I m using mac and have added rsa key on desktop
The path I 'm using is
host_key = paramiko.RSAKey(filename='~/Desktop/test_rsa.key')
Error:
Traceback (most recent call last):
File "/Users/vidit/PycharmProjects/untitled6/server.py", line 7, in <module>
host_key = paramiko.RSAKey(filename='~/Desktop/test_rsa.key')
File "/Library/Python/2.7/site-packages/paramiko/rsakey.py", line 45, in __init__
self._from_private_key_file(filename, password)
File "/Library/Python/2.7/site-packages/paramiko/rsakey.py", line 163, in _from_private_key_file
data = self._read_private_key_file('RSA', filename, password)
File "/Library/Python/2.7/site-packages/paramiko/pkey.py", line 267, in _read_private_key_file
with open(filename, 'r') as f:
IOError: [Errno 2] No such file or directory: '~/Desktop/test_rsa.key'
You can not use ~ in the path of a file directly. It is a shell feature and expanded by the shell.
Use os.path.expanduser(path) to expand the ~ in the file path before using it.
You can't use ~ in Python paths. Try hardcoding your home directory and it will work.
You can use expanduser() if you want to use tilde (~)
from os.path import expanduser
keypath = expanduser("~/Desktop/test_rsa.key")
Related
I am executing the following line:
id2word = gensim.corpora.Dictionary.load_from_text('wiki_en_wordids.txt')
This code is available at "https://radimrehurek.com/gensim/wiki.html". I downloaded the wikipedia corpus and generated the required files and wiki_en_wordids.txt is one of those files. This file is available in the following location:
~/gensim/results/wiki_en
So when i execute the code mentioned above I get the following error:
Traceback (most recent call last):
File "~\Python\Python36-32\temp.py", line 5, in <module>
id2word = gensim.corpora.Dictionary.load_from_text('wiki_en_wordids.txt')
File "~\Python\Python36-32\lib\site-packages\gensim\corpora\dictionary.py", line 344, in load_from_text
with utils.smart_open(fname) as f:
File "~\Python\Python36-32\lib\site-packages\smart_open\smart_open_lib.py", line 129, in smart_open
return file_smart_open(parsed_uri.uri_path, mode)
File "~\Python\Python36-32\lib\site-packages\smart_open\smart_open_lib.py", line 613, in file_smart_open
return open(fname, mode)
FileNotFoundError: [Errno 2] No such file or directory: 'wiki_en_wordids.txt'
Even though the file is available in the required location I get that error. Should I place the file in any other location? How do I determine what the right location is?
The code requires an absolute path here. Relative path should be used when entire operation is carried out in the same directory location, but in this case, the file name is passed as argument to some other function which is located at different location.
One way to handle this situation is using abspath -
import os
id2word = gensim.corpora.Dictionary.load_from_text(os.path.abspath('wiki_en_wordids.txt'))
I am using Pandas on Mac, to read and write a CSV file, and the weird thing is when using full path, it has error and when using just a file name, it works. I post my code which works and which not works in my comments below, and also detailed error messages. Anyone have any good ideas?
sourceDf = pd.read_csv(path_to_csv)
sourceDf['nameFull'] = sourceDf['nameFirst'] + ' ' + sourceDf['nameLast']
sourceDf.to_csv('newMaster.csv') # working
sourceDf.to_csv('~/Downloads/newMaster.csv') # not working
Traceback (most recent call last):
File "/Users/foo/PycharmProjects/DataWranglingTest/CSVTest1.py", line 36, in <module>
add_full_name(path_to_csv, path_to_new_csv)
File "/Users/foo/PycharmProjects/DataWranglingTest/CSVTest1.py", line 28, in add_full_name
sourceDf.to_csv('~/Downloads/newMaster.csv')
File "/usr/local/Cellar/python/2.7.8/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/pandas/core/frame.py", line 1189, in to_csv
formatter.save()
File "/usr/local/Cellar/python/2.7.8/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/pandas/core/format.py", line 1442, in save
encoding=self.encoding)
File "/usr/local/Cellar/python/2.7.8/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/pandas/core/common.py", line 2831, in _get_handle
f = open(path, mode)
IOError: [Errno 2] No such file or directory: '~/Downloads/newMaster.csv'
Tried to use prefix r, but not working,
path_to_csv = r'~/Downloads/Master.csv'
path_to_new_csv = r'~/Downloads/Master_new.csv'
File "/usr/local/Cellar/python/2.7.8/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/pandas/core/frame.py", line 1189, in to_csv
formatter.save()
File "/usr/local/Cellar/python/2.7.8/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/pandas/core/format.py", line 1442, in save
encoding=self.encoding)
File "/usr/local/Cellar/python/2.7.8/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/pandas/core/common.py", line 2831, in _get_handle
f = open(path, mode)
IOError: [Errno 2] No such file or directory: '~/Downloads/Master_new.csv'
thanks in advance,
Lin
Try using os.path.join().
import os
(...)
output_filename = 'newMaster.csv'
output_path = os.path.join('Downloads', output_filename)
(...)
sourceDf.to_csv(output_path)
Use the same methodology to point pandas.read_csv() in the right direction.
You didn't specify python version.
On 3.4 you can use pathlib, otherwise use os.path.join() or quoting:
sourceDf.to_csv(r'~/Downloads/newMaster.csv')
Notice the r.
The problem is that /n is newline, which is not allowed in a path.
I've been working on retrieving a file from my ftp server, the intention is to get the file, untar it on the local machine and compare the MD5 sum to the locally install package. My main focus is getting this file from the ftp server.
After running the script I get the following:
Traceback (most recent call last):
File "./tgzTest.py", line 27, in <module>
proof = tarfile.is_tarfile("test.tgz")
File "/usr/pkg/lib/python2.7/tarfile.py", line 2585, in
is_tarfile t = open(name)
File "/usr/pkg/lib/python2.7/tarfile.py", line 1660, in
open return func(name, "r", fileobj, **kwargs)
File "/usr/pkg/lib/python2.7/tarfile.py", line 1722, in
gzopen fileobj = bltn_open(name, mode + "b")
IOError: [Errno 2] No such file or directory: 'test.tgz'
The following is the code I'm currently using, thanks for any suggestions!
#!/usr/bin/python
import tarfile
import os
import ftplib
from ftplib import FTP
import hashlib
ftpServer = 'myserver.com'
password = 'null'
os.chdir("/home/user/testFolder")
ftp = FTP(ftpServer)
ftp.login('Anonymous', password)
print "You're in"
fileDir = "/pub/pkgsrc/base_pkgs"
tfile = "test.tgz"
ftp.cwd(fileDir)
print ftp.pwd()
tar = tarfile.open("test.tgz", 'r|gz')
for file in tar.getmembers():
print file.name
tar.close()
The tarfile package expects files in the local file system, not on the FTP server. You have to download the file first using the retrbinary() method of the ftp object, and pass the path to the downloaded file to tarfile.open().
I'm new to Python and I writing a script that uses the pysftp module. There is one function in the pysftp module that I'm having trouble with -- it's the rename function.
Here is the call
srv = pysftp.Connection(host = 'xxx.com', username = 'xxx', password = 'xxx')
y = srv.rename('ftptest.txt', 'renamedfile.txt')
The error I'm getting is
Traceback (most recent call last):
File "./ftp.py", line 49, in <module>
y = srv.rename('ftptest.txt', 'renamedfile.txt')
File "/usr/local/lib/python2.7/dist-packages/pysftp.py", line 740, in rename
self._sftp.rename(remote_src, remote_dest)
File "/usr/local/lib/python2.7/dist-packages/paramiko/sftp_client.py", line 365, in rename
self._request(CMD_RENAME, oldpath, newpath)
File "/usr/local/lib/python2.7/dist-packages/paramiko/sftp_client.py", line 729, in _request
return self._read_response(num)
File "/usr/local/lib/python2.7/dist-packages/paramiko/sftp_client.py", line 776, in _read_response
self._convert_status(msg)
File "/usr/local/lib/python2.7/dist-packages/paramiko/sftp_client.py", line 804, in _convert_status
raise IOError(errno.EACCES, text)
IOError: [Errno 13] Permission denied
I have verified that the file exists and it has the 777 for permissions.
With SFTP protocol (which lacks concept of a current working directory), using an absolute paths is recommended. With a relative path, the result is server implementation specific. So you cannot be sure what files you are actually trying to rename.
On *nix systems, to rename a file, you need write permissions to a containing folder. The permissions to the file you are renaming do not matter.
I am trying to execute the following code
from pytesser import *
import Image
i="C:/Documents and Settings/Administrator/Desktop/attachments/R1PNDTCB.jpg"
print i
im = Image.open(i.strip())
text = image_to_string(im)
print text
I get the following error
C:/Documents and Settings/Administrator/Desktop/attachments/R1PNDTCB.jpg
Traceback (most recent call last):
File "C:\Python27\Lib\site-packages\Pythonwin\pywin\framework\scriptutils.py", line 322, in RunScript
debugger.run(codeObject, __main__.__dict__, start_stepping=0)
File "C:\Python27\Lib\site-packages\Pythonwin\pywin\debugger\__init__.py", line 60, in run
_GetCurrentDebugger().run(cmd, globals,locals, start_stepping)
File "C:\Python27\Lib\site-packages\Pythonwin\pywin\debugger\debugger.py", line 655, in run
exec cmd in globals, locals
File "C:\Documents and Settings\Administrator\Desktop\attachments\ocr.py", line 1, in <module>
from pytesser import *
File "C:\Python27\lib\site-packages\PIL\Image.py", line 1952, in open
fp = __builtin__.open(fp, "rb")
IOError: [Errno 2] No such file or directory: 'C:/Documents and Settings/Administrator/Desktop/attachments/R1PNDTCB.jpg'
Can someone please explain what I am doing wrong here.
Renamed the image file.Shifted the python file and the images to a new folder. Shifted the folder to E drive
Now the code is as follows:
from pytesser import *
import Image
import os
i=os.path.join("E:\\","ocr","a.jpg")
print i
im = Image.open(i.strip())
text = image_to_string(im)
print text
Now the error is as follows:
E:\ocr\a.jpg
Traceback (most recent call last):
File "or.py", line 8, in <module>
text = image_to_string(im)
File "C:\Python27\lib\pytesser.py", line 31, in image_to_string
call_tesseract(scratch_image_name, scratch_text_name_root)
File "C:\Python27\lib\pytesser.py", line 21, in call_tesseract
proc = subprocess.Popen(args)
File "C:\Python27\lib\subprocess.py", line 679, in __init__
errread, errwrite)
File "C:\Python27\lib\subprocess.py", line 893, in _execute_child
startupinfo)
WindowsError: [Error 2] The system cannot find the file specified
You need to install Tesseract first. Just installing pytesseract is not enough. Then edit the tesseract_cmd variable in pytesseract.py to point the the tessseract binary. For example, in my installation I set it to
tesseract_cmd = 'C:\\Program Files (x86)\\Tesseract-OCR\\tesseract.exe'
The exception is pretty clear: the file either doesn't exist, or you lack sufficient permissions to access it. If neither is the case, please provide evidence (e.g. relevant dir commands with output, run as the same user).
your image path maybe?
i="C:\\Documents and Settings\\Administrator\\Desktop\\attachments\\R1PNDTCB.jpg"
try this:
import os
os.path.join("C:\\", "Documents and Settings", "Administrator")
you should get a string similar to the one in the previous line
Try this first:
os.path.expanduser('~/Desktop/attachments/R1PNDTCB.jpg')
It could be that the space in the 'Documents and Settings' is causing this problem.
EDIT:
Use os.path.join so it uses the correct directory separator.
Just add these two lines in your code
import OS
os.chdir('C:\Python27\Lib\site-packages\pytesser')
before
from pytesser import *
If you are using pytesseract, you have to make sure that you have installed Tesseract-OCR in your system. After that you have to insert the path of the tesseract in your code, as below
from PIL import Image
import pytesseract
pytesseract.pytesseract.tesseract_cmd = 'C:/Program Files (x86)/Tesseract
OCR/tesseract'
You can download the Tesseract-OCR form https://github.com/UB-Mannheim/tesseract/wiki