Update Existent Matplotlib Subplot with a user input - python

I am currently trying to implement a 'zoom' functionality into my code. By this I mean I would like to have two subplots side by side, one of which contains the initial data and the other which contains a 'zoomed in' plot which is decided by user input.
Currently, I can create two subplots side by side, but after calling for the user input, instead of updating the second subplot, my script is creating an entirely new figure below and not updating the second subplot. It is important that the graph containing data is plotted first so the user can choose the value for the input accordingly.
def plot_func(data):
plot_this = data
plt.close('all')
fig = plt.figure()
#Subplot 1
ax1 = fig.add_subplot(1,2,1)
ax1.plot(plot_this)
plt.show()
zoom = input("Where would you like to zoom to: ")
zoom_in = plot_this[0:int(zoom)]
#Subplot 2
ax2 = fig.add_subplot(1,2,2)
ax2.plot(zoom_in)
plt.show()
The code above is a simplified version of what I am hoping to do. Display a subplot, and let the user enter an input based on that subplot. Then either edit a subplot that is already created or create a new one that is next to the first. Again it is crucial that the 'zoomed in' subplot is alongside the first opposed to below.

I think it is not very convenient for the user to type in numbers for zooming. The more standard way would be mouse interaction as already provided by the various matplotlib tools.
There is no standard tool for zooming in a different plot, but we can easily provide this functionality using matplotlib.widgets.RectangleSelector as shown in the code below.
We need to plot the same data in two subplots and connect the RectangleSelector to one of the subplots (ax). Every time a selection is made, the data coordinates of the selection in the first subplot are simply used as axis-limits on the second subplot, effectiveliy proving zoom-in (or magnification) functionality.
import matplotlib.pyplot as plt
import numpy as np
from matplotlib.widgets import RectangleSelector
def onselect(eclick, erelease):
#http://matplotlib.org/api/widgets_api.html
xlim = np.sort(np.array([erelease.xdata,eclick.xdata ]))
ylim = np.sort(np.array([erelease.ydata,eclick.ydata ]))
ax2.set_xlim(xlim)
ax2.set_ylim(ylim)
def toggle_selector(event):
# press escape to return to non-zoomed plot
if event.key in ['escape'] and toggle_selector.RS.active:
ax2.set_xlim(ax.get_xlim())
ax2.set_ylim(ax.get_ylim())
x = np.arange(100)/(100.)*7.*np.pi
y = np.sin(x)**2
fig = plt.figure()
ax = fig.add_subplot(121)
ax2 = fig.add_subplot(122)
#plot identical data in both axes
ax.plot(x,y, lw=2)
ax.plot([5,14,21],[.3,.6,.1], marker="s", color="red", ls="none")
ax2.plot(x,y, lw=2)
ax2.plot([5,14,21],[.3,.6,.1], marker="s", color="red", ls="none")
ax.set_title("Select region with your mouse.\nPress escape to deactivate zoom")
ax2.set_title("Zoomed Plot")
toggle_selector.RS = RectangleSelector(ax, onselect, drawtype='box', interactive=True)
fig.canvas.mpl_connect('key_press_event', toggle_selector)
plt.show()

%matplotlib inline
import mpld3
mpld3.enable_notebook()

Related

Returning matplotlib plot/figure from a function and saving it later

As the title states I want to return a plt or figure (still not sure what the difference between the two things are) using matplotlib. The main idea behind it is so I can save the plt/figure later.
import seaborn as sns
from matplotlib import pyplot as plt
def graph(df, id):
# size of the graph
xlims = (-180, 180)
ylims = (-180, 180)
# dictate the colors of the scatter plot based on the grouping of hot or cold
color_dict = {'COLD': 'blue',
'HOT': 'red'}
title_name = f"{id}"
ax = sns.scatterplot(data=df, hue='GRP', x='X_GRID', y='Y_GRID',
legend=False, palette=color_dict)
ax.set_title(title_name)
ax.set(xlim=xlims)
ax.set(ylim=ylims)
if show_grid:
# pass in the prev graph so I can overlay grid
ax = self.__get_grid( ax)
circle1 = plt.Circle(xy=(0, 0), radius=150, color='black', fill=False, zorder=3)
ax.add_patch(circle1)
ax.set_aspect('equal')
plt.axis('off')
plt.savefig(title_name + '_in_ftn.png')
fig = plt.figure()
plt.clf()
return (fig, title_name + '.png')
plots = []
# dfs is just a tuple of df, id for example purposes
for df, id in dfs:
plots.append(graph(df, id))
for plot, file_name in plots:
plot.savefig(file_name)
plot.clf()
When using plot.savefig(filename) it saves, but the saved file is blank which is wrong. Am I not properly returning the object I want to save? If not what should I return to be able to save it?
I kind of having it work, but not really. I am currently saving two figures for testing purposes. For some reason when I use the fig=plt.figure() and saving it outside the function the title of the figure and the filename are different (even though they should be the same since the only difference is .png)
However, when saving it inside the function the title name of the figure and the filename name are the same.
You code has multiple issues that I'll try to discuss here:
Your confusion around plt
First of all, there is no such thing as "a plt". plt is the custom name you are giving to the matplotlib.pyplot module when you are importing it with the line import matplotlib.pyplot as plt. You are basically just renaming the module with an easy to type abbreviation. If you had just written import matplotlib, you would have to write matplotlib.pyplot.axis('off') instead of plt.axis('off').
Mix of procedural and object oriented approach
You are using a mix of the procedural and object oriented approach for matplotlib.
Either you call your methods on the axis object (ax) or you can call functions that implicitly handle the axis and figure. For example you could either create and axis and then call ax.plot(...) or instead use plt.plot(...), which implicitly creates the figure and axis. In your case, you mainly use the object oriented approach on the axis object that is returned by the seaborn function. However, you should use ax.axis('off') instead of plt.axis('off').
You create a new blank figure
When you are calling the seaborn function sns.scatterplot, you are implicitly creating a matplotlib figure and axis object. You catch that axis object in the variable ax. You then use plt.savefig to save your image in the function, which works by implicitly getting the figure corresponding to the currently used axis object. However, you are then creating a new figure by calling fig = plt.figure(), which is of course blank, and then returning it. What you should do, is getting the figure currently used by the axis object you are working with. You can get it by calling fig = plt.gcf() (which stands for "get current figure") and would be the procedural approach, or better use fig = ax.get_figure()
What you should do instead is something like this:
import seaborn as sns
from matplotlib import pyplot as plt
def graph(df, id):
# size of the graph
xlims = (-180, 180)
ylims = (-180, 180)
# dictate the colors of the scatter plot based on the grouping of hot or cold
color_dict = {'COLD': 'blue',
'HOT': 'red'}
title_name = f"{id}"
ax = sns.scatterplot(data=df, hue='GRP', x='X_GRID', y='Y_GRID',
legend=False, palette=color_dict)
ax.set_title(title_name)
ax.set(xlim=xlims)
ax.set(ylim=ylims)
if show_grid:
# pass in the prev graph so I can overlay grid
ax = self.__get_grid( ax)
circle1 = plt.Circle(xy=(0, 0), radius=150, color='black', fill=False, zorder=3)
ax.add_patch(circle1)
ax.set_aspect('equal')
ax.axis('off')
fig = ax.get_figure()
fig.savefig(title_name + '_in_ftn.png')
return (fig, title_name + '.png')

plot graph in a specific figure in python

Actually, I am not clear that
fig_1 = plt.figure()
plt.subplot(2,2,1)
...
Is the ploting like plt.subplot(2,2,1) and other plt. plot on the fig_1 or system will automatically create a new empty figure?
Then how to plot something in a specific figure, for example:
fig_1 = plt.figure()
fig_2 = plt.figure()
plt.subplot(2,2,1)
I want to subplot on fig_2.
You can access a certain figure by e.g.
ax_1_1 = fig_1.add_subplot(2,2,1)
but this has a slightly different syntax (compare plt.subplot() against fig.add_subplot())
So I would recommend to create figures with subplots already prepared vis plt.subplots which returns handles for figure and axes on the fly:
fig_1, axs_1 = plt.subplots(2, 2)
fig_2, axs_2 = plt.subplots(3, 4)
axs_1[0, 0].plot(range(10))
axs_2[2, 3].plot(range(100))
fig_1.suptitle('Figure 1')
fig_2.suptitle('Figure 2')
etc. ...
You can use figure.add_subplot which will return an ax linked to your figure on which you can plot your data. Look at this page to get a global view of the different objects used by matplotlib.

Preserve content of fig after show() in matplotlib?

I'm creating a violinplot of some data and afterwards I render a scatterplot with individual data points (red points in example) to three subplots.
Since the generation of the violinplot is relatively time consuming, I'm generating the violinplot only once, then add the scatterplot for one data row, write the result file, remove the scatterplots from the axes and add the scatterplots for the next row.
Everything works, but I would like to add the option, to show() each plot prior to saving it.
If I'm using plt.show(), the figure is shown correctly, but afterwards the figure seems to be cleared and in the next iteration I'm getting the plot without the violin plots.
Is there any way to preserve the content of the figure after plt.show()?
In short, my code is
fig = generate_plot(ws, show=False) #returns the fig instance of the violin plot
#if I do plt.show() here (or in "generate_plot()"), the violin plots are gone.
ax1, ax3, ax2 = fig.get_axes()
scatter1 = ax1.scatter(...) #draw scatter plot for first axes
[...] #same vor every axis
plt.savefig(...)
scatter1.remove()
I was thinking that a possible option is to use the event loop to advance through the plots. The following would define an updating function, which changes only the scatter points, draws the image and saves it. We can manage this via a class with a callback on the key_press - such then when you hit Space the next image is shown; upon pressing Space on the last image, the plot is closed.
import matplotlib
matplotlib.use("TkAgg")
import matplotlib.pyplot as plt
import numpy as np
class NextPlotter(object):
def __init__(self, fig, func, n):
self.__dict__.update(locals())
self.i = 0
self.cid = self.fig.canvas.mpl_connect("key_press_event", self.adv)
def adv(self, evt):
if evt.key == " " and self.i < self.n:
self.func(self.i)
self.i+=1
elif self.i >= self.n:
plt.close("all")
#Start of code:
# Create data
pos = [1, 2, 4, 5, 7, 8]
data = [np.random.normal(0, std, size=100) for std in pos]
data2 = [np.random.rayleigh(std, size=100) for std in pos]
scatterdata = np.random.normal(0, 5, size=(10,len(pos)))
#Create plot
fig, axes = plt.subplots(ncols=2)
axes[0].violinplot(data, pos, points=40, widths=0.9,
showmeans=True, showextrema=True, showmedians=True)
axes[1].violinplot(data2, pos, points=40, widths=0.9,
showmeans=True, showextrema=True, showmedians=True)
scatter = axes[0].scatter(pos, scatterdata[0,:], c="crimson", s=60)
scatter2 = axes[1].scatter(pos, scatterdata[1,:], c="crimson", s=60)
# define updating function
def update(i):
scatter.set_offsets(np.c_[pos,scatterdata[2*i,:]])
scatter2.set_offsets(np.c_[pos,scatterdata[2*i+1,:]])
fig.canvas.draw()
plt.savefig("plot{i}.png".format(i=i))
# instantiate NextPlotter; press <space> to advance to the next image
c = NextPlotter(fig, update, len(scatterdata)//2)
plt.show()
A workaround could be to not remove the scatterplot.
Why not keep the scatter plot axis, and just update the data for that set of axis?
You will most likely need a plt.draw() after update of scatter plot data to force a new rendering.
I found a way to draw figures interactively here. plt.ion() and block the process with input() seems to be important.
import matplotlib.pyplot as plt
plt.ion()
fig = plt.figure()
ax = plt.subplot(1,1,1)
ax.set_xlim([-1, 5])
ax.set_ylim([-1, 5])
ax.grid('on')
for i in range(5):
lineObject = ax.plot(i,i,'ro')
fig.savefig('%02d.png'%i)
# plt.draw() # not necessary?
input()
lineObject[0].remove()
I also tried to block the process with time.sleep(1), but it does not work at all.

matplotlib: how to get handles of existing twinx() axes?

I want to create a figure with two y-axes and add multiple curves to each of those axes at different points in my code (from different functions).
In a first function, I create a figure:
import matplotlib.pyplot as plt
from numpy import *
# Opens new figure with two axes
def function1():
f = plt.figure(1)
ax1 = plt.subplot(211)
ax2 = ax1.twinx()
x = linspace(0,2*pi,100)
ax1.plot(x,sin(x),'b')
ax2.plot(x,1000*cos(x),'g')
# other stuff will be shown in subplot 212...
Now, in a second function I want to add a curve to each of the already created axes:
def function2():
# Get handles of figure, which is already open
f = plt.figure(1)
ax3 = plt.subplot(211).axes # get handle to 1st axis
ax4 = ax3.twinx() # get handle to 2nd axis (wrong?)
# Add new curves
x = linspace(0,2*pi,100)
ax3.plot(x,sin(2*x),'m')
ax4.plot(x,1000*cos(2*x),'r')
Now my problem is that the green curve added in the first code block is not anymore visible after the second block is executed (all others are).
I think the reason for this is the line
ax4 = ax3.twinx()
in my second code block. It probably creates a new twinx() instead of returning a handle to the existing one.
How would I correctly get the handles to already existing twinx-axes in a plot?
you can use get_shared_x_axes (get_shared_y_axes) to get a handle to the axes created by twinx (twiny):
# creat some axes
f,a = plt.subplots()
# create axes that share their x-axes
atwin = a.twinx()
# in case you don't have access to atwin anymore you can get a handle to it with
atwin_alt = a.get_shared_x_axes().get_siblings(a)[0]
atwin == atwin_alt # should be True
I would guess that the cleanest way would be to create the axes outside the functions. Then you can supply whatever axes you like to the function.
import matplotlib.pyplot as plt
import numpy as np
def function1(ax1, ax2):
x = np.linspace(0,2*np.pi,100)
ax1.plot(x,np.sin(x),'b')
ax2.plot(x,1000*np.cos(x),'g')
def function2(ax1, ax2):
x = np.linspace(0,2*np.pi,100)
ax1.plot(x,np.sin(2*x),'m')
ax2.plot(x,1000*np.cos(2*x),'r')
fig, (ax, bx) = plt.subplots(nrows=2)
axtwin = ax.twinx()
function1(ax, axtwin)
function2(ax, axtwin)
plt.show()

Multiple pie charts using matplotlib

I'm trying to display two charts at the same time using matplotlib.
But I have to close one graph then only I can see the other graph.
Is there anyway to display both the graphs or more number of graphs at the same time.
Here is my code
num_pass=np.size(data[0::,1].astype(np.float))
num_survive=np.sum(data[0::,1].astype(np.float))
prop=num_survive/num_pass
num_dead=num_pass-num_survive
#print num_dead
labels='Dead','Survived'
sizes=[num_dead,num_survive]
colors=['darkorange','green']
mp.axis('equal')
mp.title('Titanic Survival Chart')
mp.pie(sizes, explode=(0.02,0), labels=labels,colors=colors,autopct='%1.1f%%', shadow=True, startangle=90)
mp.show()
women_only_stats = data[0::,4] == "female"
men_only_stats = data[0::,4] != "female"
# Using the index from above we select the females and males separately
women_onboard = data[women_only_stats,1].astype(np.float)
men_onboard = data[men_only_stats,1].astype(np.float)
labels='Men','Women'
sizes=[np.sum(women_onboard),np.sum(men_onboard)]
colors=['purple','red']
mp.axis('equal')
mp.title('People on board')
mp.pie(sizes, explode=(0.01,0), labels=labels,colors=colors,autopct='%1.1f%%', shadow=True, startangle=90)
mp.show()
How can I show both the graphs at the same time?
There are several ways to do this, and the simplest is to use multiple figure numbers. Simply tell matplotlib that you are working on separate figures, and then show them simultaneously:
import matplotlib.pyplot as plt
plt.figure(0)
# Create first chart here.
plt.figure(1)
# Create second chart here.
plt.show() #show all figures
In addition to Banana's answer, you could also plot them in different subplots within the same figure:
from matplotlib import pyplot as plt
import numpy as np
data1 = np.array([0.9, 0.1])
data2 = np.array([0.6, 0.4])
# create a figure with two subplots
fig, (ax1, ax2) = plt.subplots(1, 2)
# plot each pie chart in a separate subplot
ax1.pie(data1)
ax2.pie(data2)
plt.show()
Alternatively, you can put multiple pies on the same figure using subplots/multiple axes:
mp.subplot(211)
mp.pie(..)
mp.subplot(212)
mp.pie(...)
mp.show()
Yes. This answer of User:Banana worked for me.
I had 4 graphs and all 4 popped up as individual pie charts when I ran the plt.show() so I believe you can use as many figure numbers as you want.
plt.figure(0) # Create first chart here and specify all parameters below.
plt.figure(1) # Create second chart here and specify all parameters below.
plt.figure(3) # Create third chart here and specify all parameters below.
plt.figure(4) # Create fourth chart here and specify all parameters below.
plt.show() # show all figures.

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