellExecuteW(
None, "runas", sys.executable, " ".join(sys.argv), None, 1) > 32 and sys.exit()
def request_uac_or_exit():
ctypes.windll.shell32.IsUserAnAdmin() or (ctypes.windll.shell32.ShellExecuteW(
None, "runas", sys.executable, " ".join(sys.argv), None, 1) > 32, sys.exit())
If your script always requires an Administrator's privileges then:
runas /user:Administrator "python your_script.py"

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