I'm trying to export all of my maps that are in my subdirectories.
I have the code to export, but I cannot figure out where to add the loop that will make it do this for all subdirectories. As of right now, it is exporting the maps in the directory, but not the subfolders.
import arcpy, os
arcpy.env.workspace = ws = r"C:\Users\162708\Desktop\Burn_Zones"
for subdir, dirs, files in os.walk(ws):
for file in files:
mxd_list = arcpy.ListFiles("*.mxd")
for mxd in mxd_list:
current_mxd = arcpy.mapping.MapDocument(os.path.join(ws, mxd))
pdf_name = mxd[:-4] + ".pdf"
arcpy.mapping.ExportToPDF(current_mxd, pdf_name)
del mxd_list
What am I doing wrong that it isn't able to iterate through the subfolders?
Thank you!
Iterating through os.walk result you should give tuples containing (path, dirs, files) (the first in the tuple is the current path that contains files which is why I tend to name it that way). The current directory does not change automatically so you need to incorporate it into the path you're giving to arcpy.ListFiles like this:
arcpy.ListFiles(os.path.join(path, "*.mxd"))
You should also remove the loop for file in files. It seems like you're exporting the files per directory so why export the whole directory every time for each file?
Also you should change arcpy.mapping.MapDocument(os.path.join(ws, mxd)) to arcpy.mapping.MapDocument(os.path.join(path, mxd)) where path is again the first element from os.walk.
Related
I'm trying to make a script that iterates through folders in a directory and saves the very first one in the folder to a variable. I'm trying to do this because I have folders in a directory with hundreads of .exr files but I only need the first file in the folder to be saved to the directory. I can get it to print out all the files in each folder but thats a bit too much info than I need. Is there an easy way to do this using something like os.walk? This is what I'm working with so far
import os
def main():
dirName = r"F:\FOLDERNAME"
#Get the List of all files in the directory tree at given path
listOfFiles = getListOfFiles(dirName)
#Print the files
for elem in listOfFiles:
print(elem)
if __name__ =='__main__':
main()
Thanks yall!
If you already:
can get it to print out all the files in each folder
And you only want :
the very first one
Then all you need is something like:
first_file = list_of_files[0]
Looks like you're still learning the very basics of coding. I suggest looking up lessons/tutorials on lists, list indexing, and iterables.
If you use os.walk(), it returns a list of files in each directory. You can print the first one.
for root, dirs, files in os.walk(dirName):
if files:
print(os.path.join(root, files[0]))
The problem is to get all the file names in a list that are under a particular directory and in a particular condition.
We have a directory named "test_dir".
There, we have sub directory "sub_dir_1", "sub_dir_2", "sub_dir_3"
and inside of each sub dir, we have some files.
sub_dir_1 has files ['test.txt', 'test.wav']
sub_dir_2 has files ['test_2.txt', 'test.wav']
sub_dir_2 has files ['test_3.txt', 'test_3.tsv']
What I want to get at the end of the day is a list of of the "test.wav" that exist under the "directory" ['sub_dir_1/test.wav', 'sub_dir_2/test.wav']. As you can see the condition is to get every path of 'test.wav' under the mother directory.
mother_dir_name = "directory"
get_test_wav(mother_dir_name)
returns --> ['sub_dir_1/test.wav', 'sub_dir_2/test.wav']
EDITED
I have changed the direction of the problem.
We first have this list of file names
["sub_dir_1/test.wav","sub_dir_2/test.wav","abc.csv","abc.json","sub_dir_3/test.json"]
from this list I would like to get a list that does not contain any path that contains "test.wav" like below
["abc.csv","abc.json","sub_dir_3/test.json"]
You can use glob patterns for this. Using pathlib,
from pathlib import Path
mother_dir = Path("directory")
list(mother_dir.glob("sub_dir_*/*.wav"))
Notice that I was fairly specific about which subdirectories to check - anything starting with "sub_dir_". You can change that pattern as needed to fit your environment.
Use os.walk():
import os
def get_test_wav(folder):
found = []
for root, folders, files in os.walk(folder):
for file in files:
if file == "test.wav":
found.append(os.path.join(root, file))
return found
Or a list comprehension approach:
import os
def get_test_wav(folder):
found = [f"{arr[0]}\\test.wav" for arr in os.walk(folder) if "test.wav" in arr[2]]
return found
I think this might help you How can I search sub-folders using glob.glob module?
The main way to make a list of files in a folder (to make it callable later) is:
file_path = os.path.join(motherdirectopry, 'subdirectory')
list_files = glob.glob(file_path + "/*.wav")
just check that link to see how you can join all sub-directories in a folder.
This will also give you all the file in sub directories that only has .wav at the end:
os.chdir(motherdirectory)
glob.glob('**/*.wav', recursive=True)
I've tried to use os.path.abspath(file) as well as Path.absolute(file) to get the paths of .png files I'm working on that are on a separate drive from the project folder that the code is in. The result from the following script is "Project Folder for the code/filename.png", whereas obviously what I need is the path to the folder that the .png is in;
for root, dirs, files in os.walk(newpath):
for file in files:
if not file.startswith("."):
if file.endswith(".png"):
number, scansize, letter = file.split("-")
filepath = os.path.abspath(file)
# replace weird backslash effects
correctedpath = filepath.replace(os.sep, "/")
newentry = [number, file, correctedpath]
textures.append(newentry)
I've read other answers on here that seem to suggest that the project file for the code can't be in the same directory as the folder that is being worked on. But that isn't the case here. Can someone kindly point out what I'm not getting? I need the absolute path because the purpose of the program will be to write the paths for the files into text files.
You could use pathlib.Path.rglob here to recursively get all the pngs:
As a list comprehension:
from pathlib import Path
search_dir = "/path/to/search/dir"
# This creates a list of tuples with `number` and the resolved path
paths = [(p.name.split("-")[0], p.resolve()) for p in Path(search_dir).rglob("*.png")]
Alternatively, you can process them in a loop:
paths = []
for p in Path(search_dir).rglob("*.png"):
number, scansize, letter = p.name.split("-")
# more processing ...
paths.append([number, p.resolve()])
I just recently wrote something like what you're looking for.
This code relies on the assumption that your files are the end of the path.
it's not suitable to find a directory or something like this.
there's no need for a nested loop.
DIR = "your/full/path/to/direcetory/containing/desired/files"
def get_file_path(name, template):
"""
#:param template: file's template (txt,html...)
#return: The path to the given file.
#rtype: str
"""
substring = f'{name}.{template}'
for path in os.listdir(DIR):
full_path = os.path.join(DIR, path)
if full_path.endswith(substring):
return full_path
The result from
for root, dirs, files in os.walk(newpath):
is that files just contains the filenames without a directory path. Using just filenames means that python by default uses your project folder as directory for those filenames. In your case the files are in newpath. You can use os.path.join to add a directory path to the found filenames.
filepath = os.path.join(newpath, file)
In case you want to find the png files in subdirectories the easiest way is to use glob:
import glob
newpath = r'D:\Images'
file_paths = glob.glob(newpath + "/**/*.png", recursive=True)
for file_path in file_paths:
print(file_path)
Say I have a directory.
In this directory there are single files as well as folders.
Some of those folders could also have subfolders, etc.
What I am trying to do is find all of the files in this directory that start with "Incidences" and read each csv into a pandas data frame.
I am able to loop through all the files and get the names, but cannot read them into data frames.
I am getting the error that "___.csv" does not exist, as it might not be directly in the directory, but rather in a folder in another folder in that directory.
I have been trying the attached code.
inc_files2 = []
pop_files2 = []
for root, dirs, files in os.walk(directory):
for f in files:
if f.startswith('Incidence'):
inc_files2.append(f)
elif f.startswith('Population Count'):
pop_files2.append(f)
for file in inc_files2:
inc_frames2 = map(pd.read_csv, inc_files2)
for file in pop_files2:
pop_frames2 = map(pd.read_csv, pop_files2)
You are adding only file name to the lists, not their path. You can use something like this to add paths instead:
inc_files2.append(os.path.join(root, f))
You have to add the path from the root directory where you are
Append the entire pathname, not just the bare filename, to inc_files2.
You can use os.path.abspath(f) to read the full path of a file.
You can make use of this by making the following changes to your code.
for root, dirs, files in os.walk(directory):
for f in files:
f_abs = os.path.abspath(f)
if f.startswith('Incidence'):
inc_files2.append(f_abs)
elif f.startswith('Population Count'):
pop_files2.append(f_abs)
I'm trying to print the names of all the files from a folder directory. I have a folder called "a", and in that folder there are 3 NC files, lets call them "b","c","d", whose directory I want to print. How would I do this?
For example, given my path to the folder is
path=r"C:\\Users\\chz08006\\Documents\\Testing\\a"
I want to print the directories to all the files in the folder "a", so the result should print:
C:\\Users\\chz08006\\Documents\\Testing\\a\\b.nc
C:\\Users\\chz08006\\Documents\\Testing\\a\\c.nc
C:\\Users\\chz08006\\Documents\\Testing\\a\\d.nc
So far, I've tried
for a in path:
print(os.path.basename(path))
But that doesn't seem to be right.
I think you're looking for this:
import os
path = r"C:\\Users\\chz08006\\Documents\\Testing\\a"
for root, dirs, files in os.walk(path):
for file in files:
print("{root}\\{file}".format(root=root, file=file))
You can have a list of file names in a folder using listdir().
import os
path = "C:\\Users\\chz08006\\Documents\\Testing\\a"
l = os.listdir(path)
for a in l:
print(path + a)
You made a couple mistakes. You were using os.path.basename, that only returns the name of the file or folder represented at the end of a path after the last file separator.
Instead, use os.path.abspath to get the full path of any file.
The other mistake was one of using the wrong variable inside the loop (print(os.path.basename(path) instead of using the variable a)
Also, dont forget to use os.listdir to list the files inside the folder before looping.
import os
path = r"C:\Users\chz08006\Documents\Testing\a"
for file in os.listdir(path): #using a better name compared to a
print(os.path.abspath(file)) #you wrote path here, instead of a.
#variable names that do not have a meaning
#make these kinds of errors easier to make,
#and harder to spot