so I'm trying to get through this tutorial here .
I started by running the code in a file here:
import socket
HOST, PORT = '', 8888
listen_socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
listen_socket.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
listen_socket.bind((HOST, PORT))
listen_socket.listen(1)
print('Serving HTTP on port %s ...' % PORT)
while True:
client_connection, client_address = listen_socket.accept()
request = client_connection.recv(1024)
print(request.decode('utf-8'))
http_response = """\
HTTP/1.1 200 OK
Hello, World!
"""
client_connection.sendall(bytes(http_response, 'utf-8'))
client_connection.close()
then in the next part, it tells me to enter this line on the same computer.
$ telnet localhost 8888
I have webserver1.py running on a different cmd window (in windows). when I run this line though I get a blank screen instead of
$ telnet localhost 8888
Trying 127.0.0.1 …
Connected to localhost.
like I'm supposed to. Does anyone know why? How to fix it? I tried googling telnet localhost 8888 to no avail, I couldn't find a situation where this happened before.
so uh... unless there's an http daemon running/listening on that port, which couldn't happen anyway because of how ports typically work (but not always), that's actually about as far as that exercise will go.
The result you had was correct, based on the output you got after running telnet from another cmd session while that python script was running in the background. However, the windows oobe version of telnet is weaksauce. Using it to send additional commands to communicate with the server once a successful connection is established is kinda booty.
The script invokes the python interpreter (shoulda used #!/usr/bin/env python... just saying) and uses a few objects from the socket lib to open a socket on port 8888 on the localhost (the computer you're currently logged into).
That's it, nothing more. I ran through the exercise too, and gisted it # https://gist.github.com/mackmoe/09de098b3df5c45adf7a17b764a1eec4
Just my 2 cents here:
If you want to setup a server for the experience (and for free), just grab virtualbox, a linux server iso and use one of digital ocean's walkthroughs. Like the one # https://www.digitalocean.com/community/tutorials/how-to-install-linux-apache-mysql-php-lamp-stack-on-ubuntu-16-04
Hope That Helps Friend!
Related
I have this program which is for now supposed to only listen on port 80 and receive data either from browser connections or from another python scripts.
this code:
import socket # Import socket module
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
host = socket.gethostname() # Get local machine name
port = 80 # Reserve a port for your service.
s.bind(("192.168.252.7", port)) # Bind to the port
s.listen(5) # Now wait for client connection.
while True:
c, addr = s.accept() # Establish connection with client.
print 'Got connection from', addr
print c.recv(1024)
c.close() # Close the connection
which is all copied from tutorialspoint. This code receives data, when the port is set to anything but 80 (eg 8080, 12345), but when it is 80, it only accepts the client but seems to not receive any data despite the data being successfully sent from somewhere else....
PLEASE HELP GUYS
Port 80 and all ports <1024 are privileged ports, your program must run as root in order to properly bind to these ports. I'm guessing you are running on Windows, since on any unix calling s.bind(("127.0.0.1", 80)) results in PermissionError: [Errno 13] Permission denied exception immediately.
I'm not sure how Windows deals with priveleged ports, but quick google search points towards windows firewall messing with your program.
Proper web servers, such as Nginx or Apache, start as root, bind to the port 80 and immediately drop to a less privileged user, since running under root is dangerous.
P.S.: A couple of suggestions:
You can skip the socket.gethostname(). Use ip 127.0.0.1 if you want your program to be accessible only from your machine, or use ip 0.0.0.0 if you want to be accessible from any machine on your network.
You should try to switch to Python 3 ASAP, since Python 2 is basically dead at this point. Don't get used to two's syntax, you gonna relearn it in a couple of years tops.
I am using server(server_name.corp.com) inside a corporate company. On the server i am running a flask server to listen on 0.0.0.0:5000.
servers are not exposed to outside world but accessible via vpns.
Now when i run host server_name.corp.com in the box i get some ip1(10.*.*.*)
When i run ifconfig in the box it gives me ip2(10.*.*.*).
Also if i run ping server_name.corp.com in same box i get ip2.
Also i can ssh into server with ip1 not ip2
I am able to access the flask server at ip1:5000 but not on ip2:5000.
I am not into networking so fully confused on why there are 2 different ips and why i can access ip1:5000 from browser not ip2:5000.
Also what is equivalent of host command in python ( how to get ip1 from python. I am using socktet.gethostbyname(server_name.corp.com) which gives me ip2)
As far as I can tell, you have some kind of routing configured that allows external connections to the server by hostname (or ip1), but it does not allow connection by ip2. And there is nothing unusual in this. Probably, the system administrator can advise why it is done just like this. Assuming that there are no assynchronous network routes, the following function can help to determine public ip of server:
import socket
def get_ip():
try:
sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
sock.connect(("8.8.8.8", 80))
local_address = sock.getsockname()
sock.close()
local_address = local_address[0]
except OSError:
local_address = socket.gethostbyname(socket.gethostname())
return local_address
Not quite clear about the network status by your statements, I can only tell that if you want to get ip1 by python, you could use standard lib subprocess, which usually be used to execute os command. (See subprocess.Popen)
So you have a basic understanding of the parts im using, I have:
Arduino Uno
Seeed Studio GPRS Shield v2.0 (http://www.seeedstudio.com/wiki/GPRS_Shield_V2.0)
Ultimate GPS for Adafruit V3.3 (https://www.adafruit.com/products/746?gclid=Cj0KEQjw3-W5BRCymr_7r7SFt8cBEiQAsLtM8qn4SCfVWIvAwW-x9Mu-FLeB6hLmVd0PAPVU8IAXXPgaAtaC8P8HAQ)
Here is my problem:
I have tested the Arduino stacked with the GPRS shield, and it works fine with regards to accessing the internet through TCP, sending SMS, etc.. However, my application requires me to send GPS data from the adafruit GPS to a web server that I have already coded with Django and postgresql. The backend is set up.
I need to send the data from the Uno (client) to my laptop (server), which I coded in python (This is just to check whether it is creating a connection):
#!/usr/bin/env python
import socket
# import postgres database functions
TCP_IP = '192.168.1.112'
TCP_PORT = 10000
BUFFER_SIZE = 40
server_address = (TCP_IP,TCP_PORT)
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
print 'Socket created.'
# Bind socket to TCP server and port
try:
s.bind(server_address)
except socket.error as msg:
print 'Bind failed. Error Code : ' + str(msg[0]) + ' Message ' + msg[1]
sys.exit()
print 'Socket Bind Complete.'
# Start Listening on socket
s.listen(1) # Puts socket into server mode
print 'Listening on port: ', TCP_PORT
# Now Keep Talking with the client
while (1):
# Wait to accept a connection
conn, addr = s.accept() # Wait for incoming connection with accept()
print 'Connection address:', addr
data = conn.recv(BUFFER_SIZE)
if not data: break
print "recieved data: data", data
conn.send(data) #echo
conn.close()
I dont think there is a problem with this. From this I will post data to my postgreSQL database. However, When I try to use AT commands on the SIM900 module to connect to the server using port 10000, I cannot connect:
AT+CIPSHUT
SHUT OK
AT+CGATT?
+CGATT: 1
OK
AT+CIPMUX=0
OK
AT+CSTT="fast.t-mobile.com","",""
OK
AT+CIICR
OK
AT+CIFSR
6.60.94.49
AT+CIPSTART="TCP","192.168.1.112,"10000"
OK
STATE: TCP CLOSED
CONNECT FAIL
I have tried connecting through TCP and replaced the AT+CIPSTART line with the below statement and it worked, so I know TCP works:
AT+CIPSTART="TCP","www.vishnusharma.com", "80"
Is the IP i'm using wrong? I'm new to this, but if it makes a difference, im using Ubuntu 16.04 partitioned on my Mac OSX. I have also checked the APN for T-mobile and it seems fine.
Any help would be greatly appreciated. Thank You!
The IP you're using is inside a NAT since it starts with 192.168. Unless you have a private apn with the mobile operator you're using, you won't be able to reach your Ubuntu from a public IP. Your ISP gives you a public IP address which ir administrated by your router, so if you want this to work, you'll have to do a port forwarding from your router to your Ubuntu.
To do the port forwarding you have to get in the router's configuration page (Typically 192.168.1.1 but depends on the model) an there you'll have to redirect the port XXX to 192.168.1.112:10000. After that you have to obtain your public IP (curl ifconfig.co) and use it to access from the SIM900.
First of all as a suggestion, you can combine the two shields by using SIM908 (unless you are getting more precision on your GPS shield). Since your TCP connection is working, I bet that the port 10000 on your ubuntu is blocked by the firewall. You can first try to turn off your firewall and see if it works. If it did not worked its something else. If it worked, turn on your firewall and then unblock the tcp port using the following command:
sudo ufw allow 10000/tcp
I'm new to openshift,django and python and having a hard time trying to have two internal ports available for a python app I'm trying to install on openshift.
I read some previous post about doing this and I used the code below in an action_hook/deploy with no success.
I also attempted to execute the commands in a python shell via SSH. I received no errors, but when I did a netstat (using value returned from os.environ['OPENSHIFT_PYTHON_IP']), I still do not see the port listed.
Host = os.environ['OPENSHIFT_PYTHON_IP']
bPort = 28081
jqPort = 28092
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((Host, jqPort))
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((Host, bPort))
LIke I said I'm new to both openshift, python and django, and don't know what else to do.
I figured out the issue was in the application.
The application was attempting to bind to the port using local ip address (127.0.0.1), and it needed to use the Openshift assigned IP address. I may have been looking at something wrong when I was using netstat, because even though the above script is using the correct IP address it did not look like it was actually working. When I used the below script (I found on stackoverflow,Check If port is open) to debug, I saw that in fact it was working.
import socket;
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
result = sock.connect_ex(('127.0.0.1',80))
if result == 0:
print "Port is open"
else:
print "Port is not open"
I'm trying to create a Python program that will listen on a socket. I'm using Windows 7 with Python 2.7. Whatever I do, the socket seems to be accessible from the local machine but not from elsewhere on the network.
I've got the following code:
from werkzeug.wrappers import Request, Response
#Request.application
def application(request):
return Response('Hello World!')
if __name__ == '__main__':
from werkzeug.serving import run_simple
# Using empty string or the machine's real IP address here
# gives the same problem
run_simple('0.0.0.0', 4000, application)
If I connect from the local machine I see the response fine. If I execute
$ curl 'http://192.168.1.1:4000/'
from another (linux) box on the network, the curl hangs for a long time before timing out. Wireshark shows that I receive a SYN packet to port 4000 but don't see it ACKed.
I've tried making sure packets to this port are allowed through the firewall (the fact that I see the SYNs in Wireshark suggests this is not the problem). I've tried setting Python to run as administrator (and I've checked that ctypes.windll.shell32.IsUserAnAdmin() returns true). This isn't just Werkzeug, I've tried with SocketServer from the Python standard library as well.
Running Windows Apache on the same port works fine from across the network, which suggests there's no problem with the network or firewall or with my curl request.
netstat -an shows:
TCP 0.0.0.0:4000 0.0.0.0:0 LISTENING
Edit: I've tried with the following minimal code. On the server side (Windows 7):
import socket
s = socket.socket()
s.bind(('', 8080))
s.listen(1)
remotesock, addr = s.accept()
And on the linux client:
import socket
s = socket.socket()
s.connect('192.168.1.1', 8080)
This hangs until timeout, as with the curl.
I believe the problem is due to your address binding. Python does not allow sockets bound to localhost (or 0.0.0.0) to be visible from the outside world. Change the binding to your actual IP Address.
EDIT: Showing example code
Change your code to this
import socket
s = socket.socket()
s.bind(('192.168.1.1', 8080)) # assumes your machine's IP address is 192.168.1.1
s.listen(1)
remotesock, addr = s.accept()