Interpolation with gaps in domain - python

I have experimental results for a scalar field over a plane.
The data points are taken over a 2D grid of (x, y) coordinates in the plane, but there is a ring of (x, y) points in the plane where no data is taken, in some sense because the field isn't defined there.
How can i perform an interpolation over the 2D grid that takes into account this large lack of data points, and doesn't try to interpolate inside the torus?
Preferably I'd like to use one of the interpolators in the Python Scipy package.
Thank you

Related

Bilinear interpolation from a (distorted) rectangular 2D grid to arbitrary points, in Python

The task at hand is seemingly simple:
I have a 2D grid of data. The data is available in 2D arrays for X and Y coordinates, as well as the input variable which I want to interpolate. This means I can plot the data using rectangular cells, which means it is possible to use bilinear interpolation. Unfortunately, the data is not precisely aligned with the coordinates, and also not precisely spaced. There were some numerics involved in creating the data, which means that all sampling locations are a little off the mark, and the cell spacing is smooth but not uniform.
I would like to interpolate from this input grid to a set of predefined sample coordinates (as opposed to simply refining the mesh).
In short, an example for my type of input is:
# a nice, regular grid
Xs, Ys = np.meshgrid(np.linspace(0, 1, num=3), np.linspace(0, 1, num=5))
# ...perturbed by some systematic and some random noise ...
X_in = Xs + np.random.normal(scale=0.03, size=(5, 3))
# ...and some systematic deviation
Y_in = (Ys + np.random.normal(scale=0.03, size=(5, 3)))* (1 + Xs**1.5)
# and some variable at each node to interpolate
Z_in = np.random.normal(scale=1, size=(5, 3))
So (X_in, Y_in) are arrays of shape (n, m) which define a mesh with quadrilateral cells, and Z_in another array of ther same shape which provides a value at each node in that mesh. I am looking for some Python library that performs bilinear interpolation of Z_in across those cells.
However, all methods I have found so far either ignore the rectangular structure (and triangulate the data, or fit some 2D spline through arbitrary point clouds), or require a perfectly rectangular and equally-spaced grid as input (which mine is not).
Examples of answers/methods that seem not to be appliccable:
This answer recommends using scipy.ndimage.map_coordinates -- but that effectively uses the indices of the 2D input data array as coordinates, which won't work for me.
scipy.interpolate.interp2d requires either a regular grid (node locations provided by 1D X and Y arrays), or an irregular one, which is flattened, which means that the algorithm cannot know which nodes form a cell. This means it either fits some spline through unstructured data, or triangulates it. And it only interpolates onto regular grids or individual points.
scipy.interpolate.RectBivariateSpline is recommended for interpolation from gridded data but only accepts input points which are perfectly aligned with the coordinate system.
There's also a Matplotlib toolkit for interpolation, which I had thought should be able to do this sort of thing, as it also does interpolated contour plots of rectangular meshes, but as it turns out, even though mpl_toolkits.basemap.interp accepts arbitrary quadrilateral meshes as target for interpolation, it cannot use them as inputs ...
Upon closer inspection, it turns out that even matplotlib.plt.contour() does not seem to perform bilinear interpolation when plotting the input data:
plt.contour(X_in, Y_in, Z_in, levels=np.linspace(Z_in.min(), Z_in.max(), 50))
plt.plot(X_in, Y_in, 'k-')
plt.plot(X_in.T, Y_in.T, 'k-')
As you can see, the contour lines within the cells are straight, but with bilinear interpolation, they should not be, and there should not be those empty quadrilateral areas in the mittle of some cells. I suspect that Matplotlib only finds the contour values on the cell edges and simply draws straight lines between them.
I have found two explanations of the maths of bilinear interpolation from grids which are not perfectly aligned, but I was hoping to come across a ready-made implementation somewhere because I'm sure that this kind of task is not so rare, and a numpy or scipy implementation (if it exists) is probably way faster than whatever I'd implement myself.

2D interpolate list of many points [duplicate]

So, I have three numpy arrays which store latitude, longitude, and some property value on a grid -- that is, I have LAT(y,x), LON(y,x), and, say temperature T(y,x), for some limits of x and y. The grid isn't necessarily regular -- in fact, it's tripolar.
I then want to interpolate these property (temperature) values onto a bunch of different lat/lon points (stored as lat1(t), lon1(t), for about 10,000 t...) which do not fall on the actual grid points. I've tried matplotlib.mlab.griddata, but that takes far too long (it's not really designed for what I'm doing, after all). I've also tried scipy.interpolate.interp2d, but I get a MemoryError (my grids are about 400x400).
Is there any sort of slick, preferably fast way of doing this? I can't help but think the answer is something obvious... Thanks!!
Try the combination of inverse-distance weighting and
scipy.spatial.KDTree
described in SO
inverse-distance-weighted-idw-interpolation-with-python.
Kd-trees
work nicely in 2d 3d ..., inverse-distance weighting is smooth and local,
and the k= number of nearest neighbours can be varied to tradeoff speed / accuracy.
There is a nice inverse distance example by Roger Veciana i Rovira along with some code using GDAL to write to geotiff if you're into that.
This is of coarse to a regular grid, but assuming you project the data first to a pixel grid with pyproj or something, all the while being careful what projection is used for your data.
A copy of his algorithm and example script:
from math import pow
from math import sqrt
import numpy as np
import matplotlib.pyplot as plt
def pointValue(x,y,power,smoothing,xv,yv,values):
nominator=0
denominator=0
for i in range(0,len(values)):
dist = sqrt((x-xv[i])*(x-xv[i])+(y-yv[i])*(y-yv[i])+smoothing*smoothing);
#If the point is really close to one of the data points, return the data point value to avoid singularities
if(dist<0.0000000001):
return values[i]
nominator=nominator+(values[i]/pow(dist,power))
denominator=denominator+(1/pow(dist,power))
#Return NODATA if the denominator is zero
if denominator > 0:
value = nominator/denominator
else:
value = -9999
return value
def invDist(xv,yv,values,xsize=100,ysize=100,power=2,smoothing=0):
valuesGrid = np.zeros((ysize,xsize))
for x in range(0,xsize):
for y in range(0,ysize):
valuesGrid[y][x] = pointValue(x,y,power,smoothing,xv,yv,values)
return valuesGrid
if __name__ == "__main__":
power=1
smoothing=20
#Creating some data, with each coodinate and the values stored in separated lists
xv = [10,60,40,70,10,50,20,70,30,60]
yv = [10,20,30,30,40,50,60,70,80,90]
values = [1,2,2,3,4,6,7,7,8,10]
#Creating the output grid (100x100, in the example)
ti = np.linspace(0, 100, 100)
XI, YI = np.meshgrid(ti, ti)
#Creating the interpolation function and populating the output matrix value
ZI = invDist(xv,yv,values,100,100,power,smoothing)
# Plotting the result
n = plt.normalize(0.0, 100.0)
plt.subplot(1, 1, 1)
plt.pcolor(XI, YI, ZI)
plt.scatter(xv, yv, 100, values)
plt.title('Inv dist interpolation - power: ' + str(power) + ' smoothing: ' + str(smoothing))
plt.xlim(0, 100)
plt.ylim(0, 100)
plt.colorbar()
plt.show()
There's a bunch of options here, which one is best will depend on your data...
However I don't know of an out-of-the-box solution for you
You say your input data is from tripolar data. There are three main cases for how this data could be structured.
Sampled from a 3d grid in tripolar space, projected back to 2d LAT, LON data.
Sampled from a 2d grid in tripolar space, projected into 2d LAT LON data.
Unstructured data in tripolar space projected into 2d LAT LON data
The easiest of these is 2. Instead of interpolating in LAT LON space, "just" transform your point back into the source space and interpolate there.
Another option that works for 1 and 2 is to search for the cells that maps from tripolar space to cover your sample point. (You can use a BSP or grid type structure to speed up this search) Pick one of the cells, and interpolate inside it.
Finally there's a heap of unstructured interpolation options .. but they tend to be slow.
A personal favourite of mine is to use a linear interpolation of the nearest N points, finding those N points can again be done with gridding or a BSP. Another good option is to Delauney triangulate the unstructured points and interpolate on the resulting triangular mesh.
Personally if my mesh was case 1, I'd use an unstructured strategy as I'd be worried about having to handle searching through cells with overlapping projections. Choosing the "right" cell would be difficult.
I suggest you taking a look at GRASS (an open source GIS package) interpolation features (http://grass.ibiblio.org/gdp/html_grass62/v.surf.bspline.html). It's not in python but you can reimplement it or interface with C code.
Am I right in thinking your data grids look something like this (red is the old data, blue is the new interpolated data)?
alt text http://www.geekops.co.uk/photos/0000-00-02%20%28Forum%20images%29/DataSeparation.png
This might be a slightly brute-force-ish approach, but what about rendering your existing data as a bitmap (opengl will do simple interpolation of colours for you with the right options configured and you could render the data as triangles which should be fairly fast). You could then sample pixels at the locations of the new points.
Alternatively, you could sort your first set of points spatially and then find the closest old points surrounding your new point and interpolate based on the distances to those points.
There is a FORTRAN library called BIVAR, which is very suitable for this problem. With a few modifications you can make it usable in python using f2py.
From the description:
BIVAR is a FORTRAN90 library which interpolates scattered bivariate data, by Hiroshi Akima.
BIVAR accepts a set of (X,Y) data points scattered in 2D, with associated Z data values, and is able to construct a smooth interpolation function Z(X,Y), which agrees with the given data, and can be evaluated at other points in the plane.

Fitting polynomial surface to a 3D dataframe representing family of curves

I have a 3-D dataframe representing family of curves: yi=f(xi) which are also depending on a third variable lets say zi (yi=g(xi,zi)) as shown in the graphic below:
Family Of Curves
The yi data are measurements and each curve is valid on its own.
Now I would like to find out a proper way to fit a plane or surface to this data in order to avoid 2-D bilinear data interpolation.
In general I am trying to do a similar approach as in the link below:
2D polynomial in Python
With the difference that my x and y data do not have the same dimensions.
What I am looking for is more a solution for this kind of problem:
2D data fitting Matlab

Python - Problems contour plotting offset grid of data

My data is regularly spaced, but not quite a grid - each row of points is slightly offset from the one below.
The data is in the form of 3 1D arrays, x, y, z, with each index corresponding to a point. It is smoothly varying data - approximately Gaussian.
The point density is quite high. What is the best way to plot this data?
I tried meshgrid, but it gives me some bad contours through regions that have no data points near the contour's value.
I have tried rbf interpolation according to this post:
Python : 2d contour plot from 3 lists : x, y and rho?
but this just gives me nonsense - all the contours are on one edge - does not reflect the data at all.
Any other ideas for what I can try. Maybe I should be using some sort of nearest neighbour interpolation? Here is a picture of about a 1/4 of my data points: http://imgur.com/a/b00R6
I'm surprised it is causing me such difficulty - it seems like it should be fairly easy to plot.
The easiest way to plot ungridded data is probably tricontour or tricontourf (a filled tricontour plot).
Having 1D arrays of the x, y and z coordinates x, y and z, you'd simply call
plt.tricontourf(x,y,z, n, ...)
to obtain n levels of contours.
The other quick method is to interpolate on a grid using matplotlib.mlab.griddata to obtain a regular grid from the irregular points.
Both methods are compared in an example on the matplotlib page:
Tricontour vs. griddata
Found the answer: needed to rescale my data.

What does the Mayavi contour3d docs mean when it refers to "the arrows"?

I understand how to plot contours for a grid of data in mayavi like this:
from mayavi import mlab
mlab.contour3d(my_data_grid)
However, I'm curious what this other signature for the function is:
mlab.contour3d(x, y, z, my_data_grid)
The docs say:
If 4 arrays, (x, y, z, scalars) are passed, the 3 first arrays give
the position of the arrows, and the last the scalar value.
What are "the arrows"? I haven't found any examples and when I try to call it with my dataset I get a segfault so haven't been able to test.
EDIT: Well now I understand the format that mlab expects x, y, and z in and I was able to get it to work. However, there were no arrows! I'm assuming this is an error in the documentation...
It is not so much an error in the documentation, but more of a seemingly awkward way to describe the function. From the same document, contour3d:
Plots iso-surfaces for a 3D volume of data supplied as arguments
and it is stated that (bolding mine):
The x, y and z arrays are then supposed to have been generated by numpy.mgrid, in other words, they are 3D arrays, with positions lying on a 3D orthogonal and regularly spaced grid with nearest neighbor in space matching nearest neighbor in the array. The function builds a scalar field assuming the points are regularly spaced.
The 'arrows' seem to be a somewhat awkward way of saying that x, y and z are `
3D arrays, with positions lying on a 3D orthogonal and regularly
spaced grid
with the function 'building a scalar field' as an iso-surface, effectively 'connecting the dots (positions)'.

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